Metadata
| Key | Value |
|---|---|
| engine | transformers |
| prompt | default |
| temp | 0.2 |
| top_p | 0.95 |
| max_new_tokens | 1024 |
| n_completions | 10 |
Solutions
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constantfunc hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constantfunc hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constantfunc hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constantfunc hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constantfunc hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
var sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```var sortedNumbers = numbers.sorted() // variable 'sortedNumbers' was never mutated; consider changing to 'let' constantfunc hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
assistant
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
if sortedNumbers[i] - sortedNumbers[i - 1] < threshold {
return true
}
}
return false
}
```func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 && !group.isEmpty {
result.append(group)
group = ""
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 && !group.isEmpty {
result.append(group)
group = ""
}
}
return result
}
```var parenString = parenString.replacingOccurrences(of: " ", with: "") // variable 'parenString' was never mutated; consider changing to 'let' constantfunc separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
group.append(char)
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
if openParenCount == 0 {
result.append(group)
group = ""
}
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
group.append(char)
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
if openParenCount == 0 {
result.append(group)
group = ""
}
}
}
return result
}
```var parenString = parenString.replacingOccurrences(of: " ", with: "") // variable 'parenString' was never mutated; consider changing to 'let' constantfunc separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
group.append(char)
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
if openParenCount == 0 {
result.append(group)
group = ""
}
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
group.append(char)
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
if openParenCount == 0 {
result.append(group)
group = ""
}
}
}
return result
}
```var parenString = parenString.replacingOccurrences(of: " ", with: "") // variable 'parenString' was never mutated; consider changing to 'let' constantfunc separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString.replacingOccurrences(of: " ", with: "") {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 {
result.append(group)
group = ""
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString.replacingOccurrences(of: " ", with: "") {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 {
result.append(group)
group = ""
}
}
return result
}
```func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 && !group.isEmpty {
result.append(group)
group = ""
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 && !group.isEmpty {
result.append(group)
group = ""
}
}
return result
}
```var parenString = parenString.replacingOccurrences(of: " ", with: "") // variable 'parenString' was never mutated; consider changing to 'let' constantfunc separateParenGroups(parenString: String) -> [String] {
var groups: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString.replacingOccurrences(of: " ", with: "") {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 {
groups.append(group)
group = ""
}
}
return groups
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var groups: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString.replacingOccurrences(of: " ", with: "") {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 {
groups.append(group)
group = ""
}
}
return groups
}
```func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 {
result.append(group)
group = ""
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var result: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 {
result.append(group)
group = ""
}
}
return result
}
```var parenString = parenString.replacingOccurrences(of: " ", with: "") // variable 'parenString' was never mutated; consider changing to 'let' constantfunc separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var groups: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
group.append(char)
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
if openParenCount == 0 {
groups.append(group)
group = ""
}
}
}
return groups
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var groups: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString {
group.append(char)
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
if openParenCount == 0 {
groups.append(group)
group = ""
}
}
}
return groups
}
```var parenString = parenString.replacingOccurrences(of: " ", with: "") // variable 'parenString' was never mutated; consider changing to 'let' constantfunc separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var groups: [String] = []
var group = ""
var openParenCount = 0
for char in parenString {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 && !group.isEmpty {
groups.append(group)
group = ""
}
}
return groups
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var parenString = parenString.replacingOccurrences(of: " ", with: "")
var groups: [String] = []
var group = ""
var openParenCount = 0
for char in parenString {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 && !group.isEmpty {
groups.append(group)
group = ""
}
}
return groups
}
```var parenString = parenString.replacingOccurrences(of: " ", with: "") // variable 'parenString' was never mutated; consider changing to 'let' constantfunc separateParenGroups(parenString: String) -> [String] {
var groups: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString.replacingOccurrences(of: " ", with: "") {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 {
groups.append(group)
group = ""
}
}
return groups
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
assistant
```swift
func separateParenGroups(parenString: String) -> [String] {
var groups: [String] = []
var group: String = ""
var openParenCount: Int = 0
for char in parenString.replacingOccurrences(of: " ", with: "") {
if char == "(" {
openParenCount += 1
} else if char == ")" {
openParenCount -= 1
}
group.append(char)
if openParenCount == 0 {
groups.append(group)
group = ""
}
}
return groups
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func truncateNumber(number: Double) -> Double {
return number - floor(number)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
assistant
```swift
func truncateNumber(number: Double) -> Double {
return number - floor(number)
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
assistant
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let sumOfDeviations = deviations.reduce(0, +)
return sumOfDeviations / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let sumOfDeviations = deviations.reduce(0, +)
return sumOfDeviations / count
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let sumOfDeviations = deviations.reduce(0, +)
return sumOfDeviations / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let sumOfDeviations = deviations.reduce(0, +)
return sumOfDeviations / count
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let deviationSum = deviations.reduce(0, +)
return deviationSum / count
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let sumDeviations = deviations.reduce(0, +)
return sumDeviations / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let sumDeviations = deviations.reduce(0, +)
return sumDeviations / count
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let sumOfDeviations = deviations.reduce(0, +)
return sumOfDeviations / count
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
assistant
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let count = Double(numbers.count)
guard count > 0 else { return 0 }
let sum = numbers.reduce(0, +)
let mean = sum / count
let deviations = numbers.map { abs($0 - mean) }
let sumOfDeviations = deviations.reduce(0, +)
return sumOfDeviations / count
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
guard !numbers.isEmpty else { return [] }
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
guard !numbers.isEmpty else { return [] }
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
assistant
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result: [Int] = []
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}
```func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}
```func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}
```func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}
```func parseNestedParens(parenString: String) -> [Int] {
var nestingLevels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
nestingLevels.append(maxDepth)
}
return nestingLevels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var nestingLevels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
nestingLevels.append(maxDepth)
}
return nestingLevels
}
```func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}
```func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}
```func parseNestedParens(parenString: String) -> [Int] {
var nestingLevels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
nestingLevels.append(maxDepth)
}
return nestingLevels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var nestingLevels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
nestingLevels.append(maxDepth)
}
return nestingLevels
}
```func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}
```func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
assistant
```swift
func parseNestedParens(parenString: String) -> [Int] {
var levels: [Int] = []
let groups = parenString.split(separator: " ")
for group in groups {
var maxDepth = 0
var currentDepth = 0
for char in group {
if char == "(" {
currentDepth += 1
if currentDepth > maxDepth {
maxDepth = currentDepth
}
} else if char == ")" {
currentDepth -= 1
}
}
levels.append(maxDepth)
}
return levels
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
assistant
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
assistant
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxArray.append(max)
}
return maxArray
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxArray.append(max)
}
return maxArray
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
max = max > number ? max : number
maxNumbers.append(max)
}
return maxNumbers
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
max = max > number ? max : number
maxNumbers.append(max)
}
return maxNumbers
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxNumbers.append(max)
}
return maxNumbers
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxNumbers.append(max)
}
return maxNumbers
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxArray.append(max)
}
return maxArray
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxArray.append(max)
}
return maxArray
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxArray.append(max)
}
return maxArray
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxArray.append(max)
}
return maxArray
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
max = max > number ? max : number
maxArray.append(max)
}
return maxArray
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
max = max > number ? max : number
maxArray.append(max)
}
return maxArray
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxNumbers.append(max)
}
return maxNumbers
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxNumbers.append(max)
}
return maxNumbers
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxNumbers.append(max)
}
return maxNumbers
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxNumbers.append(max)
}
return maxNumbers
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxArray.append(max)
}
return maxArray
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxArray = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxArray.append(max)
}
return maxArray
}
```func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxNumbers.append(max)
}
return maxNumbers
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
assistant
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var maxNumbers = [Int]()
var max = Int.min
for number in numbers {
if number > max {
max = number
}
maxNumbers.append(max)
}
return maxNumbers
}
```func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let suffix = String(string.suffix(from: string.index(string.startIndex, offsetBy: i)))
if suffix == String(suffix.reversed()) {
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: i)))
return string + String(prefix.reversed())
}
}
return string + String(reversed)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let suffix = String(string.suffix(from: string.index(string.startIndex, offsetBy: i)))
if suffix == String(suffix.reversed()) {
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: i)))
return string + String(prefix.reversed())
}
}
return string + String(reversed)
}
```func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let postfix = String(string.suffix(from: string.index(string.startIndex, offsetBy: i)))
if postfix == String(postfix.reversed()) {
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: i)))
return string + String(prefix.reversed())
}
}
return string + String(reversed)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let postfix = String(string.suffix(from: string.index(string.startIndex, offsetBy: i)))
if postfix == String(postfix.reversed()) {
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: i)))
return string + String(prefix.reversed())
}
}
return string + String(reversed)
}
```func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let chars = Array(string)
var maxPalindromeLength = 1
for i in stride(from: string.count, through: 1, by: -1) {
let suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):])
if suffix == suffix.reversed() {
maxPalindromeLength = i
break
}
}
let nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):])
let palindrome = string + String(nonPalindromePart.reversed())
return palindrome
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let chars = Array(string)
var maxPalindromeLength = 1
for i in stride(from: string.count, through: 1, by: -1) {
let suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):])
if suffix == suffix.reversed() {
maxPalindromeLength = i
break
}
}
let nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):])
let palindrome = string + String(nonPalindromePart.reversed())
return palindrome
}
```let suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):]) // expected ',' separatorlet suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):]) // missing argument label 'arrayLiteral:' in calllet suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):]) // expected expression in list of expressionslet nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):]) // missing argument label 'arrayLiteral:' in calllet nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):]) // expected ',' separatorlet nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):]) // expected expression in list of expressionsfunc makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let postfix = String(string.suffix(from: string.index(string.startIndex, offsetBy: i)))
if postfix == String(postfix.reversed()) {
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: i)))
return string + String(prefix.reversed())
}
}
return string + String(string.reversed())
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let postfix = String(string.suffix(from: string.index(string.startIndex, offsetBy: i)))
if postfix == String(postfix.reversed()) {
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: i)))
return string + String(prefix.reversed())
}
}
return string + String(string.reversed())
}
```let reversed = String(string.reversed()) // initialization of immutable value 'reversed' was never used; consider replacing with assignment to '_' or removing itfunc makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
var concatenated = string + reversed
while !isPalindrome(string: concatenated) {
let index = concatenated.index(concatenated.startIndex, offsetBy: concatenated.count - 1)
concatenated.remove(at: index)
}
return concatenated
}
func isPalindrome(string: String) -> Bool {
let reversed = String(string.reversed())
return string == reversed
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
var concatenated = string + reversed
while !isPalindrome(string: concatenated) {
let index = concatenated.index(concatenated.startIndex, offsetBy: concatenated.count - 1)
concatenated.remove(at: index)
}
return concatenated
}
func isPalindrome(string: String) -> Bool {
let reversed = String(string.reversed())
return string == reversed
}
``` // XCTAssertTrue failedfunc makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let chars = Array(string)
var maxPalindromeLength = 1
for i in stride(from: string.count, through: 1, by: -1) {
let substring = String(chars[..<chars.index(chars.startIndex, offsetBy: i)])
if isPalindrome(string: substring) {
maxPalindromeLength = i
break
}
}
let nonPalindromePart = string[chars.index(chars.startIndex, offsetBy: maxPalindromeLength)...]
let reversedNonPalindromePart = String(nonPalindromePart.reversed())
return string + reversedNonPalindromePart
}
func isPalindrome(string: String) -> Bool {
let chars = Array(string)
let reversedChars = Array(string.reversed())
return chars == reversedChars
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let chars = Array(string)
var maxPalindromeLength = 1
for i in stride(from: string.count, through: 1, by: -1) {
let substring = String(chars[..<chars.index(chars.startIndex, offsetBy: i)])
if isPalindrome(string: substring) {
maxPalindromeLength = i
break
}
}
let nonPalindromePart = string[chars.index(chars.startIndex, offsetBy: maxPalindromeLength)...]
let reversedNonPalindromePart = String(nonPalindromePart.reversed())
return string + reversedNonPalindromePart
}
func isPalindrome(string: String) -> Bool {
let chars = Array(string)
let reversedChars = Array(string.reversed())
return chars == reversedChars
}
```let nonPalindromePart = string[chars.index(chars.startIndex, offsetBy: maxPalindromeLength)...] // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let chars = Array(string)
var maxPalindromeLength = 1
for i in stride(from: string.count, through: 1, by: -1) {
let suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):])
if suffix == suffix.reversed() {
maxPalindromeLength = i
break
}
}
let nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):])
let palindromePart = nonPalindromePart.reversed()
return string + String(palindromePart)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let chars = Array(string)
var maxPalindromeLength = 1
for i in stride(from: string.count, through: 1, by: -1) {
let suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):])
if suffix == suffix.reversed() {
maxPalindromeLength = i
break
}
}
let nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):])
let palindromePart = nonPalindromePart.reversed()
return string + String(palindromePart)
}
```let suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):]) // expected ',' separatorlet suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):]) // missing argument label 'arrayLiteral:' in calllet suffix = Array(chars[chars.index(chars.startIndex, offsetBy: i - 1):]) // expected expression in list of expressionslet nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):]) // missing argument label 'arrayLiteral:' in calllet nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):]) // expected ',' separatorlet nonPalindromePart = Array(chars[chars.index(chars.startIndex, offsetBy: maxPalindromeLength - 1):]) // expected expression in list of expressionsfunc makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let suffix = String(string.suffix(from: string.index(string.startIndex, offsetBy: i)))
if suffix == String(suffix.reversed()) {
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: i)))
return string + String(prefix.reversed())
}
}
return string + String(reversed)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let suffix = String(string.suffix(from: string.index(string.startIndex, offsetBy: i)))
if suffix == String(suffix.reversed()) {
let prefix = String(string.prefix(upTo: string.index(string.startIndex, offsetBy: i)))
return string + String(prefix.reversed())
}
}
return string + String(reversed)
}
```func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let suffix = String(string[string.index(string.startIndex, offsetBy: i)...])
let prefix = String(string[..<string.index(string.startIndex, offsetBy: i)])
if suffix == String(suffix.reversed()) {
return string + String(prefix.reversed())
}
}
return string + String(string.reversed())
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let reversed = String(string.reversed())
for i in 0..<string.count {
let suffix = String(string[string.index(string.startIndex, offsetBy: i)...])
let prefix = String(string[..<string.index(string.startIndex, offsetBy: i)])
if suffix == String(suffix.reversed()) {
return string + String(prefix.reversed())
}
}
return string + String(string.reversed())
}
```let reversed = String(string.reversed()) // initialization of immutable value 'reversed' was never used; consider replacing with assignment to '_' or removing itfunc makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let chars = Array(string)
var maxPalindromeLength = 0
for i in 0..<chars.count {
var left = i
var right = i
while left >= 0 && right < chars.count && chars[left] == chars[right] {
left -= 1
right += 1
}
maxPalindromeLength = max(maxPalindromeLength, right - left - 1)
}
let nonPalindromeChars = Array(chars[..<chars.index(chars.startIndex, offsetBy: maxPalindromeLength)])
let reversedNonPalindromeChars = nonPalindromeChars.reversed()
return string + String(reversedNonPalindromeChars)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
assistant
```swift
func makePalindrome(string: String) -> String {
guard string.count > 0 else { return "" }
let chars = Array(string)
var maxPalindromeLength = 0
for i in 0..<chars.count {
var left = i
var right = i
while left >= 0 && right < chars.count && chars[left] == chars[right] {
left -= 1
right += 1
}
maxPalindromeLength = max(maxPalindromeLength, right - left - 1)
}
let nonPalindromeChars = Array(chars[..<chars.index(chars.startIndex, offsetBy: maxPalindromeLength)])
let reversedNonPalindromeChars = nonPalindromeChars.reversed()
return string + String(reversedNonPalindromeChars)
}
``` // XCTAssertTrue failedfunc stringXor(a: String, b: String) -> String {
var result = ""
for (aChar, bChar) in zip(a, b) {
if aChar == bChar {
result += "0"
} else {
result += "1"
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
for (aChar, bChar) in zip(a, b) {
if aChar == bChar {
result += "0"
} else {
result += "1"
}
}
return result
}
```func stringXor(a: String, b: String) -> String {
var result = ""
let aArray = Array(a)
let bArray = Array(b)
for i in 0..<aArray.count {
if aArray[i] == bArray[i] {
result += "0"
} else {
result += "1"
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
let aArray = Array(a)
let bArray = Array(b)
for i in 0..<aArray.count {
if aArray[i] == bArray[i] {
result += "0"
} else {
result += "1"
}
}
return result
}
```func stringXor(a: String, b: String) -> String {
var result = ""
for (aChar, bChar) in zip(a, b) {
if aChar == bChar {
result += "0"
} else {
result += "1"
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
for (aChar, bChar) in zip(a, b) {
if aChar == bChar {
result += "0"
} else {
result += "1"
}
}
return result
}
```func stringXor(a: String, b: String) -> String {
var result = ""
for (a, b) in zip(a, b) {
if a == b {
result += "0"
} else {
result += "1"
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
for (a, b) in zip(a, b) {
if a == b {
result += "0"
} else {
result += "1"
}
}
return result
}
```func stringXor(a: String, b: String) -> String {
var result = ""
let aArray = Array(a)
let bArray = Array(b)
for i in 0..<aArray.count {
if aArray[i] == bArray[i] {
result += "0"
} else {
result += "1"
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
let aArray = Array(a)
let bArray = Array(b)
for i in 0..<aArray.count {
if aArray[i] == bArray[i] {
result += "0"
} else {
result += "1"
}
}
return result
}
```func stringXor(a: String, b: String) -> String {
var result = ""
for (a, b) in zip(a, b) {
if a == b {
result += "0"
} else {
result += "1"
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
for (a, b) in zip(a, b) {
if a == b {
result += "0"
} else {
result += "1"
}
}
return result
}
```func stringXor(a: String, b: String) -> String {
var result = ""
for (a, b) in zip(a, b) {
if a == b {
result += "0"
} else {
result += "1"
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
for (a, b) in zip(a, b) {
if a == b {
result += "0"
} else {
result += "1"
}
}
return result
}
```func stringXor(a: String, b: String) -> String {
var result = ""
for (aChar, bChar) in zip(a, b) {
if aChar == bChar {
result += "0"
} else {
result += "1"
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
for (aChar, bChar) in zip(a, b) {
if aChar == bChar {
result += "0"
} else {
result += "1"
}
}
return result
}
```func stringXor(a: String, b: String) -> String {
var result = ""
let aArray = Array(a)
let bArray = Array(b)
for i in 0..<aArray.count {
let aBit = Int(String(aArray[i]))!
let bBit = Int(String(bArray[i]))!
let xorBit = aBit ^ bBit
result += String(xorBit)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
let aArray = Array(a)
let bArray = Array(b)
for i in 0..<aArray.count {
let aBit = Int(String(aArray[i]))!
let bBit = Int(String(bArray[i]))!
let xorBit = aBit ^ bBit
result += String(xorBit)
}
return result
}
```func stringXor(a: String, b: String) -> String {
var result = ""
let aArray = Array(a)
let bArray = Array(b)
for i in 0..<aArray.count {
if aArray[i] == bArray[i] {
result += "0"
} else {
result += "1"
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
assistant
```swift
func stringXor(a: String, b: String) -> String {
var result = ""
let aArray = Array(a)
let bArray = Array(b)
for i in 0..<aArray.count {
if aArray[i] == bArray[i] {
result += "0"
} else {
result += "1"
}
}
return result
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
assistant
```swift
func longest(strings: [String]) -> String? {
if strings.isEmpty {
return nil
}
var longestString = strings[0]
for string in strings {
if string.count > longestString.count {
longestString = string
}
}
return longestString
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let temp = b
b = a % b
a = temp
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let temp = b
b = a % b
a = temp
}
return a
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
assistant
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b != 0 {
let t = b
b = a % b
a = t
}
return a
}
```func allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var prefixes = [String]()
for i in 1...string.count {
let range = string.index(string.startIndex, offsetBy: i)..<string.endIndex
let prefix = String(string[range])
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
assistant
```swift
func allPrefixes(string: String) -> [String] {
var result: [String] = []
for i in 1...string.count {
result.append(String(string.prefix(i)))
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += "\(i) "
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += "\(i) "
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += "\(i) "
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += "\(i) "
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
assistant
```swift
func stringSequence(n: Int) -> String {
var sequence = ""
for i in 0...n {
sequence += " \(i)"
}
return sequence.trimmingCharacters(in: .whitespacesAndNewlines)
}
```func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characterSet = CharacterSet(charactersIn: lowercasedString)
return characterSet.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characterSet = CharacterSet(charactersIn: lowercasedString)
return characterSet.count
}
```return characterSet.count // value of type 'CharacterSet' has no member 'count'func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}
``` // XCTAssertTrue failedfunc countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}
``` // XCTAssertTrue failedfunc countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}
``` // XCTAssertTrue failedfunc countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}
``` // XCTAssertTrue failedfunc countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}
``` // XCTAssertTrue failedfunc countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}
``` // XCTAssertTrue failedfunc countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}
``` // XCTAssertTrue failedfunc countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}
``` // XCTAssertTrue failedfunc countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
assistant
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
let characters = Set(lowercasedString)
let filteredCharacters = characters.filter { $0.isLetter }
return filteredCharacters.count
}
``` // XCTAssertTrue failedfunc parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o| .| o| o| .| .| .| .| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
assistant
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
continue
}
}
return beats
}
```func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex <= string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex <= string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex <= string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex <= string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
assistant
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var startIndex = string.startIndex
while startIndex < string.endIndex {
if let range = string.range(of: substring, options: [], range: startIndex..<string.endIndex, locale: nil) {
count += 1
startIndex = range.upperBound
} else {
break
}
}
return count
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let sortedNumbers = numbers.split(separator: " ").map { numberWords[$0] ?? 0 }.sorted().map { String(describing: $0) }
return sortedNumbers.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let sortedNumbers = numbers.split(separator: " ").map { numberWords[$0] ?? 0 }.sorted().map { String(describing: $0) }
return sortedNumbers.joined(separator: " ")
}
```let sortedNumbers = numbers.split(separator: " ").map { numberWords[$0] ?? 0 }.sorted().map { String(describing: $0) } // cannot convert value of type 'String.SubSequence' (aka 'Substring') to expected argument type 'String'func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}
```func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}
```func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}
```func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}
```func sortNumbers(numbers: String) -> String {
let numbersArray = numbers.split(separator: " ").map { String($0) }
let sortedNumbersArray = numbersArray.sorted {
switch $0 {
case "zero": return $1 != "zero"
case "one": return $1 != "one" && $1 != "zero"
case "two": return $1 != "two" && $1 != "one" && $1 != "zero"
case "three": return $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "four": return $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "five": return $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "six": return $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "seven": return $1 != "seven" && $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "eight": return $1 != "eight" && $1 != "seven" && $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "nine": return false
default: return false
}
}
return sortedNumbersArray.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numbersArray = numbers.split(separator: " ").map { String($0) }
let sortedNumbersArray = numbersArray.sorted {
switch $0 {
case "zero": return $1 != "zero"
case "one": return $1 != "one" && $1 != "zero"
case "two": return $1 != "two" && $1 != "one" && $1 != "zero"
case "three": return $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "four": return $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "five": return $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "six": return $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "seven": return $1 != "seven" && $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "eight": return $1 != "eight" && $1 != "seven" && $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "nine": return false
default: return false
}
}
return sortedNumbersArray.joined(separator: " ")
}
```func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}
```func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}
```func sortNumbers(numbers: String) -> String {
let numbersArray = numbers.split(separator: " ").map { String($0) }
let sortedNumbersArray = numbersArray.sorted {
switch $0 {
case "zero": return $1 != "zero"
case "one": return $1 != "one" && $1 != "zero"
case "two": return $1 != "two" && $1 != "one" && $1 != "zero"
case "three": return $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "four": return $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "five": return $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "six": return $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "seven": return $1 != "seven" && $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "eight": return $1 != "eight" && $1 != "seven" && $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "nine": return false
default: return false
}
}
return sortedNumbersArray.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numbersArray = numbers.split(separator: " ").map { String($0) }
let sortedNumbersArray = numbersArray.sorted {
switch $0 {
case "zero": return $1 != "zero"
case "one": return $1 != "one" && $1 != "zero"
case "two": return $1 != "two" && $1 != "one" && $1 != "zero"
case "three": return $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "four": return $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "five": return $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "six": return $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "seven": return $1 != "seven" && $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "eight": return $1 != "eight" && $1 != "seven" && $1 != "six" && $1 != "five" && $1 != "four" && $1 != "three" && $1 != "two" && $1 != "one" && $1 != "zero"
case "nine": return false
default: return false
}
}
return sortedNumbersArray.joined(separator: " ")
}
```func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
assistant
```swift
func sortNumbers(numbers: String) -> String {
let numberWords: [String: Int] = ["zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9]
let words = numbers.split(separator: " ").map { String($0) }
let sortedWords = words.sorted { numberWords[$0]! < numberWords[$1]! }
return sortedWords.joined(separator: " ")
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
// Sort the array in ascending order
let sortedNumbers = numbers.sorted()
// Initialize the closest pair with the first two elements
var closestPair = (sortedNumbers[0], sortedNumbers[1])
var minDifference = abs(sortedNumbers[0] - sortedNumbers[1])
// Iterate over the array to find a pair with a smaller difference
for i in 1..<sortedNumbers.count - 1 {
let difference = abs(sortedNumbers[i] - sortedNumbers[i + 1])
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i], sortedNumbers[i + 1])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
// Sort the array in ascending order
let sortedNumbers = numbers.sorted()
// Initialize the closest pair with the first two elements
var closestPair = (sortedNumbers[0], sortedNumbers[1])
var minDifference = abs(sortedNumbers[0] - sortedNumbers[1])
// Iterate over the array to find a pair with a smaller difference
for i in 1..<sortedNumbers.count - 1 {
let difference = abs(sortedNumbers[i] - sortedNumbers[i + 1])
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i], sortedNumbers[i + 1])
}
}
return closestPair
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0.0, 0.0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0.0, 0.0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
let sortedNumbers = numbers.sorted()
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}
```func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}user
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assistant
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
let sortedNumbers = numbers.sorted()
var minDifference = Double.infinity
var closestPair: (Double, Double) = (0, 0)
for i in 1..<sortedNumbers.count {
let difference = sortedNumbers[i] - sortedNumbers[i - 1]
if difference < minDifference {
minDifference = difference
closestPair = (sortedNumbers[i - 1], sortedNumbers[i])
}
}
return closestPair
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assistant
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min() ?? 0
let max = numbers.max() ?? 0
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
assistant
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { $0 as? Int }
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
assistant
```swift
func strlen(string: String) -> Int {
return string.count
}
```func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}
```func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}
```func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}
```func largestDivisor(n: Int) -> Int {
var divisor = n - 1
while divisor > 0 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return -1 // Return -1 if no divisor found
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var divisor = n - 1
while divisor > 0 {
if n % divisor == 0 {
return divisor
}
divisor -= 1
}
return -1 // Return -1 if no divisor found
}
```func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}
```func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}
```func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}
```func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1 // return -1 if no divisor found
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1 // return -1 if no divisor found
}
```func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}
```func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
assistant
```swift
func largestDivisor(n: Int) -> Int {
var i = n - 1
while i > 0 {
if n % i == 0 {
return i
}
i -= 1
}
return -1
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
assistant
```swift
func factorize(n: Int) -> [Int] {
var factors = [Int]()
var number = n
var divisor = 2
while number > 1 {
if number % divisor == 0 {
factors.append(divisor)
number /= divisor
} else {
divisor += 1
}
}
return factors
}
```func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if indexDict[number] != nil {
indexDict[number]! += 1
} else {
indexDict[number] = 1
}
}
for (index, number) in numbers.enumerated() {
if indexDict[number]! > 1 {
numbers.remove(at: index)
for (key, value) in indexDict {
if value > 1 && key == number {
indexDict[key] = value - 1
}
}
}
}
return numbers
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if indexDict[number] != nil {
indexDict[number]! += 1
} else {
indexDict[number] = 1
}
}
for (index, number) in numbers.enumerated() {
if indexDict[number]! > 1 {
numbers.remove(at: index)
for (key, value) in indexDict {
if value > 1 && key == number {
indexDict[key] = value - 1
}
}
}
}
return numbers
}
```for (index, number) in numbers.enumerated() { // immutable value 'index' was never used; consider replacing with '_' or removing it // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if indexDict[number] == nil {
indexDict[number] = index
} else {
numbers[index] = -1
}
}
return numbers.filter { $0 != -1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if indexDict[number] == nil {
indexDict[number] = index
} else {
numbers[index] = -1
}
}
return numbers.filter { $0 != -1 }
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
assistant
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var numbers = numbers
var indexDict = [Int: Int]()
for (index, number) in numbers.enumerated() {
if let _ = indexDict[number] {
numbers[index] = -1
} else {
indexDict[number] = index
}
}
return numbers.filter { $0 != -1 }
}
``` // XCTAssertTrue failedfunc flipCase(string: String) -> String {
var flippedString = ""
for char in string {
if char.isUppercase {
flippedString += char.lowercased()
} else {
flippedString += char.uppercased()
}
}
return flippedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var flippedString = ""
for char in string {
if char.isUppercase {
flippedString += char.lowercased()
} else {
flippedString += char.uppercased()
}
}
return flippedString
}
```func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}
```func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}
```func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}
```func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}
```func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}
```func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}
```func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}
```func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}
```func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
assistant
```swift
func flipCase(string: String) -> String {
var result = ""
for char in string {
if char.isUppercase {
result += char.lowercased()
} else {
result += char.uppercased()
}
}
return result
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("", { $0 + $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("", { $0 + $1 })
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("", { $0 + $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("", { $0 + $1 })
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
assistant
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
assistant
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
assistant
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
assistant
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func sortThird(l: [Int]) -> [Int] {
var result = l
let thirdIndices = result.indices.filter { $0 % 3 == 0 }
let thirdValues = thirdIndices.map { result[$0] }
let sortedThirdValues = thirdValues.sorted()
for (index, value) in zip(thirdIndices, sortedThirdValues).enumerated() {
result[thirdIndices[index]] = value
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var result = l
let thirdIndices = result.indices.filter { $0 % 3 == 0 }
let thirdValues = thirdIndices.map { result[$0] }
let sortedThirdValues = thirdValues.sorted()
for (index, value) in zip(thirdIndices, sortedThirdValues).enumerated() {
result[thirdIndices[index]] = value
}
return result
}
```result[thirdIndices[index]] = value // cannot assign value of type '(Range<Array<Int>.Index>.Element, Int)' (aka '(Int, Int)') to subscript of type 'Int'func sortThird(l: [Int]) -> [Int] {
var result = l
var thirdElements = [Int]()
for i in 0..<l.count {
if i % 3 == 0 {
thirdElements.append(l[i])
}
}
thirdElements.sort()
for i in 0..<l.count {
if i % 3 == 0 {
result[i] = thirdElements.removeFirst()
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var result = l
var thirdElements = [Int]()
for i in 0..<l.count {
if i % 3 == 0 {
thirdElements.append(l[i])
}
}
thirdElements.sort()
for i in 0..<l.count {
if i % 3 == 0 {
result[i] = thirdElements.removeFirst()
}
}
return result
}
```func sortThird(l: [Int]) -> [Int] {
var lPrime = l
var thirdIndices = [Int]()
for i in 0..<l.count {
if (i+1) % 3 == 0 {
thirdIndices.append(i)
}
}
let sortedThirdElements = thirdIndices.map { l[$0] }.sorted()
for i in 0..<thirdIndices.count {
lPrime[thirdIndices[i]] = sortedThirdElements[i]
}
return lPrime
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var lPrime = l
var thirdIndices = [Int]()
for i in 0..<l.count {
if (i+1) % 3 == 0 {
thirdIndices.append(i)
}
}
let sortedThirdElements = thirdIndices.map { l[$0] }.sorted()
for i in 0..<thirdIndices.count {
lPrime[thirdIndices[i]] = sortedThirdElements[i]
}
return lPrime
}
``` // XCTAssertTrue failedfunc sortThird(l: [Int]) -> [Int] {
var lPrime = l
var thirdElements = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }.sorted()
for (index, value) in l.enumerated() {
if index % 3 == 0 {
lPrime[index] = thirdElements.removeFirst()
}
}
return lPrime
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var lPrime = l
var thirdElements = l.enumerated().filter { $0.offset % 3 == 0 }.map { $0.element }.sorted()
for (index, value) in l.enumerated() {
if index % 3 == 0 {
lPrime[index] = thirdElements.removeFirst()
}
}
return lPrime
}
```for (index, value) in l.enumerated() { // immutable value 'value' was never used; consider replacing with '_' or removing itfunc sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}
```func sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}
```func sortThird(l: [Int]) -> [Int] {
var result = l
var thirdElements = [Int]()
for i in 0..<l.count {
if i % 3 == 0 {
thirdElements.append(l[i])
}
}
thirdElements.sort()
var j = 0
for i in 0..<l.count {
if i % 3 == 0 {
result[i] = thirdElements[j]
j += 1
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var result = l
var thirdElements = [Int]()
for i in 0..<l.count {
if i % 3 == 0 {
thirdElements.append(l[i])
}
}
thirdElements.sort()
var j = 0
for i in 0..<l.count {
if i % 3 == 0 {
result[i] = thirdElements[j]
j += 1
}
}
return result
}
```func sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}
```func sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}
```func sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
assistant
```swift
func sortThird(l: [Int]) -> [Int] {
var sorted = [Int]()
for i in stride(from: 0, to: l.count, by: 3) {
sorted.append(l[i])
}
sorted.sort()
var result = [Int]()
var sortedIndex = 0
for i in 0..<l.count {
if i % 3 == 0 {
result.append(sorted[sortedIndex])
sortedIndex += 1
} else {
result.append(l[i])
}
}
return result
}
```func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}
print(unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123])) // Output: [0, 2, 3, 5, 9, 123]
```func unique(l: [Int]) -> [Int] {
return Array(Set(l)).sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return Array(Set(l)).sorted()
}
```func unique(l: [Int]) -> [Int] {
return Array(Set(l)).sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return Array(Set(l)).sorted()
}
```func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}
print(unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123])) // Output: [0, 2, 3, 5, 9, 123]
```func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}
print(unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123])) // prints: [0, 2, 3, 5, 9, 123]
```func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}
print(unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123])) // Output: [0, 2, 3, 5, 9, 123]
```func unique(l: [Int]) -> [Int] {
return Array(Set(l)).sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return Array(Set(l)).sorted()
}
```func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}
print(unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123])) // prints: [0, 2, 3, 5, 9, 123]
```func unique(l: [Int]) -> [Int] {
return Array(Set(l)).sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return Array(Set(l)).sorted()
}
```func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
assistant
```swift
func unique(l: [Int]) -> [Int] {
return l.reduce(into: [Int]()) { (result, value) in
if !result.contains(value) {
result.append(value)
}
}.sorted()
}
print(unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123])) // Prints: [0, 2, 3, 5, 9, 123]
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
return l.max()!
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
return l.max()!
}
```func maxElement(l: [Int]) -> Int {
return l.max()!
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
return l.max()!
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for num in l {
if num > max {
max = num
}
}
return max
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for num in l {
if num > max {
max = num
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
return l.max()!
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
assistant
```swift
func maxElement(l: [Int]) -> Int {
return l.max()!
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
let str = String(i)
count += str.filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
let str = String(i)
count += str.filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
assistant
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 0..<n {
if i % 11 == 0 || i % 13 == 0 {
count += String(i).filter { $0 == "7" }.count
}
}
return count
}
```func sortEven(l: [Int]) -> [Int] {
var evens = l.indices.filter { $0 % 2 == 0 }.map { l[$0] }
evens.sort()
var result = l
for (index, value) in zip(l.indices.filter { $0 % 2 == 0 }, evens) {
result[index] = value
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var evens = l.indices.filter { $0 % 2 == 0 }.map { l[$0] }
evens.sort()
var result = l
for (index, value) in zip(l.indices.filter { $0 % 2 == 0 }, evens) {
result[index] = value
}
return result
}
```func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}
```func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}
```func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}
```func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}
```func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}
```func sortEven(l: [Int]) -> [Int] {
var oddIndicesArray = l.indices.filter { $0 % 2 != 0 }
var evenIndicesArray = l.indices.filter { $0 % 2 == 0 }
var evenSortedArray = l.filter { $0 % 2 == 0 }.sorted()
var resultArray = Array<Int>()
for i in 0..<l.count {
if oddIndicesArray.contains(i) {
resultArray.append(l[i])
} else {
resultArray.append(evenSortedArray.removeFirst())
}
}
return resultArray
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var oddIndicesArray = l.indices.filter { $0 % 2 != 0 }
var evenIndicesArray = l.indices.filter { $0 % 2 == 0 }
var evenSortedArray = l.filter { $0 % 2 == 0 }.sorted()
var resultArray = Array<Int>()
for i in 0..<l.count {
if oddIndicesArray.contains(i) {
resultArray.append(l[i])
} else {
resultArray.append(evenSortedArray.removeFirst())
}
}
return resultArray
}
```var oddIndicesArray = l.indices.filter { $0 % 2 != 0 } // variable 'oddIndicesArray' was never mutated; consider changing to 'let' constantvar evenIndicesArray = l.indices.filter { $0 % 2 == 0 } // initialization of variable 'evenIndicesArray' was never used; consider replacing with assignment to '_' or removing it // Fatal error: Can't remove first element from an empty collectionfunc sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}
```func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}
```func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
assistant
```swift
func sortEven(l: [Int]) -> [Int] {
var evenIndices = [Int]()
var evenIndexElements = [Int]()
for i in 0..<l.count {
if i % 2 == 0 {
evenIndices.append(i)
evenIndexElements.append(l[i])
}
}
evenIndexElements.sort()
var result = l
for i in 0..<evenIndices.count {
result[evenIndices[i]] = evenIndexElements[i]
}
return result
}
```func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func primeFib(n: Int) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func fibonacci(_ n: Int) -> Int {
var a = 0
var b = 1
guard n > 0 else { return a }
(0..<n-1).forEach { _ in
let temp = a
a = b
b = temp + b
}
return b
}
var count = 0
var fib = 0
while count < n {
fib += 1
if isPrime(fibonacci(fib)) {
count += 1
}
}
return fibonacci(fib)
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func fibonacci(_ n: Int) -> Int {
var a = 0
var b = 1
guard n > 0 else { return a }
(0..<n-1).forEach { _ in
let temp = a
a = b
b = temp + b
}
return b
}
var count = 0
var fib = 0
while count < n {
fib += 1
if isPrime(fibonacci(fib)) {
count += 1
}
}
return fibonacci(fib)
}
```func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
var a = 0
var b = 1
var count = 0
while true {
let temp = a
a = b
b = temp + b
if isPrime(n: b) {
count += 1
if count == n {
return b
}
}
}
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func primeFib(n: Int) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func fibonacci(_ num: Int) -> Int {
var a = 0
var b = 1
for _ in 0..<num {
let temp = a
a = b
b = temp + b
}
return a
}
var count = 0
var i = 0
while count < n {
let fib = fibonacci(i)
if isPrime(fib) {
count += 1
}
i += 1
}
return fibonacci(i-1)
}user
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
assistant
```swift
func primeFib(n: Int) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func fibonacci(_ num: Int) -> Int {
var a = 0
var b = 1
for _ in 0..<num {
let temp = a
a = b
b = temp + b
}
return a
}
var count = 0
var i = 0
while count < n {
let fib = fibonacci(i)
if isPrime(fib) {
count += 1
}
i += 1
}
return fibonacci(i-1)
}
```func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var start = i + 1
var end = sortedArray.count - 1
while start < end {
let sum = sortedArray[i] + sortedArray[start] + sortedArray[end]
if sum == 0 {
return true
} else if sum < 0 {
start += 1
} else {
end -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var start = i + 1
var end = sortedArray.count - 1
while start < end {
let sum = sortedArray[i] + sortedArray[start] + sortedArray[end]
if sum == 0 {
return true
} else if sum < 0 {
start += 1
} else {
end -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var low = i + 1
var high = sortedArray.count - 1
while low < high {
let sum = sortedArray[i] + sortedArray[low] + sortedArray[high]
if sum == 0 {
return true
} else if sum < 0 {
low += 1
} else {
high -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var low = i + 1
var high = sortedArray.count - 1
while low < high {
let sum = sortedArray[i] + sortedArray[low] + sortedArray[high]
if sum == 0 {
return true
} else if sum < 0 {
low += 1
} else {
high -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
let a = sortedArray[i]
var start = i + 1
var end = sortedArray.count - 1
while start < end {
let b = sortedArray[start]
let c = sortedArray[end]
if a + b + c == 0 {
return true
} else if a + b + c < 0 {
start += 1
} else {
end -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
let a = sortedArray[i]
var start = i + 1
var end = sortedArray.count - 1
while start < end {
let b = sortedArray[start]
let c = sortedArray[end]
if a + b + c == 0 {
return true
} else if a + b + c < 0 {
start += 1
} else {
end -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var j = i + 1
var k = sortedArray.count - 1
while j < k {
let sum = sortedArray[i] + sortedArray[j] + sortedArray[k]
if sum == 0 {
return true
} else if sum < 0 {
j += 1
} else {
k -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var j = i + 1
var k = sortedArray.count - 1
while j < k {
let sum = sortedArray[i] + sortedArray[j] + sortedArray[k]
if sum == 0 {
return true
} else if sum < 0 {
j += 1
} else {
k -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var low = i + 1
var high = sortedArray.count - 1
while low < high {
let sum = sortedArray[i] + sortedArray[low] + sortedArray[high]
if sum == 0 {
return true
} else if sum < 0 {
low += 1
} else {
high -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var low = i + 1
var high = sortedArray.count - 1
while low < high {
let sum = sortedArray[i] + sortedArray[low] + sortedArray[high]
if sum == 0 {
return true
} else if sum < 0 {
low += 1
} else {
high -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var j = i + 1
var k = sortedArray.count - 1
while j < k {
let sum = sortedArray[i] + sortedArray[j] + sortedArray[k]
if sum == 0 {
return true
} else if sum < 0 {
j += 1
} else {
k -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var j = i + 1
var k = sortedArray.count - 1
while j < k {
let sum = sortedArray[i] + sortedArray[j] + sortedArray[k]
if sum == 0 {
return true
} else if sum < 0 {
j += 1
} else {
k -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var j = i + 1
var k = sortedArray.count - 1
while j < k {
let sum = sortedArray[i] + sortedArray[j] + sortedArray[k]
if sum == 0 {
return true
} else if sum < 0 {
j += 1
} else {
k -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var j = i + 1
var k = sortedArray.count - 1
while j < k {
let sum = sortedArray[i] + sortedArray[j] + sortedArray[k]
if sum == 0 {
return true
} else if sum < 0 {
j += 1
} else {
k -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count-2 {
var j = i + 1
var k = sortedArray.count - 1
while j < k {
let sum = sortedArray[i] + sortedArray[j] + sortedArray[k]
if sum == 0 {
return true
} else if sum < 0 {
j += 1
} else {
k -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count-2 {
var j = i + 1
var k = sortedArray.count - 1
while j < k {
let sum = sortedArray[i] + sortedArray[j] + sortedArray[k]
if sum == 0 {
return true
} else if sum < 0 {
j += 1
} else {
k -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var low = i + 1
var high = sortedArray.count - 1
while low < high {
let sum = sortedArray[i] + sortedArray[low] + sortedArray[high]
if sum == 0 {
return true
} else if sum < 0 {
low += 1
} else {
high -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var low = i + 1
var high = sortedArray.count - 1
while low < high {
let sum = sortedArray[i] + sortedArray[low] + sortedArray[high]
if sum == 0 {
return true
} else if sum < 0 {
low += 1
} else {
high -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var low = i + 1
var high = sortedArray.count - 1
while low < high {
let sum = sortedArray[i] + sortedArray[low] + sortedArray[high]
if sum == 0 {
return true
} else if sum < 0 {
low += 1
} else {
high -= 1
}
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
assistant
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count - 2 {
var low = i + 1
var high = sortedArray.count - 1
while low < high {
let sum = sortedArray[i] + sortedArray[low] + sortedArray[high]
if sum == 0 {
return true
} else if sum < 0 {
low += 1
} else {
high -= 1
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc carRaceCollision(n: Int) -> Int {
// Since each car from the first set will collide with a car from the second set,
// the total number of collisions will be equal to the number of cars in each set, which is n.
return n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// Since each car from the first set will collide with a car from the second set,
// the total number of collisions will be equal to the number of cars in each set, which is n.
return n
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions will be equal to the number of cars in each group, which is n.
return n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions will be equal to the number of cars in each group, which is n.
return n
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
// In this case, the number of collisions is equal to the number of cars.
// Because each car from the first set will collide with a car from the second set.
return n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// In this case, the number of collisions is equal to the number of cars.
// Because each car from the first set will collide with a car from the second set.
return n
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions is simply the number of cars in each set, which is n.
return n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions is simply the number of cars in each set, which is n.
return n
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions will be equal to the number of cars in each group, which is n.
return n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions will be equal to the number of cars in each group, which is n.
return n
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
// In this case, the number of collisions is equal to the number of cars.
// Because each car from the first set will collide with a car from the second set.
return n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// In this case, the number of collisions is equal to the number of cars.
// Because each car from the first set will collide with a car from the second set.
return n
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
// In this case, the number of collisions is simply the product of the number of left-moving cars and the number of right-moving cars.
// Since n cars are moving in each direction, the total number of collisions is n * n.
return n * n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// In this case, the number of collisions is simply the product of the number of left-moving cars and the number of right-moving cars.
// Since n cars are moving in each direction, the total number of collisions is n * n.
return n * n
}
```func carRaceCollision(n: Int) -> Int {
// The number of collisions is equal to the product of the number of left-moving cars and the number of right-moving cars.
// Since n cars are moving in each direction, the total number of collisions is n * n.
return n * n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// The number of collisions is equal to the product of the number of left-moving cars and the number of right-moving cars.
// Since n cars are moving in each direction, the total number of collisions is n * n.
return n * n
}
```func carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions will be equal to the number of cars in each group, which is n.
return n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions will be equal to the number of cars in each group, which is n.
return n
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions will be equal to the number of cars in each group, which is n.
return n
}user
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
assistant
```swift
func carRaceCollision(n: Int) -> Int {
// In this scenario, each car from the left will collide with a car from the right.
// So the number of collisions will be equal to the number of cars in each group, which is n.
return n
}
``` // XCTAssertTrue failedfunc incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
assistant
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
assistant
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var numSet = Set<Int>()
for num in l {
if numSet.contains(-num) {
return true
}
numSet.insert(num)
}
return false
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
assistant
```swift
func changeBase(x: Int, base: Int) -> String {
var number = x
var result = ""
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
assistant
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
guard n > 2 else { return 2 }
guard n > 3 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
guard n > 2 else { return 2 }
guard n > 3 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
guard n > 2 else { return 2 }
guard n > 3 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
guard n > 2 else { return 2 }
guard n > 3 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}
```func fib4(n: Int) -> Int {
guard n > 0 else { return 0 }
var fib = [0, 0, 2, 0]
(4...n).forEach { i in
let nextFib = fib[i - 1] + fib[i - 2] + fib[i - 3] + fib[i - 4]
fib.append(nextFib)
}
return fib[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
guard n > 0 else { return 0 }
var fib = [0, 0, 2, 0]
(4...n).forEach { i in
let nextFib = fib[i - 1] + fib[i - 2] + fib[i - 3] + fib[i - 4]
fib.append(nextFib)
}
return fib[n]
}
```func fib4(n: Int) -> Int {
guard n > 0 else { return 0 }
var fib = [0, 0, 2, 0]
for i in 4...n {
let nextFib = fib[i - 1] + fib[i - 2] + fib[i - 3] + fib[i - 4]
fib.append(nextFib)
}
return fib[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
guard n > 0 else { return 0 }
var fib = [0, 0, 2, 0]
for i in 4...n {
let nextFib = fib[i - 1] + fib[i - 2] + fib[i - 3] + fib[i - 4]
fib.append(nextFib)
}
return fib[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
guard n > 2 else { return 2 }
guard n > 3 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
guard n > 2 else { return 2 }
guard n > 3 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}
```func fib4(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
guard n > 2 else { return 2 }
guard n > 3 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
guard n > 2 else { return 2 }
guard n > 3 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}
```func fib4(n: Int) -> Int {
if n < 2 {
return 0
}
if n == 2 {
return 2
}
if n == 3 {
return 0
}
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
if n < 2 {
return 0
}
if n == 2 {
return 2
}
if n == 3 {
return 0
}
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}
```func fib4(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var a = 0
var b = 0
var c = 2
var d = 0
guard n > 2 else {
return n == 2 ? c : n
}
for _ in 3...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var a = 0
var b = 0
var c = 2
var d = 0
guard n > 2 else {
return n == 2 ? c : n
}
for _ in 3...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}
``` // XCTAssertTrue failedfunc fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
assistant
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var a = 0
var b = 0
var c = 2
var d = 0
for _ in 4...n {
let temp = a + b + c + d
a = b
b = c
c = d
d = temp
}
return d
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
assistant
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let count = sorted.count
if count % 2 == 0 {
return Double(sorted[count / 2 - 1] + sorted[count / 2]) / 2
} else {
return Double(sorted[count / 2])
}
}
```func isPalindrome(text: String) -> Bool {
let lowercasedText = text.lowercased()
let reversedText = String(lowercasedText.reversed())
return lowercasedText == reversedText
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let lowercasedText = text.lowercased()
let reversedText = String(lowercasedText.reversed())
return lowercasedText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let lowercased = text.lowercased()
let reversed = String(lowercased.reversed())
return lowercased == reversed
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let lowercased = text.lowercased()
let reversed = String(lowercased.reversed())
return lowercased == reversed
}
```func isPalindrome(text: String) -> Bool {
let cleanedText = text.lowercased().components(separatedBy: CharacterSet.alphanumerics.inverted).joined()
let reversedText = String(cleanedText.reversed())
return cleanedText == reversedText
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let cleanedText = text.lowercased().components(separatedBy: CharacterSet.alphanumerics.inverted).joined()
let reversedText = String(cleanedText.reversed())
return cleanedText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let lowercased = text.lowercased()
let reversed = String(lowercased.reversed())
return lowercased == reversed
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let lowercased = text.lowercased()
let reversed = String(lowercased.reversed())
return lowercased == reversed
}
```func isPalindrome(text: String) -> Bool {
let reversedText = String(text.reversed())
return text == reversedText
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let reversedText = String(text.reversed())
return text == reversedText
}
```func isPalindrome(text: String) -> Bool {
let reversedText = String(text.reversed())
return text == reversedText
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let reversedText = String(text.reversed())
return text == reversedText
}
```func isPalindrome(text: String) -> Bool {
let lowercasedText = text.lowercased()
let reversedText = String(lowercasedText.reversed())
return lowercasedText == reversedText
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let lowercasedText = text.lowercased()
let reversedText = String(lowercasedText.reversed())
return lowercasedText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let lowercasedText = text.lowercased()
let reversedText = String(lowercasedText.reversed())
return lowercasedText == reversedText
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let lowercasedText = text.lowercased()
let reversedText = String(lowercasedText.reversed())
return lowercasedText == reversedText
}
```func isPalindrome(text: String) -> Bool {
let lowercased = text.lowercased()
let reversed = String(lowercased.reversed())
return lowercased == reversed
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let lowercased = text.lowercased()
let reversed = String(lowercased.reversed())
return lowercased == reversed
}
```func isPalindrome(text: String) -> Bool {
let cleanedText = text.lowercased().components(separatedBy: CharacterSet.alphanumerics.inverted).joined()
let reversedText = String(cleanedText.reversed())
return cleanedText == reversedText
}user
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
assistant
```swift
func isPalindrome(text: String) -> Bool {
let cleanedText = text.lowercased().components(separatedBy: CharacterSet.alphanumerics.inverted).joined()
let reversedText = String(cleanedText.reversed())
return cleanedText == reversedText
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b /= 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b /= 2
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b /= 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b /= 2
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b /= 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b /= 2
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b /= 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b /= 2
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
assistant
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
var a = 2
var b = n
while b > 0 {
if b % 2 == 1 {
result = (result * a) % p
}
a = (a * a) % p
b = b / 2
}
return result
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let textArray = Array(text)
let result = textArray.filter { !vowels.contains($0) }
return String(result)
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let textArray = Array(text)
let result = textArray.filter { !vowels.contains($0) }
return String(result)
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}
```func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}user
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
assistant
```swift
func removeVowels(text: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
return String(text.filter { !vowels.contains($0) })
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
return l.allSatisfy { $0 < t }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
return l.allSatisfy { $0 < t }
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
assistant
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}user
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
assistant
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.lowercased().sorted())
let sortedS1 = String(s1.lowercased().sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.lowercased().sorted())
let sortedS1 = String(s1.lowercased().sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
assistant
```swift
func sameChars(s0: String, s1: String) -> Bool {
let sortedS0 = String(s0.sorted())
let sortedS1 = String(s1.sorted())
return sortedS0 == sortedS1
}
``` // XCTAssertTrue failedfunc fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}
```func fib(n: Int) -> Int {
guard n > 0 else {
return 0
}
var a = 0
var b = 1
for _ in 2...n {
(a, b) = (b, a + b)
}
return b
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else {
return 0
}
var a = 0
var b = 1
for _ in 2...n {
(a, b) = (b, a + b)
}
return b
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc fib(n: Int) -> Int {
guard n > 0 else {
return 0
}
var a = 0
var b = 1
for _ in 2...n {
(a, b) = (b, a + b)
}
return b
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else {
return 0
}
var a = 0
var b = 1
for _ in 2...n {
(a, b) = (b, a + b)
}
return b
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}
```func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}
```func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}
```func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}
```func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(1..<n).forEach { _ in
(a, b) = (b, a + b)
}
return b
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(1..<n).forEach { _ in
(a, b) = (b, a + b)
}
return b
}
```func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}
```func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
assistant
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
var a = 0
var b = 1
(0..<n).forEach { _ in
(a, b) = (b, a + b)
}
return a
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
switch bracket {
case "<":
stack.append(bracket)
case ">":
if stack.isEmpty || stack.removeLast() != "<".unicodeScalars.first {
return false
}
default:
continue
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
switch bracket {
case "<":
stack.append(bracket)
case ">":
if stack.isEmpty || stack.removeLast() != "<".unicodeScalars.first {
return false
}
default:
continue
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'if stack.isEmpty || stack.removeLast() != "<".unicodeScalars.first { // cannot convert value of type 'String.UnicodeScalarView.Element?' (aka 'Optional<Unicode.Scalar>') to expected argument type 'Character'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets.unicodeScalars {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty || stack.removeLast() != "<" {
return false
}
}
}
return stack.isEmpty
}
```stack.append(bracket) // cannot convert value of type 'Unicode.Scalar' to expected argument type 'Character'func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
let diffs = zip(l[0..<l.count-1], l[1..<l.count]).map { $1 - $0 }
let increasing = diffs.allSatisfy { $0 >= 0 }
let decreasing = diffs.allSatisfy { $0 <= 0 }
return increasing || decreasing
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
let diffs = zip(l[0..<l.count-1], l[1..<l.count]).map { $1 - $0 }
let increasing = diffs.allSatisfy { $0 >= 0 }
let decreasing = diffs.allSatisfy { $0 <= 0 }
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}
```func monotonic(l: [Int]) -> Bool {
var isIncreasing = true
var isDecreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
isIncreasing = false
}
if l[i] < l[i + 1] {
isDecreasing = false
}
}
return isIncreasing || isDecreasing
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
var isIncreasing = true
var isDecreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
isIncreasing = false
}
if l[i] < l[i + 1] {
isDecreasing = false
}
}
return isIncreasing || isDecreasing
}
```func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}
```func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}
```func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}
```func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return true
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return increasing || decreasing
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 1..<l.count {
if l[i] > l[i - 1] {
decreasing = false
}
if l[i] < l[i - 1] {
increasing = false
}
if !increasing && !decreasing {
return false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
let diffs = zip(l[0..<l.count-1], l[1..<l.count]).map { $1 - $0 }
let increasing = diffs.allSatisfy { $0 >= 0 }
let decreasing = diffs.allSatisfy { $0 <= 0 }
return increasing || decreasing
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
assistant
```swift
func monotonic(l: [Int]) -> Bool {
guard l.count > 1 else { return true }
let diffs = zip(l[0..<l.count-1], l[1..<l.count]).map { $1 - $0 }
let increasing = diffs.allSatisfy { $0 >= 0 }
let decreasing = diffs.allSatisfy { $0 <= 0 }
return increasing || decreasing
}
```func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
assistant
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let commonElements = Array(Set(l1) & Set(l2))
return commonElements.sorted()
}
```let commonElements = Array(Set(l1) & Set(l2)) // binary operator '&' cannot be applied to two 'Set<Int>' operandsfunc largestPrimeFactor(n: Int) -> Int {
var number = n
var factor = 2
var largest = 0
while number > 1 {
if number % factor == 0 {
largest = factor
number /= factor
while number % factor == 0 {
number /= factor
}
}
factor += 1
}
return largest
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var factor = 2
var largest = 0
while number > 1 {
if number % factor == 0 {
largest = factor
number /= factor
while number % factor == 0 {
number /= factor
}
}
factor += 1
}
return largest
}
```func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestFactor = -1
// Divide number by 2 until it's an odd number
while number % 2 == 0 {
largestFactor = 2
number /= 2
}
// Divide number by odd numbers starting from 3 until sqrt(number)
for factor in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
while number % factor == 0 {
largestFactor = factor
number /= factor
}
}
// If number is still a prime number and larger than 2
if number > 2 {
largestFactor = number
}
return largestFactor
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestFactor = -1
// Divide number by 2 until it's an odd number
while number % 2 == 0 {
largestFactor = 2
number /= 2
}
// Divide number by odd numbers starting from 3 until sqrt(number)
for factor in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
while number % factor == 0 {
largestFactor = factor
number /= factor
}
}
// If number is still a prime number and larger than 2
if number > 2 {
largestFactor = number
}
return largestFactor
}
```func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestPrime = -1
while number % 2 == 0 {
largestPrime = 2
number /= 2
}
var factor = 3
let sqrtn = Int(Double(number).squareRoot())
while number > 1 && factor <= sqrtn {
while number % factor == 0 {
largestPrime = factor
number /= factor
sqrtn = Int(Double(number).squareRoot())
}
factor += 2
}
if number > 2 {
largestPrime = number
}
return largestPrime
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestPrime = -1
while number % 2 == 0 {
largestPrime = 2
number /= 2
}
var factor = 3
let sqrtn = Int(Double(number).squareRoot())
while number > 1 && factor <= sqrtn {
while number % factor == 0 {
largestPrime = factor
number /= factor
sqrtn = Int(Double(number).squareRoot())
}
factor += 2
}
if number > 2 {
largestPrime = number
}
return largestPrime
}
```sqrtn = Int(Double(number).squareRoot()) // cannot assign to value: 'sqrtn' is a 'let' constantfunc largestPrimeFactor(n: Int) -> Int {
var number = n
var largestPrime = -1
while number % 2 == 0 {
largestPrime = 2
number /= 2
}
var factor = 3
let sqrtn = Int(Double(number).squareRoot())
while number > 1 && factor <= sqrtn {
while number % factor == 0 {
largestPrime = factor
number /= factor
sqrtn = Int(Double(number).squareRoot())
}
factor += 2
}
if number > 2 {
largestPrime = number
}
return largestPrime
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestPrime = -1
while number % 2 == 0 {
largestPrime = 2
number /= 2
}
var factor = 3
let sqrtn = Int(Double(number).squareRoot())
while number > 1 && factor <= sqrtn {
while number % factor == 0 {
largestPrime = factor
number /= factor
sqrtn = Int(Double(number).squareRoot())
}
factor += 2
}
if number > 2 {
largestPrime = number
}
return largestPrime
}
```sqrtn = Int(Double(number).squareRoot()) // cannot assign to value: 'sqrtn' is a 'let' constantfunc largestPrimeFactor(n: Int) -> Int {
var number = n
var largestFactor = 1
// Divide number by 2 until it's an odd number
while number % 2 == 0 {
largestFactor = 2
number /= 2
}
// Check odd factors starting from 3 up to square root of number
for factor in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
while number % factor == 0 {
largestFactor = factor
number /= factor
}
}
// If number is still a prime number larger than 2
if number > 2 {
largestFactor = number
}
return largestFactor
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestFactor = 1
// Divide number by 2 until it's an odd number
while number % 2 == 0 {
largestFactor = 2
number /= 2
}
// Check odd factors starting from 3 up to square root of number
for factor in stride(from: 3, through: Int(sqrt(Double(number))), by: 2) {
while number % factor == 0 {
largestFactor = factor
number /= factor
}
}
// If number is still a prime number larger than 2
if number > 2 {
largestFactor = number
}
return largestFactor
}
```func largestPrimeFactor(n: Int) -> Int {
var number = n
var factor = 2
var largest = 0
while number > 1 {
if number % factor == 0 {
largest = factor
number /= factor
while number % factor == 0 {
number /= factor
}
}
factor += 1
}
return largest
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var factor = 2
var largest = 0
while number > 1 {
if number % factor == 0 {
largest = factor
number /= factor
while number % factor == 0 {
number /= factor
}
}
factor += 1
}
return largest
}
```func largestPrimeFactor(n: Int) -> Int {
var number = n
var largest = 0
var divisor = 2
while number > 1 {
if number % divisor == 0 {
largest = divisor
number /= divisor
} else {
divisor += 1
}
}
return largest
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var largest = 0
var divisor = 2
while number > 1 {
if number % divisor == 0 {
largest = divisor
number /= divisor
} else {
divisor += 1
}
}
return largest
}
```func largestPrimeFactor(n: Int) -> Int {
var number = n
var largest = 0
var divisor = 2
while number > 1 {
if number % divisor == 0 {
largest = divisor
number /= divisor
while number % divisor == 0 {
number /= divisor
}
}
divisor += 1
}
return largest
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var largest = 0
var divisor = 2
while number > 1 {
if number % divisor == 0 {
largest = divisor
number /= divisor
while number % divisor == 0 {
number /= divisor
}
}
divisor += 1
}
return largest
}
```func largestPrimeFactor(n: Int) -> Int {
var number = n
var factor = 2
var largest = 0
while number > 1 {
if number % factor == 0 {
number /= factor
largest = factor
} else {
factor += 1
}
}
return largest
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var factor = 2
var largest = 0
while number > 1 {
if number % factor == 0 {
number /= factor
largest = factor
} else {
factor += 1
}
}
return largest
}
```func largestPrimeFactor(n: Int) -> Int {
var number = n
var factor = 2
var largest = 0
while number > 1 {
if number % factor == 0 {
number /= factor
largest = factor
} else {
factor += 1
}
}
return largest
}user
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
assistant
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var factor = 2
var largest = 0
while number > 1 {
if number % factor == 0 {
number /= factor
largest = factor
} else {
factor += 1
}
}
return largest
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
assistant
```swift
func sumToN(n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.pop() != "(" { // value of type '[Character]' has no member 'pop'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.pop() != "(" { // value of type '[Character]' has no member 'pop'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.pop() != "(" { // value of type '[Character]' has no member 'pop'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.pop() != "(" { // value of type '[Character]' has no member 'pop'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.pop() != "(" { // value of type '[Character]' has no member 'pop'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.pop() != "(" { // value of type '[Character]' has no member 'pop'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.pop() != "(" { // value of type '[Character]' has no member 'pop'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.pop() != "(" { // value of type '[Character]' has no member 'pop'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.removeLast() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.removeLast() != "(" {
return false
}
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
assistant
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "(" {
stack.append(bracket)
} else if bracket == ")" {
if stack.isEmpty || stack.pop() != "(" {
return false
}
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.pop() != "(" { // value of type '[Character]' has no member 'pop'func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for i in 1..<xs.count {
result.append(i * xs[i])
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for i in 1..<xs.count {
result.append(i * xs[i])
}
return result
}
```func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}
```func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for i in 1..<xs.count {
result.append(i * xs[i])
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for i in 1..<xs.count {
result.append(i * xs[i])
}
return result
}
```func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}
```func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}
```func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for i in 1..<xs.count {
result.append(i * xs[i])
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for i in 1..<xs.count {
result.append(i * xs[i])
}
return result
}
```func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for i in 1..<xs.count {
result.append(i * xs[i])
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for i in 1..<xs.count {
result.append(i * xs[i])
}
return result
}
```func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}
```func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}
```func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}user
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
assistant
```swift
func derivative(xs: [Int]) -> [Int] {
var derivativeCoefficients = [Int]()
for i in 1..<xs.count {
derivativeCoefficients.append(i * xs[i])
}
return derivativeCoefficients
}
```func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var a = 0
var b = 0
var c = 1
guard n > 2 else {
return n == 2 ? c : a
}
for _ in 3...n {
let temp = a + b + c
a = b
b = c
c = temp
}
return c
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var a = 0
var b = 0
var c = 1
guard n > 2 else {
return n == 2 ? c : a
}
for _ in 3...n {
let temp = a + b + c
a = b
b = c
c = temp
}
return c
}
```func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [Int](repeating: 0, count: max(n + 1, 3))
fibfibs[2] = 1
for i in 3..<n + 1 {
fibfibs[i] = fibfibs[i - 1] + fibfibs[i - 2] + fibfibs[i - 3]
}
return fibfibs[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [Int](repeating: 0, count: max(n + 1, 3))
fibfibs[2] = 1
for i in 3..<n + 1 {
fibfibs[i] = fibfibs[i - 1] + fibfibs[i - 2] + fibfibs[i - 3]
}
return fibfibs[n]
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [Int](repeating: 0, count: n + 1)
if n > 0 {
fibfibs[1] = 0
}
if n > 1 {
fibfibs[2] = 1
}
for i in 3...n {
fibfibs[i] = fibfibs[i - 1] + fibfibs[i - 2] + fibfibs[i - 3]
}
return fibfibs[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [Int](repeating: 0, count: n + 1)
if n > 0 {
fibfibs[1] = 0
}
if n > 1 {
fibfibs[2] = 1
}
for i in 3...n {
fibfibs[i] = fibfibs[i - 1] + fibfibs[i - 2] + fibfibs[i - 3]
}
return fibfibs[n]
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
let nextFibfib = fibfibs[i-1] + fibfibs[i-2] + fibfibs[i-3]
fibfibs.append(nextFibfib)
}
return fibfibs[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
let nextFibfib = fibfibs[i-1] + fibfibs[i-2] + fibfibs[i-3]
fibfibs.append(nextFibfib)
}
return fibfibs[n]
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
let nextFibfib = fibfibs[i - 1] + fibfibs[i - 2] + fibfibs[i - 3]
fibfibs.append(nextFibfib)
}
return fibfibs[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
let nextFibfib = fibfibs[i - 1] + fibfibs[i - 2] + fibfibs[i - 3]
fibfibs.append(nextFibfib)
}
return fibfibs[n]
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc fibfib(n: Int) -> Int {
guard n > 0 else { return 0 }
var fibfibs = [0, 0, 1]
for i in 3...n {
let nextFibfib = fibfibs[i - 1] + fibfibs[i - 2] + fibfibs[i - 3]
fibfibs.append(nextFibfib)
}
return fibfibs[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
guard n > 0 else { return 0 }
var fibfibs = [0, 0, 1]
for i in 3...n {
let nextFibfib = fibfibs[i - 1] + fibfibs[i - 2] + fibfibs[i - 3]
fibfibs.append(nextFibfib)
}
return fibfibs[n]
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
fibfibs.append(fibfibs[i-1] + fibfibs[i-2] + fibfibs[i-3])
}
return fibfibs[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
fibfibs.append(fibfibs[i-1] + fibfibs[i-2] + fibfibs[i-3])
}
return fibfibs[n]
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc fibfib(n: Int) -> Int {
if n < 0 {
return -1
}
if n == 0 || n == 1 {
return 0
}
if n == 2 {
return 1
}
var a = 0
var b = 0
var c = 1
var d = 0
for _ in 3...n {
d = a + b + c
a = b
b = c
c = d
}
return d
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
if n < 0 {
return -1
}
if n == 0 || n == 1 {
return 0
}
if n == 2 {
return 1
}
var a = 0
var b = 0
var c = 1
var d = 0
for _ in 3...n {
d = a + b + c
a = b
b = c
c = d
}
return d
}
```func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
fibfibs.append(fibfibs[i-1] + fibfibs[i-2] + fibfibs[i-3])
}
return fibfibs[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
fibfibs.append(fibfibs[i-1] + fibfibs[i-2] + fibfibs[i-3])
}
return fibfibs[n]
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
fibfibs.append(fibfibs[i-1] + fibfibs[i-2] + fibfibs[i-3])
}
return fibfibs[n]
}user
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
assistant
```swift
func fibfib(n: Int) -> Int {
guard n >= 0 else {
return 0
}
var fibfibs = [0, 0, 1]
for i in 3...n {
fibfibs.append(fibfibs[i-1] + fibfibs[i-2] + fibfibs[i-3])
}
return fibfibs[n]
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last ?? ""
let count = string.filter { vowels.contains($0) }.count
return lastCharacter == "y" ? count + 1 : count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last ?? ""
let count = string.filter { vowels.contains($0) }.count
return lastCharacter == "y" ? count + 1 : count
}
```let lastCharacter = string.last ?? "" // binary operator '??' cannot be applied to operands of type 'String.Element?' (aka 'Optional<Character>') and 'String'func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
var count = 0
for char in string {
if vowels.contains(char) {
count += 1
}
}
if string.hasSuffix("y") {
count += 1
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
var count = 0
for char in string {
if vowels.contains(char) {
count += 1
}
}
if string.hasSuffix("y") {
count += 1
}
return count
}
```func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
var count = 0
for i in 0..<string.count {
let isLastCharacter = i == string.count - 1
let character = string[string.index(string.startIndex, offsetBy: i)]
if (character == "y" && isLastCharacter) || vowels.contains(character) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
var count = 0
for i in 0..<string.count {
let isLastCharacter = i == string.count - 1
let character = string[string.index(string.startIndex, offsetBy: i)]
if (character == "y" && isLastCharacter) || vowels.contains(character) {
count += 1
}
}
return count
}
```func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last
var count = 0
for char in string {
if vowels.contains(char) {
count += 1
}
}
if let lastCharacter = lastCharacter, lastCharacter == "y" {
count += 1
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last
var count = 0
for char in string {
if vowels.contains(char) {
count += 1
}
}
if let lastCharacter = lastCharacter, lastCharacter == "y" {
count += 1
}
return count
}
```func vowelsCount(s: String) -> Int {
let vowels = ["a", "e", "i", "o", "u"]
var count = 0
let lowercased = s.lowercased()
for i in lowercased {
if vowels.contains(String(i)) {
count += 1
}
}
if let last = lowercased.last, last == "y" {
count += 1
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels = ["a", "e", "i", "o", "u"]
var count = 0
let lowercased = s.lowercased()
for i in lowercased {
if vowels.contains(String(i)) {
count += 1
}
}
if let last = lowercased.last, last == "y" {
count += 1
}
return count
}
```func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
var count = 0
for char in string {
if vowels.contains(char) {
count += 1
}
}
// Check if last character is 'y' or 'Y'
if string.last == "y" || string.last == "Y" {
count += 1
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
var count = 0
for char in string {
if vowels.contains(char) {
count += 1
}
}
// Check if last character is 'y' or 'Y'
if string.last == "y" || string.last == "Y" {
count += 1
}
return count
}
```func vowelsCount(s: String) -> Int {
let vowels = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
var count = 0
for i in 0..<string.count {
let character = string[string.index(string.startIndex, offsetBy: i)]
if vowels.contains(String(character)) {
count += 1
}
}
// Check if last character is 'y' or 'Y'
if let lastChar = string.last, (lastChar == "y" || lastChar == "Y") {
count += 1
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
var count = 0
for i in 0..<string.count {
let character = string[string.index(string.startIndex, offsetBy: i)]
if vowels.contains(String(character)) {
count += 1
}
}
// Check if last character is 'y' or 'Y'
if let lastChar = string.last, (lastChar == "y" || lastChar == "Y") {
count += 1
}
return count
}
```func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last
var count = 0
for character in string {
if vowels.contains(character) {
count += 1
}
}
if let lastCharacter = lastCharacter, lastCharacter == "y" {
count += 1
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last
var count = 0
for character in string {
if vowels.contains(character) {
count += 1
}
}
if let lastCharacter = lastCharacter, lastCharacter == "y" {
count += 1
}
return count
}
```func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last
var count = 0
for char in string {
if vowels.contains(char) {
count += 1
}
}
if lastCharacter == "y" {
count += 1
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last
var count = 0
for char in string {
if vowels.contains(char) {
count += 1
}
}
if lastCharacter == "y" {
count += 1
}
return count
}
```func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last
var count = 0
for character in string {
if vowels.contains(character) {
count += 1
}
}
if let lastCharacter = lastCharacter, lastCharacter == "y" {
count += 1
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
assistant
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u"]
let string = s.lowercased()
let lastCharacter = string.last
var count = 0
for character in string {
if vowels.contains(character) {
count += 1
}
}
if let lastCharacter = lastCharacter, lastCharacter == "y" {
count += 1
}
return count
}
```func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = String(str[index...]) + String(str[..<index])
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = String(str[index...]) + String(str[..<index])
return result
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = String(str[index...]) + String(str[..<index])
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = String(str[index...]) + String(str[..<index])
return result
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = String(str[index...]) + String(str[..<index])
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = String(str[index...]) + String(str[..<index])
return result
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = String(str[index...]) + String(str[..<index])
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = String(str[index...]) + String(str[..<index])
return result
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
assistant
```swift
func circularShift(x: Int, shift: Int) -> String {
let str = String(x)
let count = str.count
if shift >= count {
return String(str.reversed())
}
let index = str.index(str.startIndex, offsetBy: count - shift)
let result = str[index...] + str[..<index]
return String(result)
}
``` // XCTAssertTrue failedfunc digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
assistant
```swift
func digitSum(s: String) -> Int {
var sum = 0
for char in s {
if char.isUppercase {
sum += Int(char.asciiValue ?? 0)
}
}
return sum
}
```func fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalApples = numbers[0]
let totalOranges = numbers[1]
let totalFruits = totalApples + totalOranges
let totalMangoes = n - totalFruits
return totalMangoes
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalApples = numbers[0]
let totalOranges = numbers[1]
let totalFruits = totalApples + totalOranges
let totalMangoes = n - totalFruits
return totalMangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalApples = numbers[0]
let totalOranges = numbers[1]
let totalMangoes = n - (totalApples + totalOranges)
return totalMangoes
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalApples = numbers[0]
let totalOranges = numbers[1]
let totalMangoes = n - (totalApples + totalOranges)
return totalMangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
return n - appleCount - orangeCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
return n - appleCount - orangeCount
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalApples = numbers[0]
let totalOranges = numbers[1]
let totalMangoes = n - (totalApples + totalOranges)
return totalMangoes
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalApples = numbers[0]
let totalOranges = numbers[1]
let totalMangoes = n - (totalApples + totalOranges)
return totalMangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
return n - appleCount - orangeCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
return n - appleCount - orangeCount
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalApples = numbers[0]
let totalOranges = numbers[1]
let totalMangoes = n - (totalApples + totalOranges)
return totalMangoes
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalApples = numbers[0]
let totalOranges = numbers[1]
let totalMangoes = n - (totalApples + totalOranges)
return totalMangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
let mangoCount = n - (appleCount + orangeCount)
return mangoCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
let mangoCount = n - (appleCount + orangeCount)
return mangoCount
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalFruits = numbers.reduce(0, +)
return n - totalFruits
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let numbers = s.components(separatedBy: " ").compactMap { Int($0) }
let totalFruits = numbers.reduce(0, +)
return n - totalFruits
}
```func fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
let mangoCount = n - (appleCount + orangeCount)
return mangoCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
let mangoCount = n - (appleCount + orangeCount)
return mangoCount
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
let mangoCount = n - (appleCount + orangeCount)
return mangoCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
assistant
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let components = s.split(separator: " ")
let appleCount = Int(components[0])!
let orangeCount = Int(components[4])!
let mangoCount = n - (appleCount + orangeCount)
return mangoCount
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value < smallestEvenValue || index < smallestEvenIndex {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value < smallestEvenValue || index < smallestEvenIndex {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}
```func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}
```func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
return smallestEvenValue == Int.max ? [] : [smallestEvenValue, smallestEvenIndex]
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
return smallestEvenValue == Int.max ? [] : [smallestEvenValue, smallestEvenIndex]
}
```func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
return smallestEvenValue == Int.max ? [] : [smallestEvenValue, smallestEvenIndex]
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
return smallestEvenValue == Int.max ? [] : [smallestEvenValue, smallestEvenIndex]
}
```func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}
```func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}
```func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}
```func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
if smallestEvenValue == Int.max {
return []
} else {
return [smallestEvenValue, smallestEvenIndex]
}
}
```func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
return smallestEvenValue == Int.max ? [] : [smallestEvenValue, smallestEvenIndex]
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
return smallestEvenValue == Int.max ? [] : [smallestEvenValue, smallestEvenIndex]
}
```func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
return smallestEvenValue == Int.max ? [] : [smallestEvenValue, smallestEvenIndex]
}user
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
assistant
```swift
func pluck(arr: [Int]) -> [Int] {
var smallestEvenValue = Int.max
var smallestEvenIndex = Int.max
for (index, value) in arr.enumerated() {
if value % 2 == 0 && value <= smallestEvenValue {
if value == smallestEvenValue {
smallestEvenIndex = min(smallestEvenIndex, index)
} else {
smallestEvenValue = value
smallestEvenIndex = index
}
}
}
return smallestEvenValue == Int.max ? [] : [smallestEvenValue, smallestEvenIndex]
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (key, value) in dict {
if key > 0 && value >= key && key > result {
result = key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (key, value) in dict {
if key > 0 && value >= key && key > result {
result = key
}
}
return result
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (key, value) in dict {
if key <= value && key > result {
result = key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (key, value) in dict {
if key <= value && key > result {
result = key
}
}
return result
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (key, value) in dict {
if key > 0 && value >= key && key > result {
result = key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (key, value) in dict {
if key > 0 && value >= key && key > result {
result = key
}
}
return result
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}
```func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
assistant
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
var result = -1
for (num, freq) in dict {
if num > 0 && freq >= num && num > result {
result = num
}
}
return result
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var resultList: [Int] = []
while !sortedList.isEmpty {
resultList.append(sortedList.removeFirst())
if !sortedList.isEmpty {
resultList.append(sortedList.removeLast())
}
}
return resultList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var resultList: [Int] = []
while !sortedList.isEmpty {
resultList.append(sortedList.removeFirst())
if !sortedList.isEmpty {
resultList.append(sortedList.removeLast())
}
}
return resultList
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
assistant
```swift
func strangeSortList(lst: [Int]) -> [Int] {
var sortedList = lst.sorted()
var result = [Int]()
while !sortedList.isEmpty {
result.append(sortedList.removeFirst())
if !sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
assistant
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b > c && a + c > b && b + c > a {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
} else {
return -1
}
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
var isPalindrome = true
for i in 0..<q.count / 2 {
if q[i] != q[q.count - 1 - i] {
isPalindrome = false
break
}
}
// If it's not palindromic, return false
if !isPalindrome {
return false
}
// Check if the sum of the elements is less than or equal to the maximum weight
let sum = q.reduce(0, +)
return sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
var isPalindrome = true
for i in 0..<q.count / 2 {
if q[i] != q[q.count - 1 - i] {
isPalindrome = false
break
}
}
// If it's not palindromic, return false
if !isPalindrome {
return false
}
// Check if the sum of the elements is less than or equal to the maximum weight
let sum = q.reduce(0, +)
return sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
var isPalindrome = true
for i in 0..<q.count / 2 {
if q[i] != q[q.count - 1 - i] {
isPalindrome = false
break
}
}
// If it's not palindromic, return false
if !isPalindrome {
return false
}
// Check if the sum of the elements is less than or equal to the maximum weight
let sum = q.reduce(0, +)
return sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
var isPalindrome = true
for i in 0..<q.count / 2 {
if q[i] != q[q.count - 1 - i] {
isPalindrome = false
break
}
}
// If it's not palindromic, return false
if !isPalindrome {
return false
}
// Check if the sum of the elements is less than or equal to the maximum weight
let sum = q.reduce(0, +)
return sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight
return isPalindrome && sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight
return isPalindrome && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
var isPalindrome = true
for i in 0...(q.count - 1) / 2 {
if q[i] != q[q.count - 1 - i] {
isPalindrome = false
break
}
}
// If it's not palindromic, return false
if !isPalindrome {
return false
}
// Check if the sum of the elements is less than or equal to the maximum weight
let sum = q.reduce(0, +)
return sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
var isPalindrome = true
for i in 0...(q.count - 1) / 2 {
if q[i] != q[q.count - 1 - i] {
isPalindrome = false
break
}
}
// If it's not palindromic, return false
if !isPalindrome {
return false
}
// Check if the sum of the elements is less than or equal to the maximum weight
let sum = q.reduce(0, +)
return sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
assistant
```swift
func willItFly(q: [Int], w: Int) -> Bool {
// Check if the array is palindromic
let isPalindrome = q == q.reversed()
// Calculate the sum of the array elements
let sum = q.reduce(0, +)
// Return true if the array is palindromic and the sum is less than or equal to the maximum weight, false otherwise
return isPalindrome && sum <= w
}
```func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}
```func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}
```func smallestChange(arr: [Int]) -> Int {
var changes = 0
var start = 0
var end = arr.count - 1
while start < end {
if arr[start] != arr[end] {
changes += 1
}
start += 1
end -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var changes = 0
var start = 0
var end = arr.count - 1
while start < end {
if arr[start] != arr[end] {
changes += 1
}
start += 1
end -= 1
}
return changes
}
```func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}
```func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}
```func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var changes = 0
var i = 0
var j = arr.count - 1
while i < j {
if arr[i] != arr[j] {
changes += 1
}
i += 1
j -= 1
}
return changes
}
```func smallestChange(arr: [Int]) -> Int {
var changes = 0
var start = 0
var end = arr.count - 1
while start < end {
if arr[start] != arr[end] {
changes += 1
}
start += 1
end -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var changes = 0
var start = 0
var end = arr.count - 1
while start < end {
if arr[start] != arr[end] {
changes += 1
}
start += 1
end -= 1
}
return changes
}
```func smallestChange(arr: [Int]) -> Int {
var changes = 0
var start = 0
var end = arr.count - 1
while start < end {
if arr[start] != arr[end] {
changes += 1
}
start += 1
end -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var changes = 0
var start = 0
var end = arr.count - 1
while start < end {
if arr[start] != arr[end] {
changes += 1
}
start += 1
end -= 1
}
return changes
}
```func smallestChange(arr: [Int]) -> Int {
var changes = 0
var start = 0
var end = arr.count - 1
while start < end {
if arr[start] != arr[end] {
changes += 1
}
start += 1
end -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var changes = 0
var start = 0
var end = arr.count - 1
while start < end {
if arr[start] != arr[end] {
changes += 1
}
start += 1
end -= 1
}
return changes
}
```func smallestChange(arr: [Int]) -> Int {
var arr = arr
var i = 0
var j = arr.count - 1
var changes = 0
while i < j {
if arr[i] != arr[j] {
changes += 1
if arr[i] < arr[j] {
arr[i] = arr[j]
} else {
arr[j] = arr[i]
}
}
i += 1
j -= 1
}
return changes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
assistant
```swift
func smallestChange(arr: [Int]) -> Int {
var arr = arr
var i = 0
var j = arr.count - 1
var changes = 0
while i < j {
if arr[i] != arr[j] {
changes += 1
if arr[i] < arr[j] {
arr[i] = arr[j]
} else {
arr[j] = arr[i]
}
}
i += 1
j -= 1
}
return changes
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
return totalCharsInLst1 <= totalCharsInLst2 ? lst1 : lst2
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
assistant
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalCharsInLst1 = lst1.reduce(0, { $0 + $1.count })
let totalCharsInLst2 = lst2.reduce(0, { $0 + $1.count })
if totalCharsInLst1 <= totalCharsInLst2 {
return lst1
} else {
return lst2
}
}
```func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primeFactors: [Int] = []
// Check for divisibility by 2
while number % 2 == 0 {
primeFactors.append(2)
number /= 2
}
// Check for divisibility by odd numbers starting from 3
var i = 3
while i * i <= number {
while number % i == 0 {
primeFactors.append(i)
number /= i
}
i += 2
}
// If number is a prime greater than 2
if number > 2 {
primeFactors.append(number)
}
// Check if the number of prime factors is 3
return primeFactors.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primeFactors: [Int] = []
// Check for divisibility by 2
while number % 2 == 0 {
primeFactors.append(2)
number /= 2
}
// Check for divisibility by odd numbers starting from 3
var i = 3
while i * i <= number {
while number % i == 0 {
primeFactors.append(i)
number /= i
}
i += 2
}
// If number is a prime greater than 2
if number > 2 {
primeFactors.append(number)
}
// Check if the number of prime factors is 3
return primeFactors.count == 3
}
```func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes: [Int] = []
// Check for prime factors
for i in 2...a {
while number % i == 0 {
if !primes.contains(i) {
primes.append(i)
}
number /= i
}
if number == 1 {
break
}
}
// Return true if exactly 3 distinct prime factors
return primes.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes: [Int] = []
// Check for prime factors
for i in 2...a {
while number % i == 0 {
if !primes.contains(i) {
primes.append(i)
}
number /= i
}
if number == 1 {
break
}
}
// Return true if exactly 3 distinct prime factors
return primes.count == 3
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
var num = a
var primes = [Int]()
var i = 2
while num != 1 {
if num % i == 0 {
num /= i
primes.append(i)
} else {
i += 1
}
}
return primes.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var num = a
var primes = [Int]()
var i = 2
while num != 1 {
if num % i == 0 {
num /= i
primes.append(i)
} else {
i += 1
}
}
return primes.count == 3
}
```func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes = [Int]()
var i = 2
while number != 1 {
if number % i == 0 {
number /= i
primes.append(i)
} else {
i += 1
}
}
return primes.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes = [Int]()
var i = 2
while number != 1 {
if number % i == 0 {
number /= i
primes.append(i)
} else {
i += 1
}
}
return primes.count == 3
}
```func isMultiplyPrime(a: Int) -> Bool {
var num = a
var primeFactors = [Int]()
while num % 2 == 0 {
primeFactors.append(2)
num /= 2
}
let sqrtNum = Int(Double(num).squareRoot())
for i in 3...sqrtNum {
while num % i == 0 {
primeFactors.append(i)
num /= i
}
}
if num > 2 {
primeFactors.append(num)
}
return primeFactors.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var num = a
var primeFactors = [Int]()
while num % 2 == 0 {
primeFactors.append(2)
num /= 2
}
let sqrtNum = Int(Double(num).squareRoot())
for i in 3...sqrtNum {
while num % i == 0 {
primeFactors.append(i)
num /= i
}
}
if num > 2 {
primeFactors.append(num)
}
return primeFactors.count == 3
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes = [Int]()
var i = 2
while primes.count < 3 && i * i <= number {
if number % i == 0 {
primes.append(i)
while number % i == 0 {
number /= i
}
}
i += 1
}
if number > 1 {
primes.append(number)
}
return primes.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes = [Int]()
var i = 2
while primes.count < 3 && i * i <= number {
if number % i == 0 {
primes.append(i)
while number % i == 0 {
number /= i
}
}
i += 1
}
if number > 1 {
primes.append(number)
}
return primes.count == 3
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes: [Int] = []
var i = 2
while i * i <= number {
if number % i == 0 {
primes.append(i)
number /= i
} else {
i += 1
}
}
if number > 1 {
primes.append(number)
}
return primes.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes: [Int] = []
var i = 2
while i * i <= number {
if number % i == 0 {
primes.append(i)
number /= i
} else {
i += 1
}
}
if number > 1 {
primes.append(number)
}
return primes.count == 3
}
```func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primeFactors: [Int] = []
// Check for divisibility by 2
while number % 2 == 0 {
primeFactors.append(2)
number /= 2
}
// Check for divisibility by odd numbers starting from 3
var i = 3
while i * i <= number {
while number % i == 0 {
primeFactors.append(i)
number /= i
}
i += 2
}
// If number is a prime
if number > 2 {
primeFactors.append(number)
}
// Check if we have exactly 3 prime factors
return primeFactors.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primeFactors: [Int] = []
// Check for divisibility by 2
while number % 2 == 0 {
primeFactors.append(2)
number /= 2
}
// Check for divisibility by odd numbers starting from 3
var i = 3
while i * i <= number {
while number % i == 0 {
primeFactors.append(i)
number /= i
}
i += 2
}
// If number is a prime
if number > 2 {
primeFactors.append(number)
}
// Check if we have exactly 3 prime factors
return primeFactors.count == 3
}
```func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primeFactors: [Int] = []
// Check for divisibility by 2
while number % 2 == 0 {
primeFactors.append(2)
number /= 2
}
// Check for divisibility by odd numbers starting from 3
var factor = 3
while factor * factor <= number {
if number % factor == 0 {
primeFactors.append(factor)
number /= factor
} else {
factor += 2
}
}
// If number itself is a prime
if number > 2 {
primeFactors.append(number)
}
// Check if we have exactly 3 prime factors
return primeFactors.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primeFactors: [Int] = []
// Check for divisibility by 2
while number % 2 == 0 {
primeFactors.append(2)
number /= 2
}
// Check for divisibility by odd numbers starting from 3
var factor = 3
while factor * factor <= number {
if number % factor == 0 {
primeFactors.append(factor)
number /= factor
} else {
factor += 2
}
}
// If number itself is a prime
if number > 2 {
primeFactors.append(number)
}
// Check if we have exactly 3 prime factors
return primeFactors.count == 3
}
```func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes: [Int] = []
var i = 2
while i * i <= number {
if number % i != 0 {
i += 1
} else {
number /= i
if !primes.contains(i) {
primes.append(i)
}
}
}
if number > 1 && !primes.contains(number) {
primes.append(number)
}
return primes.count == 3
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
assistant
```swift
func isMultiplyPrime(a: Int) -> Bool {
var number = a
var primes: [Int] = []
var i = 2
while i * i <= number {
if number % i != 0 {
i += 1
} else {
number /= i
if !primes.contains(i) {
primes.append(i)
}
}
}
if number > 1 && !primes.contains(number) {
primes.append(number)
}
return primes.count == 3
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
assistant
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
guard n != 1 else { return x == 1 }
var num = x
while num % n == 0 {
num /= n
}
return num == 1
}
```func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}
```let cubedRoot = Double(a).cbrt() // value of type 'Double' has no member 'cbrt'func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}
```let cubedRoot = Double(a).cbrt() // value of type 'Double' has no member 'cbrt'func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}
```let cubedRoot = Double(a).cbrt() // value of type 'Double' has no member 'cbrt'func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}
```let cubedRoot = Double(a).cbrt() // value of type 'Double' has no member 'cbrt'func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}
```let cubedRoot = Double(a).cbrt() // value of type 'Double' has no member 'cbrt'func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}
```let cubedRoot = Double(a).cbrt() // value of type 'Double' has no member 'cbrt'func iscube(a: Int) -> Bool {
let cubedRoot = pow(Double(abs(a)), 1/3.0)
return cubedRoot.round() == cubedRoot
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = pow(Double(abs(a)), 1/3.0)
return cubedRoot.round() == cubedRoot
}
```return cubedRoot.round() == cubedRoot // cannot use mutating member on immutable value: 'cubedRoot' is a 'let' constantreturn cubedRoot.round() == cubedRoot // binary operator '==' cannot be applied to operands of type '()' and 'Double'func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}
```let cubedRoot = Double(a).cbrt() // value of type 'Double' has no member 'cbrt'func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}
```let cubedRoot = Double(a).cbrt() // value of type 'Double' has no member 'cbrt'func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
assistant
```swift
func iscube(a: Int) -> Bool {
let cubedRoot = Double(a).cbrt()
return cubedRoot.truncatingRemainder(dividingBy: 1) == 0
}
```let cubedRoot = Double(a).cbrt() // value of type 'Double' has no member 'cbrt'func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let count = chars.filter { primes.contains(String($0)) }.count
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let count = chars.filter { primes.contains(String($0)) }.count
return count
}
```func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}
```func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let digits = num.map { String($0) }
let intersection = digits.filter { primes.contains($0) }
return intersection.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let digits = num.map { String($0) }
let intersection = digits.filter { primes.contains($0) }
return intersection.count
}
```func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let count = chars.filter { primes.contains(String($0)) }.count
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let count = chars.filter { primes.contains(String($0)) }.count
return count
}
```func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let count = chars.filter { primes.contains(String($0)) }.count
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let count = chars.filter { primes.contains(String($0)) }.count
return count
}
```func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let digits = num.map { String($0) }
let intersection = digits.filter { primes.contains($0) }
return intersection.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let digits = num.map { String($0) }
let intersection = digits.filter { primes.contains($0) }
return intersection.count
}
```func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}
```func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}
```func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}
```func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
assistant
```swift
func hexKey(num: String) -> Int {
let primes = Set(["2", "3", "5", "7", "B", "D"])
let chars = Array(num)
let intersection = chars.filter { primes.contains($0.description) }
return intersection.count
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
assistant
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func isHappy(s: String) -> Bool {
let string = String(s)
if string.count < 3 {
return false
}
for i in stride(from: 0, to: string.count - 2, by: 3) {
let substring = string[i..<(i + 3)]
let set = Set(substring)
if set.count != substring.count {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
let string = String(s)
if string.count < 3 {
return false
}
for i in stride(from: 0, to: string.count - 2, by: 3) {
let substring = string[i..<(i + 3)]
let set = Set(substring)
if set.count != substring.count {
return false
}
}
return true
}
```let substring = string[i..<(i + 3)] // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<(i+3)])
if set.count != 3 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<(i+3)])
if set.count != 3 {
return false
}
}
return true
}
```let set = Set(s[i..<(i+3)]) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func isHappy(s: String) -> Bool {
let string = String(s)
if string.count < 3 {
return false
}
for i in stride(from: 0, to: string.count - 2, by: 3) {
let substring = string[i..<(i+3)]
let set = Set(substring)
if set.count != 3 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
let string = String(s)
if string.count < 3 {
return false
}
for i in stride(from: 0, to: string.count - 2, by: 3) {
let substring = string[i..<(i+3)]
let set = Set(substring)
if set.count != 3 {
return false
}
}
return true
}
```let substring = string[i..<(i+3)] // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func isHappy(s: String) -> Bool {
let string = String(s)
if string.count < 3 {
return false
}
for i in stride(from: 0, to: string.count - 2, by: 3) {
let substring = string[i..<(i+3)]
let set = Set(substring)
if set.count != substring.count {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
let string = String(s)
if string.count < 3 {
return false
}
for i in stride(from: 0, to: string.count - 2, by: 3) {
let substring = string[i..<(i+3)]
let set = Set(substring)
if set.count != substring.count {
return false
}
}
return true
}
```let substring = string[i..<(i+3)] // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<i+3].flatMap { String($0) })
if set.count != 3 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<i+3].flatMap { String($0) })
if set.count != 3 {
return false
}
}
return true
}
```let set = Set(s[i..<i+3].flatMap { String($0) }) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func isHappy(s: String) -> Bool {
let stringArray = Array(s)
if stringArray.count < 3 {
return false
}
for i in 0..<stringArray.count - 2 {
if stringArray[i] == stringArray[i + 1] || stringArray[i] == stringArray[i + 2] || stringArray[i + 1] == stringArray[i + 2] {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
let stringArray = Array(s)
if stringArray.count < 3 {
return false
}
for i in 0..<stringArray.count - 2 {
if stringArray[i] == stringArray[i + 1] || stringArray[i] == stringArray[i + 2] || stringArray[i + 1] == stringArray[i + 2] {
return false
}
}
return true
}
```func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<i+3].flatMap { String($0) })
if set.count != 3 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<i+3].flatMap { String($0) })
if set.count != 3 {
return false
}
}
return true
}
```let set = Set(s[i..<i+3].flatMap { String($0) }) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<i+3].flatMap { String($0) })
if set.count != 3 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<i+3].flatMap { String($0) })
if set.count != 3 {
return false
}
}
return true
}
```let set = Set(s[i..<i+3].flatMap { String($0) }) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<i+3].map { String($0) })
if set.count != 3 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[i..<i+3].map { String($0) })
if set.count != 3 {
return false
}
}
return true
}
```let set = Set(s[i..<i+3].map { String($0) }) // 'subscript(_:)' is unavailable: cannot subscript String with an integer range, use a String.Index range instead.func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[s.index(s.startIndex, offsetBy: i)..<s.index(s.startIndex, offsetBy: i + 3)])
if set.count != 3 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
assistant
```swift
func isHappy(s: String) -> Bool {
if s.count < 3 {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 3) {
let set = Set(s[s.index(s.startIndex, offsetBy: i)..<s.index(s.startIndex, offsetBy: i + 3)])
if set.count != 3 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}user
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
assistant
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for grade in grades {
if grade == 4.0 {
letterGrades.append("A+")
} else if grade > 3.7 {
letterGrades.append("A")
} else if grade > 3.3 {
letterGrades.append("A-")
} else if grade > 3.0 {
letterGrades.append("B+")
} else if grade > 2.7 {
letterGrades.append("B")
} else if grade > 2.3 {
letterGrades.append("B-")
} else if grade > 2.0 {
letterGrades.append("C+")
} else if grade > 1.7 {
letterGrades.append("C")
} else if grade > 1.3 {
letterGrades.append("C-")
} else if grade > 1.0 {
letterGrades.append("D+")
} else if grade > 0.7 {
letterGrades.append("D")
} else if grade > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
assistant
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length < 2 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) * 2 - 1)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) * 2 - 1)
}
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
assistant
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 9
} else {
return 9 * (Int(pow(10.0, Double(n - 1))) + Int(pow(10.0, Double(n - 2))))
}
}
``` // XCTAssertTrue failed@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(format: "%b", sum)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(format: "%b", sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0, { $0 + Int(String($1))! })
return String(sum, radix: 2)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0, { $0 + Int(String($1))! })
return String(sum, radix: 2)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0, { $0 + Int(String($1))! })
return String(sum, radix: 2)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0, { $0 + Int(String($1))! })
return String(sum, radix: 2)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(sum, radix: 2)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(sum, radix: 2)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(sum, radix: 2)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(sum, radix: 2)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0, { $0 + Int(String($1))! })
return String(sum, radix: 2)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0, { $0 + Int(String($1))! })
return String(sum, radix: 2)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(sum, radix: 2)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(sum, radix: 2)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0, { $0 + Int(String($1))! })
return String(sum, radix: 2)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0, { $0 + Int(String($1))! })
return String(sum, radix: 2)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(format: "%b", sum)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(format: "%b", sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(format: "%b", sum)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
assistant
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let binaryDigits = Array(binaryString)
let sum = binaryDigits.reduce(0) { $0 + Int(String($1))! }
return String(format: "%b", sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopefunc add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
assistant
```swift
func add(lst: [Int]) -> Int {
var sum = 0
for i in 0..<lst.count {
if i % 2 != 0 && lst[i] % 2 == 0 {
sum += lst[i]
}
}
return sum
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello !!!Wdlor"
assistant
```swift
func antiShuffle(s: String) -> String {
let words = s.split(separator: " ")
var result: [String] = []
for word in words {
let sortedWord = String(word.sorted())
result.append(sortedWord)
}
return result.joined(separator: " ")
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, array) in lst.enumerated() {
for (col, element) in array.enumerated() {
if element == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, array) in lst.enumerated() {
for (col, element) in array.enumerated() {
if element == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, array) in lst.enumerated() {
for (col, element) in array.enumerated() {
if element == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, array) in lst.enumerated() {
for (col, element) in array.enumerated() {
if element == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, arr) in lst.enumerated() {
for (col, num) in arr.enumerated() {
if num == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, arr) in lst.enumerated() {
for (col, num) in arr.enumerated() {
if num == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, arr) in lst.enumerated() {
for (col, num) in arr.enumerated() {
if num == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, arr) in lst.enumerated() {
for (col, num) in arr.enumerated() {
if num == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (rowIndex, row) in lst.enumerated() {
for (colIndex, col) in row.enumerated() {
if col == x {
result.append((rowIndex, colIndex))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (rowIndex, row) in lst.enumerated() {
for (colIndex, col) in row.enumerated() {
if col == x {
result.append((rowIndex, colIndex))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, arr) in lst.enumerated() {
for (col, num) in arr.enumerated() {
if num == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, arr) in lst.enumerated() {
for (col, num) in arr.enumerated() {
if num == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, arr) in lst.enumerated() {
for (col, num) in arr.enumerated() {
if num == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (row, arr) in lst.enumerated() {
for (col, num) in arr.enumerated() {
if num == x {
result.append((row, col))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (rowIndex, row) in lst.enumerated() {
for (colIndex, col) in row.enumerated() {
if col == x {
result.append((rowIndex, colIndex))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (rowIndex, row) in lst.enumerated() {
for (colIndex, col) in row.enumerated() {
if col == x {
result.append((rowIndex, colIndex))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (rowIndex, row) in lst.enumerated() {
for (colIndex, col) in row.enumerated() {
if col == x {
result.append((rowIndex, colIndex))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (rowIndex, row) in lst.enumerated() {
for (colIndex, col) in row.enumerated() {
if col == x {
result.append((rowIndex, colIndex))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (rowIndex, row) in lst.enumerated() {
for (colIndex, col) in row.enumerated() {
if col == x {
result.append((rowIndex, colIndex))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
assistant
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (rowIndex, row) in lst.enumerated() {
for (colIndex, col) in row.enumerated() {
if col == x {
result.append((rowIndex, colIndex))
}
}
}
return result.sorted {
if $0.0 == $1.0 {
return $0.1 > $1.1
} else {
return $0.0 < $1.0
}
}
}
```func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first ?? 0
let last = array.last ?? 0
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first ?? 0
let last = array.last ?? 0
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}
```func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first!
let last = array.last!
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first!
let last = array.last!
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}
```func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first ?? 0
let last = array.last ?? 0
if (first + last) % 2 == 0 {
// If the sum is even, sort in descending order
return array.sorted(by: >)
} else {
// If the sum is odd, sort in ascending order
return array.sorted(by: <)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first ?? 0
let last = array.last ?? 0
if (first + last) % 2 == 0 {
// If the sum is even, sort in descending order
return array.sorted(by: >)
} else {
// If the sum is odd, sort in ascending order
return array.sorted(by: <)
}
}
```func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first!
let last = array.last!
if (first + last) % 2 == 0 {
// sum is even, sort in descending order
return array.sorted(by: >)
} else {
// sum is odd, sort in ascending order
return array.sorted(by: <)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first!
let last = array.last!
if (first + last) % 2 == 0 {
// sum is even, sort in descending order
return array.sorted(by: >)
} else {
// sum is odd, sort in ascending order
return array.sorted(by: <)
}
}
```func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first ?? 0
let last = array.last ?? 0
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first ?? 0
let last = array.last ?? 0
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}
```func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first!
let last = array.last!
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first!
let last = array.last!
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}
```func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first!
let last = array.last!
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first!
let last = array.last!
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}
```func sortArray(array: [Int]) -> [Int] {
guard !array.isEmpty else { return [] }
let first = array.first!
let last = array.last!
let sortedArray = array.sorted { (a, b) -> Bool in
if (first + last) % 2 == 0 {
return a > b
} else {
return a < b
}
}
return sortedArray
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
guard !array.isEmpty else { return [] }
let first = array.first!
let last = array.last!
let sortedArray = array.sorted { (a, b) -> Bool in
if (first + last) % 2 == 0 {
return a > b
} else {
return a < b
}
}
return sortedArray
}
```func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first ?? 0
let last = array.last ?? 0
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
if array.isEmpty {
return []
}
let first = array.first ?? 0
let last = array.last ?? 0
if (first + last) % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted(by: <)
}
}
```func sortArray(array: [Int]) -> [Int] {
// Check if array is empty
if array.isEmpty {
return []
}
// Create a copy of the array
var arrayCopy = array
// Check if the sum of the first and last index values is even or odd
if (array[0] + array[array.count - 1]) % 2 == 0 {
// If even, sort the array in descending order
arrayCopy.sort(by: >)
} else {
// If odd, sort the array in ascending order
arrayCopy.sort(by: <)
}
return arrayCopy
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
assistant
```swift
func sortArray(array: [Int]) -> [Int] {
// Check if array is empty
if array.isEmpty {
return []
}
// Create a copy of the array
var arrayCopy = array
// Check if the sum of the first and last index values is even or odd
if (array[0] + array[array.count - 1]) % 2 == 0 {
// If even, sort the array in descending order
arrayCopy.sort(by: >)
} else {
// If odd, sort the array in ascending order
arrayCopy.sort(by: <)
}
return arrayCopy
}
```func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.offset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.offset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}
```let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.offset + 4) % alphabet.count) // value of type 'String.Index' has no member 'offset'func encrypt(s: String) -> String {
var result = ""
for char in s {
if let asciiValue = char.asciiValue,
let newChar = Character(Unicode.Scalar(asciiValue + 4)!) {
result.append(newChar)
} else {
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
var result = ""
for char in s {
if let asciiValue = char.asciiValue,
let newChar = Character(Unicode.Scalar(asciiValue + 4)!) {
result.append(newChar)
} else {
result.append(char)
}
}
return result
}
```let newChar = Character(Unicode.Scalar(asciiValue + 4)!) { // cannot force unwrap value of non-optional type 'Unicode.Scalar'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}
```let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count) // 'encodedOffset' is deprecated: encodedOffset has been deprecated as most common usage is incorrect. Use utf16Offset(in:) to achieve the same behavior.func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}
```let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count) // 'encodedOffset' is deprecated: encodedOffset has been deprecated as most common usage is incorrect. Use utf16Offset(in:) to achieve the same behavior.func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(index, offsetBy: 4)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(index, offsetBy: 4)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}
``` // Fatal error: String index is out of boundsfunc encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}
```let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count) // 'encodedOffset' is deprecated: encodedOffset has been deprecated as most common usage is incorrect. Use utf16Offset(in:) to achieve the same behavior.func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(index, offsetBy: 4)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(index, offsetBy: 4)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}
``` // Fatal error: String index is out of boundsfunc encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.distance(to: alphabet.endIndex) + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.distance(to: alphabet.endIndex) + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}
```let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.distance(to: alphabet.endIndex) + 4) % alphabet.count) // value of type 'String.Index' has no member 'distance'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}
```let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count) // 'encodedOffset' is deprecated: encodedOffset has been deprecated as most common usage is incorrect. Use utf16Offset(in:) to achieve the same behavior.func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
assistant
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count)
encryptedString.append(alphabet[shiftedIndex])
}
}
return encryptedString
}
```let shiftedIndex = alphabet.index(alphabet.startIndex, offsetBy: (index.encodedOffset + 4) % alphabet.count) // 'encodedOffset' is deprecated: encodedOffset has been deprecated as most common usage is incorrect. Use utf16Offset(in:) to achieve the same behavior.func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num != smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num != smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num != smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num != smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num != smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num != smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num != smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num != smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
assistant
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var smallest = Int.max
var secondSmallest = Int.max
for num in lst {
if num < smallest {
secondSmallest = smallest
smallest = num
} else if num < secondSmallest && num > smallest {
secondSmallest = num
}
}
return secondSmallest == Int.max ? nil : secondSmallest
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespacesAndNewlines).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespacesAndNewlines).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if words.first == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if words.first == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if words.first == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if words.first == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if words.first == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespaces).components(separatedBy: " ")
if words.first == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespacesAndNewlines).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}user
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
assistant
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "?", "!"])
var boredomCount = 0
for sentence in sentences {
let words = sentence.trimmingCharacters(in: .whitespacesAndNewlines).components(separatedBy: " ")
if !words.isEmpty && words[0] == "I" {
boredomCount += 1
}
}
return boredomCount
}
```func anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(x + z == y && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(y + z == x && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) {
return true
} else {
return false
}
}
extension Double {
var isWholeNumber: Bool {
return (self as Int) == self
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(x + z == y && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(y + z == x && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) {
return true
} else {
return false
}
}
extension Double {
var isWholeNumber: Bool {
return (self as Int) == self
}
}
```return (self as Int) == self // cannot convert value of type 'Double' to type 'Int' in coercionreturn (self as Int) == self // cannot convert value of type 'Double' to expected argument type 'Int'func anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(x + z == y && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(y + z == x && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) {
return true
} else {
return false
}
}
extension Double {
var isWholeNumber: Bool {
return (self as Int) == self
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(x + z == y && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(y + z == x && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) {
return true
} else {
return false
}
}
extension Double {
var isWholeNumber: Bool {
return (self as Int) == self
}
}
```return (self as Int) == self // cannot convert value of type 'Double' to type 'Int' in coercionreturn (self as Int) == self // cannot convert value of type 'Double' to expected argument type 'Int'func anyInt(x: Double, y: Double, z: Double) -> Bool {
let numbers = [x, y, z]
// Check if all numbers are integers
if numbers.allSatisfy({ $0.isWholeNumber }) {
// Check if one number is equal to the sum of the other two
for i in 0..<3 {
if numbers[i] == numbers[(i+1)%3] + numbers[(i+2)%3] {
return true
}
}
}
return false
}
extension Double {
var isWholeNumber: Bool {
return (self as NSNumber).isInteger
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let numbers = [x, y, z]
// Check if all numbers are integers
if numbers.allSatisfy({ $0.isWholeNumber }) {
// Check if one number is equal to the sum of the other two
for i in 0..<3 {
if numbers[i] == numbers[(i+1)%3] + numbers[(i+2)%3] {
return true
}
}
}
return false
}
// Extension to check if a Double is a whole number
extension Double {
var isWholeNumber: Bool {
return (self as NSNumber).isInteger
}
}
```return (self as NSNumber).isInteger // value of type 'NSNumber' has no member 'isInteger'func anyInt(x: Double, y: Double, z: Double) -> Bool {
let numbers = [x, y, z]
for num in numbers {
if num != floor(num) {
return false
}
}
let sortedNumbers = numbers.sorted()
return sortedNumbers[0] + sortedNumbers[1] == sortedNumbers[2]
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let numbers = [x, y, z]
for num in numbers {
if num != floor(num) {
return false
}
}
let sortedNumbers = numbers.sorted()
return sortedNumbers[0] + sortedNumbers[1] == sortedNumbers[2]
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z) || (x + z == y) || (y + z == x) {
if (x.isWholeNumber() && y.isWholeNumber() && z.isWholeNumber()) {
return true
}
}
return false
}
extension Double {
func isWholeNumber() -> Bool {
return (self - floor(self)) == 0
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z) || (x + z == y) || (y + z == x) {
if (x.isWholeNumber() && y.isWholeNumber() && z.isWholeNumber()) {
return true
}
}
return false
}
extension Double {
func isWholeNumber() -> Bool {
return (self - floor(self)) == 0
}
}
```func anyInt(x: Double, y: Double, z: Double) -> Bool {
let numbers = [x, y, z]
guard numbers.allSatisfy({ $0.isWholeNumber }) else {
return false
}
let sum = numbers.reduce(0, +)
return sum == x * 2 || sum == y * 2 || sum == z * 2
}
extension Double {
var isWholeNumber: Bool {
return round(self) == self
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let numbers = [x, y, z]
guard numbers.allSatisfy({ $0.isWholeNumber }) else {
return false
}
let sum = numbers.reduce(0, +)
return sum == x * 2 || sum == y * 2 || sum == z * 2
}
extension Double {
var isWholeNumber: Bool {
return round(self) == self
}
}
```return round(self) == self // binary operator '==' cannot be applied to operands of type '()' and 'Double'return round(self) == self // cannot use mutating member on immutable value: 'self' is immutablereturn round(self) == self // cannot convert value of type 'Double' to expected argument type 'FloatingPointRoundingRule'func anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(x + z == y && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(y + z == x && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) {
return true
} else {
return false
}
}
extension Double {
var isWholeNumber: Bool {
return (self as NSNumber).isInteger
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(x + z == y && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) ||
(y + z == x && x.isWholeNumber && y.isWholeNumber && z.isWholeNumber) {
return true
} else {
return false
}
}
extension Double {
var isWholeNumber: Bool {
return (self as NSNumber).isInteger
}
}
```return (self as NSNumber).isInteger // value of type 'NSNumber' has no member 'isInteger'func anyInt(x: Double, y: Double, z: Double) -> Bool {
// Check if all inputs are integers
if (x.truncatingRemainder(dividingBy: 1) == 0) && (y.truncatingRemainder(dividingBy: 1) == 0) && (z.truncatingRemainder(dividingBy: 1) == 0) {
// Check if one of the numbers is equal to the sum of the other two
if (x == y + z) || (y == x + z) || (z == x + y) {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
// Check if all inputs are integers
if (x.truncatingRemainder(dividingBy: 1) == 0) && (y.truncatingRemainder(dividingBy: 1) == 0) && (z.truncatingRemainder(dividingBy: 1) == 0) {
// Check if one of the numbers is equal to the sum of the other two
if (x == y + z) || (y == x + z) || (z == x + y) {
return true
}
}
return false
}
```func anyInt(x: Double, y: Double, z: Double) -> Bool {
// Check if all numbers are integers
if (x.truncatingRemainder(dividingBy: 1) == 0) && (y.truncatingRemainder(dividingBy: 1) == 0) && (z.truncatingRemainder(dividingBy: 1) == 0) {
// Check if one of the numbers is equal to the sum of the other two
if x == y + z || y == x + z || z == x + y {
return true
}
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
// Check if all numbers are integers
if (x.truncatingRemainder(dividingBy: 1) == 0) && (y.truncatingRemainder(dividingBy: 1) == 0) && (z.truncatingRemainder(dividingBy: 1) == 0) {
// Check if one of the numbers is equal to the sum of the other two
if x == y + z || y == x + z || z == x + y {
return true
}
}
return false
}
```func anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z && x == floor(x) && y == floor(y) && z == floor(z)) ||
(x + z == y && x == floor(x) && y == floor(y) && z == floor(z)) ||
(y + z == x && x == floor(x) && y == floor(y) && z == floor(z)) {
return true
} else {
return false
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
assistant
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
if (x + y == z && x == floor(x) && y == floor(y) && z == floor(z)) ||
(x + z == y && x == floor(x) && y == floor(y) && z == floor(z)) ||
(y + z == x && x == floor(x) && y == floor(y) && z == floor(z)) {
return true
} else {
return false
}
}
```func encode(message: String) -> String {
var encodedMessage = ""
for char in message {
if let asciiValue = char.asciiValue, 65 <= asciiValue && asciiValue <= 90 {
let newChar = (asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!)
encodedMessage.append(String(newChar).lowercased())
} else if let asciiValue = char.asciiValue, 97 <= asciiValue && asciiValue <= 122 {
let newChar = (asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!)
encodedMessage.append(String(newChar).uppercased())
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
var encodedMessage = ""
for char in message {
if let asciiValue = char.asciiValue, 65 <= asciiValue && asciiValue <= 90 {
let newChar = (asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!)
encodedMessage.append(String(newChar).lowercased())
} else if let asciiValue = char.asciiValue, 97 <= asciiValue && asciiValue <= 122 {
let newChar = (asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!)
encodedMessage.append(String(newChar).uppercased())
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}
```let newChar = (asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!) // cannot force unwrap value of non-optional type 'Unicode.Scalar'let newChar = (asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!) // cannot force unwrap value of non-optional type 'Unicode.Scalar'let newChar = (asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!) // cannot force unwrap value of non-optional type 'Unicode.Scalar'let newChar = (asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!) // cannot force unwrap value of non-optional type 'Unicode.Scalar'func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let isUppercase = char.isUppercase
let asciiValue = char.asciiValue!
var encodedChar: Character
if isUppercase {
encodedChar = Character(UnicodeScalar(asciiValue + 2)!)
} else {
encodedChar = Character(UnicodeScalar(asciiValue - 2)!)
}
encodedMessage.append(encodedChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let isUppercase = char.isUppercase
let asciiValue = char.asciiValue!
var encodedChar: Character
if isUppercase {
encodedChar = Character(UnicodeScalar(asciiValue + 2)!)
} else {
encodedChar = Character(UnicodeScalar(asciiValue - 2)!)
}
encodedMessage.append(encodedChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}
```encodedChar = Character(UnicodeScalar(asciiValue + 2)!) // cannot force unwrap value of non-optional type 'UnicodeScalar' (aka 'Unicode.Scalar')encodedChar = Character(UnicodeScalar(asciiValue - 2)!) // cannot force unwrap value of non-optional type 'UnicodeScalar' (aka 'Unicode.Scalar')func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let isUppercase = char.isUppercase
let asciiValue = char.asciiValue!
var encodedChar: Character
if isUppercase {
encodedChar = Character(UnicodeScalar(asciiValue + 2)!)
} else {
encodedChar = Character(UnicodeScalar(asciiValue - 2)!)
}
encodedMessage.append(encodedChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let isUppercase = char.isUppercase
let asciiValue = char.asciiValue!
var encodedChar: Character
if isUppercase {
encodedChar = Character(UnicodeScalar(asciiValue + 2)!)
} else {
encodedChar = Character(UnicodeScalar(asciiValue - 2)!)
}
encodedMessage.append(encodedChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}
```encodedChar = Character(UnicodeScalar(asciiValue + 2)!) // cannot force unwrap value of non-optional type 'UnicodeScalar' (aka 'Unicode.Scalar')encodedChar = Character(UnicodeScalar(asciiValue - 2)!) // cannot force unwrap value of non-optional type 'UnicodeScalar' (aka 'Unicode.Scalar')func encode(message: String) -> String {
var encodedMessage = ""
for char in message {
if let asciiValue = char.asciiValue, 65...90 ~= asciiValue { // Uppercase
let newChar = String((asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!))
encodedMessage.append(newChar.lowercased())
} else if let asciiValue = char.asciiValue, 97...122 ~= asciiValue { // Lowercase
let newChar = String((asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!))
encodedMessage.append(newChar.uppercased())
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
var encodedMessage = ""
for char in message {
if let asciiValue = char.asciiValue, 65...90 ~= asciiValue { // Uppercase
let newChar = String((asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!))
encodedMessage.append(newChar.lowercased())
} else if let asciiValue = char.asciiValue, 97...122 ~= asciiValue { // Lowercase
let newChar = String((asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!))
encodedMessage.append(newChar.uppercased())
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}
```let newChar = String((asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!)) // cannot force unwrap value of non-optional type 'Unicode.Scalar'let newChar = String((asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!)) // cannot force unwrap value of non-optional type 'Unicode.Scalar'let newChar = String((asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!)) // cannot force unwrap value of non-optional type 'Unicode.Scalar'let newChar = String((asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!)) // cannot force unwrap value of non-optional type 'Unicode.Scalar'func encode(message: String) -> String {
var encodedMessage = ""
let vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character: Character] = ["a":"c", "e":"g", "i":"k", "o":"q", "u":"w", "A":"C", "E":"G", "I":"K", "O":"Q", "U":"W"]
for char in message {
if vowels.contains(String(char)) {
encodedMessage.append(replacements[char] ?? char)
} else if char.isLetter {
let newChar = char.isUppercase ? char.lowercased() : char.uppercased()
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
var encodedMessage = ""
let vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character: Character] = ["a":"c", "e":"g", "i":"k", "o":"q", "u":"w", "A":"C", "E":"G", "I":"K", "O":"Q", "U":"W"]
for char in message {
if vowels.contains(String(char)) {
encodedMessage.append(replacements[char] ?? char)
} else if char.isLetter {
let newChar = char.isUppercase ? char.lowercased() : char.uppercased()
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}
``` // XCTAssertTrue failedfunc encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let newChar = char.isUppercase ? Character(Unicode.Scalar(char.unicodeScalars.first!.value - 30)!) : Character(Unicode.Scalar(char.unicodeScalars.first!.value + 32)!)
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let newChar = char.isUppercase ? Character(Unicode.Scalar(char.unicodeScalars.first!.value - 30)!) : Character(Unicode.Scalar(char.unicodeScalars.first!.value + 32)!)
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}
``` // XCTAssertTrue failedfunc encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let newChar = char.isUppercase ? char.lowercased() : char.uppercased()
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let newChar = char.isUppercase ? char.lowercased() : char.uppercased()
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}
``` // XCTAssertTrue failedfunc encode(message: String) -> String {
var encodedMessage = ""
for char in message {
if let asciiValue = char.asciiValue {
if asciiValue >= 65 && asciiValue <= 90 { // Uppercase letter
let newChar = String((asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!))
encodedMessage.append(newChar.lowercased())
} else if asciiValue >= 97 && asciiValue <= 122 { // Lowercase letter
let newChar = String((asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!))
encodedMessage.append(newChar.uppercased())
}
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
var encodedMessage = ""
for char in message {
if let asciiValue = char.asciiValue {
if asciiValue >= 65 && asciiValue <= 90 { // Uppercase letter
let newChar = String((asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!))
encodedMessage.append(newChar.lowercased())
} else if asciiValue >= 97 && asciiValue <= 122 { // Lowercase letter
let newChar = String((asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!))
encodedMessage.append(newChar.uppercased())
}
}
}
return encodedMessage
}
```let newChar = String((asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!)) // cannot force unwrap value of non-optional type 'Unicode.Scalar'let newChar = String((asciiValue + 2 > 90) ? Character(Unicode.Scalar(asciiValue + 2 - 26)!) : Character(Unicode.Scalar(asciiValue + 2)!)) // cannot force unwrap value of non-optional type 'Unicode.Scalar'let newChar = String((asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!)) // cannot force unwrap value of non-optional type 'Unicode.Scalar'let newChar = String((asciiValue - 2 < 97) ? Character(Unicode.Scalar(asciiValue - 2 + 26)!) : Character(Unicode.Scalar(asciiValue - 2)!)) // cannot force unwrap value of non-optional type 'Unicode.Scalar'func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let newChar = char.isUppercase ? Character(Unicode.Scalar(char.unicodeScalars.first!.value - 30)!) : Character(Unicode.Scalar(char.unicodeScalars.first!.value + 32)!)
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let newChar = char.isUppercase ? Character(Unicode.Scalar(char.unicodeScalars.first!.value - 30)!) : Character(Unicode.Scalar(char.unicodeScalars.first!.value + 32)!)
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}
``` // XCTAssertTrue failedfunc encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let newChar = char.isUppercase ? Character(Unicode.Scalar(char.unicodeScalars.first!.value - 30)!) : Character(Unicode.Scalar(char.unicodeScalars.first!.value + 32)!)
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
assistant
```swift
func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let replacements: [Character] = ["c", "g", "k", "q", "w", "C", "G", "K", "Q", "W"]
var encodedMessage = ""
for char in message {
if let index = vowels.firstIndex(of: char) {
encodedMessage.append(replacements[index])
} else if char.isLetter {
let newChar = char.isUppercase ? Character(Unicode.Scalar(char.unicodeScalars.first!.value - 30)!) : Character(Unicode.Scalar(char.unicodeScalars.first!.value + 32)!)
encodedMessage.append(newChar)
} else {
encodedMessage.append(char)
}
}
return encodedMessage
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num < 2 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).map { Int(String($0))! }.reduce(0, +)
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num < 2 {
return false
}
for i in 2..<num {
if num % i == 0 {
return false
}
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).map { Int(String($0))! }.reduce(0, +)
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ n: Int) -> Int {
return String(n).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ n: Int) -> Int {
return String(n).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ n: Int) -> Int {
return String(n).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ n: Int) -> Int {
return String(n).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
assistant
```swift
func skjkasdkd(lst: [Int]) -> Int {
func isPrime(_ num: Int) -> Bool {
if num <= 1 {
return false
}
if num <= 3 {
return true
}
if num % 2 == 0 || num % 3 == 0 {
return false
}
var i = 5
while i * i <= num {
if num % i == 0 || num % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
func sumOfDigits(_ num: Int) -> Int {
return String(num).reduce(0, { $0 + Int(String($1))! })
}
var maxPrime = 0
for num in lst {
if isPrime(num) && num > maxPrime {
maxPrime = num
}
}
return sumOfDigits(maxPrime)
}
```func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
assistant
```swift
func countUpTo(n: Int) -> [Int] {
var primes = [Int]()
for possiblePrime in 2..<n {
var isPrime = true
for number in 2..<possiblePrime {
if possiblePrime % number == 0 {
isPrime = false
break
}
}
if isPrime {
primes.append(possiblePrime)
}
}
return primes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}user
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
assistant
```swift
func multiply(a: Int, b: Int) -> Int {
let lastDigitA = abs(a) % 10
let lastDigitB = abs(b) % 10
return lastDigitA * lastDigitB
}
```func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for i in stride(from: 0, to: s.count, by: 2) {
let index = s.index(s.startIndex, offsetBy: i)
let character = s[index]
if upperVowels.contains(String(character)) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for i in stride(from: 0, to: s.count, by: 2) {
let index = s.index(s.startIndex, offsetBy: i)
let character = s[index]
if upperVowels.contains(String(character)) {
count += 1
}
}
return count
}
```func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, upperVowels.contains(String(char)) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, upperVowels.contains(String(char)) {
count += 1
}
}
return count
}
```func countUpper(s: String) -> Int {
let uppercaseVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, uppercaseVowels.contains(String(char)) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let uppercaseVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, uppercaseVowels.contains(String(char)) {
count += 1
}
}
return count
}
```func countUpper(s: String) -> Int {
let upperVowels = Set(["A", "E", "I", "O", "U"])
let stringArray = Array(s)
var count = 0
for i in stride(from: 0, to: stringArray.count, by: 2) {
if upperVowels.contains(String(stringArray[i])) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let upperVowels = Set(["A", "E", "I", "O", "U"])
let stringArray = Array(s)
var count = 0
for i in stride(from: 0, to: stringArray.count, by: 2) {
if upperVowels.contains(String(stringArray[i])) {
count += 1
}
}
return count
}
```func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && upperVowels.contains(String(char)) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && upperVowels.contains(String(char)) {
count += 1
}
}
return count
}
```func countUpper(s: String) -> Int {
let uppercaseVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, uppercaseVowels.contains(String(char)) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let uppercaseVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, uppercaseVowels.contains(String(char)) {
count += 1
}
}
return count
}
```func countUpper(s: String) -> Int {
let uppercaseVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, uppercaseVowels.contains(String(char)) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let uppercaseVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, uppercaseVowels.contains(String(char)) {
count += 1
}
}
return count
}
```func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && upperVowels.contains(String(char)) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && upperVowels.contains(String(char)) {
count += 1
}
}
return count
}
```func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, upperVowels.contains(String(char)) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let upperVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, upperVowels.contains(String(char)) {
count += 1
}
}
return count
}
```func countUpper(s: String) -> Int {
let uppercaseVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, uppercaseVowels.contains(String(char)) {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
assistant
```swift
func countUpper(s: String) -> Int {
let uppercaseVowels = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0, uppercaseVowels.contains(String(char)) {
count += 1
}
}
return count
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + (number >= 0 ? 0.5 : -0.5))
}
return Int(rounded)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + (number >= 0 ? 0.5 : -0.5))
}
return Int(rounded)
}
```func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + (number >= 0 ? 0.5 : -0.5))
}
return Int(rounded)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + (number >= 0 ? 0.5 : -0.5))
}
return Int(rounded)
}
```func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
} else {
return Int(rounded)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
} else {
return Int(rounded)
}
}
```func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
}
return Int(rounded)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
}
return Int(rounded)
}
```func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
}
return Int(rounded)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
}
return Int(rounded)
}
```func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
}
return Int(rounded)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
}
return Int(rounded)
}
```func closestInteger(value: String) -> Int {
let number = Double(value)!
if number < 0 {
return Int(number.rounded(.awayFromZero))
} else {
return Int(number.rounded(.toNearestEven))
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)!
if number < 0 {
return Int(number.rounded(.awayFromZero))
} else {
return Int(number.rounded(.toNearestEven))
}
}
```return Int(number.rounded(.toNearestEven)) // type 'FloatingPointRoundingRule' has no member 'toNearestEven'func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int((number > 0) ? ceil(number) : floor(number))
}
return Int(rounded)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int((number > 0) ? ceil(number) : floor(number))
}
return Int(rounded)
}
```func closestInteger(value: String) -> Int {
let number = Double(value) ?? 0
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded * 2)
}
return Int(rounded)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let number = Double(value) ?? 0
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded * 2)
}
return Int(rounded)
}
```func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
}
return Int(rounded)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
assistant
```swift
func closestInteger(value: String) -> Int {
let floatValue = Float(value)
guard let number = floatValue else {
return 0
}
let rounded = round(number)
if rounded - floor(number) == 0.5 {
return Int(rounded + 0.5)
}
return Int(rounded)
}
```func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}
```func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}
```func makeAPile(n: Int) -> [Int] {
var stones = n
var result = [Int]()
for _ in 0..<n {
result.append(stones)
stones = stones % 2 == 0 ? stones + 2 : stones + 1
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var stones = n
var result = [Int]()
for _ in 0..<n {
result.append(stones)
stones = stones % 2 == 0 ? stones + 2 : stones + 1
}
return result
}
``` // XCTAssertTrue failedfunc makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}
```func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}
```func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}
```func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}
```func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}
```func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}
```func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
assistant
```swift
func makeAPile(n: Int) -> [Int] {
var result = [Int]()
var currentNumberOfStones = n
for _ in 0..<n {
result.append(currentNumberOfStones)
if currentNumberOfStones % 2 == 0 {
currentNumberOfStones += 2
} else {
currentNumberOfStones += 2
}
}
return result
}
```func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}
```func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}
```func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [" ", ","])
return words.filter { !$0.isEmpty }
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [" ", ","])
return words.filter { !$0.isEmpty }
}
```func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [" ", ","])
return words.filter { !$0.isEmpty }
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [" ", ","])
return words.filter { !$0.isEmpty }
}
```func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}
```func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [" ", ","])
return words.filter { !$0.isEmpty }
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [" ", ","])
return words.filter { !$0.isEmpty }
}
```func wordsString(s: String) -> [String] {
var words = s.components(separatedBy: " ")
for i in 0..<words.count {
if words[i].contains(",") {
let newWords = words[i].components(separatedBy: ",")
words.replaceSubrange(i...i, with: newWords)
}
}
return words
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
var words = s.components(separatedBy: " ")
for i in 0..<words.count {
if words[i].contains(",") {
let newWords = words[i].components(separatedBy: ",")
words.replaceSubrange(i...i, with: newWords)
}
}
return words
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [" ", ","])
return words.filter { !$0.isEmpty }
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [" ", ","])
return words.filter { !$0.isEmpty }
}
```func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}
```func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
assistant
```swift
func wordsString(s: String) -> [String] {
let words = s.components(separatedBy: [",", " "])
return words.filter { !$0.isEmpty }
}
```func chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var maxEvenNum = -1
for num in x...y {
if num % 2 == 0 && num > maxEvenNum {
maxEvenNum = num
}
}
return maxEvenNum
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEvenNum = -1
for num in x...y {
if num % 2 == 0 && num > maxEvenNum {
maxEvenNum = num
}
}
return maxEvenNum
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var maxEvenNum = -1
for num in x...y {
if num % 2 == 0 && num > maxEvenNum {
maxEvenNum = num
}
}
return maxEvenNum
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEvenNum = -1
for num in x...y {
if num % 2 == 0 && num > maxEvenNum {
maxEvenNum = num
}
}
return maxEvenNum
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEven = -1
for num in x...y {
if num % 2 == 0 && num > maxEven {
maxEven = num
}
}
return maxEven
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var maxEvenNum = -1
for num in x...y {
if num % 2 == 0 && num > maxEvenNum {
maxEvenNum = num
}
}
return maxEvenNum
}user
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
assistant
```swift
func chooseNum(x: Int, y: Int) -> Int {
var maxEvenNum = -1
for num in x...y {
if num % 2 == 0 && num > maxEvenNum {
maxEvenNum = num
}
}
return maxEvenNum
}
``` // Fatal error: Range requires lowerBound <= upperBoundextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}
```return .success(String(Int(avg), radix: 2, prefix: "0b")) // extra argument 'prefix' in callextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}
```return .success(String(Int(avg), radix: 2, prefix: "0b")) // extra argument 'prefix' in callextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}
```return .success(String(Int(avg), radix: 2, prefix: "0b")) // extra argument 'prefix' in callextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let average = Double(sum) / Double(m - n + 1)
let roundedAverage = Int(round(average))
return .success(String(roundedAverage, radix: 2, prefix: "0b"))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let average = Double(sum) / Double(m - n + 1)
let roundedAverage = Int(round(average))
return .success(String(roundedAverage, radix: 2, prefix: "0b"))
}
```return .success(String(roundedAverage, radix: 2, prefix: "0b")) // extra argument 'prefix' in callextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}
```return .success(String(Int(avg), radix: 2, prefix: "0b")) // extra argument 'prefix' in callextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}
```return .success(String(Int(avg), radix: 2, prefix: "0b")) // extra argument 'prefix' in callextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
if n > m {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
if n > m {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}
```return .success(String(Int(avg), radix: 2, prefix: "0b")) // extra argument 'prefix' in callextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let average = Double(sum) / Double(m - n + 1)
let roundedAverage = Int(round(average))
return .success(String(roundedAverage, radix: 2, prefix: "0b"))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let average = Double(sum) / Double(m - n + 1)
let roundedAverage = Int(round(average))
return .success(String(roundedAverage, radix: 2, prefix: "0b"))
}
```return .success(String(roundedAverage, radix: 2, prefix: "0b")) // extra argument 'prefix' in callextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let avg = round(Double(sum) / Double(m - n + 1))
return .success(String(Int(avg), radix: 2, prefix: "0b"))
}
```return .success(String(Int(avg), radix: 2, prefix: "0b")) // extra argument 'prefix' in callextension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let average = Int(Double(sum) / Double(m - n + 1).rounded())
return .success("0b" + String(average, radix: 2))
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) == .success("0b11")
roundedAvg(n: 7, m: 5) == .failure(-1)
roundedAvg(n: 10, m: 20) == .success("0b1111")
roundedAvg(n: 20, m: 33) == .success("0b11010")
assistant
```swift
extension Int: Error {
}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else {
return .failure(-1)
}
let sum = (n...m).reduce(0, +)
let average = Int(Double(sum) / Double(m - n + 1).rounded())
return .success("0b" + String(average, radix: 2))
}
``` // XCTAssertTrue failedfunc uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filtered.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filtered.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let filteredArray = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filteredArray.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filteredArray = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filteredArray.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filtered.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filtered.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let filteredArray = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filteredArray.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filteredArray = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filteredArray.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filtered.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains("2") || $0.description.contains("4") || $0.description.contains("6") || $0.description.contains("8") || $0.description.contains("0")) }
return filtered.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
assistant
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let filtered = x.filter { !($0.description.contains(where: { $0.wholeNumberValue! % 2 == 0 })) }
return filtered.sorted()
}
```func byLength(arr: [Int]) -> [String] {
let numberNames = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
var result = [String]()
for number in arr {
if numberNames.keys.contains(number) {
result.append(numberNames[number]!)
}
}
return result.sorted().reversed()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let numberNames = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
var result = [String]()
for number in arr {
if numberNames.keys.contains(number) {
result.append(numberNames[number]!)
}
}
return result.sorted().reversed()
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(numberNames[num - 1])
}
}
return result.sorted().reversed()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(numberNames[num - 1])
}
}
return result.sorted().reversed()
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numberNames = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
var result = arr.filter { $0 >= 1 && $0 <= 9 }.sorted(by: >).map { numberNames[$0]! }
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let numberNames = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
var result = arr.filter { $0 >= 1 && $0 <= 9 }.sorted(by: >).map { numberNames[$0]! }
return result
}
```var result = arr.filter { $0 >= 1 && $0 <= 9 }.sorted(by: >).map { numberNames[$0]! } // variable 'result' was never mutated; consider changing to 'let' constantfunc byLength(arr: [Int]) -> [String] {
let digitNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(digitNames[num - 1])
}
}
return result.sorted().reversed()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let digitNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(digitNames[num - 1])
}
}
return result.sorted().reversed()
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numberNames: [String] = ["", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result: [String] = []
for num in arr {
if num >= 1 && num <= 9 {
result.append(numberNames[num])
}
}
return result.sorted().reversed()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let numberNames: [String] = ["", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result: [String] = []
for num in arr {
if num >= 1 && num <= 9 {
result.append(numberNames[num])
}
}
return result.sorted().reversed()
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let digitNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(digitNames[num - 1])
}
}
return result.sorted().reversed()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let digitNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(digitNames[num - 1])
}
}
return result.sorted().reversed()
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numberNames = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
if let name = numberNames[num] {
result.append(name)
}
}
}
return result.sorted().reversed()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let numberNames = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
if let name = numberNames[num] {
result.append(name)
}
}
}
return result.sorted().reversed()
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(numberNames[num - 1])
}
}
return result.sorted().reversed()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(numberNames[num - 1])
}
}
return result.sorted().reversed()
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numberNames: [Int: String] = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
let sortedArray = arr.filter { $0 >= 1 && $0 <= 9 }.sorted().reversed()
return Array(sortedArray.map { numberNames[$0]! })
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let numberNames: [Int: String] = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
let sortedArray = arr.filter { $0 >= 1 && $0 <= 9 }.sorted().reversed()
return Array(sortedArray.map { numberNames[$0]! })
}
```func byLength(arr: [Int]) -> [String] {
let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(numberNames[num - 1])
}
}
return result.sorted().reversed()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
assistant
```swift
func byLength(arr: [Int]) -> [String] {
let numberNames = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
var result = [String]()
for num in arr {
if num >= 1 && num <= 9 {
result.append(numberNames[num - 1])
}
}
return result.sorted().reversed()
}
``` // XCTAssertTrue failedfunc f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
result.append(factorial(i))
} else {
result.append(sum(i))
}
}
return result
}
func factorial(_ n: Int) -> Int {
guard n > 1 else { return 1 }
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
return (1...n).reduce(0, +)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
result.append(factorial(i))
} else {
result.append(sum(i))
}
}
return result
}
func factorial(_ n: Int) -> Int {
guard n > 1 else { return 1 }
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
return (1...n).reduce(0, +)
}
```func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
assistant
```swift
func f(n: Int) -> [Int] {
var result = [Int]()
for i in 1...n {
if i % 2 == 0 {
var factorial = 1
for j in 1...i {
factorial *= j
}
result.append(factorial)
} else {
var sum = 0
for j in 1...i {
sum += j
}
result.append(sum)
}
}
return result
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let reversedStringI = String(stringI.reversed())
if stringI == reversedStringI {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let reversedStringI = String(stringI.reversed())
if stringI == reversedStringI {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let reversedStringI = String(stringI.reversed())
if stringI == reversedStringI {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let reversedStringI = String(stringI.reversed())
if stringI == reversedStringI {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let reversedStringI = String(stringI.reversed())
if stringI == reversedStringI {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let reversedStringI = String(stringI.reversed())
if stringI == reversedStringI {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let isPalindrome = stringI == String(stringI.reversed())
if isPalindrome {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let isPalindrome = stringI == String(stringI.reversed())
if isPalindrome {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let str = String(i)
let reversedStr = String(str.reversed())
if str == reversedStr {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let isPalindrome = stringI == String(stringI.reversed())
if isPalindrome {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
assistant
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var evenCount = 0
var oddCount = 0
for i in 1...n {
let stringI = String(i)
let isPalindrome = stringI == String(stringI.reversed())
if isPalindrome {
if i % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
}
return (evenCount, oddCount)
}
```func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
assistant
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
let digits = String(num).map { Int(String($0))! }
let sum = digits.reduce(0, +)
if sum > 0 {
count += 1
}
}
return count
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}
```var sortedArray = arr.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}
```var sortedArray = arr.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
// Perform right shift operation
let lastElement = rotatedArray.removeLast()
rotatedArray.insert(lastElement, at: 0)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
// Perform right shift operation
let lastElement = rotatedArray.removeLast()
rotatedArray.insert(lastElement, at: 0)
}
return false
}
```var sortedArray = arr.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if sortedArray == rotatedArray {
return true
}
rotatedArray = [rotatedArray.last!] + Array(rotatedArray.dropLast())
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if sortedArray == rotatedArray {
return true
}
rotatedArray = [rotatedArray.last!] + Array(rotatedArray.dropLast())
}
return false
}
```var sortedArray = arr.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}
```var sortedArray = arr.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}
```var sortedArray = arr.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var count = 0
for i in 0..<arr.count {
let shiftedArray = arr.dropFirst(i).reversed().dropFirst().reversed()
if Array(shiftedArray) == sortedArray {
count += 1
}
}
return count > 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var count = 0
for i in 0..<arr.count {
let shiftedArray = arr.dropFirst(i).reversed().dropFirst().reversed()
if Array(shiftedArray) == sortedArray {
count += 1
}
}
return count > 0
}
```var sortedArray = arr.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}
```var sortedArray = arr.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constantfunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArr = arr.sorted()
var count = 0
for i in 0..<arr.count {
let shiftedArr = arr.dropFirst(i).reversed().dropFirst().reversed()
if Array(shiftedArr) == sortedArr {
count += 1
}
}
return count > 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArr = arr.sorted()
var count = 0
for i in 0..<arr.count {
let shiftedArr = arr.dropFirst(i).reversed().dropFirst().reversed()
if Array(shiftedArr) == sortedArr {
count += 1
}
}
return count > 0
}
```var sortedArr = arr.sorted() // variable 'sortedArr' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
assistant
```swift
func moveOneBall(arr: [Int]) -> Bool {
if arr.count == 0 {
return true
}
var sortedArray = arr.sorted()
var rotatedArray = arr
for _ in 0..<arr.count {
if rotatedArray == sortedArray {
return true
}
rotatedArray.insert(rotatedArray.removeLast(), at: 0)
}
return false
}
```var sortedArray = arr.sorted() // variable 'sortedArray' was never mutated; consider changing to 'let' constantfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}
```let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 } // initialization of immutable value 'evenNumbersLst1' was never used; consider replacing with assignment to '_' or removing itlet oddNumbersLst2 = lst2.filter { $0 % 2 != 0 } // initialization of immutable value 'oddNumbersLst2' was never used; consider replacing with assignment to '_' or removing itfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}
```let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 } // initialization of immutable value 'evenNumbersLst1' was never used; consider replacing with assignment to '_' or removing itlet oddNumbersLst2 = lst2.filter { $0 % 2 != 0 } // initialization of immutable value 'oddNumbersLst2' was never used; consider replacing with assignment to '_' or removing itfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}
```let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 } // initialization of immutable value 'evenNumbersLst1' was never used; consider replacing with assignment to '_' or removing itlet oddNumbersLst2 = lst2.filter { $0 % 2 != 0 } // initialization of immutable value 'oddNumbersLst2' was never used; consider replacing with assignment to '_' or removing itfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}
```let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 } // initialization of immutable value 'evenNumbersLst1' was never used; consider replacing with assignment to '_' or removing itlet oddNumbersLst2 = lst2.filter { $0 % 2 != 0 } // initialization of immutable value 'oddNumbersLst2' was never used; consider replacing with assignment to '_' or removing itfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }
if oddNumbersInLst1.count <= evenNumbersInLst2.count + evenNumbersInLst1.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }
if oddNumbersInLst1.count <= evenNumbersInLst2.count + evenNumbersInLst1.count {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }
if oddNumbersInLst1.count <= evenNumbersInLst2.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }
if oddNumbersInLst1.count <= evenNumbersInLst2.count {
return "YES"
} else {
return "NO"
}
}
```let evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 } // initialization of immutable value 'evenNumbersInLst1' was never used; consider replacing with assignment to '_' or removing itfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}
```let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 } // initialization of immutable value 'evenNumbersLst1' was never used; consider replacing with assignment to '_' or removing itlet oddNumbersLst2 = lst2.filter { $0 % 2 != 0 } // initialization of immutable value 'oddNumbersLst2' was never used; consider replacing with assignment to '_' or removing itfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}
```let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 } // initialization of immutable value 'evenNumbersLst1' was never used; consider replacing with assignment to '_' or removing itlet oddNumbersLst2 = lst2.filter { $0 % 2 != 0 } // initialization of immutable value 'oddNumbersLst2' was never used; consider replacing with assignment to '_' or removing itfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersLst2 = lst2.filter { $0 % 2 == 0 }
let oddNumbersLst2 = lst2.filter { $0 % 2 != 0 }
if oddNumbersLst1.count <= evenNumbersLst2.count {
return "YES"
} else {
return "NO"
}
}
```let evenNumbersLst1 = lst1.filter { $0 % 2 == 0 } // initialization of immutable value 'evenNumbersLst1' was never used; consider replacing with assignment to '_' or removing itlet oddNumbersLst2 = lst2.filter { $0 % 2 != 0 } // initialization of immutable value 'oddNumbersLst2' was never used; consider replacing with assignment to '_' or removing itfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }
if oddNumbersInLst1.count <= evenNumbersInLst2.count {
return "YES"
} else {
return "NO"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
assistant
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 }
let oddNumbersInLst1 = lst1.filter { $0 % 2 != 0 }
let evenNumbersInLst2 = lst2.filter { $0 % 2 == 0 }
if oddNumbersInLst1.count <= evenNumbersInLst2.count {
return "YES"
} else {
return "NO"
}
}
```let evenNumbersInLst1 = lst1.filter { $0 % 2 == 0 } // initialization of immutable value 'evenNumbersInLst1' was never used; consider replacing with assignment to '_' or removing itfunc histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
// Find the maximum occurrence
let maxOccurrence = dict.values.max()
// Filter the dictionary to only include entries with the maximum occurrence
let result = dict.filter { $1 == maxOccurrence }
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
// Find the maximum occurrence
let maxOccurrence = dict.values.max()
// Filter the dictionary to only include entries with the maximum occurrence
let result = dict.filter { $1 == maxOccurrence }
return result
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word]! += 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func histogram(test: String) -> [String : Int] {
var dict = [String: Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word] = dict[word]! + 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String: Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if dict[word] == nil {
dict[word] = 1
} else {
dict[word] = dict[word]! + 1
}
}
}
if dict.isEmpty {
return [:]
}
let maxValue = dict.values.max()
return dict.filter { $1 == maxValue }
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if result[word] == nil {
result[word] = 1
} else {
result[word]! += 1
}
}
}
if result.isEmpty {
return [:]
}
let maxValue = result.values.max()
return result.filter { $1 == maxValue }
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
assistant
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let words = test.split(separator: " ")
for word in words {
if let word = String(word).trimmingCharacters(in: .whitespaces) {
if result[word] == nil {
result[word] = 1
} else {
result[word]! += 1
}
}
}
if result.isEmpty {
return [:]
}
let maxValue = result.values.max()
return result.filter { $1 == maxValue }
}
```if let word = String(word).trimmingCharacters(in: .whitespaces) { // initializer for conditional binding must have Optional type, not 'String'func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = ""
for char in s {
if !c.contains(char) {
result.append(char)
}
}
let reversed = String(result.reversed())
return (result, result == reversed)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = ""
for char in s {
if !c.contains(char) {
result.append(char)
}
}
let reversed = String(result.reversed())
return (result, result == reversed)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constantfunc reverseDelete(s: String, c: String) -> (String, Bool) {
var result = ""
for char in s {
if !c.contains(char) {
result.append(char)
}
}
let reversed = String(result.reversed())
return (result, result == reversed)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = ""
for char in s {
if !c.contains(char) {
result.append(char)
}
}
let reversed = String(result.reversed())
return (result, result == reversed)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constantfunc reverseDelete(s: String, c: String) -> (String, Bool) {
var result = ""
for char in s {
if !c.contains(char) {
result.append(char)
}
}
let reversed = String(result.reversed())
return (result, result == reversed)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = ""
for char in s {
if !c.contains(char) {
result.append(char)
}
}
let reversed = String(result.reversed())
return (result, result == reversed)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constantfunc reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constantfunc reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constantfunc reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constantfunc reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
assistant
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
var result = s.filter { !c.contains($0) }
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```var result = s.filter { !c.contains($0) } // variable 'result' was never mutated; consider changing to 'let' constantfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(index)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(index)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(index)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(index)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(index)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(index)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, string) in lst.enumerated() {
let oddDigitsCount = string.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(oddDigitsCount)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, str) in lst.enumerated() {
let oddDigitsCount = str.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(index)nput."
result.append(outputString)
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
assistant
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for (index, str) in lst.enumerated() {
let oddDigitsCount = str.filter { $0.wholeNumberValue! % 2 != 0 }.count
let outputString = "the number of odd elements \(oddDigitsCount)n the str\(oddDigitsCount)ng \(index) of the \(index)nput."
result.append(outputString)
}
return result
}
``` // XCTAssertTrue failedfunc minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var current_sum = nums[0]
var min_sum = nums[0]
for i in 1..<nums.count {
current_sum = min(nums[i], current_sum + nums[i])
min_sum = min(min_sum, current_sum)
}
return min_sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var current_sum = nums[0]
var min_sum = nums[0]
for i in 1..<nums.count {
current_sum = min(nums[i], current_sum + nums[i])
min_sum = min(min_sum, current_sum)
}
return min_sum
}
```func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
assistant
```swift
func minSubArraySum(nums: [Int]) -> Int {
var currentSum = nums[0]
var minSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
assistant
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var grid = grid
var count = 0
var bucket = capacity
for i in 0..<grid.count {
for j in 0..<grid[i].count {
if grid[i][j] == 1 && bucket > 0 {
grid[i][j] = 0
bucket -= 1
} else if grid[i][j] == 1 && bucket == 0 {
count += 1
bucket = capacity
grid[i][j] = 0
bucket -= 1
}
}
if bucket == 0 {
count += 1
bucket = capacity
}
}
return count
}
``` // XCTAssertTrue failedfunc sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
assistant
```swift
func sortArray(arr: [Int]) -> [Int] {
return arr.sorted {
let binary1 = String($0, radix: 2)
let binary2 = String($1, radix: 2)
let count1 = binary1.filter { $0 == "1" }.count
let count2 = binary2.filter { $0 == "1" }.count
if count1 == count2 {
return $0 < $1
} else {
return count1 < count2
}
}
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}
```func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
let words = s.split(separator: " ").map { String($0) }
return words.filter {
$0.lowercased().filter { consonants.contains($0) }.count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
let words = s.split(separator: " ").map { String($0) }
return words.filter {
$0.lowercased().filter { consonants.contains($0) }.count == n
}
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.split(separator: " ").map { String($0) }
let consonants = "bcdfghjklmnpqrstvwxyz"
return words.filter { word in
let lowercasedWord = word.lowercased()
let count = lowercasedWord.filter { consonants.contains($0) }.count
return count == n
}
}
```func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
let words = s.split(separator: " ").map { String($0) }
return words.filter {
let lowercased = $0.lowercased()
let count = lowercased.filter { consonants.contains($0) }.count
return count == n
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
assistant
```swift
func selectWords(s: String, n: Int) -> [String] {
let consonants = "bcdfghjklmnpqrstvwxyz"
let words = s.split(separator: " ").map { String($0) }
return words.filter {
let lowercased = $0.lowercased()
let count = lowercased.filter { consonants.contains($0) }.count
return count == n
}
}
```func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]),
!vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]),
!vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}
``` // XCTAssertTrue failedfunc getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) && !vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) && !vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}
``` // XCTAssertTrue failedfunc getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) &&
!vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) &&
!vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}
``` // XCTAssertTrue failedfunc getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) &&
!vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) &&
!vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}
``` // XCTAssertTrue failedfunc getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word)
for i in stride(from: characters.count - 2, through: 1, by: -1) {
if vowels.contains(characters[i]),
!vowels.contains(characters[i - 1]),
!vowels.contains(characters[i + 1]) {
return String(characters[i])
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word)
for i in stride(from: characters.count - 2, through: 1, by: -1) {
if vowels.contains(characters[i]),
!vowels.contains(characters[i - 1]),
!vowels.contains(characters[i + 1]) {
return String(characters[i])
}
}
return ""
}
```func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word)
for i in stride(from: characters.count - 2, through: 1, by: -1) {
if vowels.contains(characters[i]) && !vowels.contains(characters[i - 1]) && !vowels.contains(characters[i + 1]) {
return String(characters[i])
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word)
for i in stride(from: characters.count - 2, through: 1, by: -1) {
if vowels.contains(characters[i]) && !vowels.contains(characters[i - 1]) && !vowels.contains(characters[i + 1]) {
return String(characters[i])
}
}
return ""
}
```func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["A", "E", "I", "O", "U", "a", "e", "i", "o", "u"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) &&
!vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["A", "E", "I", "O", "U", "a", "e", "i", "o", "u"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) &&
!vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}
``` // XCTAssertTrue failedfunc getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["A", "E", "I", "O", "U", "a", "e", "i", "o", "u"]
let characters = Array(word.dropFirst().dropLast()).reversed()
for char in characters {
if vowels.contains(char) {
return String(char)
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["A", "E", "I", "O", "U", "a", "e", "i", "o", "u"]
let characters = Array(word.dropFirst().dropLast()).reversed()
for char in characters {
if vowels.contains(char) {
return String(char)
}
}
return ""
}
``` // XCTAssertTrue failedfunc getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word)
for i in stride(from: characters.count - 2, through: 1, by: -1) {
if vowels.contains(characters[i]),
!vowels.contains(characters[i - 1]),
!vowels.contains(characters[i + 1]) {
return String(characters[i])
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word)
for i in stride(from: characters.count - 2, through: 1, by: -1) {
if vowels.contains(characters[i]),
!vowels.contains(characters[i - 1]),
!vowels.contains(characters[i + 1]) {
return String(characters[i])
}
}
return ""
}
```func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) && !vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
assistant
```swift
func getClosestVowel(word: String) -> String {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
let characters = Array(word.dropFirst().dropLast())
for (index, char) in characters.enumerated().reversed() {
if vowels.contains(char),
index > 0 && index < characters.count - 1,
!vowels.contains(characters[index - 1]) && !vowels.contains(characters[index + 1]) {
return String(char)
}
}
return ""
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for ch in str {
if ch == "(" {
openCount += 1
} else if ch == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for ch in str {
if ch == "(" {
openCount += 1
} else if ch == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for ch in str {
if ch == "(" {
openCount += 1
} else if ch == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for ch in str {
if ch == "(" {
openCount += 1
} else if ch == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for ch in str {
if ch == "(" {
openCount += 1
} else if ch == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for ch in str {
if ch == "(" {
openCount += 1
} else if ch == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for char in str {
if char == "(" {
openCount += 1
} else if char == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for ch in str {
if ch == "(" {
openCount += 1
} else if ch == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
assistant
```swift
func matchParens(lst: [String]) -> String {
var openCount = 0
var closeCount = 0
for str in lst {
for ch in str {
if ch == "(" {
openCount += 1
} else if ch == ")" {
closeCount += 1
}
}
}
if openCount == closeCount {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var array = arr
array.sort(by: >)
return Array(array.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var array = arr
array.sort(by: >)
return Array(array.prefix(k))
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var array = arr
array.sort(by: >)
return Array(array.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var array = arr
array.sort(by: >)
return Array(array.prefix(k))
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var array = arr
array.sort(by: >)
return Array(array.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var array = arr
array.sort(by: >)
return Array(array.prefix(k))
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var array = arr
array.sort(by: >)
return Array(array.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var array = arr
array.sort(by: >)
return Array(array.prefix(k))
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
assistant
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort(by: >)
return Array(arr.prefix(k))
}
``` // XCTAssertTrue failedfunc solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
assistant
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for i in stride(from: 0, to: lst.count, by: 2) {
if lst[i] % 2 != 0 {
sum += lst[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 && arr[i] > -100 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 && arr[i] > -100 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 && arr[i] > -100 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 && arr[i] > -100 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 && arr[i] > -100 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 && arr[i] > -100 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
assistant
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
let numDigits = String(arr[i]).count
if numDigits <= 2 {
sum += arr[i]
}
}
return sum
}
```func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var oddNumbers = [Int]()
while number != 1 {
if number % 2 != 0 && !oddNumbers.contains(number) {
oddNumbers.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
if !oddNumbers.contains(1) {
oddNumbers.append(1)
}
return oddNumbers.sorted()
}
```func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}
```func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}
```func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzArray: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzArray.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzArray.append(1)
return collatzArray.sorted()
}
```func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = Set<Int>()
while current != 1 {
if current % 2 != 0 {
oddNumbers.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.insert(1)
return oddNumbers.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var current = n
var oddNumbers = Set<Int>()
while current != 1 {
if current % 2 != 0 {
oddNumbers.insert(current)
}
current = current % 2 == 0 ? current / 2 : 3 * current + 1
}
oddNumbers.insert(1)
return oddNumbers.sorted()
}
```func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzSequence: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzSequence.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzSequence.append(1) // Add 1 to the sequence as per the Collatz conjecture
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
assistant
```swift
func getOddCollatz(n: Int) -> [Int] {
var number = n
var collatzSequence: [Int] = []
while number != 1 {
if number % 2 != 0 {
collatzSequence.append(number)
}
number = (number % 2 == 0) ? number / 2 : 3 * number + 1
}
collatzSequence.append(1) // Add 1 to the sequence as per the Collatz conjecture
return collatzSequence.filter { $0 % 2 != 0 }.sorted()
}
```func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.year, .month, .day], from: date)
guard let year = components.year,
let month = components.month,
let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if day < 1 || (month == 2 && (day > 29 || (day == 29 && !calendar.isLeapYear(year)))) || (month <= 7 && month % 2 == 0 && day > 30) || (month > 7 && month % 2 != 0 && day > 30) || (month > 7 && month % 2 == 0 && day > 31) || (month <= 7 && month % 2 != 0 && day > 31) {
return false
}
return true
} else {
return false
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.year, .month, .day], from: date)
guard let year = components.year,
let month = components.month,
let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if day < 1 || (month == 2 && (day > 29 || (day == 29 && !calendar.isLeapYear(year)))) || (month <= 7 && month % 2 == 0 && day > 30) || (month > 7 && month % 2 != 0 && day > 30) || (month > 7 && month % 2 == 0 && day > 31) || (month <= 7 && month % 2 != 0 && day > 31) {
return false
}
return true
} else {
return false
}
}
```if day < 1 || (month == 2 && (day > 29 || (day == 29 && !calendar.isLeapYear(year)))) || (month <= 7 && month % 2 == 0 && day > 30) || (month > 7 && month % 2 != 0 && day > 30) || (month > 7 && month % 2 == 0 && day > 31) || (month <= 7 && month % 2 != 0 && day > 31) { // value of type 'Calendar' has no member 'isLeapYear'func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.year, .month, .day], from: date)
guard let year = components.year,
let month = components.month,
let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if day < 1 || (month == 2 && (day > 29 || (day == 29 && !calendar.isLeapYear(year)))) || (month <= 7 && month % 2 == 0 && day > 30) || (month > 7 && month % 2 != 0 && day > 30) || (month > 7 && month % 2 == 0 && day > 31) || (month <= 7 && month % 2 != 0 && day > 31) {
return false
}
return true
} else {
return false
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.year, .month, .day], from: date)
guard let year = components.year,
let month = components.month,
let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if day < 1 || (month == 2 && (day > 29 || (day == 29 && !calendar.isLeapYear(year)))) || (month <= 7 && month % 2 == 0 && day > 30) || (month > 7 && month % 2 != 0 && day > 30) || (month > 7 && month % 2 == 0 && day > 31) || (month <= 7 && month % 2 != 0 && day > 31) {
return false
}
return true
} else {
return false
}
}
```if day < 1 || (month == 2 && (day > 29 || (day == 29 && !calendar.isLeapYear(year)))) || (month <= 7 && month % 2 == 0 && day > 30) || (month > 7 && month % 2 != 0 && day > 30) || (month > 7 && month % 2 == 0 && day > 31) || (month <= 7 && month % 2 != 0 && day > 31) { // value of type 'Calendar' has no member 'isLeapYear'func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.year, .month, .day], from: date)
guard let year = components.year,
let month = components.month,
let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if day < 1 || (month == 2 && (day > 29 || (day == 29 && !calendar.isLeapYear(year)))) || (month <= 7 && month % 2 == 0 && day > 30) || (month > 7 && month % 2 != 0 && day > 30) || (month > 7 && month % 2 == 0 && day > 31) || (month <= 7 && month % 2 != 0 && day > 31) {
return false
}
return true
} else {
return false
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.year, .month, .day], from: date)
guard let year = components.year,
let month = components.month,
let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if day < 1 || (month == 2 && (day > 29 || (day == 29 && !calendar.isLeapYear(year)))) || (month <= 7 && month % 2 == 0 && day > 30) || (month > 7 && month % 2 != 0 && day > 30) || (month > 7 && month % 2 == 0 && day > 31) || (month <= 7 && month % 2 != 0 && day > 31) {
return false
}
return true
} else {
return false
}
}
```if day < 1 || (month == 2 && (day > 29 || (day == 29 && !calendar.isLeapYear(year)))) || (month <= 7 && month % 2 == 0 && day > 30) || (month > 7 && month % 2 != 0 && day > 30) || (month > 7 && month % 2 == 0 && day > 31) || (month <= 7 && month % 2 != 0 && day > 31) { // value of type 'Calendar' has no member 'isLeapYear'func validDate(date: String) -> Bool {
if date.count != 10 {
return false
}
let components = date.split(separator: "-")
if components.count != 3 {
return false
}
guard let month = Int(components[0]),
let day = Int(components[1]),
let year = Int(components[2]) else {
return false
}
if month < 1 || month > 12 {
return false
}
let maxDay: Int
switch month {
case 4, 6, 9, 11: maxDay = 30
case 2: maxDay = 29
default: maxDay = 31
}
if day < 1 || day > maxDay {
return false
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
if date.count != 10 {
return false
}
let components = date.split(separator: "-")
if components.count != 3 {
return false
}
guard let month = Int(components[0]),
let day = Int(components[1]),
let year = Int(components[2]) else {
return false
}
if month < 1 || month > 12 {
return false
}
let maxDay: Int
switch month {
case 4, 6, 9, 11: maxDay = 30
case 2: maxDay = 29
default: maxDay = 31
}
if day < 1 || day > maxDay {
return false
}
return true
}
```let year = Int(components[2]) else { // immutable value 'year' was never used; consider replacing with '_' or removing itfunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.month, .day, .year], from: date)
guard let month = components.month, let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31) {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30) {
return false
}
if month == 2 && (day < 1 || day > 29) {
return false
}
return true
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.month, .day, .year], from: date)
guard let month = components.month, let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31) {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30) {
return false
}
if month == 2 && (day < 1 || day > 29) {
return false
}
return true
}
return false
}
```func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.month, .day, .year], from: date)
let month = components.month!
let day = components.day!
if month < 1 || month > 12 {
return false
}
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31) {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30) {
return false
}
if month == 2 && (day < 1 || day > 29) {
return false
}
return true
} else {
return false
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.month, .day, .year], from: date)
let month = components.month!
let day = components.day!
if month < 1 || month > 12 {
return false
}
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31) {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30) {
return false
}
if month == 2 && (day < 1 || day > 29) {
return false
}
return true
} else {
return false
}
}
```func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.month, .day, .year], from: date)
guard let month = components.month, let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31) {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30) {
return false
}
if month == 2 && (day < 1 || day > 29) {
return false
}
return true
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormatter.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.month, .day, .year], from: date)
guard let month = components.month, let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31) {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30) {
return false
}
if month == 2 && (day < 1 || day > 29) {
return false
}
return true
}
return false
}
```func validDate(date: String) -> Bool {
let dateFormat = DateFormatter()
dateFormat.dateFormat = "MM-dd-yyyy"
dateFormat.locale = Locale(identifier: "en_US")
dateFormat.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormat.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.month, .day, .year], from: date)
guard let month = components.month, let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31) {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30) {
return false
}
if month == 2 && (day < 1 || day > 29) {
return false
}
return true
} else {
return false
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
let dateFormat = DateFormatter()
dateFormat.dateFormat = "MM-dd-yyyy"
dateFormat.locale = Locale(identifier: "en_US")
dateFormat.timeZone = TimeZone(abbreviation: "UTC")
if date.count == 0 {
return false
}
if let date = dateFormat.date(from: date) {
let calendar = Calendar(identifier: .gregorian)
let components = calendar.dateComponents([.month, .day, .year], from: date)
guard let month = components.month, let day = components.day else {
return false
}
if month < 1 || month > 12 {
return false
}
if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31) {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30) {
return false
}
if month == 2 && (day < 1 || day > 29) {
return false
}
return true
} else {
return false
}
}
```func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(identifier: "UTC")
if date.count != 10 {
return false
}
if let _ = dateFormatter.date(from: date) {
let components = date.split(separator: "-").map { Int($0)! }
let month = components[0]
let day = components[1]
let year = components[2]
if month < 1 || month > 12 {
return false
}
if day < 1 || day > 31 {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && day > 30 {
return false
}
if month == 2 {
if day > 29 {
return false
}
if day == 29 && !(year % 4 == 0 && (year % 100 != 0 || year % 400 == 0)) {
return false
}
}
return true
}
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(identifier: "UTC")
if date.count != 10 {
return false
}
if let _ = dateFormatter.date(from: date) {
let components = date.split(separator: "-").map { Int($0)! }
let month = components[0]
let day = components[1]
let year = components[2]
if month < 1 || month > 12 {
return false
}
if day < 1 || day > 31 {
return false
}
if (month == 4 || month == 6 || month == 9 || month == 11) && day > 30 {
return false
}
if month == 2 {
if day > 29 {
return false
}
if day == 29 && !(year % 4 == 0 && (year % 100 != 0 || year % 400 == 0)) {
return false
}
}
return true
}
return false
}
```func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(identifier: "UTC")
dateFormatter.calendar = Calendar(identifier: .gregorian)
if date.count != 10 {
return false
}
if let _ = dateFormatter.date(from: date) {
let components = date.components(separatedBy: "-")
let month = Int(components[0]) ?? 0
let day = Int(components[1]) ?? 0
if month < 1 || month > 12 || day < 1 {
return false
}
switch month {
case 1, 3, 5, 7, 8, 10, 12 where day > 31:
return false
case 4, 6, 9, 11 where day > 30:
return false
case 2 where day > 29:
return false
default:
return true
}
} else {
return false
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
assistant
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US")
dateFormatter.timeZone = TimeZone(identifier: "UTC")
dateFormatter.calendar = Calendar(identifier: .gregorian)
if date.count != 10 {
return false
}
if let _ = dateFormatter.date(from: date) {
let components = date.components(separatedBy: "-")
let month = Int(components[0]) ?? 0
let day = Int(components[1]) ?? 0
if month < 1 || month > 12 || day < 1 {
return false
}
switch month {
case 1, 3, 5, 7, 8, 10, 12 where day > 31:
return false
case 4, 6, 9, 11 where day > 30:
return false
case 2 where day > 29:
return false
default:
return true
}
} else {
return false
}
}
```case 1, 3, 5, 7, 8, 10, 12 where day > 31: // 'where' only applies to the second pattern match in this casecase 4, 6, 9, 11 where day > 30: // 'where' only applies to the second pattern match in this case // XCTAssertTrue failedextension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let split = txt.split(separator: " ").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: " ").map { String($0) })
} else if let split = txt.split(separator: ",").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddOrderedLetters = lowerCaseLetters.filter { (($0.asciiValue ?? 0) - 97) % 2 == 1 }
return .failure(oddOrderedLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let split = txt.split(separator: " ").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: " ").map { String($0) })
} else if let split = txt.split(separator: ",").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddOrderedLetters = lowerCaseLetters.filter { (($0.asciiValue ?? 0) - 97) % 2 == 1 }
return .failure(oddOrderedLetters.count)
}
}
```if let split = txt.split(separator: " ").first(where: { $0.count > 0 }) { // value 'split' was defined but never used; consider replacing with boolean test} else if let split = txt.split(separator: ",").first(where: { $0.count > 0 }) { // value 'split' was defined but never used; consider replacing with boolean test // XCTAssertTrue failedextension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return .success(txt.split(separator: " ").map { String($0) })
} else if txt.contains(",") {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return .success(txt.split(separator: " ").map { String($0) })
} else if txt.contains(",") {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}
```extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return .success(txt.split(separator: " ").map { String($0) })
} else if txt.contains(",") {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return .success(txt.split(separator: " ").map { String($0) })
} else if txt.contains(",") {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}
```extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return .success(txt.split(separator: " ").map { String($0) })
} else if txt.contains(",") {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return .success(txt.split(separator: " ").map { String($0) })
} else if txt.contains(",") {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}
```extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.components(separatedBy: " ").firstWhere({ !$0.isEmpty }) {
return .success(txt.components(separatedBy: " "))
} else if let splitText = txt.components(separatedBy: ",").firstWhere({ !$0.isEmpty }) {
return .success(txt.components(separatedBy: ","))
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.components(separatedBy: " ").firstWhere({ !$0.isEmpty }) {
return .success(txt.components(separatedBy: " "))
} else if let splitText = txt.components(separatedBy: ",").firstWhere({ !$0.isEmpty }) {
return .success(txt.components(separatedBy: ","))
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}
```if let splitText = txt.components(separatedBy: " ").firstWhere({ !$0.isEmpty }) { // value of type '[String]' has no member 'firstWhere'} else if let splitText = txt.components(separatedBy: ",").firstWhere({ !$0.isEmpty }) { // value of type '[String]' has no member 'firstWhere'extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.split(separator: " ").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: " ").map { String($0) })
} else if let splitText = txt.split(separator: ",").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLetter && $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { Int($0.lowercased().unicodeScalars.first!.value) % 2 == 1 }
return .failure(oddLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.split(separator: " ").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: " ").map { String($0) })
} else if let splitText = txt.split(separator: ",").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLetter && $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { Int($0.lowercased().unicodeScalars.first!.value) % 2 == 1 }
return .failure(oddLetters.count)
}
}
```if let splitText = txt.split(separator: " ").first(where: { $0.count > 0 }) { // value 'splitText' was defined but never used; consider replacing with boolean test} else if let splitText = txt.split(separator: ",").first(where: { $0.count > 0 }) { // value 'splitText' was defined but never used; consider replacing with boolean test // XCTAssertTrue failedextension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.split(separator: " ").first {
return .success(txt.split(separator: " ").map { String($0) })
} else if let splitText = txt.split(separator: ",").first {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.split(separator: " ").first {
return .success(txt.split(separator: " ").map { String($0) })
} else if let splitText = txt.split(separator: ",").first {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { ($0.lowercased().unicodeScalars.first!.value - 97) % 2 == 1 }
return .failure(oddLetters.count)
}
}
```if let splitText = txt.split(separator: " ").first { // value 'splitText' was defined but never used; consider replacing with boolean test} else if let splitText = txt.split(separator: ",").first { // value 'splitText' was defined but never used; consider replacing with boolean test // XCTAssertTrue failedextension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.split(separator: " ").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: " ").map { String($0) })
} else if let splitText = txt.split(separator: ",").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLetter && $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { Int($0.lowercased().unicodeScalars.first!.value) % 2 == 1 }
return .failure(oddLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.split(separator: " ").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: " ").map { String($0) })
} else if let splitText = txt.split(separator: ",").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLetter && $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { Int($0.lowercased().unicodeScalars.first!.value) % 2 == 1 }
return .failure(oddLetters.count)
}
}
```if let splitText = txt.split(separator: " ").first(where: { $0.count > 0 }) { // value 'splitText' was defined but never used; consider replacing with boolean test} else if let splitText = txt.split(separator: ",").first(where: { $0.count > 0 }) { // value 'splitText' was defined but never used; consider replacing with boolean test // XCTAssertTrue failedextension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let split = txt.split(separator: " ").first {
return .success(txt.split(separator: " ").map { String($0) })
} else if let split = txt.split(separator: ",").first {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { (($0.asciiValue ?? 0) - Int("a".asciiValue ?? 0)) % 2 == 1 }
return .failure(oddLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let split = txt.split(separator: " ").first {
return .success(txt.split(separator: " ").map { String($0) })
} else if let split = txt.split(separator: ",").first {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { (($0.asciiValue ?? 0) - Int("a".asciiValue ?? 0)) % 2 == 1 }
return .failure(oddLetters.count)
}
}
```extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.split(separator: " ").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: " ").map { String($0) })
} else if let splitText = txt.split(separator: ",").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { (($0.asciiValue ?? 0) - Int("a".asciiValue ?? 0)) % 2 == 1 }
return .failure(oddLetters.count)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
Examples
splitWords(txt: "Hello world!") == .success(["Hello", "world!"])
splitWords(txt: "Hello,world!") == .success(["Hello", "world!"])
splitWords(txt: "abcdef") == .failure(3)
assistant
```swift
extension Int: Error {
}
func splitWords(txt: String) -> Result<[String], Int> {
if let splitText = txt.split(separator: " ").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: " ").map { String($0) })
} else if let splitText = txt.split(separator: ",").first(where: { $0.count > 0 }) {
return .success(txt.split(separator: ",").map { String($0) })
} else {
let lowerCaseLetters = txt.filter { $0.isLowercase }
let oddLetters = lowerCaseLetters.filter { (($0.asciiValue ?? 0) - Int("a".asciiValue ?? 0)) % 2 == 1 }
return .failure(oddLetters.count)
}
}
```func isSorted(lst: [Int]) -> Bool {
if lst.count < 2 {
return true
}
var prev = lst[0]
var count = 1
for num in lst.dropFirst() {
if num == prev {
count += 1
if count > 2 {
return false
}
} else {
if num < prev {
return false
}
prev = num
count = 1
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
if lst.count < 2 {
return true
}
var prev = lst[0]
var count = 1
for num in lst.dropFirst() {
if num == prev {
count += 1
if count > 2 {
return false
}
} else {
if num < prev {
return false
}
prev = num
count = 1
}
}
return true
}
```func isSorted(lst: [Int]) -> Bool {
if lst.count < 2 {
return true
}
var prev = lst[0]
var count = 1
for num in lst.dropFirst() {
if num == prev {
count += 1
if count > 2 {
return false
}
} else {
if num < prev {
return false
}
prev = num
count = 1
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
if lst.count < 2 {
return true
}
var prev = lst[0]
var count = 1
for num in lst.dropFirst() {
if num == prev {
count += 1
if count > 2 {
return false
}
} else {
if num < prev {
return false
}
prev = num
count = 1
}
}
return true
}
```func isSorted(lst: [Int]) -> Bool {
var previousNumber: Int?
var duplicateCount = 0
for number in lst {
if let previousNumber = previousNumber {
if number < previousNumber {
return false
}
if number == previousNumber {
duplicateCount += 1
if duplicateCount > 1 {
return false
}
} else {
duplicateCount = 0
}
}
previousNumber = number
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
var previousNumber: Int?
var duplicateCount = 0
for number in lst {
if let previousNumber = previousNumber {
if number < previousNumber {
return false
}
if number == previousNumber {
duplicateCount += 1
if duplicateCount > 1 {
return false
}
} else {
duplicateCount = 0
}
}
previousNumber = number
}
return true
}
```func isSorted(lst: [Int]) -> Bool {
var duplicateCheck = [Int: Int]()
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
if let count = duplicateCheck[lst[i]] {
if count > 1 {
return false
}
duplicateCheck[lst[i]] = count + 1
} else {
duplicateCheck[lst[i]] = 1
}
}
if let count = duplicateCheck[lst.last!] {
if count > 1 {
return false
}
} else {
duplicateCheck[lst.last!] = 1
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
var duplicateCheck = [Int: Int]()
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
if let count = duplicateCheck[lst[i]] {
if count > 1 {
return false
}
duplicateCheck[lst[i]] = count + 1
} else {
duplicateCheck[lst[i]] = 1
}
}
if let count = duplicateCheck[lst.last!] {
if count > 1 {
return false
}
} else {
duplicateCheck[lst.last!] = 1
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc isSorted(lst: [Int]) -> Bool {
var duplicateCheck = [Int: Int]()
for i in 0..<(lst.count - 1) {
if lst[i] > lst[i + 1] {
return false
}
if let count = duplicateCheck[lst[i]] {
if count > 1 {
return false
}
duplicateCheck[lst[i]] = count + 1
} else {
duplicateCheck[lst[i]] = 1
}
}
if let count = duplicateCheck[lst.last!] {
if count > 1 {
return false
}
} else {
duplicateCheck[lst.last!] = 1
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
var duplicateCheck = [Int: Int]()
for i in 0..<(lst.count - 1) {
if lst[i] > lst[i + 1] {
return false
}
if let count = duplicateCheck[lst[i]] {
if count > 1 {
return false
}
duplicateCheck[lst[i]] = count + 1
} else {
duplicateCheck[lst[i]] = 1
}
}
if let count = duplicateCheck[lst.last!] {
if count > 1 {
return false
}
} else {
duplicateCheck[lst.last!] = 1
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc isSorted(lst: [Int]) -> Bool {
if lst.count < 2 {
return true
}
var prev = lst[0]
var count = 1
for num in lst.dropFirst() {
if num == prev {
count += 1
if count > 2 {
return false
}
} else {
if num < prev {
return false
}
prev = num
count = 1
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
if lst.count < 2 {
return true
}
var prev = lst[0]
var count = 1
for num in lst.dropFirst() {
if num == prev {
count += 1
if count > 2 {
return false
}
} else {
if num < prev {
return false
}
prev = num
count = 1
}
}
return true
}
```func isSorted(lst: [Int]) -> Bool {
var previousNumber: Int?
var duplicateCount = 0
for number in lst {
if let previousNumber = previousNumber {
if number < previousNumber {
return false
}
if number == previousNumber {
duplicateCount += 1
if duplicateCount > 1 {
return false
}
} else {
duplicateCount = 0
}
}
previousNumber = number
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
var previousNumber: Int?
var duplicateCount = 0
for number in lst {
if let previousNumber = previousNumber {
if number < previousNumber {
return false
}
if number == previousNumber {
duplicateCount += 1
if duplicateCount > 1 {
return false
}
} else {
duplicateCount = 0
}
}
previousNumber = number
}
return true
}
```func isSorted(lst: [Int]) -> Bool {
var duplicateCheck = [Int: Int]()
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
if let count = duplicateCheck[lst[i]] {
if count > 1 {
return false
}
duplicateCheck[lst[i]] = count + 1
} else {
duplicateCheck[lst[i]] = 1
}
}
if let count = duplicateCheck[lst.last!] {
if count > 1 {
return false
}
} else {
duplicateCheck[lst.last!] = 1
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
var duplicateCheck = [Int: Int]()
for i in 0..<lst.count - 1 {
if lst[i] > lst[i + 1] {
return false
}
if let count = duplicateCheck[lst[i]] {
if count > 1 {
return false
}
duplicateCheck[lst[i]] = count + 1
} else {
duplicateCheck[lst[i]] = 1
}
}
if let count = duplicateCheck[lst.last!] {
if count > 1 {
return false
}
} else {
duplicateCheck[lst.last!] = 1
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc isSorted(lst: [Int]) -> Bool {
if lst.count < 2 {
return true
}
var prev = lst[0]
var count = 1
for num in lst.dropFirst() {
if num == prev {
count += 1
if count > 2 {
return false
}
} else {
if num < prev {
return false
}
prev = num
count = 1
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
if lst.count < 2 {
return true
}
var prev = lst[0]
var count = 1
for num in lst.dropFirst() {
if num == prev {
count += 1
if count > 2 {
return false
}
} else {
if num < prev {
return false
}
prev = num
count = 1
}
}
return true
}
```func isSorted(lst: [Int]) -> Bool {
var count = 0
for i in 0..<(lst.count - 1) {
if lst[i] > lst[i + 1] {
return false
} else if lst[i] == lst[i + 1] {
count += 1
if count > 1 {
return false
}
} else {
count = 0
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
assistant
```swift
func isSorted(lst: [Int]) -> Bool {
var count = 0
for i in 0..<(lst.count - 1) {
if lst[i] > lst[i + 1] {
return false
} else if lst[i] == lst[i + 1] {
count += 1
if count > 1 {
return false
}
} else {
count = 0
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length < 2 { return "NO" }
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length < 2 { return "NO" }
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length < 2 { return "NO" }
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else { return "NO" }
let length = end - start + 1
if length < 2 { return "NO" }
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
assistant
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
guard start <= end else {
return "NO"
}
let length = end - start + 1
if length < 2 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns = 1
var sumOfMagnitudes = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns = 1
var sumOfMagnitudes = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns = 1
var sumOfMagnitudes = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns = 1
var sumOfMagnitudes = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns = 1
var sumOfMagnitudes = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns = 1
var sumOfMagnitudes = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
assistant
```swift
func prodSigns(arr: [Int]) -> Int? {
if arr.isEmpty {
return nil
}
var productOfSigns: Int = 1
var sumOfMagnitudes: Int = 0
for num in arr {
if num == 0 {
return 0
}
productOfSigns *= (num > 0 ? 1 : -1)
sumOfMagnitudes += abs(num)
}
return productOfSigns * sumOfMagnitudes
}
```func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
let newMask = mask ^ (1 << i)
if dp[i][mask].count + 1 < dp[ni][newMask].count || dp[ni][newMask].isEmpty {
dp[ni][newMask] = dp[i][mask] + [grid[x][y]]
}
}
}
}
}
}
}
}
}
for mask in 1..<1 << n * n {
if dp[(n - 1) * n + (n - 1)][mask].count == k {
if minPath.isEmpty || dp[(n - 1) * n + (n - 1)][mask] < minPath {
minPath = dp[(n - 1) * n + (n - 1)][mask]
}
}
}
return minPath
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
let newMask = mask ^ (1 << i)
if dp[i][mask].count + 1 < dp[ni][newMask].count || dp[ni][newMask].isEmpty {
dp[ni][newMask] = dp[i][mask] + [grid[x][y]]
}
}
}
}
}
}
}
}
}
for mask in 1..<1 << n * n {
if dp[(n - 1) * n + (n - 1)][mask].count == k {
if minPath.isEmpty || dp[(n - 1) * n + (n - 1)][mask] < minPath {
minPath = dp[(n - 1) * n + (n - 1)][mask]
}
}
}
return minPath
}
```if minPath.isEmpty || dp[(n - 1) * n + (n - 1)][mask] < minPath { // binary operator '<' cannot be applied to two '[Int]' operandsfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: n), count: n)
var d = [[-1, 0], [0, -1], [1, 0], [0, 1]]
for i in 0..<n {
for j in 0..<n {
dp[i][j] = [grid[i][j]]
}
}
for _ in 1..<k {
var ndp = Array(repeating: Array(repeating: [Int](), count: n), count: n)
for i in 0..<n {
for j in 0..<n {
for dx in d {
let ni = i + dx[0]
let nj = j + dx[1]
if ni >= 0 && ni < n && nj >= 0 && nj < n {
for path in dp[ni][nj] {
var newPath = path
newPath.append(grid[i][j])
newPath.sort()
if ndp[i][j].count == 0 || newPath < ndp[i][j] {
ndp[i][j] = newPath
}
}
}
}
}
}
dp = ndp
}
var res = [Int]()
for i in 0..<n {
for j in 0..<n {
if res.count == 0 || dp[i][j] < res {
res = dp[i][j]
}
}
}
return res
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: n), count: n)
var d = [[-1, 0], [0, -1], [1, 0], [0, 1]]
for i in 0..<n {
for j in 0..<n {
dp[i][j] = [grid[i][j]]
}
}
for _ in 1..<k {
var ndp = Array(repeating: Array(repeating: [Int](), count: n), count: n)
for i in 0..<n {
for j in 0..<n {
for dx in d {
let ni = i + dx[0]
let nj = j + dx[1]
if ni >= 0 && ni < n && nj >= 0 && nj < n {
for path in dp[ni][nj] {
var newPath = path
newPath.append(grid[i][j])
newPath.sort()
if ndp[i][j].count == 0 || newPath < ndp[i][j] {
ndp[i][j] = newPath
}
}
}
}
}
}
dp = ndp
}
var res = [Int]()
for i in 0..<n {
for j in 0..<n {
if res.count == 0 || dp[i][j] < res {
res = dp[i][j]
}
}
}
return res
}
```newPath.append(grid[i][j]) // value of type 'Int' has no member 'append'newPath.sort() // value of type 'Int' has no member 'sort'if ndp[i][j].count == 0 || newPath < ndp[i][j] { // cannot convert value of type '[Int]' to expected argument type 'Int'ndp[i][j] = newPath // cannot assign value of type 'Int' to subscript of type '[Int]'if res.count == 0 || dp[i][j] < res { // binary operator '<' cannot be applied to two '[Int]' operandsfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
for path in dp[ni][mask ^ (1 << i)] {
let newPath = dp[i][mask] + [grid[x][y]] + path
if newPath.count <= k {
if dp[i][mask].isEmpty || newPath < dp[i][mask] {
dp[i][mask] = newPath
}
}
}
}
}
}
}
}
}
}
}
for i in 0..<n * n {
if !dp[i][(1 << n * n) - 1].isEmpty && (minPath.isEmpty || dp[i][(1 << n * n) - 1] < minPath) {
minPath = dp[i][(1 << n * n) - 1]
}
}
return minPath
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
for path in dp[ni][mask ^ (1 << i)] {
let newPath = dp[i][mask] + [grid[x][y]] + path
if newPath.count <= k {
if dp[i][mask].isEmpty || newPath < dp[i][mask] {
dp[i][mask] = newPath
}
}
}
}
}
}
}
}
}
}
}
for i in 0..<n * n {
if !dp[i][(1 << n * n) - 1].isEmpty && (minPath.isEmpty || dp[i][(1 << n * n) - 1] < minPath) {
minPath = dp[i][(1 << n * n) - 1]
}
}
return minPath
}
```let newPath = dp[i][mask] + [grid[x][y]] + path // cannot convert value of type 'Int' to expected argument type 'Array<Int>'if dp[i][mask].isEmpty || newPath < dp[i][mask] { // binary operator '<' cannot be applied to operands of type '()' and '[Int]'if !dp[i][(1 << n * n) - 1].isEmpty && (minPath.isEmpty || dp[i][(1 << n * n) - 1] < minPath) { // binary operator '<' cannot be applied to two '[Int]' operandsfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
for path in dp[ni][mask ^ (1 << i)] {
let newPath = path + [grid[x][y]]
if dp[i][mask].isEmpty || newPath < dp[i][mask] {
dp[i][mask] = newPath
}
}
}
}
}
}
}
}
}
}
for i in 0..<n * n {
if dp[i][(1 << n * n) - 1].count == k && (minPath.isEmpty || dp[i][(1 << n * n) - 1] < minPath) {
minPath = dp[i][(1 << n * n) - 1]
}
}
return minPath
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
for path in dp[ni][mask ^ (1 << i)] {
let newPath = path + [grid[x][y]]
if dp[i][mask].isEmpty || newPath < dp[i][mask] {
dp[i][mask] = newPath
}
}
}
}
}
}
}
}
}
}
for i in 0..<n * n {
if dp[i][(1 << n * n) - 1].count == k && (minPath.isEmpty || dp[i][(1 << n * n) - 1] < minPath) {
minPath = dp[i][(1 << n * n) - 1]
}
}
return minPath
}
```let newPath = path + [grid[x][y]] // binary operator '+' cannot be applied to operands of type 'Int' and '[Int]'if dp[i][mask].isEmpty || newPath < dp[i][mask] { // binary operator '<' cannot be applied to operands of type '()' and '[Int]'if dp[i][(1 << n * n) - 1].count == k && (minPath.isEmpty || dp[i][(1 << n * n) - 1] < minPath) { // binary operator '<' cannot be applied to two '[Int]' operandsfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if (mask >> i & 1) == 0 { continue }
let prevMask = mask ^ 1 << i
if dp[i][prevMask].isEmpty { continue }
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if dx == 0 && dy == 0 { continue }
let nx = x + dx
let ny = y + dy
if nx < 0 || nx >= n || ny < 0 || ny >= n { continue }
let ni = nx * n + ny
if (prevMask >> ni & 1) == 0 { continue }
let newPath = dp[i][prevMask] + [grid[nx][ny]]
if newPath.count > k { continue }
if dp[ni][mask].isEmpty || newPath < dp[ni][mask] {
dp[ni][mask] = newPath
}
}
}
}
}
var result = [Int]()
for i in 0..<n * n {
if dp[i][(1 << n * n) - 1].count == k && (result.isEmpty || dp[i][(1 << n * n) - 1] < result) {
result = dp[i][(1 << n * n) - 1]
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if (mask >> i & 1) == 0 { continue }
let prevMask = mask ^ 1 << i
if dp[i][prevMask].isEmpty { continue }
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if dx == 0 && dy == 0 { continue }
let nx = x + dx
let ny = y + dy
if nx < 0 || nx >= n || ny < 0 || ny >= n { continue }
let ni = nx * n + ny
if (prevMask >> ni & 1) == 0 { continue }
let newPath = dp[i][prevMask] + [grid[nx][ny]]
if newPath.count > k { continue }
if dp[ni][mask].isEmpty || newPath < dp[ni][mask] {
dp[ni][mask] = newPath
}
}
}
}
}
var result = [Int]()
for i in 0..<n * n {
if dp[i][(1 << n * n) - 1].count == k && (result.isEmpty || dp[i][(1 << n * n) - 1] < result) {
result = dp[i][(1 << n * n) - 1]
}
}
return result
}
```if dp[ni][mask].isEmpty || newPath < dp[ni][mask] { // binary operator '<' cannot be applied to two '[Int]' operandsif dp[i][(1 << n * n) - 1].count == k && (result.isEmpty || dp[i][(1 << n * n) - 1] < result) { // binary operator '<' cannot be applied to two '[Int]' operandsfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
for path in dp[ni][mask ^ (1 << i)] {
let newPath = dp[i][mask] + [grid[x][y]] + path
if newPath.count <= k {
if dp[i][mask].isEmpty || newPath < dp[i][mask][0] {
dp[i][mask] = [newPath]
} else if newPath == dp[i][mask][0] {
dp[i][mask].append(newPath)
}
}
}
}
}
}
}
}
}
}
}
for i in 0..<n * n {
if !dp[i][(1 << n * n) - 1].isEmpty && (minPath.isEmpty || dp[i][(1 << n * n) - 1][0] < minPath) {
minPath = dp[i][(1 << n * n) - 1][0]
}
}
return minPath
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
for path in dp[ni][mask ^ (1 << i)] {
let newPath = dp[i][mask] + [grid[x][y]] + path
if newPath.count <= k {
if dp[i][mask].isEmpty || newPath < dp[i][mask][0] {
dp[i][mask] = [newPath]
} else if newPath == dp[i][mask][0] {
dp[i][mask].append(newPath)
}
}
}
}
}
}
}
}
}
}
}
for i in 0..<n * n {
if !dp[i][(1 << n * n) - 1].isEmpty && (minPath.isEmpty || dp[i][(1 << n * n) - 1][0] < minPath) {
minPath = dp[i][(1 << n * n) - 1][0]
}
}
return minPath
}
```let newPath = dp[i][mask] + [grid[x][y]] + path // cannot convert value of type 'Int' to expected argument type 'Array<Int>'if !dp[i][(1 << n * n) - 1].isEmpty && (minPath.isEmpty || dp[i][(1 << n * n) - 1][0] < minPath) { // cannot convert value of type '[Int]' to expected argument type 'Int'minPath = dp[i][(1 << n * n) - 1][0] // cannot assign value of type 'Int' to type '[Int]'func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
for path in dp[ni][mask ^ (1 << i)] {
let newPath = dp[i][mask] + [grid[x][y]] + path
if newPath.count <= k {
if dp[i][mask].isEmpty || newPath < dp[i][mask][0] {
dp[i][mask] = [newPath]
} else if newPath == dp[i][mask][0] {
dp[i][mask].append(newPath)
}
}
}
}
}
}
}
}
}
}
}
for i in 0..<n * n {
if !dp[i][(1 << n * n) - 1].isEmpty && (minPath.isEmpty || dp[i][(1 << n * n) - 1][0] < minPath) {
minPath = dp[i][(1 << n * n) - 1][0]
}
}
return minPath
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
var minPath = [Int]()
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if ((mask >> i) & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if ((mask >> ni) & 1) == 1 {
for path in dp[ni][mask ^ (1 << i)] {
let newPath = dp[i][mask] + [grid[x][y]] + path
if newPath.count <= k {
if dp[i][mask].isEmpty || newPath < dp[i][mask][0] {
dp[i][mask] = [newPath]
} else if newPath == dp[i][mask][0] {
dp[i][mask].append(newPath)
}
}
}
}
}
}
}
}
}
}
}
for i in 0..<n * n {
if !dp[i][(1 << n * n) - 1].isEmpty && (minPath.isEmpty || dp[i][(1 << n * n) - 1][0] < minPath) {
minPath = dp[i][(1 << n * n) - 1][0]
}
}
return minPath
}
```let newPath = dp[i][mask] + [grid[x][y]] + path // cannot convert value of type 'Int' to expected argument type 'Array<Int>'if !dp[i][(1 << n * n) - 1].isEmpty && (minPath.isEmpty || dp[i][(1 << n * n) - 1][0] < minPath) { // cannot convert value of type '[Int]' to expected argument type 'Int'minPath = dp[i][(1 << n * n) - 1][0] // cannot assign value of type 'Int' to type '[Int]'func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if (mask >> i & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if (mask >> ni & 1) == 0 {
let newMask = mask | 1 << ni
if dp[ni].count < k {
dp[ni][newMask] = dp[i][mask] + [grid[nx][ny]]
} else if dp[ni].count == k && dp[ni][newMask] > dp[i][mask] + [grid[nx][ny]] {
dp[ni][newMask] = dp[i][mask] + [grid[nx][ny]]
}
}
}
}
}
}
}
}
}
var result = [Int]()
for i in 0..<n * n {
if dp[i].count == k && (result.count == 0 || result > dp[i][(1 << n * n) - 1]) {
result = dp[i][(1 << n * n) - 1]
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if (mask >> i & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if (mask >> ni & 1) == 0 {
let newMask = mask | 1 << ni
if dp[ni].count < k {
dp[ni][newMask] = dp[i][mask] + [grid[nx][ny]]
} else if dp[ni].count == k && dp[ni][newMask] > dp[i][mask] + [grid[nx][ny]] {
dp[ni][newMask] = dp[i][mask] + [grid[nx][ny]]
}
}
}
}
}
}
}
}
}
var result = [Int]()
for i in 0..<n * n {
if dp[i].count == k && (result.count == 0 || result > dp[i][(1 << n * n) - 1]) {
result = dp[i][(1 << n * n) - 1]
}
}
return result
}
```func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if (mask >> i & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if (mask >> ni & 1) == 0 {
let newMask = mask | 1 << ni
if dp[ni].count < k {
dp[ni][newMask] = dp[i][mask] + [grid[nx][ny]]
} else if dp[ni].count == k && dp[ni][newMask] > dp[i][mask] + [grid[nx][ny]] {
dp[ni][newMask] = dp[i][mask] + [grid[nx][ny]]
}
}
}
}
}
}
}
}
}
var result = [Int]()
for i in 0..<n * n {
if dp[i].count == k && (result.count == 0 || result > dp[i][(1 << n * n) - 1]) {
result = dp[i][(1 << n * n) - 1]
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if (mask >> i & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if (mask >> ni & 1) == 0 {
let newMask = mask | 1 << ni
if dp[ni].count < k {
dp[ni][newMask] = dp[i][mask] + [grid[nx][ny]]
} else if dp[ni].count == k && dp[ni][newMask] > dp[i][mask] + [grid[nx][ny]] {
dp[ni][newMask] = dp[i][mask] + [grid[nx][ny]]
}
}
}
}
}
}
}
}
}
var result = [Int]()
for i in 0..<n * n {
if dp[i].count == k && (result.count == 0 || result > dp[i][(1 << n * n) - 1]) {
result = dp[i][(1 << n * n) - 1]
}
}
return result
}
```func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if (mask >> i & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if (mask >> ni & 1) == 1 {
let newMask = mask ^ (1 << i)
if dp[i][mask].count + 1 < dp[ni][newMask].count || dp[i][mask].count + 1 == dp[ni][newMask].count && dp[i][mask] + [grid[x][y]] < dp[ni][newMask] {
dp[ni][newMask] = dp[i][mask] + [grid[x][y]]
}
}
}
}
}
}
}
}
}
var result = [Int]()
for i in 0..<n * n {
if dp[i][(1 << n * n) - 1].count == k && (result.count == 0 || dp[i][(1 << n * n) - 1] < result) {
result = dp[i][(1 << n * n) - 1]
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
assistant
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: [Int](), count: 1 << n), count: n * n)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1 << i * n + j] = [grid[i][j]]
}
}
for mask in 1..<1 << n * n {
for i in 0..<n * n {
if (mask >> i & 1) == 1 {
let x = i / n
let y = i % n
for dx in [-1, 0, 1] {
for dy in [-1, 0, 1] {
if abs(dx) + abs(dy) == 1 {
let nx = x + dx
let ny = y + dy
if nx >= 0 && nx < n && ny >= 0 && ny < n {
let ni = nx * n + ny
if (mask >> ni & 1) == 1 {
let newMask = mask ^ (1 << i)
if dp[i][mask].count + 1 < dp[ni][newMask].count || dp[i][mask].count + 1 == dp[ni][newMask].count && dp[i][mask] + [grid[x][y]] < dp[ni][newMask] {
dp[ni][newMask] = dp[i][mask] + [grid[x][y]]
}
}
}
}
}
}
}
}
}
var result = [Int]()
for i in 0..<n * n {
if dp[i][(1 << n * n) - 1].count == k && (result.count == 0 || dp[i][(1 << n * n) - 1] < result) {
result = dp[i][(1 << n * n) - 1]
}
}
return result
}
```func tri(n: Int) -> [Int] {
var sequence = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 || i == 1 {
sequence[i] = 1
} else if i == 2 {
sequence[i] = 2
} else {
if i % 2 == 0 {
sequence[i] = 1 + i / 2
} else {
sequence[i] = sequence[i - 1] + sequence[i - 2] + sequence[i + 1]
}
}
}
return sequence
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
var sequence = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 || i == 1 {
sequence[i] = 1
} else if i == 2 {
sequence[i] = 2
} else {
if i % 2 == 0 {
sequence[i] = 1 + i / 2
} else {
sequence[i] = sequence[i - 1] + sequence[i - 2] + sequence[i + 1]
}
}
}
return sequence
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
guard n >= 0 else {
return []
}
var sequence = [Int](repeating: 0, count: n + 1)
sequence[0] = 1
for i in 1...n {
if i % 2 == 0 {
sequence[i] = 1 + i / 2
} else {
sequence[i] = sequence[i - 1] + (i - 1 >= 0 ? sequence[i - 2] : 0) + (i + 1 <= n ? sequence[i + 1] : 0)
}
}
return sequence
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
guard n >= 0 else {
return []
}
var sequence = [Int](repeating: 0, count: n + 1)
sequence[0] = 1
for i in 1...n {
if i % 2 == 0 {
sequence[i] = 1 + i / 2
} else {
sequence[i] = sequence[i - 1] + (i - 1 >= 0 ? sequence[i - 2] : 0) + (i + 1 <= n ? sequence[i + 1] : 0)
}
}
return sequence
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 || i == 1 {
arr[i] = 1
} else if i == 2 {
arr[i] = 2
} else {
if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i - 3]
}
}
}
return arr
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 || i == 1 {
arr[i] = 1
} else if i == 2 {
arr[i] = 2
} else {
if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i - 3]
}
}
}
return arr
}
``` // XCTAssertTrue failedfunc tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 || i == 1 {
arr[i] = 1
} else if i == 2 {
arr[i] = 2
} else {
if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
}
return arr
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 || i == 1 {
arr[i] = 1
} else if i == 2 {
arr[i] = 2
} else {
if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
}
return arr
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
arr[i] = 1
} else if i == 1 {
arr[i] = 3
} else if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
return arr
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
arr[i] = 1
} else if i == 1 {
arr[i] = 3
} else if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
return arr
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
arr[i] = 1
} else if i == 1 {
arr[i] = 3
} else {
if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
}
return arr
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
arr[i] = 1
} else if i == 1 {
arr[i] = 3
} else {
if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
}
return arr
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = Array(repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
result[i] = 1
} else if i == 1 {
result[i] = 3
} else {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
var result = Array(repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
result[i] = 1
} else if i == 1 {
result[i] = 3
} else {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var sequence = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
sequence[i] = 1
} else if i == 1 {
sequence[i] = 3
} else {
if i % 2 == 0 {
sequence[i] = 1 + i / 2
} else {
sequence[i] = sequence[i - 1] + sequence[i - 2] + sequence[i + 1]
}
}
}
return sequence
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
var sequence = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
sequence[i] = 1
} else if i == 1 {
sequence[i] = 3
} else {
if i % 2 == 0 {
sequence[i] = 1 + i / 2
} else {
sequence[i] = sequence[i - 1] + sequence[i - 2] + sequence[i + 1]
}
}
}
return sequence
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
arr[i] = 1
} else if i == 1 {
arr[i] = 3
} else if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
return arr
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
arr[i] = 1
} else if i == 1 {
arr[i] = 3
} else if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
return arr
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
arr[i] = 1
} else if i == 1 {
arr[i] = 3
} else if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
return arr
}user
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
assistant
```swift
func tri(n: Int) -> [Int] {
var arr = [Int](repeating: 0, count: n + 1)
for i in 0...n {
if i == 0 {
arr[i] = 1
} else if i == 1 {
arr[i] = 3
} else if i % 2 == 0 {
arr[i] = 1 + i / 2
} else {
arr[i] = arr[i - 1] + arr[i - 2] + arr[i + 1]
}
}
return arr
}
``` // Fatal error: Index out of rangefunc digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
assistant
```swift
func digits(n: Int) -> Int {
let digits = String(n).map { Int(String($0))! }
let oddDigits = digits.filter { $0 % 2 != 0 }
if oddDigits.isEmpty {
return 0
} else {
return oddDigits.reduce(1, *)
}
}
```func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
assistant
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty || stack.last != "[" {
return false
}
stack.removeLast()
}
}
return !stack.isEmpty
}
``` // XCTAssertTrue failedfunc sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
assistant
```swift
func sumSquares(lst: [Double]) -> Int {
return lst.map { Int(ceil($0)) }.reduce(0, { $0 + $1 * $1 })
}
```func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
assistant
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
if txt.isEmpty {
return false
}
let lastChar = txt.last!
if !lastChar.isLetter {
return false
}
let penultimateIndex = txt.index(txt.endIndex, offsetBy: -2)
let penultimateChar = txt[penultimateIndex]
return !penultimateChar.isLetter
}
``` // Fatal error: String index is out of boundsfunc canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
assistant
```swift
func canArrange(arr: [Int]) -> Int {
for i in stride(from: arr.count - 1, through: 0, by: -1) {
if i > 0 && arr[i] < arr[i - 1] {
return i
}
}
return -1
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
assistant
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int? = nil
var smallestPositive: Int? = nil
for num in lst {
if num < 0 && (largestNegative == nil || num > largestNegative!) {
largestNegative = num
} else if num > 0 && (smallestPositive == nil || num < smallestPositive!) {
smallestPositive = num
}
}
return (largestNegative, smallestPositive)
}
```enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
if aInt == bInt {
return nil
} else {
return aInt > bInt ? a : b
}
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
if aDouble == bDouble {
return nil
} else {
return aDouble > bDouble ? a : b
}
case (.stringValue(let aString), .stringValue(let bString)):
if aString == bString {
return nil
} else {
return aString > bString ? a : b
}
case (.intValue(let aInt), .stringValue(let bString)):
let bInt = bString.replacingOccurrences(of: ",", with: ".").doubleValue
if aInt == bInt {
return nil
} else {
return aInt > bInt ? a : b
}
case (.stringValue(let aString), .intValue(let bInt)):
let aInt = aString.replacingOccurrences(of: ",", with: ".").doubleValue
if aInt == bInt {
return nil
} else {
return aInt > bInt ? a : b
}
case (.doubleValue(let aDouble), .stringValue(let bString)):
let bDouble = bString.replacingOccurrences(of: ",", with: ".").doubleValue
if aDouble == bDouble {
return nil
} else {
return aDouble > bDouble ? a : b
}
case (.stringValue(let aString), .doubleValue(let bDouble)):
let aDouble = aString.replacingOccurrences(of: ",", with: ".").doubleValue
if aDouble == bDouble {
return nil
} else {
return aDouble > bDouble ? a : b
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
if aInt == bInt {
return nil
} else {
return aInt > bInt ? a : b
}
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
if aDouble == bDouble {
return nil
} else {
return aDouble > bDouble ? a : b
}
case (.stringValue(let aString), .stringValue(let bString)):
if aString == bString {
return nil
} else {
return aString > bString ? a : b
}
case (.intValue(let aInt), .stringValue(let bString)):
let bInt = bString.replacingOccurrences(of: ",", with: ".").doubleValue
if aInt == bInt {
return nil
} else {
return aInt > bInt ? a : b
}
case (.stringValue(let aString), .intValue(let bInt)):
let aInt = aString.replacingOccurrences(of: ",", with: ".").doubleValue
if aInt == bInt {
return nil
} else {
return aInt > bInt ? a : b
}
case (.doubleValue(let aDouble), .stringValue(let bString)):
let bDouble = bString.replacingOccurrences(of: ",", with: ".").doubleValue
if aDouble == bDouble {
return nil
} else {
return aDouble > bDouble ? a : b
}
case (.stringValue(let aString), .doubleValue(let bDouble)):
let aDouble = aString.replacingOccurrences(of: ",", with: ".").doubleValue
if aDouble == bDouble {
return nil
} else {
return aDouble > bDouble ? a : b
}
}
}
```switch (a, b) { // switch must be exhaustivelet bInt = bString.replacingOccurrences(of: ",", with: ".").doubleValue // value of type 'String' has no member 'doubleValue'let aInt = aString.replacingOccurrences(of: ",", with: ".").doubleValue // value of type 'String' has no member 'doubleValue'let bDouble = bString.replacingOccurrences(of: ",", with: ".").doubleValue // value of type 'String' has no member 'doubleValue'let aDouble = aString.replacingOccurrences(of: ",", with: ".").doubleValue // value of type 'String' has no member 'doubleValue'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
default:
return nil
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
default:
return nil
}
}
```if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) { // initializer for conditional binding must have Optional type, not 'Double'return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) { // initializer for conditional binding must have Optional type, not 'Double'return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
default:
return nil
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
default:
return nil
}
}
```if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) { // initializer for conditional binding must have Optional type, not 'Double'return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) { // initializer for conditional binding must have Optional type, not 'Double'return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
return aString > bString ? a : (aString == bString ? nil : b)
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return Double(aInt) > bDouble ? a : (Double(aInt) == bDouble ? nil : b)
}
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > Double(bInt) ? a : (aDouble == Double(bInt) ? nil : b)
}
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
case (.doubleValue(let aDouble), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
return aDouble > Double(bString) ? a : (aDouble == Double(bString) ? nil : b)
case (.stringValue(let aString), .doubleValue(let bDouble)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
return Double(aString) > bDouble ? a : (Double(aString) == bDouble ? nil : b)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
return aString > bString ? a : (aString == bString ? nil : b)
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return Double(aInt) > bDouble ? a : (Double(aInt) == bDouble ? nil : b)
}
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > Double(bInt) ? a : (aDouble == Double(bInt) ? nil : b)
}
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
case (.doubleValue(let aDouble), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
return aDouble > Double(bString) ? a : (aDouble == Double(bString) ? nil : b)
case (.stringValue(let aString), .doubleValue(let bDouble)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
return Double(aString) > bDouble ? a : (Double(aString) == bDouble ? nil : b)
}
}
```switch (a, b) { // switch must be exhaustivereturn aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aDouble > Double(bString) ? a : (aDouble == Double(bString) ? nil : b) // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(aString) > bDouble ? a : (Double(aString) == bDouble ? nil : b) // value of optional type 'Double?' must be unwrapped to a value of type 'Double'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return Double(aInt) > bDouble ? a : (Double(aInt) == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > Double(bInt) ? a : (aDouble == Double(bInt) ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
case (.doubleValue(let aDouble), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aDouble > Double(bString) ? a : (aDouble == Double(bString) ? nil : b)
}
case (.stringValue(let aString), .doubleValue(let bDouble)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Double(aString) > bDouble ? a : (Double(aString) == bDouble ? nil : b)
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return Double(aInt) > bDouble ? a : (Double(aInt) == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > Double(bInt) ? a : (aDouble == Double(bInt) ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
case (.doubleValue(let aDouble), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aDouble > Double(bString) ? a : (aDouble == Double(bString) ? nil : b)
}
case (.stringValue(let aString), .doubleValue(let bDouble)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Double(aString) > bDouble ? a : (Double(aString) == bDouble ? nil : b)
}
}
}
```switch (a, b) { // switch must be exhaustivereturn aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return aDouble > Double(bString) ? a : (aDouble == Double(bString) ? nil : b) // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(aString) > bDouble ? a : (Double(aString) == bDouble ? nil : b) // value of optional type 'Double?' must be unwrapped to a value of type 'Double'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)),
(.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aInt),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
case (.doubleValue(let aDouble), .stringValue(let bString)),
(.stringValue(let aString), .doubleValue(let bDouble)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
default:
return nil
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)),
(.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aInt),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
case (.doubleValue(let aDouble), .stringValue(let bString)),
(.stringValue(let aString), .doubleValue(let bDouble)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
default:
return nil
}
}
```case (.intValue(let aInt), .stringValue(let bString)), // 'bString' must be bound in every patterncase (.intValue(let aInt), .stringValue(let bString)), // 'aInt' must be bound in every pattern(.stringValue(let aString), .intValue(let bInt)): // 'aString' must be bound in every pattern(.stringValue(let aString), .intValue(let bInt)): // 'bInt' must be bound in every patternif let aDouble = Double(aInt), // initializer for conditional binding must have Optional type, not 'Double'case (.doubleValue(let aDouble), .stringValue(let bString)), // 'aDouble' must be bound in every patterncase (.doubleValue(let aDouble), .stringValue(let bString)), // 'bString' must be bound in every pattern(.stringValue(let aString), .doubleValue(let bDouble)): // 'aString' must be bound in every pattern(.stringValue(let aString), .doubleValue(let bDouble)): // 'bDouble' must be bound in every patternif let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), // cannot find 'aString' in scopeenum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
if aInt == bInt { return nil }
return aInt > bInt ? a : b
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
if aDouble == bDouble { return nil }
return aDouble > bDouble ? a : b
case (.stringValue(let aString), .stringValue(let bString)):
let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? Double(aString)
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? Double(bString)
if aDouble == bDouble { return nil }
return aDouble! > bDouble! ? a : b
case (.intValue(let aInt), .stringValue(let bString)):
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? Double(bString)
if Double(aInt) == bDouble { return nil }
return Double(aInt)! > bDouble! ? a : Value.stringValue(bString)
case (.stringValue(let aString), .intValue(let bInt)):
let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? Double(aString)
if aDouble == Double(bInt) { return nil }
return aDouble! > Double(bInt)! ? Value.stringValue(aString) : b
case (.doubleValue(let aDouble), .stringValue(let bString)):
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? Double(bString)
if aDouble == bDouble { return nil }
return aDouble > bDouble ? a : Value.stringValue(bString)
case (.stringValue(let aString), .doubleValue(let bDouble)):
let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? Double(aString)
if aDouble == bDouble { return nil }
return aDouble > bDouble ? Value.stringValue(aString) : b
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
if aInt == bInt { return nil }
return aInt > bInt ? a : b
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
if aDouble == bDouble { return nil }
return aDouble > bDouble ? a : b
case (.stringValue(let aString), .stringValue(let bString)):
let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? Double(aString)
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? Double(bString)
if aDouble == bDouble { return nil }
return aDouble! > bDouble! ? a : b
case (.intValue(let aInt), .stringValue(let bString)):
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? Double(bString)
if Double(aInt) == bDouble { return nil }
return Double(aInt)! > bDouble! ? a : Value.stringValue(bString)
case (.stringValue(let aString), .intValue(let bInt)):
let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? Double(aString)
if aDouble == Double(bInt) { return nil }
return aDouble! > Double(bInt)! ? Value.stringValue(aString) : b
case (.doubleValue(let aDouble), .stringValue(let bString)):
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) ?? Double(bString)
if aDouble == bDouble { return nil }
return aDouble > bDouble ? a : Value.stringValue(bString)
case (.stringValue(let aString), .doubleValue(let bDouble)):
let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")) ?? Double(aString)
if aDouble == bDouble { return nil }
return aDouble > bDouble ? Value.stringValue(aString) : b
}
}
```switch (a, b) { // switch must be exhaustivereturn Double(aInt)! > bDouble! ? a : Value.stringValue(bString) // cannot force unwrap value of non-optional type 'Double'return aDouble! > Double(bInt)! ? Value.stringValue(aString) : b // cannot force unwrap value of non-optional type 'Double'return aDouble > bDouble ? a : Value.stringValue(bString) // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return aDouble > bDouble ? Value.stringValue(aString) : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
default:
return nil
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")),
let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
}
default:
return nil
}
}
```} // missing return in global function expected to return 'Value?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
default:
return nil
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
default:
return nil
}
}
```if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) { // initializer for conditional binding must have Optional type, not 'Double'return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) { // initializer for conditional binding must have Optional type, not 'Double'return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
default:
return nil
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compareOne(a: .intValue(1), b: .doubleValue(2.5)) == .doubleValue(2.5)
compareOne(a: .intValue(1), b: .stringValue("2,3")) == .stringValue("2,3")
compareOne(a: .stringValue("5,1"), b: .stringValue("6")) == .stringValue("6")
compareOne(a: .stringValue("1"), b: .intValue(1)) == nil
assistant
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let aInt), .intValue(let bInt)):
return aInt > bInt ? a : (aInt == bInt ? nil : b)
case (.doubleValue(let aDouble), .doubleValue(let bDouble)):
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
case (.stringValue(let aString), .stringValue(let bString)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aString > bString ? a : (aString == bString ? nil : b)
}
case (.intValue(let aInt), .stringValue(let bString)):
if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b)
}
case (.stringValue(let aString), .intValue(let bInt)):
if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) {
return aDouble > bDouble ? a : (aDouble == bDouble ? nil : b)
} else {
return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b)
}
default:
return nil
}
}
```if let bDouble = Double(bString.replacingOccurrences(of: ",", with: ".")), let aDouble = Double(aInt) { // initializer for conditional binding must have Optional type, not 'Double'return aInt > Int(bString) ? a : (aInt == Int(bString) ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'if let aDouble = Double(aString.replacingOccurrences(of: ",", with: ".")), let bDouble = Double(bInt) { // initializer for conditional binding must have Optional type, not 'Double'return Int(aString) > bInt ? a : (Int(aString) == bInt ? nil : b) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}
```func isEqualToSumEven(n: Int) -> Bool {
// If n is less than 8, it cannot be written as the sum of 4 positive even numbers
if n < 8 {
return false
}
// If n is even, it can be written as the sum of 4 positive even numbers
if n % 2 == 0 {
return true
}
// If n is odd, it cannot be written as the sum of 4 positive even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If n is less than 8, it cannot be written as the sum of 4 positive even numbers
if n < 8 {
return false
}
// If n is even, it can be written as the sum of 4 positive even numbers
if n % 2 == 0 {
return true
}
// If n is odd, it cannot be written as the sum of 4 positive even numbers
return false
}
```func isEqualToSumEven(n: Int) -> Bool {
// If n is less than 8, it cannot be written as the sum of 4 positive even numbers
if n < 8 {
return false
}
// If n is even, it can be written as the sum of 4 positive even numbers
if n % 2 == 0 {
return true
}
// If n is odd, it cannot be written as the sum of 4 positive even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If n is less than 8, it cannot be written as the sum of 4 positive even numbers
if n < 8 {
return false
}
// If n is even, it can be written as the sum of 4 positive even numbers
if n % 2 == 0 {
return true
}
// If n is odd, it cannot be written as the sum of 4 positive even numbers
return false
}
```func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}
```func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}
```func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}
```func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 positive even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 positive even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 positive even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 positive even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 positive even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 positive even numbers
return false
}
```func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it can't be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it can't be written as the sum of 4 even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it can't be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it can't be written as the sum of 4 even numbers
return false
}
```func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 even numbers
return false
}
```func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 positive even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 positive even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 positive even numbers
return false
}user
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
assistant
```swift
func isEqualToSumEven(n: Int) -> Bool {
// If the number is less than 8, it cannot be written as the sum of 4 positive even numbers
if n < 8 {
return false
}
// If the number is even, it can be written as the sum of 4 positive even numbers
if n % 2 == 0 {
return true
}
// If the number is odd, it cannot be written as the sum of 4 positive even numbers
return false
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else { return 1 }
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
assistant
```swift
func specialFactorial(n: Int) -> Int {
guard n > 0 else {
return 1
}
var result = 1
for i in 1...n {
var factorial = 1
for j in 1...i {
factorial *= j
}
result *= factorial
}
return result
}
```func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaceCount = 0
for char in text {
if char == " " {
consecutiveSpaceCount += 1
if consecutiveSpaceCount > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaceCount = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaceCount = 0
for char in text {
if char == " " {
consecutiveSpaceCount += 1
if consecutiveSpaceCount > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaceCount = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaceCount = 0
for char in text {
if char == " " {
consecutiveSpaceCount += 1
if consecutiveSpaceCount > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaceCount = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaceCount = 0
for char in text {
if char == " " {
consecutiveSpaceCount += 1
if consecutiveSpaceCount > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaceCount = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
assistant
```swift
func fixSpaces(text: String) -> String {
var result = ""
var consecutiveSpaces = 0
for char in text {
if char == " " {
consecutiveSpaces += 1
if consecutiveSpaces > 2 {
result.append("-")
} else {
result.append("_")
}
} else {
consecutiveSpaces = 0
result.append(char)
}
}
return result
}
``` // XCTAssertTrue failedfunc fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
let digitCount = name.filter { $0.isNumber }.count
if digitCount > 3 || name.isEmpty || !name.first!.isLetter {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
if !validExtensions.contains(extensionName) {
return "No"
}
return "Yes"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
let digitCount = name.filter { $0.isNumber }.count
if digitCount > 3 || name.isEmpty || !name.first!.isLetter {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
if !validExtensions.contains(extensionName) {
return "No"
}
return "Yes"
}
```if !validExtensions.contains(extensionName) { // instance method 'contains' requires the types 'String' and 'Substring.Element' (aka 'Character') be equivalentfunc fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
// Check if the file's name contains exactly one dot '.'
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
// Check if the substring before the dot should not be empty, and it starts with a letter from the latin alphabet ('a'-'z' and 'A'-'Z').
if name.count == 0 || !name.unicodeScalars.first!.isLetter {
return "No"
}
// Check if the substring after the dot should be one of these: ['txt', 'exe', 'dll']
if !["txt", "exe", "dll"].contains(extensionName) {
return "No"
}
// Check if there should not be more than three digits ('0'-'9') in the file's name.
let digitCount = fileName.unicodeScalars.filter { $0.isNumber }.count
if digitCount > 3 {
return "No"
}
return "Yes"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
// Check if the file's name contains exactly one dot '.'
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
// Check if the substring before the dot should not be empty, and it starts with a letter from the latin alphabet ('a'-'z' and 'A'-'Z').
if name.count == 0 || !name.unicodeScalars.first!.isLetter {
return "No"
}
// Check if the substring after the dot should be one of these: ['txt', 'exe', 'dll']
if !["txt", "exe", "dll"].contains(extensionName) {
return "No"
}
// Check if there should not be more than three digits ('0'-'9') in the file's name.
let digitCount = fileName.unicodeScalars.filter { $0.isNumber }.count
if digitCount > 3 {
return "No"
}
return "Yes"
}
```if name.count == 0 || !name.unicodeScalars.first!.isLetter { // value of type 'String.UnicodeScalarView.Element' (aka 'Unicode.Scalar') has no member 'isLetter'let digitCount = fileName.unicodeScalars.filter { $0.isNumber }.count // value of type 'String.UnicodeScalarView.Element' (aka 'Unicode.Scalar') has no member 'isNumber'func fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
let isValidBeforeDot = !beforeDot.isEmpty && beforeDot.first!.isLetter && beforeDot.filter({$0.isDigit}).count <= 3
let isValidAfterDot = ["txt", "exe", "dll"].contains(afterDot)
return isValidBeforeDot && isValidAfterDot ? "Yes" : "No"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
let isValidBeforeDot = !beforeDot.isEmpty && beforeDot.first!.isLetter && beforeDot.filter({$0.isDigit}).count <= 3
let isValidAfterDot = ["txt", "exe", "dll"].contains(afterDot)
return isValidBeforeDot && isValidAfterDot ? "Yes" : "No"
}
```let isValidBeforeDot = !beforeDot.isEmpty && beforeDot.first!.isLetter && beforeDot.filter({$0.isDigit}).count <= 3 // value of type 'Substring.Element' (aka 'Character') has no member 'isDigit'func fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
// Check if the file's name contains exactly one dot '.'
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
// Check if the substring before the dot should not be empty, and it starts with a letter from the latin alphabet ('a'-'z' and 'A'-'Z').
if beforeDot.count == 0 || !CharacterSet.letters.contains(beforeDot.first!.unicodeScalars.first!) {
return "No"
}
// Check if the substring after the dot should be one of these: ['txt', 'exe', 'dll']
if !["txt", "exe", "dll"].contains(afterDot) {
return "No"
}
// Check if there should not be more than three digits ('0'-'9') in the file's name.
let digits = CharacterSet.decimalDigits
let digitCount = fileName.unicodeScalars.filter { $0.isNumber }.count
if digitCount > 3 {
return "No"
}
return "Yes"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
// Check if the file's name contains exactly one dot '.'
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
// Check if the substring before the dot should not be empty, and it starts with a letter from the latin alphabet ('a'-'z' and 'A'-'Z').
if beforeDot.count == 0 || !CharacterSet.letters.contains(beforeDot.first!.unicodeScalars.first!) {
return "No"
}
// Check if the substring after the dot should be one of these: ['txt', 'exe', 'dll']
if !["txt", "exe", "dll"].contains(afterDot) {
return "No"
}
// Check if there should not be more than three digits ('0'-'9') in the file's name.
let digits = CharacterSet.decimalDigits
let digitCount = fileName.unicodeScalars.filter { $0.isNumber }.count
if digitCount > 3 {
return "No"
}
return "Yes"
}
```let digitCount = fileName.unicodeScalars.filter { $0.isNumber }.count // value of type 'String.UnicodeScalarView.Element' (aka 'Unicode.Scalar') has no member 'isNumber'func fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
let digitCount = name.filter { $0.isNumber }.count
if digitCount > 3 || name.isEmpty || !name.first!.isLetter {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
if !validExtensions.contains(extensionName) {
return "No"
}
return "Yes"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
let digitCount = name.filter { $0.isNumber }.count
if digitCount > 3 || name.isEmpty || !name.first!.isLetter {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
if !validExtensions.contains(extensionName) {
return "No"
}
return "Yes"
}
```if !validExtensions.contains(extensionName) { // instance method 'contains' requires the types 'String' and 'Substring.Element' (aka 'Character') be equivalentfunc fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
let isValidBeforeDot = !beforeDot.isEmpty && beforeDot.range(of: "\\d", options: .regularExpression)?.upperBound ?? beforeDot.startIndex > beforeDot.index(beforeDot.startIndex, offsetBy: 3) && beforeDot.first!.isLetter
let isValidAfterDot = ["txt", "exe", "dll"].contains(afterDot)
return isValidBeforeDot && isValidAfterDot ? "Yes" : "No"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
let isValidBeforeDot = !beforeDot.isEmpty && beforeDot.range(of: "\\d", options: .regularExpression)?.upperBound ?? beforeDot.startIndex > beforeDot.index(beforeDot.startIndex, offsetBy: 3) && beforeDot.first!.isLetter
let isValidAfterDot = ["txt", "exe", "dll"].contains(afterDot)
return isValidBeforeDot && isValidAfterDot ? "Yes" : "No"
}
``` // XCTAssertTrue failedfunc fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
let digitCount = beforeDot.filter { $0.isNumber }.count
if digitCount > 3 || afterDot.filter { $0.isNumber }.count > 0 {
return "No"
}
if !beforeDot.first!.isLetter || beforeDot.dropFirst().filter { $0.isLetter || $0.isNumber }.count != beforeDot.count - 1 {
return "No"
}
if !["txt", "exe", "dll"].contains(afterDot) {
return "No"
}
return "Yes"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.split(separator: ".")
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
let digitCount = beforeDot.filter { $0.isNumber }.count
if digitCount > 3 || afterDot.filter { $0.isNumber }.count > 0 {
return "No"
}
if !beforeDot.first!.isLetter || beforeDot.dropFirst().filter { $0.isLetter || $0.isNumber }.count != beforeDot.count - 1 {
return "No"
}
if !["txt", "exe", "dll"].contains(afterDot) {
return "No"
}
return "Yes"
}
```if digitCount > 3 || afterDot.filter { $0.isNumber }.count > 0 { // trailing closure in this context is confusable with the body of the statement; pass as a parenthesized argument to silence this warningif !beforeDot.first!.isLetter || beforeDot.dropFirst().filter { $0.isLetter || $0.isNumber }.count != beforeDot.count - 1 { // trailing closure in this context is confusable with the body of the statement; pass as a parenthesized argument to silence this warning // XCTAssertTrue failedfunc fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
let digitCount = name.filter { $0.isNumber }.count
if digitCount > 3 || name.isEmpty || !name.first!.isLetter {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
if !validExtensions.contains(extensionName) {
return "No"
}
return "Yes"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
let digitCount = name.filter { $0.isNumber }.count
if digitCount > 3 || name.isEmpty || !name.first!.isLetter {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
if !validExtensions.contains(extensionName) {
return "No"
}
return "Yes"
}
```func fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
let isValidName = name.count > 0 && name.range(of: "\\d", options: .regularExpression)?.upperBound ?? name.endIndex == name.endIndex && name.first! >= "A" && name.first! <= "z"
let isValidExtension = ["txt", "exe", "dll"].contains(extensionName)
return isValidName && isValidExtension ? "Yes" : "No"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
if components.count != 2 {
return "No"
}
let name = components[0]
let extensionName = components[1]
let isValidName = name.count > 0 && name.range(of: "\\d", options: .regularExpression)?.upperBound ?? name.endIndex == name.endIndex && name.first! >= "A" && name.first! <= "z"
let isValidExtension = ["txt", "exe", "dll"].contains(extensionName)
return isValidName && isValidExtension ? "Yes" : "No"
}
``` // XCTAssertTrue failedfunc fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
let isValidBeforeDot = !beforeDot.isEmpty && beforeDot.range(of: "\\d", options: .regularExpression)?.upperBound ?? beforeDot.startIndex > beforeDot.index(beforeDot.startIndex, offsetBy: 3) && beforeDot.first?.isLetter == true
let isValidAfterDot = ["txt", "exe", "dll"].contains(afterDot)
return isValidBeforeDot && isValidAfterDot ? "Yes" : "No"
}user
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
assistant
```swift
func fileNameCheck(fileName: String) -> String {
let components = fileName.components(separatedBy: ".")
if components.count != 2 {
return "No"
}
let beforeDot = components[0]
let afterDot = components[1]
let isValidBeforeDot = !beforeDot.isEmpty && beforeDot.range(of: "\\d", options: .regularExpression)?.upperBound ?? beforeDot.startIndex > beforeDot.index(beforeDot.startIndex, offsetBy: 3) && beforeDot.first?.isLetter == true
let isValidAfterDot = ["txt", "exe", "dll"].contains(afterDot)
return isValidBeforeDot && isValidAfterDot ? "Yes" : "No"
}
``` // XCTAssertTrue failedfunc wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords = [String]()
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords = [String]()
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords = [String]()
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords = [String]()
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords = [String]()
for word in words {
if isPrime(word.count) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords = [String]()
for word in words {
if isPrime(word.count) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
let length = word.count
if length > 1 && isPrime(n: length) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
if isPrime(word.count) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
assistant
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.split(separator: " ")
var primeWords: [String] = []
for word in words {
if isPrime(word.count) {
primeWords.append(String(word))
}
}
return primeWords.joined(separator: " ")
}
func isPrime(_ n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}
```return result.truncatingRemainder(dividingBy: 1) == 0 // value of type 'Int' has no member 'truncatingRemainder'func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}
```return result.truncatingRemainder(dividingBy: 1) == 0 // value of type 'Int' has no member 'truncatingRemainder'func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}
```return result.truncatingRemainder(dividingBy: 1) == 0 // value of type 'Int' has no member 'truncatingRemainder'func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}
```return result.truncatingRemainder(dividingBy: 1) == 0 // value of type 'Int' has no member 'truncatingRemainder'func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}
```return result.truncatingRemainder(dividingBy: 1) == 0 // value of type 'Int' has no member 'truncatingRemainder'func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}
```return result.truncatingRemainder(dividingBy: 1) == 0 // value of type 'Int' has no member 'truncatingRemainder'func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}
```return result.truncatingRemainder(dividingBy: 1) == 0 // value of type 'Int' has no member 'truncatingRemainder'func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.isWholeNumber
}
extension Double {
var isWholeNumber: Bool {
return (self - floor(self)).isZero
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.isWholeNumber
}
extension Double {
var isWholeNumber: Bool {
return (self - floor(self)).isZero
}
}
```return result.isWholeNumber // value of type 'Int' has no member 'isWholeNumber'func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.truncatingRemainder(dividingBy: 1) == 0
}
```return result.truncatingRemainder(dividingBy: 1) == 0 // value of type 'Int' has no member 'truncatingRemainder'func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.rounded() == result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
assistant
```swift
func simplify(x: String, n: String) -> Bool {
let xParts = x.split(separator: "/").map { Int($0)! }
let nParts = n.split(separator: "/").map { Int($0)! }
let result = xParts[0] * nParts[0] / xParts[1] / nParts[1]
return result.rounded() == result
}
```return result.rounded() == result // value of type 'Int' has no member 'rounded'func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).dropFirst(1)
let b = String($1).dropFirst(1)
let sum1 = a.compactMap { Int(String($0)) }.reduce(0, +)
let sum2 = b.compactMap { Int(String($0)) }.reduce(0, +)
return sum1 < sum2 || (sum1 == sum2 && nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).dropFirst(1)
let b = String($1).dropFirst(1)
let sum1 = a.compactMap { Int(String($0)) }.reduce(0, +)
let sum2 = b.compactMap { Int(String($0)) }.reduce(0, +)
return sum1 < sum2 || (sum1 == sum2 && nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!)
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).dropFirst(1)
let b = String($1).dropFirst(1)
let sum1 = a.compactMap { Int(String($0)) }.reduce(0, +)
let sum2 = b.compactMap { Int(String($0)) }.reduce(0, +)
return sum1 < sum2 || (sum1 == sum2 && nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).dropFirst(1)
let b = String($1).dropFirst(1)
let sum1 = a.compactMap { Int(String($0)) }.reduce(0, +)
let sum2 = b.compactMap { Int(String($0)) }.reduce(0, +)
return sum1 < sum2 || (sum1 == sum2 && nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!)
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).dropFirst(1)
let b = String($1).dropFirst(1)
let sum1 = a.compactMap { Int(String($0)) }.reduce(0, +)
let sum2 = b.compactMap { Int(String($0)) }.reduce(0, +)
return sum1 < sum2 || (sum1 == sum2 && nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).dropFirst(1)
let b = String($1).dropFirst(1)
let sum1 = a.compactMap { Int(String($0)) }.reduce(0, +)
let sum2 = b.compactMap { Int(String($0)) }.reduce(0, +)
return sum1 < sum2 || (sum1 == sum2 && nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!)
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
let b = String($1).filter { $0.isNumber }.reduce(0, { $0 * 10 + Int(String($1))! })
return a < b
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).dropFirst(1)
let b = String($1).dropFirst(1)
let sum1 = a.compactMap { Int(String($0)) }.reduce(0, +)
let sum2 = b.compactMap { Int(String($0)) }.reduce(0, +)
return sum1 < sum2 || (sum1 == sum2 && nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
assistant
```swift
func orderByPoints(nums: [Int]) -> [Int] {
return nums.sorted {
let a = String($0).dropFirst(1)
let b = String($1).dropFirst(1)
let sum1 = a.compactMap { Int(String($0)) }.reduce(0, +)
let sum2 = b.compactMap { Int(String($0)) }.reduce(0, +)
return sum1 < sum2 || (sum1 == sum2 && nums.firstIndex(of: $0)! < nums.firstIndex(of: $1)!)
}
}
``` // XCTAssertTrue failedfunc specialFilter(nums: [Int]) -> Int {
let oddDigits = ["1", "3", "5", "7", "9"]
let filtered = nums.filter { num in
let strNum = String(abs(num))
let firstDigit = strNum.first
let lastDigit = strNum.last
return num > 10 &&
oddDigits.contains(firstDigit) &&
oddDigits.contains(lastDigit)
}
return filtered.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = ["1", "3", "5", "7", "9"]
let filtered = nums.filter { num in
let strNum = String(abs(num))
let firstDigit = strNum.first
let lastDigit = strNum.last
return num > 10 &&
oddDigits.contains(firstDigit) &&
oddDigits.contains(lastDigit)
}
return filtered.count
}
```oddDigits.contains(firstDigit) && // cannot convert value of type 'String.Element?' (aka 'Optional<Character>') to expected argument type 'String'oddDigits.contains(lastDigit) // cannot convert value of type 'String.Element?' (aka 'Optional<Character>') to expected argument type 'String'func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String($0.absolute)
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String($0.absolute)
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}
```return nums.filter { $0 > 10 }.filter { // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurefunc specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String($0.absolute)
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String($0.absolute)
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}
```return nums.filter { $0 > 10 }.filter { // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurefunc specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }
.filter { oddDigits.contains(abs($0) % 10)) && oddDigits.contains(abs($0) / Int(pow(10.0, Double(log10(Double(abs($0)))))))}
.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }
.filter { oddDigits.contains(abs($0) % 10)) && oddDigits.contains(abs($0) / Int(pow(10.0, Double(log10(Double(abs($0)))))))}
.count
}
```.filter { oddDigits.contains(abs($0) % 10)) && oddDigits.contains(abs($0) / Int(pow(10.0, Double(log10(Double(abs($0)))))))} // consecutive statements on a line must be separated by ';'.filter { oddDigits.contains(abs($0) % 10)) && oddDigits.contains(abs($0) / Int(pow(10.0, Double(log10(Double(abs($0)))))))} // expected expressionfunc specialFilter(nums: [Int]) -> Int {
let oddDigits = ["1", "3", "5", "7", "9"]
return nums.filter { num in
let strNum = String(abs(num))
let firstDigit = strNum.first!
let lastDigit = strNum.last!
return num > 10 && oddDigits.contains(String(firstDigit)) && oddDigits.contains(String(lastDigit))
}.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = ["1", "3", "5", "7", "9"]
return nums.filter { num in
let strNum = String(abs(num))
let firstDigit = strNum.first!
let lastDigit = strNum.last!
return num > 10 && oddDigits.contains(String(firstDigit)) && oddDigits.contains(String(lastDigit))
}.count
}
```func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String($0.absolute)
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String($0.absolute)
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}
```return nums.filter { $0 > 10 }.filter { // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurefunc specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String(abs($0))
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String(abs($0))
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}
```func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String($0.absolute)
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String($0.absolute)
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}
```return nums.filter { $0 > 10 }.filter { // trailing closure passed to parameter of type 'Predicate<Int>' that does not accept a closurefunc specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String(abs($0))
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String(abs($0))
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}
```func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String(abs($0))
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
assistant
```swift
func specialFilter(nums: [Int]) -> Int {
let oddDigits = [1, 3, 5, 7, 9]
return nums.filter { $0 > 10 }.filter {
let strNum = String(abs($0))
let firstDigit = Int(String(strNum.first!))!
let lastDigit = Int(String(strNum.last!))!
return oddDigits.contains(firstDigit) && oddDigits.contains(lastDigit)
}.count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i+1)..<n {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i+1)..<n {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i + 1)..<n {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i+1)..<n {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
assistant
```swift
func getMaxTriples(n: Int) -> Int {
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
var count = 0
for i in 0..<n {
for j in (i+1)..<n {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func sortedListSum(lst: [String]) -> [String] {
var result = lst.filter { $0.count % 2 == 0 }
result.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var result = lst.filter { $0.count % 2 == 0 }
result.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return result
}
```func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}
```func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}
```func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}
```func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}
```func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}
```func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}
```func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}
```func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}
```func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
assistant
```swift
func sortedListSum(lst: [String]) -> [String] {
var filteredList = lst.filter { $0.count % 2 == 0 }
filteredList.sort {
if $0.count == $1.count {
return $0 < $1
} else {
return $0.count < $1.count
}
}
return filteredList
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}user
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
assistant
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime ? x : y
}
```func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 != 0 { // cannot use mutating member on immutable value: 'num' is a 'let' constantif num > 0 && num.round() == num && num % 2 != 0 { // cannot convert value of type 'Double' to expected argument type '()'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 != 0 { // cannot use mutating member on immutable value: 'num' is a 'let' constantif num > 0 && num.round() == num && num % 2 != 0 { // cannot convert value of type 'Double' to expected argument type '()'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 == 1 { // cannot convert value of type 'Double' to expected argument type '()'if num > 0 && num.round() == num && num % 2 == 1 { // cannot use mutating member on immutable value: 'num' is a 'let' constantfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 != 0 { // cannot use mutating member on immutable value: 'num' is a 'let' constantif num > 0 && num.round() == num && num % 2 != 0 { // cannot convert value of type 'Double' to expected argument type '()'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 == 1 { // cannot convert value of type 'Double' to expected argument type '()'if num > 0 && num.round() == num && num % 2 == 1 { // cannot use mutating member on immutable value: 'num' is a 'let' constantfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 == 1 { // cannot convert value of type 'Double' to expected argument type '()'if num > 0 && num.round() == num && num % 2 == 1 { // cannot use mutating member on immutable value: 'num' is a 'let' constantfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 != 0 { // cannot use mutating member on immutable value: 'num' is a 'let' constantif num > 0 && num.round() == num && num % 2 != 0 { // cannot convert value of type 'Double' to expected argument type '()'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 == 1 { // cannot convert value of type 'Double' to expected argument type '()'if num > 0 && num.round() == num && num % 2 == 1 { // cannot use mutating member on immutable value: 'num' is a 'let' constantfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 == 1 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 == 1 { // cannot convert value of type 'Double' to expected argument type '()'if num > 0 && num.round() == num && num % 2 == 1 { // cannot use mutating member on immutable value: 'num' is a 'let' constantfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
assistant
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
for num in lst {
if num > 0 && num.round() == num && num % 2 != 0 {
sum += Int(num * num)
}
}
return sum
}
```if num > 0 && num.round() == num && num % 2 != 0 { // cannot use mutating member on immutable value: 'num' is a 'let' constantif num > 0 && num.round() == num && num % 2 != 0 { // cannot convert value of type 'Double' to expected argument type '()'func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { game[$0.offset] - guess[$0.offset] }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { game[$0.offset] - guess[$0.offset] }
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}user
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
assistant
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return zip(game, guess).map { abs($0 - $1) }
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = -1000
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = -1000
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}user
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
assistant
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
var strongestExtension = ""
var maxStrength = Int.min
for extensionName in extensions {
let CAP = Array(extensionName).filter { $0.isUppercase }.count
let SM = Array(extensionName).filter { $0.isLowercase }.count
let strength = CAP - SM
if strength > maxStrength {
maxStrength = strength
strongestExtension = extensionName
}
}
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typefunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = popLast()!
insert(last, at: 0)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = popLast()!
insert(last, at: 0)
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !isEmpty {
let last = self.removeLast()
self.insert(last, at: 0)
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !isEmpty {
let last = self.removeLast()
self.insert(last, at: 0)
}
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !isEmpty {
append(removeFirst())
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !isEmpty {
append(removeFirst())
}
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !isEmpty {
let last = self.removeLast()
self.insert(last, at: 0)
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !isEmpty {
let last = self.removeLast()
self.insert(last, at: 0)
}
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = popLast()!
insert(last, at: 0)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = popLast()!
insert(last, at: 0)
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = self.removeLast()
insert(last, at: 0)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = self.removeLast()
insert(last, at: 0)
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !self.isEmpty {
self.insert(self.removeLast(), at: 0)
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !self.isEmpty {
self.insert(self.removeLast(), at: 0)
}
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = self.removeLast()
insert(last, at: 0)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = self.removeLast()
insert(last, at: 0)
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !isEmpty {
let last = self.removeLast()
self.insert(last, at: 0)
}
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if !isEmpty {
let last = self.removeLast()
self.insert(last, at: 0)
}
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = self.removeLast()
insert(last, at: 0)
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
assistant
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
if a.count < b.count {
return false
}
let bArray = Array(b)
for _ in 0..<b.count {
if a.contains(String(bArray)) {
return true
}
bArray.rotateRight()
}
return false
}
extension Array where Element == Character {
mutating func rotateRight() {
if isEmpty {
return
}
let last = self.removeLast()
insert(last, at: 0)
}
}
```bArray.rotateRight() // cannot use mutating member on immutable value: 'bArray' is a 'let' constantfunc evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
assistant
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(abs(num)).map { Int(String($0))! }
var evenCount = 0
var oddCount = 0
for digit in digits {
if digit % 2 == 0 {
evenCount += 1
} else {
oddCount += 1
}
}
return (evenCount, oddCount)
}
```func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let map: [(Int, String)] = [(1000, "m"), (900, "cm"), (500, "d"), (400, "cd"), (100, "c"), (90, "xc"), (50, "l"), (40, "xl"), (10, "x"), (9, "ix"), (5, "v"), (4, "iv"), (1, "i")]
var num = number
var result = ""
for (value, rn) in map {
while num >= value {
num -= value
result += rn
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map: [(Int, String)] = [(1000, "m"), (900, "cm"), (500, "d"), (400, "cd"), (100, "c"), (90, "xc"), (50, "l"), (40, "xl"), (10, "x"), (9, "ix"), (5, "v"), (4, "iv"), (1, "i")]
var num = number
var result = ""
for (value, rn) in map {
while num >= value {
num -= value
result += rn
}
}
return result
}
```func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
assistant
```swift
func intToMiniRoman(number: Int) -> String {
let map = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc",
50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in map {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, precision: Double = 0.00001) -> Bool {
return abs(self - value) < precision
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, precision: Double = 0.00001) -> Bool {
return abs(self - value) < precision
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ number: Double, accuracy: Double = 0.00001) -> Bool {
return abs(self - number) < accuracy
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ number: Double, accuracy: Double = 0.00001) -> Bool {
return abs(self - number) < accuracy
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, accuracy: Double = 0.00001) -> Bool {
return abs(self - value) < accuracy
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, accuracy: Double = 0.00001) -> Bool {
return abs(self - value) < accuracy
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, precision: Double = 0.00001) -> Bool {
return abs(self - value) < precision
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, precision: Double = 0.00001) -> Bool {
return abs(self - value) < precision
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ number: Double, accuracy: Double = 0.00001) -> Bool {
return abs(self - number) < accuracy
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ number: Double, accuracy: Double = 0.00001) -> Bool {
return abs(self - number) < accuracy
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, precision: Double = 0.00001) -> Bool {
return abs(self - value) < precision
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, precision: Double = 0.00001) -> Bool {
return abs(self - value) < precision
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ b: Double, precision: Double = 0.00001) -> Bool {
return abs(self - b) < precision
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ b: Double, precision: Double = 0.00001) -> Bool {
return abs(self - b) < precision
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, precision: Double = 0.00001) -> Bool {
return abs(self - value) < precision
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ value: Double, precision: Double = 0.00001) -> Bool {
return abs(self - value) < precision
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ number: Double, accuracy: Double = 0.00001) -> Bool {
return abs(self - number) < accuracy
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ number: Double, accuracy: Double = 0.00001) -> Bool {
return abs(self - number) < accuracy
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ b: Double, precision: Double = 0.00001) -> Bool {
return abs(self - b) < precision
}
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
assistant
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let sides = [a, b, c].sorted()
return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2])
}
extension Double {
func isCloseTo(_ b: Double, precision: Double = 0.00001) -> Bool {
return abs(self - b) < precision
}
}
```return Double(sides[0] * sides[0] + sides[1] * sides[1]).isCloseTo(sides[2] * sides[2]) // cannot convert value of type 'Int' to expected argument type 'Double'func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}user
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
assistant
```swift
func findMax(words: [String]) -> String {
var maxUniqueCount = 0
var maxUniqueWord = ""
for word in words {
let uniqueCharacters = Set(word)
if uniqueCharacters.count > maxUniqueCount {
maxUniqueCount = uniqueCharacters.count
maxUniqueWord = word
} else if uniqueCharacters.count == maxUniqueCount {
if word < maxUniqueWord {
maxUniqueWord = word
}
}
}
return maxUniqueWord
}
```@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
for _ in 1...need {
if remainingCarrots > 0 {
totalEaten += 1
remainingCarrots -= 1
} else {
break
}
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
for _ in 1...need {
if remainingCarrots > 0 {
totalEaten += 1
remainingCarrots -= 1
} else {
break
}
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
// Check if there are enough remaining carrots to meet the need
if need <= remaining {
totalEaten += need
remainingCarrots -= need
} else {
// If not, eat all remaining carrots and still be hungry
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
// Check if there are enough remaining carrots to meet the need
if need <= remaining {
totalEaten += need
remainingCarrots -= need
} else {
// If not, eat all remaining carrots and still be hungry
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}user
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
assistant
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
var totalEaten = number
var remainingCarrots = remaining
if remaining >= need {
totalEaten += need
remainingCarrots -= need
} else {
totalEaten += remaining
remainingCarrots = 0
}
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
let operators = ["+", "*", "-"]
let operands = [2, 3, 4, 5]
let result = doAlgebra(operators: operators, operands: operands)
print(result) // prints: 9
``` // XCTAssertTrue failedfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
``` // XCTAssertTrue failedfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
``` // XCTAssertTrue failedfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
``` // XCTAssertTrue failedfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
``` // XCTAssertTrue failedfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
``` // XCTAssertTrue failedfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result = result / operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
``` // XCTAssertTrue failedfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
let operators = ["+", "*", "-"]
let operands = [2, 3, 4, 5]
let result = doAlgebra(operators: operators, operands: operands)
print(result) // Output: 9
``` // XCTAssertTrue failedfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
``` // XCTAssertTrue failedfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
assistant
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
switch operators[i] {
case "+":
result += operands[i + 1]
case "-":
result -= operands[i + 1]
case "*":
result *= operands[i + 1]
case "//":
result /= operands[i + 1]
case "**":
result = Int(pow(Double(result), Double(operands[i + 1])))
default:
break
}
}
return result
}
``` // XCTAssertTrue failedfunc solve(s: String) -> String {
var result = ""
let string = Array(s)
if !s.rangeOfCharacter(from: CharacterSet.letters).isNil {
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
} else {
result = String(string.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let string = Array(s)
if !s.rangeOfCharacter(from: CharacterSet.letters).isNil {
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
} else {
result = String(string.reversed())
}
return result
}
```if !s.rangeOfCharacter(from: CharacterSet.letters).isNil { // value of type 'Range<String.Index>?' has no member 'isNil'func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result.range(of: "[a-zA-Z]", options: .regularExpression) == nil {
result = String(result.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result.range(of: "[a-zA-Z]", options: .regularExpression) == nil {
result = String(result.reversed())
}
return result
}
```func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}
```func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}
```func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}
```func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}
```func solve(s: String) -> String {
var result = ""
let lowercaseLetters = CharacterSet.lowercaseLetters
let uppercaseLetters = CharacterSet.uppercaseLetters
for char in s {
if lowercaseLetters.contains(char.unicodeScalars.first!) {
result += String(char).uppercased()
} else if uppercaseLetters.contains(char.unicodeScalars.first!) {
result += String(char).lowercased()
} else {
result += String(char)
}
}
if result.range(of: "[a-zA-Z]", options: .regularExpression) == nil {
result = String(result.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let lowercaseLetters = CharacterSet.lowercaseLetters
let uppercaseLetters = CharacterSet.uppercaseLetters
for char in s {
if lowercaseLetters.contains(char.unicodeScalars.first!) {
result += String(char).uppercased()
} else if uppercaseLetters.contains(char.unicodeScalars.first!) {
result += String(char).lowercased()
} else {
result += String(char)
}
}
if result.range(of: "[a-zA-Z]", options: .regularExpression) == nil {
result = String(result.reversed())
}
return result
}
```func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}
```func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}
```func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
assistant
```swift
func solve(s: String) -> String {
var result = ""
let string = Array(s)
for char in string {
if char.isLetter {
if char.isLowercase {
result += String(char).uppercased()
} else {
result += String(char).lowercased()
}
} else {
result += String(char)
}
}
if result == s && s.rangeOfCharacter(from: CharacterSet.letters) == nil {
return String(string.reversed())
}
return result
}
```import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hashString = digest.map { String(format: "%02x", $0) }.joined()
return hashString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hashString = digest.map { String(format: "%02x", $0) }.joined()
return hashString
}
```CC_MD5(data, data.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'CC_MD5(data, data.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}
```CC_MD5(data, data.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'CC_MD5(data, data.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hashString = digest.map { String(format: "%02x", $0) }.joined()
return hashString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hashString = digest.map { String(format: "%02x", $0) }.joined()
return hashString
}
```CC_MD5(data, data.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'CC_MD5(data, data.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hashString = digest.map { String(format: "%02x", $0) }.joined()
return hashString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hashString = digest.map { String(format: "%02x", $0) }.joined()
return hashString
}
```CC_MD5(data, data.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'CC_MD5(data, data.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}
```CC_MD5(data, data.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'CC_MD5(data, data.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}
```CC_MD5(data, data.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'CC_MD5(data, data.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}
```CC_MD5(data, data.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'CC_MD5(data, data.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hashString = digest.map { String(format: "%02x", $0) }.joined()
return hashString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hashString = digest.map { String(format: "%02x", $0) }.joined()
return hashString
}
```CC_MD5(data, data.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'CC_MD5(data, data.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(data, data.count, &digest)
let hexString = String(format: "%02x", arguments: digest)
return hexString
}
```CC_MD5(data, data.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'CC_MD5(data, data.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let textData = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(textData, textData.count, &digest)
let md5String = digest.map { String(format: "%02x", $0) }.joined()
return md5String
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
assistant
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let textData = text.data(using: .utf8)!
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(textData, textData.count, &digest)
let md5String = digest.map { String(format: "%02x", $0) }.joined()
return md5String
}
```CC_MD5(textData, textData.count, &digest) // cannot convert value of type 'Int' to expected argument type 'CC_LONG' (aka 'UInt32')CC_MD5(textData, textData.count, &digest) // cannot convert value of type 'Data' to expected argument type 'UnsafeRawPointer?'func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var start = a
var end = b
if a > b {
start = b
end = a
}
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var start = a
var end = b
if a > b {
start = b
end = a
}
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var start = a
var end = b
if a > b {
start = b
end = a
}
var result: [Int] = []
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var start = a
var end = b
if a > b {
start = b
end = a
}
var result: [Int] = []
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var start = a
var end = b
if a > b {
start = b
end = a
}
var result: [Int] = []
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var start = a
var end = b
if a > b {
start = b
end = a
}
var result: [Int] = []
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result = [Int]()
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let start = a < b ? a : b
let end = a < b ? b : a
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let start = a < b ? a : b
let end = a < b ? b : a
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var start = a
var end = b
if a > b {
start = b
end = a
}
var evenDigits: [Int] = []
for i in start...end {
if i % 2 == 0 {
evenDigits.append(i)
}
}
return evenDigits
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var start = a
var end = b
if a > b {
start = b
end = a
}
var evenDigits: [Int] = []
for i in start...end {
if i % 2 == 0 {
evenDigits.append(i)
}
}
return evenDigits
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result: [Int] = []
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}user
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
assistant
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
let start = a < b ? a : b
let end = a < b ? b : a
var result: [Int] = []
for i in start...end {
if i % 2 == 0 {
result.append(i)
}
}
return result
}
```