func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        let firstNumber = numbers[i]
        for j in (i+1)..<numbers.count {
            let secondNumber = numbers[j]
            if abs(firstNumber - secondNumber) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        let firstNumber = numbers[i]
        for j in (i+1)..<numbers.count {
            let secondNumber = numbers[j]
            if abs(firstNumber - secondNumber) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            if abs(numbers[i] - numbers[j]) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        let firstNumber = numbers[i]
        for j in (i+1)..<numbers.count {
            let secondNumber = numbers[j]
            if abs(firstNumber - secondNumber) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        let firstNumber = numbers[i]
        for j in (i+1)..<numbers.count {
            let secondNumber = numbers[j]
            if abs(firstNumber - secondNumber) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        let firstNumber = numbers[i]
        for j in (i+1)..<numbers.count {
            let secondNumber = numbers[j]
            if abs(firstNumber - secondNumber) < threshold {
                return true
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        let firstNumber = numbers[i]
        for j in (i+1)..<numbers.count {
            let secondNumber = numbers[j]
            if abs(firstNumber - secondNumber) < threshold {
                return true
            }
        }
    }
    return false
}
```

func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        let first = numbers[i]
        let second = numbers[i+1]
        if abs(first - second) < threshold {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true

Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
    for i in 0..<numbers.count-1 {
        let first = numbers[i]
        let second = numbers[i+1]
        if abs(first - second) < threshold {
            return true
        }
    }
    return false
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var balance = 0
    
    for char in parenString {
        if char == " " {
            continue
        } else if char == "(" {
            balance += 1
            currentGroup.append(char)
        } else if char == ")" {
            balance -= 1
            currentGroup.append(char)
            if balance == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var balance = 0
    
    for char in parenString {
        if char == " " {
            continue
        } else if char == "(" {
            balance += 1
            currentGroup.append(char)
        } else if char == ")" {
            balance -= 1
            currentGroup.append(char)
            if balance == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var balance = 0
    
    for char in parenString {
        if char == " " {
            continue
        } else if char == "(" {
            balance += 1
            currentGroup.append(char)
        } else if char == ")" {
            balance -= 1
            currentGroup.append(char)
            if balance == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var balance = 0
    
    for char in parenString {
        if char == " " {
            continue
        } else if char == "(" {
            balance += 1
            currentGroup.append(char)
        } else if char == ")" {
            balance -= 1
            currentGroup.append(char)
            if balance == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var balance = 0
    
    for char in parenString {
        if char == " " {
            continue
        } else if char == "(" {
            balance += 1
            currentGroup.append(char)
        } else if char == ")" {
            balance -= 1
            currentGroup.append(char)
            if balance == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return groups
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var balance = 0
    
    for char in parenString {
        if char == " " {
            continue
        } else if char == "(" {
            balance += 1
            currentGroup.append(char)
        } else if char == ")" {
            balance -= 1
            currentGroup.append(char)
            if balance == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return groups
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " {
            continue
        }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " {
            continue
        }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " {
            continue
        }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " {
            continue
        }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var balance = 0
    
    for char in parenString {
        if char == " " {
            continue
        } else if char == "(" {
            balance += 1
            currentGroup.append(char)
        } else if char == ")" {
            balance -= 1
            currentGroup.append(char)
            if balance == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var balance = 0
    
    for char in parenString {
        if char == " " {
            continue
        } else if char == "(" {
            balance += 1
            currentGroup.append(char)
        } else if char == ")" {
            balance -= 1
            currentGroup.append(char)
            if balance == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " {
            continue
        }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result = [String]()
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " {
            continue
        }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " { continue }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " { continue }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}
```

func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var openCount = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
            currentGroup.append(char)
        } else if char == ")" {
            openCount -= 1
            currentGroup.append(char)
            if openCount == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return groups
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var groups = [String]()
    var currentGroup = ""
    var openCount = 0
    
    for char in parenString {
        if char == "(" {
            openCount += 1
            currentGroup.append(char)
        } else if char == ")" {
            openCount -= 1
            currentGroup.append(char)
            if openCount == 0 {
                groups.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    
    return groups
}
```

func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " {
            continue
        }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]

Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
    var result: [String] = []
    var currentGroup = ""
    var depth = 0
    for char in parenString {
        if char == " " {
            continue
        }
        if char == "(" {
            depth += 1
            currentGroup.append(char)
        } else if char == ")" {
            depth -= 1
            currentGroup.append(char)
            if depth == 0 {
                result.append(currentGroup)
                currentGroup = ""
            }
        }
    }
    return result
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    return number - Double(Int(number))
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5

Answer:
```swift
func truncateNumber(number: Double) -> Double {
    let integerPart = Int(number)
    let decimalPart = number - Double(integerPart)
    return decimalPart
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true

Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
    var balance = 0
    for operation in operations {
        balance += operation
        if balance < 0 {
            return true
        }
    }
    return false
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    guard let mean = numbers.reduce(0, +) / Double(numbers.count) else {
        return 0
    }
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    guard let mean = numbers.reduce(0, +) / Double(numbers.count) else {
        return 0
    }
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0

Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
    let mean = numbers.reduce(0, +) / Double(numbers.count)
    let absoluteDeviations = numbers.map { abs($0 - mean) }
    let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
    return mad
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]

Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
    var result = [Int]()
    for (index, number) in numbers.enumerated() {
        result.append(number)
        if index < numbers.count - 1 {
            result.append(delimeter)
        }
    }
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    
    for parenGroup in parenString.components(separatedBy: " ") {
        var currentNestingLevel = 0
        
        for paren in parenGroup {
            if paren == "(" {
                currentNestingLevel += 1
                maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
            } else {
                currentNestingLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxNestingLevel)
        maxNestingLevel = 0
    }
    
    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    
    for parenGroup in parenString.components(separatedBy: " ") {
        var currentNestingLevel = 0
        
        for paren in parenGroup {
            if paren == "(" {
                currentNestingLevel += 1
                maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
            } else {
                currentNestingLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxNestingLevel)
        maxNestingLevel = 0
    }
    
    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    var currentNestingLevel = 0

    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }

    maxNestingLevels.append(maxNestingLevel)

    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    var currentNestingLevel = 0

    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }

    maxNestingLevels.append(maxNestingLevel)

    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []

    var currentNestingLevel = 0
    for character in parenString {
        if character == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
        } else if character == ")" {
            currentNestingLevel -= 1
        }
    }

    maxNestingLevels.append(maxNestingLevel)

    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []

    var currentNestingLevel = 0
    for character in parenString {
        if character == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
        } else if character == ")" {
            currentNestingLevel -= 1
        }
    }

    maxNestingLevels.append(maxNestingLevel)

    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    var currentNestingLevel = 0

    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }

    maxNestingLevels.append(maxNestingLevel)

    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    var currentNestingLevel = 0

    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }

    maxNestingLevels.append(maxNestingLevel)

    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var result: [Int] = []
    var currentNestingLevel = 0

    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }

    return [Int](repeating: maxNestingLevel, count: parenString.count)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var result: [Int] = []
    var currentNestingLevel = 0

    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }

    return [Int](repeating: maxNestingLevel, count: parenString.count)
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    
    for parenGroup in parenString.components(separatedBy: " ") {
        var currentNestingLevel = 0
        
        for paren in parenGroup {
            if paren == "(" {
                currentNestingLevel += 1
                maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
            } else {
                currentNestingLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxNestingLevel)
        maxNestingLevel = 0
    }
    
    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    
    for parenGroup in parenString.components(separatedBy: " ") {
        var currentNestingLevel = 0
        
        for paren in parenGroup {
            if paren == "(" {
                currentNestingLevel += 1
                maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
            } else {
                currentNestingLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxNestingLevel)
        maxNestingLevel = 0
    }
    
    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    
    for parenGroup in parenString.components(separatedBy: " ") {
        var currentNestingLevel = 0
        
        for paren in parenGroup {
            if paren == "(" {
                currentNestingLevel += 1
                maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
            } else {
                currentNestingLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxNestingLevel)
        maxNestingLevel = 0
    }
    
    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    
    for parenGroup in parenString.components(separatedBy: " ") {
        var currentNestingLevel = 0
        
        for paren in parenGroup {
            if paren == "(" {
                currentNestingLevel += 1
                maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
            } else {
                currentNestingLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxNestingLevel)
        maxNestingLevel = 0
    }
    
    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    
    for parenGroup in parenString.components(separatedBy: " ") {
        var currentNestingLevel = 0
        
        for paren in parenGroup {
            if paren == "(" {
                currentNestingLevel += 1
                maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
            } else {
                currentNestingLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxNestingLevel)
        maxNestingLevel = 0
    }
    
    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    
    for parenGroup in parenString.components(separatedBy: " ") {
        var currentNestingLevel = 0
        
        for paren in parenGroup {
            if paren == "(" {
                currentNestingLevel += 1
                maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
            } else {
                currentNestingLevel -= 1
            }
        }
        
        maxNestingLevels.append(maxNestingLevel)
        maxNestingLevel = 0
    }
    
    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var result: [Int] = []
    var currentNestingLevel = 0
    
    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }
    
    result.append(maxNestingLevel)
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var result: [Int] = []
    var currentNestingLevel = 0
    
    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }
    
    result.append(maxNestingLevel)
    
    return result
}
```

func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    var currentNestingLevel = 0

    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }

    maxNestingLevels.append(maxNestingLevel)

    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]

Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
    var maxNestingLevel = 0
    var maxNestingLevels: [Int] = []
    var currentNestingLevel = 0

    for char in parenString {
        if char == "(" {
            currentNestingLevel += 1
            maxNestingLevel = max(currentNestingLevel, maxNestingLevel)
        } else if char == ")" {
            currentNestingLevel -= 1
        }
    }

    maxNestingLevels.append(maxNestingLevel)

    return maxNestingLevels
}

func maxNesting(_ a: Int, _ b: Int) -> Int {
    return a > b? a : b
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]

Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
    return strings.filter { $0.contains(substring) }
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)

Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
    var sum = 0
    var product = 1
    for number in numbers {
        sum += number
        product *= number
    }
    return (sum, product)
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers.first!
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers.first!
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers[0]
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers.first!
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers.first!
    for number in numbers {
        max = max > number? max : number
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers.first!
    result.append(maxElement)
    for number in numbers[1..<numbers.count] {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers.first!
    result.append(maxElement)
    for number in numbers[1..<numbers.count] {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers.first!
    result.append(max)
    for number in numbers[1..<numbers.count] {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var max = numbers.first!
    result.append(max)
    for number in numbers[1..<numbers.count] {
        if number > max {
            max = number
        }
        result.append(max)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}
```

func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]

Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var maxElement = numbers[0]
    for number in numbers {
        if number > maxElement {
            maxElement = number
        }
        result.append(maxElement)
    }
    return result
}
```

func makePalindrome(string: String) -> String {
    let string = string.lowercased()
    let reversedString = String(string.reversed())
    let range = string.index(string.startIndex, offsetBy: string.count - 1)..<string.endIndex
    let prefix = string[string.startIndex..<range.lowerBound]
    let palindromicSuffix = string[range]
    let reversedPrefix = String(prefix.reversed())
    let palindrome = palindromicSuffix + reversedPrefix
    return palindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let string = string.lowercased()
    let reversedString = String(string.reversed())
    let range = string.index(string.startIndex, offsetBy: string.count - 1)..<string.endIndex
    let prefix = string[string.startIndex..<range.lowerBound]
    let palindromicSuffix = string[range]
    let reversedPrefix = String(prefix.reversed())
    let palindrome = palindromicSuffix + reversedPrefix
    return palindrome
}
```

func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindromicSuffix = characters.suffix(while: { reversed.contains($0) })
    let prefixReversed = prefix.reversed()
    let result = prefix + palindromicSuffix + prefixReversed
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindromicSuffix = characters.suffix(while: { reversed.contains($0) })
    let prefixReversed = prefix.reversed()
    let result = prefix + palindromicSuffix + prefixReversed
    return String(result)
}
```

func makePalindrome(string: String) -> String {
    let string = string.lowercased()
    let reversedString = String(string.reversed())
    let hasPalindromePrefix = string.hasPrefix(reversedString)
    guard!hasPalindromePrefix else { return string }
    let reversedPrefix = reversedString.prefix(while: { reversedString.hasPrefix(String($0)})
    let prefix = String(reversedPrefix.reversed())
    return string + prefix
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let string = string.lowercased()
    let reversedString = String(string.reversed())
    let hasPalindromePrefix = string.hasPrefix(reversedString)
    guard!hasPalindromePrefix else { return string }
    let reversedPrefix = reversedString.prefix(while: { reversedString.hasPrefix(String($0)})
    let prefix = String(reversedPrefix.reversed())
    return string + prefix
}
```

func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindrome = prefix + characters + prefix.reversed()
    return String(palindrome)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindrome = prefix + characters + prefix.reversed()
    return String(palindrome)
}
```

func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindrome = prefix + characters + prefix.reversed()
    return String(palindrome)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindrome = prefix + characters + prefix.reversed()
    return String(palindrome)
}
```

func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindromicSuffix = characters.suffix(while: { reversed.contains($0) })
    let prefixReversed = prefix.reversed()
    let result = prefix + palindromicSuffix + prefixReversed
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindromicSuffix = characters.suffix(while: { reversed.contains($0) })
    let prefixReversed = prefix.reversed()
    let result = prefix + palindromicSuffix + prefixReversed
    return String(result)
}
```

func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindromicSuffix = characters.suffix(while: { reversed.contains($0) })
    let prefixReversed = prefix.reversed()
    let result = prefix + palindromicSuffix + prefixReversed
    return String(result)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindromicSuffix = characters.suffix(while: { reversed.contains($0) })
    let prefixReversed = prefix.reversed()
    let result = prefix + palindromicSuffix + prefixReversed
    return String(result)
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindromicSuffix = reversedString.longestPalindromicSuffix
    let prefix = String(string.prefix(string.count - longestPalindromicSuffix.count))
    let reversedPrefix = String(prefix.reversed())
    return string + reversedPrefix
}

extension String {
    var reversed: ReversedCollection<String> {
        return reversed()
    }

    func prefix(_ length: Int) -> Substring {
        return prefix(length)
    }

    func suffix(_ length: Int) -> Substring {
        return suffix(length)
    }
}

extension StringProtocol StringProtocol {
    var reversed: ReversedCollection<Self> { get }
    func prefix(_ length: Int) -> Substring
    func suffix(_ length: Int) -> Substring
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindromicSuffix = reversedString.longestPalindromicSuffix
    let prefix = String(string.prefix(string.count - longestPalindromicSuffix.count))
    let reversedPrefix = String(prefix.reversed())
    return string + reversedPrefix
}

extension String {
    var reversed: ReversedCollection<String> {
        return reversed()
    }

    func prefix(_ length: Int) -> Substring {
        return prefix(length)
    }

    func suffix(_ length: Int) -> Substring {
        return suffix(length)
    }
}

extension StringProtocol StringProtocol {
    var reversed: ReversedCollection<Self> { get }
    func prefix(_ length: Int) -> Substring
    func suffix(_ length: Int) -> Substring
}
```

func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindromicSuffix = reversedString.longestPalindromicSuffix
    let prefix = String(string.prefix(string.count - longestPalindromicSuffix.count))
    let reversedPrefix = String(prefix.reversed())
    return string + reversedPrefix
}

extension String {
    var reversed: String {
        return String(self.reversed())
    }

    var longestPalindromicSuffix: String {
        var longestPalindromicSuffix = ""
        for i in 0..<self.count {
            let prefix = String(self.prefix(i + 1))
            let suffix = String(self.suffix(self.count - i - 1))
            if prefix == suffix {
                longestPalindromicSuffix = prefix
            }
        }
        return longestPalindromicSuffix
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let reversedString = String(string.reversed())
    let longestPalindromicSuffix = reversedString.longestPalindromicSuffix
    let prefix = String(string.prefix(string.count - longestPalindromicSuffix.count))
    let reversedPrefix = String(prefix.reversed())
    return string + reversedPrefix
}

extension String {
    var reversed: String {
        return String(self.reversed())
    }

    var longestPalindromicSuffix: String {
        var longestPalindromicSuffix = ""
        for i in 0..<self.count {
            let prefix = String(self.prefix(i + 1))
            let suffix = String(self.suffix(self.count - i - 1))
            if prefix == suffix {
                longestPalindromicSuffix = prefix
            }
        }
        return longestPalindromicSuffix
    }
}
```

func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindrome = string + String(prefix.reversed())
    return palindrome
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"

Answer:
```swift
func makePalindrome(string: String) -> String {
    let characters = Array(string)
    let reversed = characters.reversed()
    let prefix = characters.prefix(while: { reversed.contains($0) })
    let palindrome = string + String(prefix.reversed())
    return palindrome
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(xorResult), encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(xorResult), encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(bytes: xorResult), encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(bytes: xorResult), encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.xor(bData)
    return String(data: xorResult, encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.xor(bData)
    return String(data: xorResult, encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(bytes: xorResult), encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(bytes: xorResult), encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(bytes: xorResult), encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(bytes: xorResult), encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(bytes: xorResult), encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let xorResult = aData.zip(bData).map { $0 ^ $1 }
    return String(data: Data(bytes: xorResult), encoding:.utf8)!
}
```

func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"

Answer:
```swift
func stringXor(a: String, b: String) -> String {
    let aData = Data(a.utf8)
    let bData = Data(b.utf8)
    let resultData = aData.xor(bData)
    return String(data: resultData, encoding:.utf8)!
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max(by: { $0.count < $1.count })
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}
```

func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"

Answer:
```swift
func longest(strings: [String]) -> String? {
    guard!strings.isEmpty else { return nil }
    return strings.max { $0.count < $1.count }
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b!= 0 {
        let remainder = a % b
        a = b
        b = remainder
    }
    return a
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    var a = a
    var b = b
    while b!= 0 {
        let remainder = a % b
        a = b
        b = remainder
    }
    return a
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        } else {
            return gcd(b, a % b)
        }
    }
    return gcd(a, b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        } else {
            return gcd(b, a % b)
        }
    }
    return gcd(a, b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        } else {
            return gcd(b, a % b)
        }
    }
    return gcd(a, b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        } else {
            return gcd(b, a % b)
        }
    }
    return gcd(a, b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}
```

func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5

Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
    func gcd(_ a: Int, _ b: Int) -> Int {
        if b == 0 {
            return a
        }
        return gcd(b, a % b)
    }
    return gcd(a, b)
}
```

func allPrefixes(string: String) -> [String] {
    return (1...string.count).map { string.prefix(upTo: string.index(string.startIndex, offsetBy: $0)) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    return (1...string.count).map { string.prefix(upTo: string.index(string.startIndex, offsetBy: $0)) }
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        prefixes.append(String(string.prefix(i)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        let prefix = String(string.prefix(i + 1))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 0..<string.count {
        prefixes.append(String(string.prefix(i + 1)))
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]

Answer:
```swift
func allPrefixes(string: String) -> [String] {
    var prefixes: [String] = []
    for i in 1...string.count {
        let prefix = String(string.prefix(i))
        prefixes.append(prefix)
    }
    return prefixes
}
```

func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}
```

func stringSequence(n: Int) -> String {
    return String(describing: stride(from: 0, through: n, by: 1))
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing: stride(from: 0, through: n, by: 1))
}
```

func stringSequence(n: Int) -> String {
    return String(describing: stride(from: 0, through: n, by: 1))
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing: stride(from: 0, through: n, by: 1))
}
```

func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}
```

func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}
```

func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}
```

func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}
```

func stringSequence(n: Int) -> String {
    return String(describing: (0...n).reduce(into: "") { result, element in
        result += "\(element) "
    }.trimmingCharacters(in:.whitespaces))
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing: (0...n).reduce(into: "") { result, element in
        result += "\(element) "
    }.trimmingCharacters(in:.whitespaces))
}
```

func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing: 0...n).replacingOccurrences(of: ",", with: " ")
}
```

func stringSequence(n: Int) -> String {
    return String(describing:stride(from: 0, through: n, by: 1))
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"

Answer:
```swift
func stringSequence(n: Int) -> String {
    return String(describing:stride(from: 0, through: n, by: 1))
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowerCaseString = string.lowercased()
    var seenCharacters = Set<Character>()
    
    for character in lowerCaseString {
        seenCharacters.insert(character)
    }
    
    return seenCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowerCaseString = string.lowercased()
    var seenCharacters = Set<Character>()
    
    for character in lowerCaseString {
        seenCharacters.insert(character)
    }
    
    return seenCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var seenCharacters = Set<Character>()
    
    for character in lowercaseString {
        seenCharacters.insert(character)
    }
    
    return seenCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var seenCharacters = Set<Character>()
    
    for character in lowercaseString {
        seenCharacters.insert(character)
    }
    
    return seenCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var seenCharacters = Set<Character>()
    
    for character in lowercaseString {
        seenCharacters.insert(character)
    }
    
    return seenCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var seenCharacters = Set<Character>()
    
    for character in lowercaseString {
        seenCharacters.insert(character)
    }
    
    return seenCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4

Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
    let lowercaseString = string.lowercased()
    var distinctCharacters = Set<Character>()
    
    for character in lowercaseString {
        distinctCharacters.insert(character)
    }
    
    return distinctCharacters.count
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    
    return beats
}
```

func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]

Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
    let notes = musicString.split(separator: " ")
    var beats = [Int]()
    for note in notes {
        switch note {
        case "o":
            beats.append(4)
        case "o|":
            beats.append(2)
        case ".|":
            beats.append(1)
        default:
            break
        }
    }
    return beats
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3

Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
    var count = 0
    var idx = string.startIndex
    
    while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
        count += 1
        idx = range.upperBound
    }
    
    return count
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    let sortedNumberalsString = sortedNumberals.joined(separator: " ")
    return sortedNumberalsString
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    let sortedNumberalsString = sortedNumberals.joined(separator: " ")
    return sortedNumberalsString
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { number -> Int? in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return nil
        }
    }.compactMap { $0 }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { number -> String in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedNumberals.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { number -> Int? in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return nil
        }
    }.compactMap { $0 }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { number -> String in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedNumberals.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { number -> Int? in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return nil
        }
    }.compactMap { $0 }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { number -> String in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedNumberals.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { number -> Int? in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return nil
        }
    }.compactMap { $0 }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { number -> String in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedNumberals.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { number -> Int? in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return nil
        }
    }.compactMap { $0 }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { number -> String in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedNumberals.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { number -> Int? in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return nil
        }
    }.compactMap { $0 }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { number -> String in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedNumberals.joined(separator: " ")
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { numberToNumber($0) }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
    return sortedNumberals.joined(separator: " ")
}

func numberToNumber(_ numberal: String) -> Int {
    switch numberal {
    case "zero": return 0
    case "one": return 1
    case "two": return 2
    case "three": return 3
    case "four": return 4
    case "five": return 5
    case "six": return 6
    case "seven": return 7
    case "eight": return 8
    case "nine": return 9
    default: return 0
    }
}

func numberToNumberal(_ number: Int) -> String {
    switch number {
    case 0: return "zero"
    case 1: return "one"
    case 2: return "two"
    case 3: return "three"
    case 4: return "four"
    case 5: return "five"
    case 6: return "six"
    case 7: return "seven"
    case 8: return "eight"
    case 9: return "nine"
    default: return "zero"
    }
}
```

func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { number -> Int? in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return nil
        }
    }.compactMap { $0 }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { number -> String in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedNumberals.joined(separator: " ")
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"

Answer:
```swift
func sortNumbers(numbers: String) -> String {
    let numberals = numbers.components(separatedBy: " ")
    let numbers = numberals.map { number -> Int? in
        switch number {
        case "zero": return 0
        case "one": return 1
        case "two": return 2
        case "three": return 3
        case "four": return 4
        case "five": return 5
        case "six": return 6
        case "seven": return 7
        case "eight": return 8
        case "nine": return 9
        default: return nil
        }
    }.compactMap { $0 }
    let sortedNumbers = numbers.sorted()
    let sortedNumberals = sortedNumbers.map { number -> String in
        switch number {
        case 0: return "zero"
        case 1: return "one"
        case 2: return "two"
        case 3: return "three"
        case 4: return "four"
        case 5: return "five"
        case 6: return "six"
        case 7: return "seven"
        case 8: return "eight"
        case 9: return "nine"
        default: return ""
        }
    }
    return sortedNumberals.joined(separator: " ")
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var closestElements = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var closestElements = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            closestElements = (numbers[i], numbers[i+1])
        }
    }
    
    return closestElements
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var closestPair = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let difference = abs(numbers[i] - numbers[j])
            if difference < minDifference {
                minDifference = difference
                closestPair = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestPair
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var closestPair = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        for j in i+1..<numbers.count {
            let difference = abs(numbers[i] - numbers[j])
            if difference < minDifference {
                minDifference = difference
                closestPair = (numbers[i], numbers[j])
            }
        }
    }
    
    return closestPair
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}
```

func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)

Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
    var minDifference = abs(numbers[0] - numbers[1])
    var result = (numbers[0], numbers[1])
    
    for i in 0..<numbers.count-1 {
        let difference = abs(numbers[i] - numbers[i+1])
        if difference < minDifference {
            minDifference = difference
            result = (numbers[i], numbers[i+1])
        }
    }
    
    return result
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]

Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
    let min = numbers.min()!
    let max = numbers.max()!
    let range = max - min
    return numbers.map { ($0 - min) / range }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]

Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
    return values.compactMap { value in
        if let intValue = value as? Int {
            return intValue
        }
        return nil
    }
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func strlen(string: String) -> Int {
    return string.count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3

Answer:
```swift
func strlen(string: String) -> Int {
    return string.count
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 2, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 2, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 2, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 2, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}
```

func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 2, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    for i in stride(from: n - 1, through: 2, by: -1) {
        if n % i == 0 {
            return i
        }
    }
    return 1
}
```

func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}
```

func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}
```

func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}
```

func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}
```

func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5

Answer:
```swift
func largestDivisor(n: Int) -> Int {
    var largest = 0
    for i in 1...n {
        if n % i == 0 {
            largest = i
        }
    }
    return largest
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var factor = 2
    while number > 1 {
        while number % factor == 0 {
            factors.append(factor)
            number /= factor
        }
        factor += 1
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var factor = 2
    while number > 1 {
        while number % factor == 0 {
            factors.append(factor)
            number /= factor
        }
        factor += 1
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var n = n
    var factors: [Int] = []
    var factor = 2

    while n > 1 {
        while n % factor == 0 {
            factors.append(factor)
            n /= factor
        }
        factor += 1
    }

    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var n = n
    var factors: [Int] = []
    var factor = 2

    while n > 1 {
        while n % factor == 0 {
            factors.append(factor)
            n /= factor
        }
        factor += 1
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    var divisor = 2

    while number > 1 {
        while number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        }
        divisor += 1
    }

    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    var divisor = 2

    while number > 1 {
        while number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        }
        divisor += 1
    }

    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var divisor = 2
    
    while number > 1 {
        while number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        }
        divisor += 1
    }
    
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var divisor = 2
    
    while number > 1 {
        while number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        }
        divisor += 1
    }
    
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var factor = 2
    while number > 1 {
        while number % factor == 0 {
            factors.append(factor)
            number /= factor
        }
        factor += 1
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var factor = 2
    while number > 1 {
        while number % factor == 0 {
            factors.append(factor)
            number /= factor
        }
        factor += 1
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...n {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var number = n
    var factors: [Int] = []
    
    for i in 2...n {
        while number % i == 0 {
            factors.append(i)
            number /= i
        }
    }
    
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var divisor = 2
    while number > 1 {
        while number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        }
        divisor += 1
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var divisor = 2
    while number > 1 {
        while number % divisor == 0 {
            factors.append(divisor)
            number /= divisor
        }
        divisor += 1
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var n = n
    var factors: [Int] = []
    var factor = 2
    while n > 1 {
        while n % factor == 0 {
            factors.append(factor)
            n /= factor
        }
        factor += 1
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var n = n
    var factors: [Int] = []
    var factor = 2
    while n > 1 {
        while n % factor == 0 {
            factors.append(factor)
            n /= factor
        }
        factor += 1
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var factor = 2
    while number > 1 {
        while number % factor == 0 {
            factors.append(factor)
            number /= factor
        }
        factor += 1
    }
    return factors
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var factors: [Int] = []
    var number = n
    var factor = 2
    while number > 1 {
        while number % factor == 0 {
            factors.append(factor)
            number /= factor
        }
        factor += 1
    }
    return factors
}
```

func factorize(n: Int) -> [Int] {
    var n = n
    var result: [Int] = []
    var divisor = 2
    while n > 1 {
        while n % divisor == 0 {
            result.append(divisor)
            n /= divisor
        }
        divisor += 1
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]

Answer:
```swift
func factorize(n: Int) -> [Int] {
    var n = n
    var result: [Int] = []
    var divisor = 2
    while n > 1 {
        while n % divisor == 0 {
            result.append(divisor)
            n /= divisor
        }
        divisor += 1
    }
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if seen.contains(number) {
            continue
        }
        seen.insert(number)
        result.append(number)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if seen.contains(number) {
            continue
        }
        seen.insert(number)
        result.append(number)
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueElements: [Int] = []
    var frequencyTable: [Int: Int] = [:]
    
    for number in numbers {
        if frequencyTable[number] == nil {
            frequencyTable[number] = 1
            uniqueElements.append(number)
        } else {
            frequencyTable[number]! += 1
        }
    }
    
    return uniqueElements
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueElements: [Int] = []
    var frequencyTable: [Int: Int] = [:]
    
    for number in numbers {
        if frequencyTable[number] == nil {
            frequencyTable[number] = 1
            uniqueElements.append(number)
        } else {
            frequencyTable[number]! += 1
        }
    }
    
    return uniqueElements
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int]()
    var frequency = [Int: Int]()
    
    for number in numbers {
        if frequency[number] == nil {
            frequency[number] = 1
            uniqueNumbers.append(number)
        } else {
            frequency[number]! += 1
        }
    }
    
    return uniqueNumbers
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int]()
    var frequency = [Int: Int]()
    
    for number in numbers {
        if frequency[number] == nil {
            frequency[number] = 1
            uniqueNumbers.append(number)
        } else {
            frequency[number]! += 1
        }
    }
    
    return uniqueNumbers
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if seen.contains(number) {
            continue
        }
        
        seen.insert(number)
        result.append(number)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if seen.contains(number) {
            continue
        }
        
        seen.insert(number)
        result.append(number)
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: Set<Int> = []
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result: [Int] = []
    var seen: Set<Int> = []
    
    for number in numbers {
        if!seen.contains(number) {
            result.append(number)
            seen.insert(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int: Int]()
    var result = [Int]()
    
    for number in numbers {
        if uniqueNumbers[number] == nil {
            uniqueNumbers[number] = 1
            result.append(number)
        }
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var uniqueNumbers = [Int: Int]()
    var result = [Int]()
    
    for number in numbers {
        if uniqueNumbers[number] == nil {
            uniqueNumbers[number] = 1
            result.append(number)
        }
    }
    
    return result
}
```

func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if seen.contains(number) {
            continue
        }
        seen.insert(number)
        result.append(number)
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]

Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
    var result = [Int]()
    var seen = Set<Int>()
    
    for number in numbers {
        if seen.contains(number) {
            continue
        }
        seen.insert(number)
        result.append(number)
    }
    
    return result
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"

Answer:
```swift
func flipCase(string: String) -> String {
    return String(string.unicodeScalars.map {
        $0.isLowercase? $0.toUppercase() : $0.toLowercase()
    })
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.reduce("", +)
}
```

func concatenate(strings: [String]) -> String {
    return strings.joined()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"

Answer:
```swift
func concatenate(strings: [String]) -> String {
    return strings.joined()
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]

Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
    return strings.filter { $0.hasPrefix(prefix) }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]

Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
    return l.filter { $0 > 0 }
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    
    var i = 2
    while i * i <= n {
        if n % i == 0 {
            return false
        }
        i += 1
    }
    
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    guard n > 1 else { return false }
    for i in 2..<n {
        if n % i == 0 {
            return false
        }
    }
    return true
}
```

func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false

Answer:
```swift
func isPrime(n: Int) -> Bool {
    if n <= 1 {
        return false
    }
    if n <= 3 {
        return true
    }
    if n % 2 == 0 || n % 3 == 0 {
        return false
    }
    var i = 5
    while i * i <= n {
        if n % i == 0 || n % (i + 2) == 0 {
            return false
        }
        i += 6
    }
    return true
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indicies = stride(from: 0, to: l.count, by: 3).map { $0 % 3 == 0 }
    let sorted = l[indicies].sorted()
    for (i, index) in indicies.enumerated() {
        if index {
            l[i] = sorted[i / 3]
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indicies = stride(from: 0, to: l.count, by: 3).map { $0 % 3 == 0 }
    let sorted = l[indicies].sorted()
    for (i, index) in indicies.enumerated() {
        if index {
            l[i] = sorted[i / 3]
        }
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3).map { $0 }
    for i in indices {
        let start = i
        let end = Swift.min(start + 3, l.count)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3).map { $0 }
    for i in indices {
        let start = i
        let end = Swift.min(start + 3, l.count)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3)
    for i in indices {
        let start = i
        let end = Swift.min(l.count, start + 3)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3)
    for i in indices {
        let start = i
        let end = Swift.min(l.count, start + 3)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3)
    for i in indices {
        let start = i
        let end = Swift.min(l.count, start + 3)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3)
    for i in indices {
        let start = i
        let end = Swift.min(l.count, start + 3)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indicies = stride(from: 0, to: l.count, by: 3)
    for i in indicies {
        let start = i
        let end = Swift.min(l.count, start + 3)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indicies = stride(from: 0, to: l.count, by: 3)
    for i in indicies {
        let start = i
        let end = Swift.min(l.count, start + 3)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indicies = stride(from: 0, to: l.count, by: 3).map { $0 % 3 == 0 }
    let indiciesToSort = stride(from: 0, to: l.count, by: 3).filter { $0 % 3 == 0 }
    let valuesToSort = indiciesToSort.map { l[$0] }
    let sortedValues = valuesToSort.sorted()
    for (index, value) in zip(indiciesToSort, sortedValues) {
        l[index] = value
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indicies = stride(from: 0, to: l.count, by: 3).map { $0 % 3 == 0 }
    let indiciesToSort = stride(from: 0, to: l.count, by: 3).filter { $0 % 3 == 0 }
    let valuesToSort = indiciesToSort.map { l[$0] }
    let sortedValues = valuesToSort.sorted()
    for (index, value) in zip(indiciesToSort, sortedValues) {
        l[index] = value
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let sorted = l[l.indices.filter({ $0 % 3 == 0 })].sorted()
    for (i, v) in sorted.enumerated() {
        l[l.indices.filter({ $0 % 3 == 0 })[i]] = v
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let sorted = l[l.indices.filter({ $0 % 3 == 0 })].sorted()
    for (i, v) in sorted.enumerated() {
        l[l.indices.filter({ $0 % 3 == 0 })[i]] = v
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3)
    for i in indices {
        let start = i
        let end = Swift.min(start + 3, l.count)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3)
    for i in indices {
        let start = i
        let end = Swift.min(start + 3, l.count)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3).map { $0 % 3 }
    let sorted = indices.map { l[$0] }.sorted()
    for (i, index) in indices.enumerated() {
        l[index] = sorted[i]
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3).map { $0 % 3 }
    let sorted = indices.map { l[$0] }.sorted()
    for (i, index) in indices.enumerated() {
        l[index] = sorted[i]
    }
    return l
}
```

func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3)
    for i in indices {
        let start = i
        let end = Swift.min(l.count, start + 3)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]

Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
    var l = l
    let indices = stride(from: 0, to: l.count, by: 3)
    for i in indices {
        let start = i
        let end = Swift.min(l.count, start + 3)
        let subArray = Array(l[start..<end])
        let sortedSubArray = subArray.sorted()
        l[start..<end] = sortedSubArray
    }
    return l
}
```

func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    return s.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    return s.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for item in l {
        if!result.contains(item) {
            result.append(item)
        }
    }
    return result.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var result = [Int]()
    for item in l {
        if!result.contains(item) {
            result.append(item)
        }
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    return s.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    return s.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    return s.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    return s.sorted()
}
```

func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]

Answer:
```swift
func unique(l: [Int]) -> [Int] {
    var s = Set(l)
    var result: [Int] = []
    for item in s {
        result.append(item)
    }
    return result.sorted()
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123

Answer:
```swift
func maxElement(l: [Int]) -> Int {
    var max = l[0]
    for i in 1..<l.count {
        if l[i] > max {
            max = l[i]
        }
    }
    return max
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numString = String(i)
            if numString.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numString = String(i)
            if numString.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numberString = String(i)
            if numberString.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numberString = String(i)
            if numberString.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += String(i).filter { $0 == "7" }.count
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            count += String(i).filter { $0 == "7" }.count
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            let numString = String(i)
            if numString.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 1...n-1 {
        if i % 11 == 0 || i % 13 == 0 {
            let numString = String(i)
            if numString.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numString = String(i)
            if numString.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numString = String(i)
            if numString.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numberString = String(i)
            if numberString.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numberString = String(i)
            if numberString.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            if String(i).contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let num = String(i)
            if num.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let num = String(i)
            if num.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numString = String(i)
            if numString.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let numString = String(i)
            if numString.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let num = String(i)
            if num.contains("7") {
                count += 1
            }
        }
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3

Answer:
```swift
func fizzBuzz(n: Int) -> Int {
    var count = 0
    for i in 0..<n {
        if i % 11 == 0 || i % 13 == 0 {
            let num = String(i)
            if num.contains("7") {
                count += 1
            }
        }
    }
    return count
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2!= 0 }.map { $0.element }
    l.enumerated().forEach {
        if $0.offset % 2 == 0 {
            $0.element = even[$0.offset / 2]
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2!= 0 }.map { $0.element }
    l.enumerated().forEach {
        if $0.offset % 2 == 0 {
            $0.element = even[$0.offset / 2]
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2!= 0 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2!= 0 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2!= 0 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2!= 0 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    l.enumerated().forEach {
        if $0.offset % 2 == 0 {
            $0.element = even[$0.offset / 2]
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    l.enumerated().forEach {
        if $0.offset % 2 == 0 {
            $0.element = even[$0.offset / 2]
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2!= 0 }.map { $0.element }
    l.enumerated().forEach {
        if $0.offset % 2 == 0 {
            l[$0.offset] = even[$0.offset / 2]
        }
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2!= 0 }.map { $0.element }
    l.enumerated().forEach {
        if $0.offset % 2 == 0 {
            l[$0.offset] = even[$0.offset / 2]
        }
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (i, e) in sortedEven.enumerated() {
        l[i * 2] = e
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (i, e) in sortedEven.enumerated() {
        l[i * 2] = e
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}
```

func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]

Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
    var l = l
    let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
    let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
    let sortedEven = even.sorted()
    for (index, value) in sortedEven.enumerated() {
        l[index * 2] = value
    }
    return l
}
```

func primeFib(n: Int) -> Int {
    var result = [2, 3]
    var a = 0
    var b = 1
    var c: Int
    while result.count < n {
        c = a + b
        if isPrime(c) {
            result.append(c)
        }
        a = b
        b = c
    }
    return result[n - 1]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var result = [2, 3]
    var a = 0
    var b = 1
    var c: Int
    while result.count < n {
        c = a + b
        if isPrime(c) {
            result.append(c)
        }
        a = b
        b = c
    }
    return result[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    for i in 2..<number { if number % i == 0 { return false } } return true }
```

func primeFib(n: Int) -> Int {
    var result = [2, 3]
    var next = 5
    var index = 2
    while result.count < n {
        if isPrime(next) {
            result.append(next)
        }
        let newNext = result[index] + result[index - 1]
        index += 1
        next = newNext
    }
    return result.last!
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var result = [2, 3]
    var next = 5
    var index = 2
    while result.count < n {
        if isPrime(next) {
            result.append(next)
        }
        let newNext = result[index] + result[index - 1]
        index += 1
        next = newNext
    }
    return result.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    for i in 2..<number { if number % i == 0 { return false } } return true }
```

func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    for i in 2..<number { if number % i == 0 { return false } } return true }
```

func primeFib(n: Int) -> Int {
    var result = [2, 3]
    var next = 5
    var index = 2
    while result.count < n {
        if isPrime(next) {
            result.append(next)
        }
        let a = result[index]
        let b = result[index - 1]
        next = a + b
        index += 1
    }
    return result.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var result = [2, 3]
    var next = 5
    var index = 2
    while result.count < n {
        if isPrime(next) {
            result.append(next)
        }
        let a = result[index]
        let b = result[index - 1]
        next = a + b
        index += 1
    }
    return result.last!
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var result = [2, 3]
    var a = 0
    var b = 1
    var i = 2
    while result.count < n {
        let next = a + b
        if isPrime(next) {
            result.append(next)
        }
        a = b
        b = next
        i += 1
    }
    return result[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number { if number % i == 0 { return false } i += 1 }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var result = [2, 3]
    var a = 0
    var b = 1
    var i = 2
    while result.count < n {
        let next = a + b
        if isPrime(next) {
            result.append(next)
        }
        a = b
        b = next
        i += 1
    }
    return result[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number { if number % i == 0 { return false } i += 1 }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}
```

func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89

Answer:
```swift
func primeFib(n: Int) -> Int {
    var fibonacci = [2, 3]
    var index = 2
    while fibonacci.count < n {
        let next = fibonacci[index - 1] + fibonacci[index - 2]
        if isPrime(next) {
            fibonacci.append(next)
        }
        index += 1
    }
    return fibonacci[n - 1]
}

func isPrime(_ number: Int) -> Bool {
    if number <= 1 { return false }
    if number <= 3 { return true }
    var i = 2
    while i * i <= number {
        if number % i == 0 { return false }
        i += 1
    }
    return true
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        let left = i+1
        let right = sortedArray.count-1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sortedArray = l.sorted()
    for i in 0..<sortedArray.count-2 {
        let left = i+1
        let right = sortedArray.count-1
        while left < right {
            let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count - 2 {
        let left = i + 1
        let right = sorted.count - 1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count - 2 {
        let left = i + 1
        let right = sorted.count - 1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    for i in 0..<sorted.count-2 {
        let left = i+1
        let right = sorted.count-1
        while left < right {
            let sum = sorted[i] + sorted[left] + sorted[right]
            if sum == 0 {
                return true
            } else if sum < 0 {
                left += 1
            } else {
                right -= 1
            }
        }
    }
    return false
}
```

func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    var left = 0
    var right = sorted.count - 1
    while left < right {
        let sum = sorted[left] + sorted[right]
        if sum == 0 {
            return true
        } else if sum < 0 {
            left += 1
        } else {
            right -= 1
        }
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false

Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
    let sorted = l.sorted()
    var left = 0
    var right = sorted.count - 1
    while left < right {
        let sum = sorted[left] + sorted[right]
        if sum == 0 {
            return true
        } else if sum < 0 {
            left += 1
        } else {
            right -= 1
        }
    }
    return false
}
```

func carRaceCollision(n: Int) -> Int {
    var count = 0
    var leftCar = 0
    var rightCar = n
    while leftCar < rightCar {
        leftCar += 1
        rightCar -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var count = 0
    var leftCar = 0
    var rightCar = n
    while leftCar < rightCar {
        leftCar += 1
        rightCar -= 1
        count += 1
    }
    return count
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}
```

func carRaceCollision(n: Int) -> Int {
    var count = 0
    var left = 0
    var right = n
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var count = 0
    var left = 0
    var right = n
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}
```

func carRaceCollision(n: Int) -> Int {
    var count = 0
    var left = 0
    var right = n
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var count = 0
    var left = 0
    var right = n
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}
```

func carRaceCollision(n: Int) -> Int {
    var count = 0
    var left = 0
    var right = n
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var count = 0
    var left = 0
    var right = n
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}
```

func carRaceCollision(n: Int) -> Int {
    var count = 0
    var left = 0
    var right = n
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var count = 0
    var left = 0
    var right = n
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}
```

func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right;  simultaneously, a different set of n cars
are driving right to left.   The two sets of cars start out being very far from
each other.  All cars move in the same speed.  Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.


Answer:
```swift
func carRaceCollision(n: Int) -> Int {
    var left = 0
    var right = n
    var count = 0
    while left < right {
        left += 1
        right -= 1
        count += 1
    }
    return count
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]

Answer:
```swift
func incrList(l: [Int]) -> [Int] {
    return l.map { $0 + 1 }
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false

Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
    var set = Set<Int>()
    for num in l {
        if set.contains(-num) {
            return true
        }
        set.insert(num)
    }
    return false
}
```

func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    let digits = "0123456789"
    
    while x > 0 {
        result = digits[x % base] + result
        x /= base
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    let digits = "0123456789"
    
    while x > 0 {
        result = digits[x % base] + result
        x /= base
    }
    
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    let digits = "0123456789"
    
    while x > 0 {
        result = digits[x % base] + result
        x /= base
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    let digits = "0123456789"
    
    while x > 0 {
        result = digits[x % base] + result
        x /= base
    }
    
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    let digits = "0123456789"
    
    while x > 0 {
        result = digits[x % base] + result
        x /= base
    }
    
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    var x = x
    var result = ""
    let digits = "0123456789"
    
    while x > 0 {
        result = digits[x % base] + result
        x /= base
    }
    
    return result
}
```

func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"

Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
    let digits = "0123456789"
    var result = ""
    var number = x
    while number > 0 {
        result = digits[number % base] + result
        number /= base
    }
    return result
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5

Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
    return Double(a * h) / 2
}
```

func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = 0
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 3...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = 0
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 3...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }
    return result
}
```

func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = 0
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 3...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = 0
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 3...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }
    return result
}
```

func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let newElement = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(newElement)
    }
    return result[n]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let newElement = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(newElement)
    }
    return result[n]
}
```

func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var a = 0, b = 0, c = 2, d = 0
    for _ in 3...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var a = 0, b = 0, c = 2, d = 0
    for _ in 3...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    return d
}
```

func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = 0
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 3...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }
    return result
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = 0
    var a = 0
    var b = 0
    var c = 2
    var d = 0
    for _ in 3...n {
        result = a + b + c + d
        a = b
        b = c
        c = d
        d = result
    }
    return result
}
```

func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let newElement = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(newElement)
    }
    return result[n]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let newElement = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(newElement)
    }
    return result[n]
}
```

func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var a = 0, b = 0, c = 2, d = 0
    for _ in 3...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    return d
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    guard n > 1 else { return 0 }
    var a = 0, b = 0, c = 2, d = 0
    for _ in 3...n {
        let next = a + b + c + d
        a = b
        b = c
        c = d
        d = next
    }
    return d
}
```

func fib4(n: Int) -> Int {
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(nextValue)
    }
    return result[n]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(nextValue)
    }
    return result[n]
}
```

func fib4(n: Int) -> Int {
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(nextValue)
    }
    return result[n]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(nextValue)
    }
    return result[n]
}
```

func fib4(n: Int) -> Int {
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(nextValue)
    }
    return result[n]
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14

Answer:
```swift
func fib4(n: Int) -> Int {
    var result = [0, 0, 2, 0]
    for i in 4...n {
        let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
        result.append(nextValue)
    }
    return result[n]
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let middle = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[middle - 1] + sorted[middle]) / 2
    } else {
        return Double(sorted[middle])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let middleIndex = sortedArray.count / 2
    if sortedArray.count % 2 == 0 {
        return Double(sortedArray[middleIndex] + sortedArray[middleIndex - 1]) / 2
    } else {
        return Double(sortedArray[middleIndex])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let middleIndex = sortedArray.count / 2
    if sortedArray.count % 2 == 0 {
        return Double(sortedArray[middleIndex] + sortedArray[middleIndex - 1]) / 2
    } else {
        return Double(sortedArray[middleIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let middleIndex = sortedArray.count / 2
    if sortedArray.count % 2 == 0 {
        return Double(sortedArray[middleIndex] + sortedArray[middleIndex - 1]) / 2
    } else {
        return Double(sortedArray[middleIndex])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let middleIndex = sortedArray.count / 2
    if sortedArray.count % 2 == 0 {
        return Double(sortedArray[middleIndex] + sortedArray[middleIndex - 1]) / 2
    } else {
        return Double(sortedArray[middleIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 0 {
        let mid = count / 2
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        let mid = count / 2
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let count = sorted.count
    if count % 2 == 0 {
        let mid = count / 2
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        let mid = count / 2
        return Double(sorted[mid])
    }
}
```

func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let middleIndex = sortedArray.count / 2
    if sortedArray.count % 2 == 0 {
        return Double(sortedArray[middleIndex] + sortedArray[middleIndex - 1]) / 2
    } else {
        return Double(sortedArray[middleIndex])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sortedArray = l.sorted()
    let middleIndex = sortedArray.count / 2
    if sortedArray.count % 2 == 0 {
        return Double(sortedArray[middleIndex] + sortedArray[middleIndex - 1]) / 2
    } else {
        return Double(sortedArray[middleIndex])
    }
}
```

func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0

Answer:
```swift
func median(l: [Int]) -> Double {
    let sorted = l.sorted()
    let mid = sorted.count / 2
    if sorted.count % 2 == 0 {
        return Double(sorted[mid - 1] + sorted[mid]) / 2
    } else {
        return Double(sorted[mid])
    }
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText.lowercased() == reversedText.lowercased()
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText.lowercased() == reversedText.lowercased()
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```

func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}

Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false

Answer:
```swift
func isPalindrome(text: String) -> Bool {
    let cleanText = text.lowercased().replacingOccurrences(of: "\\W", with: "", options:.regularExpression)
    let reversedText = String(cleanText.reversed())
    return cleanText == reversedText
}
```