Metadata
| Key | Value |
|---|---|
| engine | transformers |
| prompt | default |
| temp | 0.2 |
| top_p | 0.95 |
| max_new_tokens | 1024 |
| n_completions | 10 |
Solutions
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in (i+1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in (i+1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count - 1 {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count - 1 {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in (i+1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in (i+1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count - 1 {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count - 1 {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count - 1 {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count - 1 {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count - 1 {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count - 1 {
for j in (i + 1)..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if in given array of numbers, are any two numbers closer to each other than
given threshold.
hasCloseElements(numbers: [1.0, 2.0, 3.0], threshold: 0.5) == false
hasCloseElements(numbers: [1.0, 2.8, 3.0, 4.0, 5.0, 2.0], threshold: 0.3) == true
Answer:
```swift
func hasCloseElements(numbers: [Double], threshold: Double) -> Bool {
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
if abs(numbers[i] - numbers[j]) <= threshold {
return true
}
}
}
return false
}
```func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var stack: [Character] = []
for char in parenString {
if char == "(" {
stack.append(char)
currentGroup.append(char)
} else if char == ")" {
if let top = stack.last, top == "(" {
stack.removeLast()
currentGroup.append(char)
}
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var stack: [Character] = []
for char in parenString {
if char == "(" {
stack.append(char)
currentGroup.append(char)
} else if char == ")" {
if let top = stack.last, top == "(" {
stack.removeLast()
currentGroup.append(char)
}
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
```func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup: String = ""
var stack: [Character] = []
for char in parenString {
if char == "(" {
stack.append(char)
currentGroup.append(char)
} else if char == ")" {
if let top = stack.last, top == "(" {
stack.removeLast()
currentGroup.append(char)
}
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup: String = ""
var stack: [Character] = []
for char in parenString {
if char == "(" {
stack.append(char)
currentGroup.append(char)
} else if char == ")" {
if let top = stack.last, top == "(" {
stack.removeLast()
currentGroup.append(char)
}
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var openCount = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
openCount += 1
currentGroup.append(char)
} else if char == ")" {
openCount -= 1
currentGroup.append(char)
if openCount == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var openCount = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
openCount += 1
currentGroup.append(char)
} else if char == ")" {
openCount -= 1
currentGroup.append(char)
if openCount == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
}
return result
}
```func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
```func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var stack: [Character] = []
for char in parenString {
if char == "(" {
stack.append(char)
currentGroup.append(char)
} else if char == ")" {
if let top = stack.last, top == "(" {
stack.removeLast()
currentGroup.append(char)
}
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var stack: [Character] = []
for char in parenString {
if char == "(" {
stack.append(char)
currentGroup.append(char)
} else if char == ")" {
if let top = stack.last, top == "(" {
stack.removeLast()
currentGroup.append(char)
}
}
if stack.isEmpty {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
``` // XCTAssertTrue failedfunc separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
```func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var openCount = 0
for char in parenString {
if char == "(" {
openCount += 1
currentGroup.append(char)
} else if char == ")" {
openCount -= 1
currentGroup.append(char)
if openCount == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var openCount = 0
for char in parenString {
if char == "(" {
openCount += 1
currentGroup.append(char)
} else if char == ")" {
openCount -= 1
currentGroup.append(char)
if openCount == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
}
return result
}
```func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
```func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the array of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
separateParenGroups(parenString: "( ) (( )) (( )( ))") == ["()", "(())", "(()())"]
Answer:
```swift
func separateParenGroups(parenString: String) -> [String] {
var result: [String] = []
var currentGroup = ""
var balance = 0
for char in parenString {
if char == " " {
continue
}
if char == "(" {
balance += 1
currentGroup.append(char)
} else if char == ")" {
balance -= 1
currentGroup.append(char)
}
if balance == 0 {
result.append(currentGroup)
currentGroup = ""
}
}
return result
}
```func truncateNumber(number: Double) -> Double {
return number - Double(Int(number))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
return number - Double(Int(number))
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
truncateNumber(number: 3.5) == 0.5
Answer:
```swift
func truncateNumber(number: Double) -> Double {
let integerPart = Int(number)
let decimalPart = number - Double(integerPart)
return decimalPart
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're given an array of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return true. Otherwise it should return false.
belowZero(operations: [1, 2, 3]) == false
belowZero(operations: [1, 2, -4, 5]) == true
Answer:
```swift
func belowZero(operations: [Int]) -> Bool {
var balance = 0
for operation in operations {
balance += operation
if balance < 0 {
return true
}
}
return false
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return mad
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return mad
}
```guard!numbers.isEmpty else { return 0 } // expected expression, var, let or case in 'guard' conditionfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}
```guard!numbers.isEmpty else { return 0.0 } // expected expression, var, let or case in 'guard' conditionfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}
```guard!numbers.isEmpty else { return 0.0 } // expected expression, var, let or case in 'guard' conditionfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return mad
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let mad = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return mad
}
```guard!numbers.isEmpty else { return 0.0 } // expected expression, var, let or case in 'guard' conditionfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}
```guard!numbers.isEmpty else { return 0.0 } // expected expression, var, let or case in 'guard' conditionfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}
```guard!numbers.isEmpty else { return 0.0 } // expected expression, var, let or case in 'guard' conditionfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard!numbers.isEmpty else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}
```guard!numbers.isEmpty else { return 0.0 } // expected expression, var, let or case in 'guard' conditionfunc meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let meanAbsoluteDeviation = absoluteDeviations.reduce(0, +) / Double(absoluteDeviations.count)
return meanAbsoluteDeviation
}
```func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard numbers.count > 0 else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let mad = absoluteDeviations.reduce(0, +) / Double(numbers.count)
return mad
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
meanAbsoluteDeviation(numbers: [1.0, 2.0, 3.0, 4.0]) == 1.0
Answer:
```swift
func meanAbsoluteDeviation(numbers: [Double]) -> Double {
guard numbers.count > 0 else { return 0.0 }
let mean = numbers.reduce(0, +) / Double(numbers.count)
let absoluteDeviations = numbers.map { abs($0 - mean) }
let mad = absoluteDeviations.reduce(0, +) / Double(numbers.count)
return mad
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
guard!numbers.isEmpty else { return [] }
var result = [numbers[0]]
for number in numbers.dropFirst() {
result.append(delimeter)
result.append(number)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
guard!numbers.isEmpty else { return [] }
var result = [numbers[0]]
for number in numbers.dropFirst() {
result.append(delimeter)
result.append(number)
}
return result
}
```guard!numbers.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionfunc intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Insert a number 'delimeter' between every two consecutive elements of input array `numbers'
intersperse(numbers: [] as [Int], delimeter: 4) == [] as [Int]
intersperse(numbers: [1, 2, 3], delimeter: 4) == [1, 4, 2, 4, 3]
Answer:
```swift
func intersperse(numbers: [Int], delimeter: Int) -> [Int] {
var result = [Int]()
for (index, number) in numbers.enumerated() {
result.append(number)
if index < numbers.count - 1 {
result.append(delimeter)
}
}
return result
}
```func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var result: [Int] = []
for group in parenString.components(separatedBy: " ") {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
result.append(maxNestingLevel)
maxNestingLevel = 0
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var result: [Int] = []
for group in parenString.components(separatedBy: " ") {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
result.append(maxNestingLevel)
maxNestingLevel = 0
}
return result
}
```func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var result: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
result.append(maxNestingLevel)
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var result: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
result.append(maxNestingLevel)
return result
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
for char in parenString {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
if currentNestingLevel == 0 {
maxNestingLevels.append(maxNestingLevel)
maxNestingLevel = 0
}
}
return maxNestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
for char in parenString {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
if currentNestingLevel == 0 {
maxNestingLevels.append(maxNestingLevel)
maxNestingLevel = 0
}
}
return maxNestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
for char in parenString {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
if currentNestingLevel == 0 {
maxNestingLevels.append(maxNestingLevel)
maxNestingLevel = 0
}
}
return maxNestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
for char in parenString {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
if currentNestingLevel == 0 {
maxNestingLevels.append(maxNestingLevel)
maxNestingLevel = 0
}
}
return maxNestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
maxNestingLevels.append(maxNestingLevel)
return maxNestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
maxNestingLevels.append(maxNestingLevel)
return maxNestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
for char in parenString {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
if currentNestingLevel == 0 {
maxNestingLevels.append(maxNestingLevel)
maxNestingLevel = 0
}
}
return maxNestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
for char in parenString {
if char == "(" {
currentNestingLevel += 1
} else if char == ")" {
currentNestingLevel -= 1
}
if currentNestingLevel == 0 {
maxNestingLevels.append(maxNestingLevel)
maxNestingLevel = 0
}
}
return maxNestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
maxNestingLevels.append(maxNestingLevel)
return maxNestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
maxNestingLevels.append(maxNestingLevel)
return maxNestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
maxNestingLevels.append(maxNestingLevel)
return maxNestingLevels
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var maxNestingLevels: [Int] = []
var currentNestingLevel = 0
for char in parenString {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
maxNestingLevels.append(maxNestingLevel)
return maxNestingLevels
}
``` // XCTAssertTrue failedfunc parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var result: [Int] = []
for group in parenString.components(separatedBy: " ") {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
result.append(maxNestingLevel)
maxNestingLevel = 0
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var result: [Int] = []
for group in parenString.components(separatedBy: " ") {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
result.append(maxNestingLevel)
maxNestingLevel = 0
}
return result
}
```func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var result: [Int] = []
for group in parenString.components(separatedBy: " ") {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
result.append(maxNestingLevel)
maxNestingLevel = 0
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
parseNestedParens(parenString: "(()()) ((())) () ((())()())") == [2, 3, 1, 3]
Answer:
```swift
func parseNestedParens(parenString: String) -> [Int] {
var maxNestingLevel = 0
var result: [Int] = []
for group in parenString.components(separatedBy: " ") {
var currentNestingLevel = 0
for char in group {
if char == "(" {
currentNestingLevel += 1
maxNestingLevel = max(maxNestingLevel, currentNestingLevel)
} else if char == ")" {
currentNestingLevel -= 1
}
}
result.append(maxNestingLevel)
maxNestingLevel = 0
}
return result
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that contain given substring
filterBySubstring(strings: [] as [String], substring: "a") == [] as [String]
filterBySubstring(strings: ["abc", "bacd", "cde", "array"], substring: "a") == ["abc", "bacd", "array"]
Answer:
```swift
func filterBySubstring(strings: [String], substring: String) -> [String] {
return strings.filter { $0.contains(substring) }
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given array of integers, return a tuple consisting of a sum and a product of all the integers in an array.
Empty sum should be equal to 0 and empty product should be equal to 1.
sumProduct(numbers: [] as [Int]) == (0, 1)
sumProduct(numbers: [1, 2, 3, 4]) == (10, 24)
Answer:
```swift
func sumProduct(numbers: [Int]) -> (Int, Int) {
var sum = 0
var product = 1
for number in numbers {
sum += number
product *= number
}
return (sum, product)
}
```func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first!
for number in numbers {
max = max > number? max : number
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first!
for number in numbers {
max = max > number? max : number
result.append(max)
}
return result
}
```max = max > number? max : number // cannot use optional chaining on non-optional value of type 'Int'max = max > number? max : number // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max > number? max : number // variable is unusedmax = max > number? max : number // expected expressionmax = max > number? max : number // consecutive statements on a line must be separated by ';'max = max > number? max : number // cannot assign value of type 'Bool' to type 'Int'max = max > number? max : number // consecutive statements on a line must be separated by ';'func rollingMax(numbers: [Int]) -> [Int] {
var result: [Int] = []
var maxElement = numbers.first!
for number in numbers {
if number > maxElement {
maxElement = number
}
result.append(maxElement)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result: [Int] = []
var maxElement = numbers.first!
for number in numbers {
if number > maxElement {
maxElement = number
}
result.append(maxElement)
}
return result
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first!
for number in numbers {
max = max > number? max : number
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first!
for number in numbers {
max = max > number? max : number
result.append(max)
}
return result
}
```max = max > number? max : number // cannot use optional chaining on non-optional value of type 'Int'max = max > number? max : number // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max > number? max : number // variable is unusedmax = max > number? max : number // expected expressionmax = max > number? max : number // consecutive statements on a line must be separated by ';'max = max > number? max : number // cannot assign value of type 'Bool' to type 'Int'max = max > number? max : number // consecutive statements on a line must be separated by ';'func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers[0]
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers[0]
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}
``` // Fatal error: Index out of rangefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
max = max > number? max : number
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers[0]
for number in numbers {
max = max > number? max : number
result.append(max)
}
return result
}
```max = max > number? max : number // cannot use optional chaining on non-optional value of type 'Int'max = max > number? max : number // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max > number? max : number // variable is unusedmax = max > number? max : number // expected expressionmax = max > number? max : number // consecutive statements on a line must be separated by ';'max = max > number? max : number // cannot assign value of type 'Bool' to type 'Int'max = max > number? max : number // consecutive statements on a line must be separated by ';'func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers.first!
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers.first!
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers[0]
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers[0]
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}
``` // Fatal error: Index out of rangefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first!
for number in numbers {
max = max > number? max : number
result.append(max)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var max = numbers.first!
for number in numbers {
max = max > number? max : number
result.append(max)
}
return result
}
```max = max > number? max : number // cannot use optional chaining on non-optional value of type 'Int'max = max > number? max : number // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max > number? max : number // variable is unusedmax = max > number? max : number // expected expressionmax = max > number? max : number // consecutive statements on a line must be separated by ';'max = max > number? max : number // cannot assign value of type 'Bool' to type 'Int'max = max > number? max : number // consecutive statements on a line must be separated by ';'func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers[0]
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers[0]
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}
``` // Fatal error: Index out of rangefunc rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers[0]
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a given array of integers, generate an array of rolling maximum element found until given moment
in the sequence.
rollingMax(numbers: [1, 2, 3, 2, 3, 4, 2]) == [1, 2, 3, 3, 3, 4, 4]
Answer:
```swift
func rollingMax(numbers: [Int]) -> [Int] {
var result = [Int]()
var maxElement = numbers[0]
for number in numbers {
maxElement = max(maxElement, number)
result.append(maxElement)
}
return result
}
``` // Fatal error: Index out of rangefunc makePalindrome(string: String) -> String {
let characters = Array(string)
guard!characters.isEmpty else { return "" }
var longestPalindromicSuffix = ""
for i in stride(from: characters.count, to: 0, by: -1) {
let prefix = Array(characters[0..<i])
let suffix = Array(characters[i..<characters.count])
if prefix == suffix.reversed() {
longestPalindromicSuffix = String(suffix)
break
}
}
let prefixToAppend = String(characters[0..<characters.count - longestPalindromicSuffix.count].reversed())
return string + prefixToAppend
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
guard!characters.isEmpty else { return "" }
var longestPalindromicSuffix = ""
for i in stride(from: characters.count, to: 0, by: -1) {
let prefix = Array(characters[0..<i])
let suffix = Array(characters[i..<characters.count])
if prefix == suffix.reversed() {
longestPalindromicSuffix = String(suffix)
break
}
}
let prefixToAppend = String(characters[0..<characters.count - longestPalindromicSuffix.count].reversed())
return string + prefixToAppend
}
```guard!characters.isEmpty else { return "" } // expected expression, var, let or case in 'guard' conditionfunc makePalindrome(string: String) -> String {
let characters = Array(string)
guard!characters.isEmpty else { return string }
let reversed = characters.reversed()
var longestPalindromicSuffix = 0
for (index, character) in characters.enumerated() {
if character == reversed[index] {
longestPalindromicSuffix += 1
} else {
break
}
}
let prefix = characters[0..< characters.count - longestPalindromicSuffix]
let reversedPrefix = prefix.reversed()
let palindrome = string + String(reversedPrefix)
return palindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
guard!characters.isEmpty else { return string }
let reversed = characters.reversed()
var longestPalindromicSuffix = 0
for (index, character) in characters.enumerated() {
if character == reversed[index] {
longestPalindromicSuffix += 1
} else {
break
}
}
let prefix = characters[0..< characters.count - longestPalindromicSuffix]
let reversedPrefix = prefix.reversed()
let palindrome = string + String(reversedPrefix)
return palindrome
}
```guard!characters.isEmpty else { return string } // expected expression, var, let or case in 'guard' conditionif character == reversed[index] { // cannot convert value of type 'Int' to expected argument type 'ReversedCollection<[String.Element]>.Index' (aka 'ReversedCollection<Array<Character>>.Index')let prefix = characters[0..< characters.count - longestPalindromicSuffix] // '..<' is not a postfix unary operatorlet prefix = characters[0..< characters.count - longestPalindromicSuffix] // extra argument in subscriptlet prefix = characters[0..< characters.count - longestPalindromicSuffix] // expected ',' separatorfunc makePalindrome(string: String) -> String {
let characters = Array(string)
guard!characters.isEmpty else { return "" }
var postfix = Array(characters.reversed())
while!isPalindrome(postfix) {
postfix.removeFirst()
}
let prefix = Array(characters.prefix(characters.count - postfix.count))
let reversePrefix = prefix.reversed()
let palindrome = characters + reversePrefix
return String(palindrome)
}
func isPalindrome(_ characters: [Character]) -> Bool {
let charactersCount = characters.count
guard charactersCount > 1 else { return true }
for i in 0..<charactersCount / 2 {
if characters[i]!= characters[charactersCount - 1 - i] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
guard!characters.isEmpty else { return "" }
var postfix = Array(characters.reversed())
while!isPalindrome(postfix) {
postfix.removeFirst()
}
let prefix = Array(characters.prefix(characters.count - postfix.count))
let reversePrefix = prefix.reversed()
let palindrome = characters + reversePrefix
return String(palindrome)
}
func isPalindrome(_ characters: [Character]) -> Bool {
let charactersCount = characters.count
guard charactersCount > 1 else { return true }
for i in 0..<charactersCount / 2 {
if characters[i]!= characters[charactersCount - 1 - i] {
return false
}
}
return true
}
```guard!characters.isEmpty else { return "" } // expected expression, var, let or case in 'guard' conditionwhile!isPalindrome(postfix) { // expected expression, var, or let in 'while' conditionif characters[i]!= characters[charactersCount - 1 - i] { // '=' must have consistent whitespace on both sidesif characters[i]!= characters[charactersCount - 1 - i] { // cannot force unwrap value of non-optional type 'Character'if characters[i]!= characters[charactersCount - 1 - i] { // use of '=' in a boolean context, did you mean '=='?func makePalindrome(string: String) -> String {
let characters = Array(string)
guard!characters.isEmpty else { return "" }
var postfix = Array(characters.reversed())
while!isPalindrome(postfix) {
postfix.removeFirst()
}
let prefix = Array(characters.prefix(characters.count - postfix.count))
let reversePrefix = prefix.reversed()
return String(characters) + String(reversePrefix)
}
func isPalindrome(_ characters: [Character]) -> Bool {
let charactersCount = characters.count
guard charactersCount > 1 else { return true }
for i in 0..<charactersCount/2 {
if characters[i]!= characters[charactersCount - i - 1] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
guard!characters.isEmpty else { return "" }
var postfix = Array(characters.reversed())
while!isPalindrome(postfix) {
postfix.removeFirst()
}
let prefix = Array(characters.prefix(characters.count - postfix.count))
let reversePrefix = prefix.reversed()
return String(characters) + String(reversePrefix)
}
func isPalindrome(_ characters: [Character]) -> Bool {
let charactersCount = characters.count
guard charactersCount > 1 else { return true }
for i in 0..<charactersCount/2 {
if characters[i]!= characters[charactersCount - i - 1] {
return false
}
}
return true
}
```guard!characters.isEmpty else { return "" } // expected expression, var, let or case in 'guard' conditionwhile!isPalindrome(postfix) { // expected expression, var, or let in 'while' conditionif characters[i]!= characters[charactersCount - i - 1] { // cannot force unwrap value of non-optional type 'Character'if characters[i]!= characters[charactersCount - i - 1] { // use of '=' in a boolean context, did you mean '=='?if characters[i]!= characters[charactersCount - i - 1] { // '=' must have consistent whitespace on both sidesfunc makePalindrome(string: String) -> String {
let characters = Array(string)
let palindrome = longestPalindromicPostfix(characters)
let prefix = String(characters.prefix(characters.count - palindrome.count))
let reversedPrefix = String(prefix.reversed())
return string + reversedPrefix
}
func longestPalindromicPostfix(_ characters: [Character]) -> [Character] {
var palindrome = [Character]()
for i in stride(from: characters.count - 1, to: 0, by: -1) {
let prefix = Array(characters[0..<i])
if prefix == prefix.reversed() {
palindrome = prefix
break
}
}
return palindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
let palindrome = longestPalindromicPostfix(characters)
let prefix = String(characters.prefix(characters.count - palindrome.count))
let reversedPrefix = String(prefix.reversed())
return string + reversedPrefix
}
func longestPalindromicPostfix(_ characters: [Character]) -> [Character] {
var palindrome = [Character]()
for i in stride(from: characters.count - 1, to: 0, by: -1) {
let prefix = Array(characters[0..<i])
if prefix == prefix.reversed() {
palindrome = prefix
break
}
}
return palindrome
}
``` // XCTAssertTrue failedfunc makePalindrome(string: String) -> String {
let characters = Array(string)
let palindrome = findLongestPalindromicPostfix(characters)
let prefix = String(characters.prefix(characters.count - palindrome.count))
let reversedPrefix = String(prefix.reversed())
return string + reversedPrefix
}
func findLongestPalindromicPostfix(_ characters: [Character]) -> [Character] {
var palindrome = [Character]()
for i in 0..<characters.count {
let prefix = Array(characters.prefix(i + 1))
let suffix = Array(characters.suffix(i + 1))
if prefix == suffix {
palindrome = prefix
}
}
return palindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
let palindrome = findLongestPalindromicPostfix(characters)
let prefix = String(characters.prefix(characters.count - palindrome.count))
let reversedPrefix = String(prefix.reversed())
return string + reversedPrefix
}
func findLongestPalindromicPostfix(_ characters: [Character]) -> [Character] {
var palindrome = [Character]()
for i in 0..<characters.count {
let prefix = Array(characters.prefix(i + 1))
let suffix = Array(characters.suffix(i + 1))
if prefix == suffix {
palindrome = prefix
}
}
return palindrome
}
``` // XCTAssertTrue failedfunc makePalindrome(string: String) -> String {
let characters = Array(string)
let reversed = characters.reversed()
let prefix = characters.prefix(while: { reversed.contains($0) })
let palindrome = String(characters) + String(prefix.reversed())
return palindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
let reversed = characters.reversed()
let prefix = characters.prefix(while: { reversed.contains($0) })
let palindrome = String(characters) + String(prefix.reversed())
return palindrome
}
``` // XCTAssertTrue failedfunc makePalindrome(string: String) -> String {
let characters = Array(string)
let reversed = characters.reversed()
let palindromicSuffix = characters.enumerated().reversed().first(where: { reversed[$0.offset..<characters.count] == $0.element })?.offset?? -1
let prefix = String(characters[0..<palindromicSuffix + 1])
let reversedPrefix = String(prefix.reversed())
return string + reversedPrefix
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
let reversed = characters.reversed()
let palindromicSuffix = characters.enumerated().reversed().first(where: { reversed[$0.offset..<characters.count] == $0.element })?.offset?? -1
let prefix = String(characters[0..<palindromicSuffix + 1])
let reversedPrefix = String(prefix.reversed())
return string + reversedPrefix
}
```let palindromicSuffix = characters.enumerated().reversed().first(where: { reversed[$0.offset..<characters.count] == $0.element })?.offset?? -1 // consecutive statements on a line must be separated by ';'let palindromicSuffix = characters.enumerated().reversed().first(where: { reversed[$0.offset..<characters.count] == $0.element })?.offset?? -1 // integer literal is unusedlet palindromicSuffix = characters.enumerated().reversed().first(where: { reversed[$0.offset..<characters.count] == $0.element })?.offset?? -1 // cannot use optional chaining on non-optional value of type 'Int'let palindromicSuffix = characters.enumerated().reversed().first(where: { reversed[$0.offset..<characters.count] == $0.element })?.offset?? -1 // cannot use optional chaining on non-optional value of type 'Int'let palindromicSuffix = characters.enumerated().reversed().first(where: { reversed[$0.offset..<characters.count] == $0.element })?.offset?? -1 // cannot convert value of type 'Range<Int>' to expected argument type 'ReversedCollection<[String.Element]>.Index' (aka 'ReversedCollection<Array<Character>>.Index')func makePalindrome(string: String) -> String {
let characters = Array(string)
let reversed = characters.reversed()
let prefix = characters.prefix(while: { reversed.contains($0) })
let palindrome = String(characters) + String(prefix.reversed())
return palindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
let reversed = characters.reversed()
let prefix = characters.prefix(while: { reversed.contains($0) })
let palindrome = String(characters) + String(prefix.reversed())
return palindrome
}
``` // XCTAssertTrue failedfunc makePalindrome(string: String) -> String {
let characters = Array(string)
let reversed = characters.reversed()
let prefix = characters.prefix(while: { reversed.contains($0) })
let palindrome = String(prefix) + string + String(prefix.reversed())
return palindrome
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
makePalindrome(string: "") == ""
makePalindrome(string: "cat") == "catac"
makePalindrome(string: "cata") == "catac"
Answer:
```swift
func makePalindrome(string: String) -> String {
let characters = Array(string)
let reversed = characters.reversed()
let prefix = characters.prefix(while: { reversed.contains($0) })
let palindrome = String(prefix) + string + String(prefix.reversed())
return palindrome
}
``` // XCTAssertTrue failedfunc stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}
```let resultData = aData.xor(bData) // value of type 'Data' has no member 'xor'func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}
```let resultData = aData.xor(bData) // value of type 'Data' has no member 'xor'func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}
```let resultData = aData.xor(bData) // value of type 'Data' has no member 'xor'func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let xorResult = aData.zip(bData).map { $0 ^ $1 }
return String(data: Data(xorResult), encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let xorResult = aData.zip(bData).map { $0 ^ $1 }
return String(data: Data(xorResult), encoding:.utf8)!
}
```let xorResult = aData.zip(bData).map { $0 ^ $1 } // value of type 'Data' has no member 'zip'func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let xorResult = aData.zip(bData).map { $0 ^ $1 }
return String(data: Data(xorResult), encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let xorResult = aData.zip(bData).map { $0 ^ $1 }
return String(data: Data(xorResult), encoding:.utf8)!
}
```let xorResult = aData.zip(bData).map { $0 ^ $1 } // value of type 'Data' has no member 'zip'func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}
```let resultData = aData.xor(bData) // value of type 'Data' has no member 'xor'func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}
```let resultData = aData.xor(bData) // value of type 'Data' has no member 'xor'func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}
```let resultData = aData.xor(bData) // value of type 'Data' has no member 'xor'func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let resultData = aData.xor(bData)
return String(data: resultData, encoding:.utf8)!
}
```let resultData = aData.xor(bData) // value of type 'Data' has no member 'xor'func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let xorResult = aData.zip(bData).map { $0 ^ $1 }
return String(data: Data(xorResult), encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
stringXor(a: "010", b: "110") == "100"
Answer:
```swift
func stringXor(a: String, b: String) -> String {
let aData = Data(a.utf8)
let bData = Data(b.utf8)
let xorResult = aData.zip(bData).map { $0 ^ $1 }
return String(data: Data(xorResult), encoding:.utf8)!
}
```let xorResult = aData.zip(bData).map { $0 ^ $1 } // value of type 'Data' has no member 'zip'func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Out of array of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return nil in case the input array is empty.
longest(strings: [] as [String]) == nil
longest(strings: ["a", "b", "c"]) == "a"
longest(strings: ["a", "bb", "ccc"]) == "ccc"
Answer:
```swift
func longest(strings: [String]) -> String? {
guard!strings.isEmpty else { return nil }
return strings.max { $0.count < $1.count }
}
```guard!strings.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```while b!= 0 { // use of '=' in a boolean context, did you mean '=='?while b!= 0 { // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // '=' must have consistent whitespace on both sidesfunc greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```while b!= 0 { // use of '=' in a boolean context, did you mean '=='?while b!= 0 { // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // '=' must have consistent whitespace on both sidesfunc greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
} else {
return gcd(b, a % b)
}
}
return gcd(a, b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
} else {
return gcd(b, a % b)
}
}
return gcd(a, b)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
return gcd(a, b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
return gcd(a, b)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
} else {
return gcd(b, a % b)
}
}
return gcd(a, b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
} else {
return gcd(b, a % b)
}
}
return gcd(a, b)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```while b!= 0 { // use of '=' in a boolean context, did you mean '=='?while b!= 0 { // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // '=' must have consistent whitespace on both sidesfunc greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
return gcd(a, b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
return gcd(a, b)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
return gcd(a, b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
return gcd(a, b)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
return gcd(a, b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
}
return gcd(b, a % b)
}
return gcd(a, b)
}
```func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
} else {
return gcd(b, a % b)
}
}
return gcd(a, b)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a greatest common divisor of two integers a and b
greatestCommonDivisor(a: 3, b: 5) == 1
greatestCommonDivisor(a: 25, b: 15) == 5
Answer:
```swift
func greatestCommonDivisor(a: Int, b: Int) -> Int {
func gcd(_ a: Int, _ b: Int) -> Int {
if b == 0 {
return a
} else {
return gcd(b, a % b)
}
}
return gcd(a, b)
}
```func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of all prefixes from shortest to longest of the input string
allPrefixes(string: "abc") == ["a", "ab", "abc"]
Answer:
```swift
func allPrefixes(string: String) -> [String] {
var prefixes: [String] = []
for i in 1...string.count {
let prefix = String(string.prefix(i))
prefixes.append(prefix)
}
return prefixes
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc stringSequence(n: Int) -> String {
return String(repeating: "0 1 2 3 4 5 ".dropLast(), count: n + 1).trimmingCharacters(in:.whitespacesAndNewlines)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(repeating: "0 1 2 3 4 5 ".dropLast(), count: n + 1).trimmingCharacters(in:.whitespacesAndNewlines)
}
```return String(repeating: "0 1 2 3 4 5 ".dropLast(), count: n + 1).trimmingCharacters(in:.whitespacesAndNewlines) // no exact matches in call to initializerfunc stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}
``` // XCTAssertTrue failedfunc stringSequence(n: Int) -> String {
return String(data: Data(bytes: Array(0...n)), encoding:.utf8)!
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(data: Data(bytes: Array(0...n)), encoding:.utf8)!
}
```return String(data: Data(bytes: Array(0...n)), encoding:.utf8)! // type of expression is ambiguous without a type annotationfunc stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}
``` // XCTAssertTrue failedfunc stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}
``` // XCTAssertTrue failedfunc stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}
``` // XCTAssertTrue failedfunc stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}
``` // XCTAssertTrue failedfunc stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}
``` // XCTAssertTrue failedfunc stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}
``` // XCTAssertTrue failedfunc stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return a string containing space-delimited numbers starting from 0 upto n inclusive.
stringSequence(n: 0) == "0"
stringSequence(n: 5) == "0 1 2 3 4 5"
Answer:
```swift
func stringSequence(n: Int) -> String {
return String(describing: stride(from: 0, through: n, by: 1))
}
``` // XCTAssertTrue failedfunc countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercasedString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercasedString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercasedString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string, find out how many distinct characters (regardless of case) does it consist of
countDistinctCharacters(string: "xyzXYZ") == 3
countDistinctCharacters(string: "Jerry") == 4
Answer:
```swift
func countDistinctCharacters(string: String) -> Int {
let lowercaseString = string.lowercased()
var distinctCharacters = Set<Character>()
for character in lowercaseString {
distinctCharacters.insert(character)
}
return distinctCharacters.count
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.components(separatedBy: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.components(separatedBy: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.split(separator: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.components(separatedBy: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.components(separatedBy: " ")
var beats: [Int] = []
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func parseMusic(musicString: String) -> [Int] {
let notes = musicString.components(separatedBy: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return array of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
parseMusic(musicString: "o o|.| o| o|.|.|.|.| o o") == [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
Answer:
```swift
func parseMusic(musicString: String) -> [Int] {
let notes = musicString.components(separatedBy: " ")
var beats = [Int]()
for note in notes {
switch note {
case "o":
beats.append(4)
case "o|":
beats.append(2)
case ".|":
beats.append(1)
default:
break
}
}
return beats
}
```func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) {
count += 1
index = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) {
count += 1
index = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) {
count += 1
index = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) {
count += 1
index = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) {
count += 1
index = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) {
count += 1
index = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) {
count += 1
index = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var index = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) {
count += 1
index = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: index..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Find how many times a given substring can be found in the original string. Count overlaping cases.
howManyTimes(string: "", substring: "a") == 0
howManyTimes(string: "aaa", substring: "a") == 3
howManyTimes(string: "aaaa", substring: "aa") == 3
Answer:
```swift
func howManyTimes(string: String, substring: String) -> Int {
var count = 0
var idx = string.startIndex
while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) {
count += 1
idx = range.upperBound
}
return count
}
```while let range = string.range(of: substring, options:.overlapping, range: idx..<string.endIndex) { // type 'String.CompareOptions' (aka 'NSString.CompareOptions') has no member 'overlapping'func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { numberToNumber($0) }
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
return sortedNumberals.joined(separator: " ")
}
func numberToNumber(_ numberal: String) -> Int {
switch numberal {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
func numberToNumberal(_ number: Int) -> String {
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return "zero"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { numberToNumber($0) }
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { numberToNumberal($0) }
return sortedNumberals.joined(separator: " ")
}
func numberToNumber(_ numberal: String) -> Int {
switch numberal {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
func numberToNumberal(_ number: Int) -> String {
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return "zero"
}
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return "zero"
}
}
return sortedNumberals.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return "zero"
}
}
return sortedNumberals.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return "zero"
}
}
return sortedNumberals.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return "zero"
}
}
return sortedNumberals.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return ""
}
}
return sortedNumberals.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return "zero"
}
}
return sortedNumberals.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five','six','seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
sortNumbers(numbers: "three one five") == "one three five"
Answer:
```swift
func sortNumbers(numbers: String) -> String {
let numberals = numbers.components(separatedBy: " ")
let numbers = numberals.map { number -> Int in
switch number {
case "zero": return 0
case "one": return 1
case "two": return 2
case "three": return 3
case "four": return 4
case "five": return 5
case "six": return 6
case "seven": return 7
case "eight": return 8
case "nine": return 9
default: return 0
}
}
let sortedNumbers = numbers.sorted()
let sortedNumberals = sortedNumbers.map { number -> String in
switch number {
case 0: return "zero"
case 1: return "one"
case 2: return "two"
case 3: return "three"
case 4: return "four"
case 5: return "five"
case 6: return "six"
case 7: return "seven"
case 8: return "eight"
case 9: return "nine"
default: return "zero"
}
}
return sortedNumberals.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let currentDifference = abs(numbers[i] - numbers[i+1])
if currentDifference < minDifference {
minDifference = currentDifference
result = (numbers[i], numbers[i+1])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let currentDifference = abs(numbers[i] - numbers[i+1])
if currentDifference < minDifference {
minDifference = currentDifference
result = (numbers[i], numbers[i+1])
}
}
return result
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[j])
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[j])
}
}
}
return result
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let currentDifference = abs(numbers[i] - numbers[i+1])
if currentDifference < minDifference {
minDifference = currentDifference
result = (numbers[i], numbers[i+1])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let currentDifference = abs(numbers[i] - numbers[i+1])
if currentDifference < minDifference {
minDifference = currentDifference
result = (numbers[i], numbers[i+1])
}
}
return result
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let currentDifference = abs(numbers[i] - numbers[i+1])
if currentDifference < minDifference {
minDifference = currentDifference
result = (numbers[i], numbers[i+1])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let currentDifference = abs(numbers[i] - numbers[i+1])
if currentDifference < minDifference {
minDifference = currentDifference
result = (numbers[i], numbers[i+1])
}
}
return result
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
let difference = abs(numbers[i] - numbers[i+1])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[i+1])
}
}
return result
}
``` // XCTAssertTrue failedfunc findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[j])
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From a supplied array of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
findClosestElements(numbers: [1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
Answer:
```swift
func findClosestElements(numbers: [Double]) -> (Double, Double) {
var minDifference = abs(numbers[0] - numbers[1])
var result = (numbers[0], numbers[1])
for i in 0..<numbers.count-1 {
for j in i+1..<numbers.count {
let difference = abs(numbers[i] - numbers[j])
if difference < minDifference {
minDifference = difference
result = (numbers[i], numbers[j])
}
}
}
return result
}
``` // XCTAssertTrue failedfunc rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
let range = max - min
return numbers.map { ($0 - min) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
let range = max - min
return numbers.map { ($0 - min) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
let range = max - min
return numbers.map { ($0 - min) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let min = numbers.min()!
let max = numbers.max()!
let range = max - min
return numbers.map { ($0 - min) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}
```func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of numbers (of at least two elements), apply a linear transform to that array,
such that the smallest number will become 0 and the largest will become 1
rescaleToUnit(numbers: [1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
Answer:
```swift
func rescaleToUnit(numbers: [Double]) -> [Double] {
let minValue = numbers.min()!
let maxValue = numbers.max()!
let range = maxValue - minValue
return numbers.map { ($0 - minValue) / range }
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter given array of any swiftthon values only for integers
filterIntegers(values: ["a", 3.14, 5]) == [5]
filterIntegers(values: [1, 2, 3, "abc", [:] as [AnyHashable : AnyHashable], [] as [AnyHashable]]) == [1, 2, 3]
Answer:
```swift
func filterIntegers(values: [AnyHashable]) -> [Int] {
return values.compactMap { value in
if let intValue = value as? Int {
return intValue
}
return nil
}
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func strlen(string: String) -> Int {
return string.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return length of given string
strlen(string: "") == 0
strlen(string: "abc") == 3
Answer:
```swift
func strlen(string: String) -> Int {
return string.count
}
```func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in (1...n).reversed() {
if n % i == 0 {
return i
}
}
return 1
}
``` // XCTAssertTrue failedfunc largestDivisor(n: Int) -> Int {
for i in stride(from: n - 1, through: 1, by: -1) {
if n % i == 0 {
return i
}
}
return 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given number n, find the largest number that divides n evenly, smaller than n
largestDivisor(n: 15) == 5
Answer:
```swift
func largestDivisor(n: Int) -> Int {
for i in stride(from: n - 1, through: 1, by: -1) {
if n % i == 0 {
return i
}
}
return 1
}
```func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var factor = 2
while number > 1 {
while number % factor == 0 {
factors.append(factor)
number /= factor
}
factor += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var factor = 2
while number > 1 {
while number % factor == 0 {
factors.append(factor)
number /= factor
}
factor += 1
}
return factors
}
```func factorize(n: Int) -> [Int] {
var result: [Int] = []
var number = n
var divisor = 2
while number > 1 {
while number % divisor == 0 {
result.append(divisor)
number /= divisor
}
divisor += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var result: [Int] = []
var number = n
var divisor = 2
while number > 1 {
while number % divisor == 0 {
result.append(divisor)
number /= divisor
}
divisor += 1
}
return result
}
```func factorize(n: Int) -> [Int] {
var n = n
var result: [Int] = []
var divisor = 2
while n > 1 {
while n % divisor == 0 {
result.append(divisor)
n /= divisor
}
divisor += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var n = n
var result: [Int] = []
var divisor = 2
while n > 1 {
while n % divisor == 0 {
result.append(divisor)
n /= divisor
}
divisor += 1
}
return result
}
```func factorize(n: Int) -> [Int] {
var result: [Int] = []
var number = n
var divisor = 2
while number > 1 {
while number % divisor == 0 {
result.append(divisor)
number /= divisor
}
divisor += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var result: [Int] = []
var number = n
var divisor = 2
while number > 1 {
while number % divisor == 0 {
result.append(divisor)
number /= divisor
}
divisor += 1
}
return result
}
```func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var factor = 2
while number > 1 {
while number % factor == 0 {
factors.append(factor)
number /= factor
}
factor += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var factor = 2
while number > 1 {
while number % factor == 0 {
factors.append(factor)
number /= factor
}
factor += 1
}
return factors
}
```func factorize(n: Int) -> [Int] {
var result: [Int] = []
var number = n
var divisor = 2
while number > 1 {
while number % divisor == 0 {
result.append(divisor)
number /= divisor
}
divisor += 1
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var result: [Int] = []
var number = n
var divisor = 2
while number > 1 {
while number % divisor == 0 {
result.append(divisor)
number /= divisor
}
divisor += 1
}
return result
}
```func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var factor = 2
while number > 1 {
while number % factor == 0 {
factors.append(factor)
number /= factor
}
factor += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var factor = 2
while number > 1 {
while number % factor == 0 {
factors.append(factor)
number /= factor
}
factor += 1
}
return factors
}
```func factorize(n: Int) -> [Int] {
var n = n
var factors: [Int] = []
for i in 2...n {
while n % i == 0 {
factors.append(i)
n /= i
}
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var n = n
var factors: [Int] = []
for i in 2...n {
while n % i == 0 {
factors.append(i)
n /= i
}
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var factor = 2
while number > 1 {
while number % factor == 0 {
factors.append(factor)
number /= factor
}
factor += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var factor = 2
while number > 1 {
while number % factor == 0 {
factors.append(factor)
number /= factor
}
factor += 1
}
return factors
}
```func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var divisor = 2
while number > 1 {
while number % divisor == 0 {
factors.append(divisor)
number /= divisor
}
divisor += 1
}
return factors
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array of prime factors of given integer in the order from smallest to largest.
Each of the factors should be arrayed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
factorize(n: 8) == [2, 2, 2]
factorize(n: 25) == [5, 5]
factorize(n: 70) == [2, 5, 7]
Answer:
```swift
func factorize(n: Int) -> [Int] {
var factors: [Int] = []
var number = n
var divisor = 2
while number > 1 {
while number % divisor == 0 {
factors.append(divisor)
number /= divisor
}
divisor += 1
}
return factors
}
```func removeDuplicates(numbers: [Int]) -> [Int] {
var result: [Int] = []
var seen: Set<Int> = []
for number in numbers {
if!seen.contains(number) {
result.append(number)
seen.insert(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result: [Int] = []
var seen: Set<Int> = []
for number in numbers {
if!seen.contains(number) {
result.append(number)
seen.insert(number)
}
}
return result
}
```if!seen.contains(number) { // expected expression, var, or let in 'if' conditionfunc removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers = [Int]()
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers = [Int]()
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var result: [Int] = []
var seen: Set<Int> = []
for number in numbers {
if seen.contains(number) {
continue
}
seen.insert(number)
result.append(number)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var result: [Int] = []
var seen: Set<Int> = []
for number in numbers {
if seen.contains(number) {
continue
}
seen.insert(number)
result.append(number)
}
return result
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueElements: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueElements.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueElements
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueElements: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueElements.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueElements
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequency = [Int: Int]()
for number in numbers {
if frequency[number] == nil {
frequency[number] = 1
uniqueNumbers.append(number)
} else {
frequency[number]! += 1
}
}
return uniqueNumbers
}
``` // XCTAssertTrue failedfunc removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequencyTable: [Int: Int] = [:]
for number in numbers {
if frequencyTable[number] == nil {
frequencyTable[number] = 1
uniqueNumbers.append(number)
} else {
frequencyTable[number]! += 1
}
}
return uniqueNumbers
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
From an array of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
removeDuplicates(numbers: [1, 2, 3, 2, 4]) == [1, 3, 4]
Answer:
```swift
func removeDuplicates(numbers: [Int]) -> [Int] {
var uniqueNumbers: [Int] = []
var frequencyTable: [Int: Int] = [:]
for number in numbers {
if frequencyTable[number] == nil {
frequencyTable[number] = 1
uniqueNumbers.append(number)
} else {
frequencyTable[number]! += 1
}
}
return uniqueNumbers
}
``` // XCTAssertTrue failedfunc flipCase(string: String) -> String {
return String(string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
})
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return String(string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
})
}
```$0.isLowercase? $0.uppercased() : $0.lowercased() // cannot use optional chaining on non-optional value of type 'Bool'$0.isLowercase? $0.uppercased() : $0.lowercased() // expected expression$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'func flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}
```return string.map { // cannot convert return expression of type '[()]' to return type 'String'$0.isLowercase? $0.uppercased() : $0.lowercased() // cannot use optional chaining on non-optional value of type 'Bool'$0.isLowercase? $0.uppercased() : $0.lowercased() // expected expression$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'func flipCase(string: String) -> String {
return String(string.unicodeScalars.map {
$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0
})
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return String(string.unicodeScalars.map {
$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0
})
}
```$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0 // consecutive statements on a line must be separated by ';'$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0 // cannot use optional chaining on non-optional value of type 'Bool'$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0 // consecutive statements on a line must be separated by ';'$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0 // expected expressionfunc flipCase(string: String) -> String {
return String(string.map { $0.isLowercase? $0.uppercased() : $0.lowercased() })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return String(string.map { $0.isLowercase? $0.uppercased() : $0.lowercased() })
}
```return String(string.map { $0.isLowercase? $0.uppercased() : $0.lowercased() }) // expected expressionreturn String(string.map { $0.isLowercase? $0.uppercased() : $0.lowercased() }) // consecutive statements on a line must be separated by ';'return String(string.map { $0.isLowercase? $0.uppercased() : $0.lowercased() }) // consecutive statements on a line must be separated by ';'return String(string.map { $0.isLowercase? $0.uppercased() : $0.lowercased() }) // cannot use optional chaining on non-optional value of type 'Bool'func flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}
```return string.map { // cannot convert return expression of type '[()]' to return type 'String'$0.isLowercase? $0.uppercased() : $0.lowercased() // cannot use optional chaining on non-optional value of type 'Bool'$0.isLowercase? $0.uppercased() : $0.lowercased() // expected expression$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'func flipCase(string: String) -> String {
return String(string.unicodeScalars.map {
$0.isASCII? Character(UnicodeScalar(65 + 97 - $0.value)!) : $0
})
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return String(string.unicodeScalars.map {
$0.isASCII? Character(UnicodeScalar(65 + 97 - $0.value)!) : $0
})
}
```$0.isASCII? Character(UnicodeScalar(65 + 97 - $0.value)!) : $0 // expected expression$0.isASCII? Character(UnicodeScalar(65 + 97 - $0.value)!) : $0 // consecutive statements on a line must be separated by ';'$0.isASCII? Character(UnicodeScalar(65 + 97 - $0.value)!) : $0 // cannot use optional chaining on non-optional value of type 'Bool'$0.isASCII? Character(UnicodeScalar(65 + 97 - $0.value)!) : $0 // consecutive statements on a line must be separated by ';'func flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}
```return string.map { // cannot convert return expression of type '[()]' to return type 'String'$0.isLowercase? $0.uppercased() : $0.lowercased() // cannot use optional chaining on non-optional value of type 'Bool'$0.isLowercase? $0.uppercased() : $0.lowercased() // expected expression$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'func flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}
```return string.map { // cannot convert return expression of type '[()]' to return type 'String'$0.isLowercase? $0.uppercased() : $0.lowercased() // cannot use optional chaining on non-optional value of type 'Bool'$0.isLowercase? $0.uppercased() : $0.lowercased() // expected expression$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'func flipCase(string: String) -> String {
return String(string.unicodeScalars.map {
$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0
})
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return String(string.unicodeScalars.map {
$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0
})
}
```$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0 // consecutive statements on a line must be separated by ';'$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0 // cannot use optional chaining on non-optional value of type 'Bool'$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0 // consecutive statements on a line must be separated by ';'$0.isASCII? Character(UnicodeScalar(65 + 90 - $0.value)!) : $0 // expected expressionfunc flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
flipCase(string: "Hello") == "hELLO"
Answer:
```swift
func flipCase(string: String) -> String {
return string.map {
$0.isLowercase? $0.uppercased() : $0.lowercased()
}
}
```return string.map { // cannot convert return expression of type '[()]' to return type 'String'$0.isLowercase? $0.uppercased() : $0.lowercased() // cannot use optional chaining on non-optional value of type 'Bool'$0.isLowercase? $0.uppercased() : $0.lowercased() // expected expression$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'$0.isLowercase? $0.uppercased() : $0.lowercased() // consecutive statements on a line must be separated by ';'func concatenate(strings: [String]) -> String {
return strings.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("", +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("", +)
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("", +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("", +)
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("", +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("", +)
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func concatenate(strings: [String]) -> String {
return strings.reduce("", +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.reduce("", +)
}
```func concatenate(strings: [String]) -> String {
return strings.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Concatenate array of strings into a single string
concatenate(strings: [] as [String]) == ""
concatenate(strings: ["a", "b", "c"]) == "abc"
Answer:
```swift
func concatenate(strings: [String]) -> String {
return strings.joined()
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Filter an input array of strings only for ones that start with a given prefix.
filterByPrefix(strings: [] as [String], prefix: "a") == [] as [String]
filterByPrefix(strings: ["abc", "bcd", "cde", "array"], prefix: "a") == ["abc", "array"]
Answer:
```swift
func filterByPrefix(strings: [String], prefix: String) -> [String] {
return strings.filter { $0.hasPrefix(prefix) }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return only positive numbers in the array.
getPositive(l: [-1, 2, -4, 5, 6]) == [2, 5, 6]
getPositive(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 9, 123, 1]
Answer:
```swift
func getPositive(l: [Int]) -> [Int] {
return l.filter { $0 > 0 }
}
```func isPrime(n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
if n % 2 == 0 || n % 3 == 0 {
return false
}
var i = 5
while i * i <= n {
if n % i == 0 || n % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}
```func isPrime(n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}
```func isPrime(n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func isPrime(n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
guard n > 1 else { return false }
for i in 2..<n {
if n % i == 0 {
return false
}
}
return true
}
```func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if a given number is prime, and false otherwise.
isPrime(n: 6) == false
isPrime(n: 101) == true
isPrime(n: 11) == true
isPrime(n: 13441) == true
isPrime(n: 61) == true
isPrime(n: 4) == false
isPrime(n: 1) == false
Answer:
```swift
func isPrime(n: Int) -> Bool {
if n <= 1 {
return false
}
if n <= 3 {
return true
}
var i = 2
while i * i <= n {
if n % i == 0 {
return false
}
i += 1
}
return true
}
```func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l[l.indices.filter({ $0 % 3 == 0 })].sorted()
for (i, v) in sorted.enumerated() {
l[l.indices.filter({ $0 % 3 == 0 })[i]] = v
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l[l.indices.filter({ $0 % 3 == 0 })].sorted()
for (i, v) in sorted.enumerated() {
l[l.indices.filter({ $0 % 3 == 0 })[i]] = v
}
return l
}
```let sorted = l[l.indices.filter({ $0 % 3 == 0 })].sorted() // cannot convert value of type '[Range<Array<Int>.Index>.Element]' (aka 'Array<Int>') to expected argument type 'Range<Int>'func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l[l.indices.filter({ $0 % 3 == 0 })].sorted()
for (index, value) in sorted.enumerated() {
l[index * 3] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l[l.indices.filter({ $0 % 3 == 0 })].sorted()
for (index, value) in sorted.enumerated() {
l[index * 3] = value
}
return l
}
```let sorted = l[l.indices.filter({ $0 % 3 == 0 })].sorted() // cannot convert value of type '[Range<Array<Int>.Index>.Element]' (aka 'Array<Int>') to expected argument type 'Range<Int>'func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (index, value) in sorted.enumerated() {
l[index * 3] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (index, value) in sorted.enumerated() {
l[index * 3] = value
}
return l
}
``` // XCTAssertTrue failedfunc sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (i, v) in sorted.enumerated() {
l[i * 3] = v
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (i, v) in sorted.enumerated() {
l[i * 3] = v
}
return l
}
``` // XCTAssertTrue failedfunc sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (i, v) in sorted.enumerated() {
l[i * 3] = v
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (i, v) in sorted.enumerated() {
l[i * 3] = v
}
return l
}
``` // XCTAssertTrue failedfunc sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (index, value) in sorted.enumerated() {
l[index * 3] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (index, value) in sorted.enumerated() {
l[index * 3] = value
}
return l
}
``` // XCTAssertTrue failedfunc sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (i, v) in sorted.enumerated() {
l[i * 3] = v
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (i, v) in sorted.enumerated() {
l[i * 3] = v
}
return l
}
``` // XCTAssertTrue failedfunc sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (index, element) in sorted.enumerated() {
l[index * 3] = element
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (index, element) in sorted.enumerated() {
l[index * 3] = element
}
return l
}
``` // XCTAssertTrue failedfunc sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (index, element) in sorted.enumerated() {
l[index * 3] = element
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (index, element) in sorted.enumerated() {
l[index * 3] = element
}
return l
}
``` // XCTAssertTrue failedfunc sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (i, v) in sorted.enumerated() {
l[i * 3] = v
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
sortThird(l: [1, 2, 3]) == [1, 2, 3]
sortThird(l: [5, 6, 3, 4, 8, 9, 2]) == [2, 6, 3, 4, 8, 9, 5]
Answer:
```swift
func sortThird(l: [Int]) -> [Int] {
var l = l
let sorted = l.enumerated().filter { $0.offset % 3 == 0 }.sorted { $0.element > $1.element }.map { $0.element }
for (i, v) in sorted.enumerated() {
l[i * 3] = v
}
return l
}
``` // XCTAssertTrue failedfunc unique(l: [Int]) -> [Int] {
var uniqueElements: [Int] = []
for element in l {
if!uniqueElements.contains(element) {
uniqueElements.append(element)
}
}
return uniqueElements.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var uniqueElements: [Int] = []
for element in l {
if!uniqueElements.contains(element) {
uniqueElements.append(element)
}
}
return uniqueElements.sorted()
}
```if!uniqueElements.contains(element) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var result: [Int] = []
for item in l {
if!result.contains(item) {
result.append(item)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var result: [Int] = []
for item in l {
if!result.contains(item) {
result.append(item)
}
}
return result.sorted()
}
```if!result.contains(item) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var s = Set(l)
return s.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var s = Set(l)
return s.sorted()
}
```var s = Set(l) // variable 's' was never mutated; consider changing to 'let' constantfunc unique(l: [Int]) -> [Int] {
var uniqueElements: [Int] = []
for element in l {
if!uniqueElements.contains(element) {
uniqueElements.append(element)
}
}
return uniqueElements.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var uniqueElements: [Int] = []
for element in l {
if!uniqueElements.contains(element) {
uniqueElements.append(element)
}
}
return uniqueElements.sorted()
}
```if!uniqueElements.contains(element) { // expected expression, var, or let in 'if' conditionfunc unique(l: [Int]) -> [Int] {
var s = Set(l)
var result: [Int] = []
for item in s {
result.append(item)
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var s = Set(l)
var result: [Int] = []
for item in s {
result.append(item)
}
return result.sorted()
}
```var s = Set(l) // variable 's' was never mutated; consider changing to 'let' constantfunc unique(l: [Int]) -> [Int] {
var s = Set(l)
var result: [Int] = []
for item in s {
result.append(item)
}
result.sort()
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var s = Set(l)
var result: [Int] = []
for item in s {
result.append(item)
}
result.sort()
return result
}
```var s = Set(l) // variable 's' was never mutated; consider changing to 'let' constantfunc unique(l: [Int]) -> [Int] {
var unique = Set(l)
return unique.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var unique = Set(l)
return unique.sorted()
}
```var unique = Set(l) // variable 'unique' was never mutated; consider changing to 'let' constantfunc unique(l: [Int]) -> [Int] {
var s = Set(l)
return s.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var s = Set(l)
return s.sorted()
}
```var s = Set(l) // variable 's' was never mutated; consider changing to 'let' constantfunc unique(l: [Int]) -> [Int] {
var s = Set(l)
var result: [Int] = []
for item in s {
result.append(item)
}
result.sort()
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var s = Set(l)
var result: [Int] = []
for item in s {
result.append(item)
}
result.sort()
return result
}
```var s = Set(l) // variable 's' was never mutated; consider changing to 'let' constantfunc unique(l: [Int]) -> [Int] {
var s = Set(l)
return s.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique elements in an array
unique(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
Answer:
```swift
func unique(l: [Int]) -> [Int] {
var s = Set(l)
return s.sorted()
}
```var s = Set(l) // variable 's' was never mutated; consider changing to 'let' constantfunc maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return maximum element in the array.
maxElement(l: [1, 2, 3]) == 3
maxElement(l: [5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == 123
Answer:
```swift
func maxElement(l: [Int]) -> Int {
var max = l[0]
for i in 1..<l.count {
if l[i] > max {
max = l[i]
}
}
return max
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let numString = String(i)
if numString.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let numString = String(i)
if numString.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1..<n {
if i % 11 == 0 || i % 13 == 0 {
let num = String(i)
if num.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1..<n {
if i % 11 == 0 || i % 13 == 0 {
let num = String(i)
if num.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
count += string.filter { $0 == "7" }.count
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
count += string.filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
count += string.filter { $0 == "7" }.count
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
count += string.filter { $0 == "7" }.count
}
}
return count
}
```func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
fizzBuzz(n: 50) == 0
fizzBuzz(n: 78) == 2
fizzBuzz(n: 79) == 3
Answer:
```swift
func fizzBuzz(n: Int) -> Int {
var count = 0
for i in 1...n-1 {
if i % 11 == 0 || i % 13 == 0 {
let string = String(i)
if string.contains("7") {
count += 1
}
}
}
return count
}
``` // XCTAssertTrue failedfunc sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}
```let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element } // initialization of immutable value 'odd' was never used; consider replacing with assignment to '_' or removing itfunc sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}
```let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element } // initialization of immutable value 'odd' was never used; consider replacing with assignment to '_' or removing itfunc sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}
```let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element } // initialization of immutable value 'odd' was never used; consider replacing with assignment to '_' or removing itfunc sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }
let sortedEven = even.sorted { $0.element < $1.element }
for (index, element) in sortedEven {
l[index] = element
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }
let sortedEven = even.sorted { $0.element < $1.element }
for (index, element) in sortedEven {
l[index] = element
}
return l
}
``` // XCTAssertTrue failedfunc sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}
```func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 0 }.map { $0.element }
let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2] = value
}
return l
}
```let odd = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element } // initialization of immutable value 'odd' was never used; consider replacing with assignment to '_' or removing itfunc sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2 + 1] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2 + 1] = value
}
return l
}
``` // XCTAssertTrue failedfunc sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2 + 1] = value
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }.map { $0.element }
let sortedEven = even.sorted()
for (index, value) in sortedEven.enumerated() {
l[index * 2 + 1] = value
}
return l
}
``` // XCTAssertTrue failedfunc sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }.sorted { $0.element > $1.element }
for (i, v) in even {
l[i] = v
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }.sorted { $0.element > $1.element }
for (i, v) in even {
l[i] = v
}
return l
}
``` // XCTAssertTrue failedfunc sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }
let sortedEven = even.sorted { $0.element < $1.element }
for (index, element) in sortedEven {
l[index] = element
}
return l
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes an array l and returns an array l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
sortEven(l: [1, 2, 3]) == [1, 2, 3]
sortEven(l: [5, 6, 3, 4]) == [3, 6, 5, 4]
Answer:
```swift
func sortEven(l: [Int]) -> [Int] {
var l = l
let even = l.enumerated().filter { $0.offset % 2 == 1 }
let sortedEven = even.sorted { $0.element < $1.element }
for (index, element) in sortedEven {
l[index] = element
}
return l
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Index out of rangefunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Index out of rangefunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci.last!
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci.last!
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Index out of rangefunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Index out of rangefunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Index out of rangefunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Index out of rangefunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Index out of rangefunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Index out of rangefunc primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
primeFib(n: 1) == 2
primeFib(n: 2) == 3
primeFib(n: 3) == 5
primeFib(n: 4) == 13
primeFib(n: 5) == 89
Answer:
```swift
func primeFib(n: Int) -> Int {
var fibonacci = [2, 3]
var index = 2
while fibonacci.count < n {
let next = fibonacci[index - 1] + fibonacci[index - 2]
if isPrime(next) {
fibonacci.append(next)
}
index += 1
}
return fibonacci[n - 1]
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Index out of rangefunc triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for (i, num) in sorted.enumerated() {
if i > 0 && num == sorted[i - 1] { continue }
let left = i + 1
let right = sorted.count - 1
while left < right {
let sum = num + sorted[left] + sorted[right]
if sum == 0 { return true }
if sum < 0 { left += 1 }
else { right -= 1 }
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for (i, num) in sorted.enumerated() {
if i > 0 && num == sorted[i - 1] { continue }
let left = i + 1
let right = sorted.count - 1
while left < right {
let sum = num + sorted[left] + sorted[right]
if sum == 0 { return true }
if sum < 0 { left += 1 }
else { right -= 1 }
}
}
return false
}
```if sum < 0 { left += 1 } // left side of mutating operator isn't mutable: 'left' is a 'let' constantelse { right -= 1 } // left side of mutating operator isn't mutable: 'right' is a 'let' constantfunc triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for i in 0..<sorted.count-2 {
if i == 0 || sorted[i]!= sorted[i-1] {
let left = i+1
let right = sorted.count-1
while left < right {
let sum = sorted[i] + sorted[left] + sorted[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for i in 0..<sorted.count-2 {
if i == 0 || sorted[i]!= sorted[i-1] {
let left = i+1
let right = sorted.count-1
while left < right {
let sum = sorted[i] + sorted[left] + sorted[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
}
return false
}
```if i == 0 || sorted[i]!= sorted[i-1] { // expression is not assignable: '||' returns immutable valueif i == 0 || sorted[i]!= sorted[i-1] { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif i == 0 || sorted[i]!= sorted[i-1] { // use of '=' in a boolean context, did you mean '=='?if i == 0 || sorted[i]!= sorted[i-1] { // cannot force unwrap value of non-optional type 'Int'if i == 0 || sorted[i]!= sorted[i-1] { // '=' must have consistent whitespace on both sidesleft += 1 // left side of mutating operator isn't mutable: 'left' is a 'let' constantright -= 1 // left side of mutating operator isn't mutable: 'right' is a 'let' constantfunc triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for i in 0..<sorted.count-2 {
if i == 0 || sorted[i]!= sorted[i-1] {
let left = i+1
let right = sorted.count-1
while left < right {
let sum = sorted[i] + sorted[left] + sorted[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for i in 0..<sorted.count-2 {
if i == 0 || sorted[i]!= sorted[i-1] {
let left = i+1
let right = sorted.count-1
while left < right {
let sum = sorted[i] + sorted[left] + sorted[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
}
return false
}
```if i == 0 || sorted[i]!= sorted[i-1] { // expression is not assignable: '||' returns immutable valueif i == 0 || sorted[i]!= sorted[i-1] { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif i == 0 || sorted[i]!= sorted[i-1] { // use of '=' in a boolean context, did you mean '=='?if i == 0 || sorted[i]!= sorted[i-1] { // cannot force unwrap value of non-optional type 'Int'if i == 0 || sorted[i]!= sorted[i-1] { // '=' must have consistent whitespace on both sidesleft += 1 // left side of mutating operator isn't mutable: 'left' is a 'let' constantright -= 1 // left side of mutating operator isn't mutable: 'right' is a 'let' constantfunc triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for i in 0..<sorted.count-2 {
if i == 0 || sorted[i]!= sorted[i-1] {
let left = i+1
let right = sorted.count-1
while left < right {
let sum = sorted[i] + sorted[left] + sorted[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for i in 0..<sorted.count-2 {
if i == 0 || sorted[i]!= sorted[i-1] {
let left = i+1
let right = sorted.count-1
while left < right {
let sum = sorted[i] + sorted[left] + sorted[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
}
return false
}
```if i == 0 || sorted[i]!= sorted[i-1] { // expression is not assignable: '||' returns immutable valueif i == 0 || sorted[i]!= sorted[i-1] { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif i == 0 || sorted[i]!= sorted[i-1] { // use of '=' in a boolean context, did you mean '=='?if i == 0 || sorted[i]!= sorted[i-1] { // cannot force unwrap value of non-optional type 'Int'if i == 0 || sorted[i]!= sorted[i-1] { // '=' must have consistent whitespace on both sidesleft += 1 // left side of mutating operator isn't mutable: 'left' is a 'let' constantright -= 1 // left side of mutating operator isn't mutable: 'right' is a 'let' constantfunc triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count-2 {
for j in (i+1)..<l.count-1 {
for k in (j+1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count-2 {
for j in (i+1)..<l.count-1 {
for k in (j+1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for i in 0..<sorted.count-2 {
if i == 0 || sorted[i]!= sorted[i-1] {
let left = i+1
let right = sorted.count-1
while left < right {
let sum = sorted[i] + sorted[left] + sorted[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sorted = l.sorted()
for i in 0..<sorted.count-2 {
if i == 0 || sorted[i]!= sorted[i-1] {
let left = i+1
let right = sorted.count-1
while left < right {
let sum = sorted[i] + sorted[left] + sorted[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
}
return false
}
```if i == 0 || sorted[i]!= sorted[i-1] { // expression is not assignable: '||' returns immutable valueif i == 0 || sorted[i]!= sorted[i-1] { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif i == 0 || sorted[i]!= sorted[i-1] { // use of '=' in a boolean context, did you mean '=='?if i == 0 || sorted[i]!= sorted[i-1] { // cannot force unwrap value of non-optional type 'Int'if i == 0 || sorted[i]!= sorted[i-1] { // '=' must have consistent whitespace on both sidesleft += 1 // left side of mutating operator isn't mutable: 'left' is a 'let' constantright -= 1 // left side of mutating operator isn't mutable: 'right' is a 'let' constantfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
var left = 0
var right = sortedArray.count - 1
while left < right {
let sum = sortedArray[left] + sortedArray[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
var left = 0
var right = sortedArray.count - 1
while left < right {
let sum = sortedArray[left] + sortedArray[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
return false
}
``` // XCTAssertTrue failedfunc triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count-2 {
let left = i+1
let right = sortedArray.count-1
while left < right {
let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
let sortedArray = l.sorted()
for i in 0..<sortedArray.count-2 {
let left = i+1
let right = sortedArray.count-1
while left < right {
let sum = sortedArray[i] + sortedArray[left] + sortedArray[right]
if sum == 0 {
return true
} else if sum < 0 {
left += 1
} else {
right -= 1
}
}
}
return false
}
```left += 1 // left side of mutating operator isn't mutable: 'left' is a 'let' constantright -= 1 // left side of mutating operator isn't mutable: 'right' is a 'let' constantfunc triplesSumToZero(l: [Int]) -> Bool {
var set = Set(l)
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if set.contains(-(l[i] + l[j])) {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
var set = Set(l)
for i in 0..<l.count {
for j in (i + 1)..<l.count {
if set.contains(-(l[i] + l[j])) {
return true
}
}
}
return false
}
```var set = Set(l) // variable 'set' was never mutated; consider changing to 'let' constantfunc triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count-2 {
for j in (i+1)..<l.count-1 {
for k in (j+1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
triples_sum_to_zero takes an array of integers as an input.
it returns true if there are three distinct elements in the array that
sum to zero, and false otherwise.
triplesSumToZero(l: [1, 3, 5, 0]) == false
triplesSumToZero(l: [1, 3, -2, 1]) == true
triplesSumToZero(l: [1, 2, 3, 7]) == false
triplesSumToZero(l: [2, 4, -5, 3, 9, 7]) == true
triplesSumToZero(l: [1]) == false
Answer:
```swift
func triplesSumToZero(l: [Int]) -> Bool {
for i in 0..<l.count-2 {
for j in (i+1)..<l.count-1 {
for k in (j+1)..<l.count {
if l[i] + l[j] + l[k] == 0 {
return true
}
}
}
}
return false
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if right > left {
right -= 1
}
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if right > left {
right -= 1
}
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if right > left {
right -= 1
}
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if right > left {
right -= 1
}
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if right > left {
right -= 1
}
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if right > left {
right -= 1
}
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
count += 1
}
if left < right {
right -= 1
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
count += 1
}
if left < right {
right -= 1
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
Answer:
```swift
func carRaceCollision(n: Int) -> Int {
var left = 0
var right = n - 1
var count = 0
while left < right {
if left < right {
left += 1
}
if left < right {
right -= 1
}
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return array with elements incremented by 1.
incrList(l: [1, 2, 3]) == [2, 3, 4]
incrList(l: [5, 3, 5, 2, 3, 3, 9, 0, 123]) == [6, 4, 6, 3, 4, 4, 10, 1, 124]
Answer:
```swift
func incrList(l: [Int]) -> [Int] {
return l.map { $0 + 1 }
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
pairs_sum_to_zero takes an array of integers as an input.
it returns true if there are two distinct elements in the array that
sum to zero, and false otherwise.
pairsSumToZero(l: [1, 3, 5, 0]) == false
pairsSumToZero(l: [1, 3, -2, 1]) == false
pairsSumToZero(l: [1, 2, 3, 7]) == false
pairsSumToZero(l: [2, 4, -5, 3, 5, 7]) == true
pairsSumToZero(l: [1]) == false
Answer:
```swift
func pairsSumToZero(l: [Int]) -> Bool {
var set = Set<Int>()
for num in l {
if set.contains(-num) {
return true
}
set.insert(num)
}
return false
}
```func changeBase(x: Int, base: Int) -> String {
var x = x
var result = ""
let digits = "0123456789"
while x > 0 {
result = digits[x % base] + result
x /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var x = x
var result = ""
let digits = "0123456789"
while x > 0 {
result = digits[x % base] + result
x /= base
}
return result
}
```result = digits[x % base] + result // no exact matches in call to subscriptfunc changeBase(x: Int, base: Int) -> String {
var x = x
var result = ""
let digits = "0123456789"
while x > 0 {
result = digits[x % base] + result
x /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var x = x
var result = ""
let digits = "0123456789"
while x > 0 {
result = digits[x % base] + result
x /= base
}
return result
}
```result = digits[x % base] + result // no exact matches in call to subscriptfunc changeBase(x: Int, base: Int) -> String {
let digits = "0123456789"
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = digits[remainder] + result
number /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
let digits = "0123456789"
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = digits[remainder] + result
number /= base
}
return result
}
```result = digits[remainder] + result // no exact matches in call to subscriptfunc changeBase(x: Int, base: Int) -> String {
let digits = "0123456789"
var result = ""
var number = x
while number > 0 {
result = digits[number % base] + result
number /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
let digits = "0123456789"
var result = ""
var number = x
while number > 0 {
result = digits[number % base] + result
number /= base
}
return result
}
```result = digits[number % base] + result // no exact matches in call to subscriptfunc changeBase(x: Int, base: Int) -> String {
var x = x
var result = ""
let digits = "0123456789"
while x > 0 {
result = digits[x % base] + result
x /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var x = x
var result = ""
let digits = "0123456789"
while x > 0 {
result = digits[x % base] + result
x /= base
}
return result
}
```result = digits[x % base] + result // no exact matches in call to subscriptfunc changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = "\(remainder)" + result
number /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = "\(remainder)" + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
changeBase(x: 8, base: 3) == "22"
changeBase(x: 8, base: 2) == "1000"
changeBase(x: 7, base: 2) == "111"
Answer:
```swift
func changeBase(x: Int, base: Int) -> String {
var result = ""
var number = x
while number > 0 {
let remainder = number % base
result = String(remainder) + result
number /= base
}
return result
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given length of a side and high return area for a triangle.
triangleArea(a: 5, h: 3) == 7.5
Answer:
```swift
func triangleArea(a: Int, h: Int) -> Double {
return Double(a * h) / 2
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextElement = result[i - 4] + result[i - 3] + result[i - 2] + result[i - 1]
result.append(nextElement)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextElement = result[i - 4] + result[i - 3] + result[i - 2] + result[i - 1]
result.append(nextElement)
}
return result[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let next = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(next)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let next = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(next)
}
return result[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let next = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(next)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let next = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(next)
}
return result[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let next = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(next)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let next = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(next)
}
return result[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let next = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(next)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let next = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(next)
}
return result[n]
}
```func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
fib4(n: 5) == 4
fib4(n: 6) == 8
fib4(n: 7) == 14
Answer:
```swift
func fib4(n: Int) -> Int {
guard n > 1 else { return 0 }
var result = [0, 0, 2, 0]
for i in 4...n {
let nextValue = result[i - 1] + result[i - 2] + result[i - 3] + result[i - 4]
result.append(nextValue)
}
return result[n]
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middle = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middle - 1] + sorted[middle]) / 2
} else {
return Double(sorted[middle])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middle = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middle - 1] + sorted[middle]) / 2
} else {
return Double(sorted[middle])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let mid = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[mid - 1] + sorted[mid]) / 2
} else {
return Double(sorted[mid])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let mid = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[mid - 1] + sorted[mid]) / 2
} else {
return Double(sorted[mid])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex] + sorted[middleIndex - 1]) / 2
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let middleIndex = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[middleIndex - 1] + sorted[middleIndex]) / 2
} else {
return Double(sorted[middleIndex])
}
}
```func median(l: [Int]) -> Double {
let sorted = l.sorted()
let mid = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[mid - 1] + sorted[mid]) / 2
} else {
return Double(sorted[mid])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return median of elements in the array l.
median(l: [3, 1, 2, 4, 5]) == 3
median(l: [-10, 4, 6, 1000, 10, 20]) == 15.0
Answer:
```swift
func median(l: [Int]) -> Double {
let sorted = l.sorted()
let mid = sorted.count / 2
if sorted.count % 2 == 0 {
return Double(sorted[mid - 1] + sorted[mid]) / 2
} else {
return Double(sorted[mid])
}
}
```func isPalindrome(text: String) -> Bool {
let cleansed = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let length = cleansed.count
if length < 2 {
return true
}
let forward = Array(cleansed)
let backward = Array(cleansed.reversed())
for i in 0..<length {
if forward[i]!= backward[i] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleansed = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let length = cleansed.count
if length < 2 {
return true
}
let forward = Array(cleansed)
let backward = Array(cleansed.reversed())
for i in 0..<length {
if forward[i]!= backward[i] {
return false
}
}
return true
}
```if forward[i]!= backward[i] { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')if forward[i]!= backward[i] { // use of '=' in a boolean context, did you mean '=='?if forward[i]!= backward[i] { // '=' must have consistent whitespace on both sidesfunc isPalindrome(text: String) -> Bool {
let cleansed = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let length = cleansed.count
if length < 2 {
return true
}
let forward = Array(cleansed)
let backward = Array(cleansed.reversed())
for i in 0..<length {
if forward[i]!= backward[i] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleansed = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let length = cleansed.count
if length < 2 {
return true
}
let forward = Array(cleansed)
let backward = Array(cleansed.reversed())
for i in 0..<length {
if forward[i]!= backward[i] {
return false
}
}
return true
}
```if forward[i]!= backward[i] { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')if forward[i]!= backward[i] { // use of '=' in a boolean context, did you mean '=='?if forward[i]!= backward[i] { // '=' must have consistent whitespace on both sidesfunc isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let length = cleanText.count
if length < 2 {
return true
}
let forward = Array(cleanText)
let backward = Array(cleanText.reversed())
for i in 0..<length {
if forward[i]!= backward[i] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let length = cleanText.count
if length < 2 {
return true
}
let forward = Array(cleanText)
let backward = Array(cleanText.reversed())
for i in 0..<length {
if forward[i]!= backward[i] {
return false
}
}
return true
}
```if forward[i]!= backward[i] { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')if forward[i]!= backward[i] { // use of '=' in a boolean context, did you mean '=='?if forward[i]!= backward[i] { // '=' must have consistent whitespace on both sidesfunc isPalindrome(text: String) -> Bool {
let stripped = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let length = stripped.count
if length < 2 {
return true
}
let forward = Array(stripped)
let backward = Array(stripped.reversed())
for i in 0..<length {
if forward[i]!= backward[i] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let stripped = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let length = stripped.count
if length < 2 {
return true
}
let forward = Array(stripped)
let backward = Array(stripped.reversed())
for i in 0..<length {
if forward[i]!= backward[i] {
return false
}
}
return true
}
```if forward[i]!= backward[i] { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')if forward[i]!= backward[i] { // use of '=' in a boolean context, did you mean '=='?if forward[i]!= backward[i] { // '=' must have consistent whitespace on both sidesfunc isPalindrome(text: String) -> Bool {
let cleansed = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversed = String(cleansed.reversed())
return cleansed.lowercased() == reversed.lowercased()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleansed = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversed = String(cleansed.reversed())
return cleansed.lowercased() == reversed.lowercased()
}
```func isPalindrome(text: String) -> Bool {
let stripped = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversed = String(stripped.reversed())
return stripped.lowercased() == reversed.lowercased()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let stripped = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversed = String(stripped.reversed())
return stripped.lowercased() == reversed.lowercased()
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversedText = String(cleanText.reversed())
return cleanText.lowercased() == reversedText.lowercased()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversedText = String(cleanText.reversed())
return cleanText.lowercased() == reversedText.lowercased()
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversedText = String(cleanText.reversed())
return cleanText.lowercased() == reversedText.lowercased()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversedText = String(cleanText.reversed())
return cleanText.lowercased() == reversedText.lowercased()
}
```func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversedText = String(cleanText.reversed())
return cleanText.lowercased() == reversedText.lowercased()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleanText = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversedText = String(cleanText.reversed())
return cleanText.lowercased() == reversedText.lowercased()
}
```func isPalindrome(text: String) -> Bool {
let cleansed = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversed = String(cleansed.reversed())
return cleansed.lowercased() == reversed.lowercased()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Checks if given string is a palindrome
isPalindrome(text: "") == true
isPalindrome(text: "aba") == true
isPalindrome(text: "aaaaa") == true
isPalindrome(text: "zbcd") == false
Answer:
```swift
func isPalindrome(text: String) -> Bool {
let cleansed = text.replacingOccurrences(of: "\\W", with: "", options:.regularExpression, range: nil)
let reversed = String(cleansed.reversed())
return cleansed.lowercased() == reversed.lowercased()
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}
```func modp(n: Int, p: Int) -> Int {
return pow(2, n) % p
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
return pow(2, n) % p
}
```return pow(2, n) % p // cannot convert value of type 'Decimal' to expected argument type 'Int'func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}
```func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return 2^n modulo p (be aware of numerics).
modp(n: 3, p: 5) == 3
modp(n: 1101, p: 101) == 2
modp(n: 0, p: 101) == 1
modp(n: 3, p: 11) == 8
modp(n: 100, p: 101) == 1
Answer:
```swift
func modp(n: Int, p: Int) -> Int {
var result = 1
for _ in 0..<n {
result = (result * 2) % p
}
return result
}
```func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}
```if!vowels.contains(char) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}
```if!vowels.contains(char) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}
```if!vowels.contains(char) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}
```if!vowels.contains(char) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}
```if!vowels.contains(char) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}
```if!vowels.contains(char) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for character in text {
if!vowels.contains(character) {
result.append(character)
}
}
return result
}
```if!vowels.contains(character) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}
```if!vowels.contains(char) { // expected expression, var, or let in 'if' conditionfunc removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
remove_vowels is a function that takes string and returns string without vowels.
removeVowels(text: "") == ""
removeVowels(text: "abcdef") == "bcdf"
removeVowels(text: "aaaaa") == ""
removeVowels(text: "aaBAA") == "B"
removeVowels(text: "zbcd") == "zbcd"
Answer:
```swift
func removeVowels(text: String) -> String {
let vowels = "aeiouAEIOU"
var result = ""
for char in text {
if!vowels.contains(char) {
result.append(char)
}
}
return result
}
```if!vowels.contains(char) { // expected expression, var, or let in 'if' conditionfunc belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
return l.reduce(true) { $0 && $1 < t }
}
```func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true if all numbers in the array l are below threshold t.
belowThreshold(l: [1, 2, 4, 10], t: 100) == true
belowThreshold(l: [1, 20, 4, 10], t: 5) == false
Answer:
```swift
func belowThreshold(l: [Int], t: Int) -> Bool {
for num in l {
if num >= t {
return false
}
}
return true
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func add(x: Int, y: Int) -> Int {
return x + y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Add two numbers x and y
add(x: 2, y: 3) == 5
add(x: 5, y: 7) == 12
Answer:
```swift
func add(x: Int, y: Int) -> Int {
return x + y
}
```func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}
```if s0CharsSet!= s1CharsSet { // cannot force unwrap value of non-optional type 'Set<String.Element>' (aka 'Set<Character>')if s0CharsSet!= s1CharsSet { // use of '=' in a boolean context, did you mean '=='?if s0CharsSet!= s1CharsSet { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // use of '=' in a boolean context, did you mean '=='?if s0CharsCount!= s1CharsCount { // cannot force unwrap value of non-optional type 'Int'if s0CharsCount!= s1CharsCount { // '=' must have consistent whitespace on both sidesfunc sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0Chars.count
let s1CharsCount = s1Chars.count
if s0CharsCount!= s1CharsCount {
return false
}
for i in 0..<s0CharsCount {
if s0Chars[i]!= s1Chars[i] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0Chars.count
let s1CharsCount = s1Chars.count
if s0CharsCount!= s1CharsCount {
return false
}
for i in 0..<s0CharsCount {
if s0Chars[i]!= s1Chars[i] {
return false
}
}
return true
}
```if s0CharsSet!= s1CharsSet { // cannot force unwrap value of non-optional type 'Set<String.Element>' (aka 'Set<Character>')if s0CharsSet!= s1CharsSet { // '=' must have consistent whitespace on both sidesif s0CharsSet!= s1CharsSet { // use of '=' in a boolean context, did you mean '=='?if s0CharsCount!= s1CharsCount { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // cannot force unwrap value of non-optional type 'Int'if s0CharsCount!= s1CharsCount { // use of '=' in a boolean context, did you mean '=='?if s0Chars[i]!= s1Chars[i] { // '=' must have consistent whitespace on both sidesif s0Chars[i]!= s1Chars[i] { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')if s0Chars[i]!= s1Chars[i] { // use of '=' in a boolean context, did you mean '=='?func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}
```if s0CharsSet!= s1CharsSet { // cannot force unwrap value of non-optional type 'Set<String.Element>' (aka 'Set<Character>')if s0CharsSet!= s1CharsSet { // '=' must have consistent whitespace on both sidesif s0CharsSet!= s1CharsSet { // use of '=' in a boolean context, did you mean '=='?if s0CharsCount!= s1CharsCount { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // cannot force unwrap value of non-optional type 'Int'if s0CharsCount!= s1CharsCount { // use of '=' in a boolean context, did you mean '=='?func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}
```if s0CharsSet!= s1CharsSet { // cannot force unwrap value of non-optional type 'Set<String.Element>' (aka 'Set<Character>')if s0CharsSet!= s1CharsSet { // use of '=' in a boolean context, did you mean '=='?if s0CharsSet!= s1CharsSet { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // cannot force unwrap value of non-optional type 'Int'if s0CharsCount!= s1CharsCount { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // use of '=' in a boolean context, did you mean '=='?func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0Chars.count
let s1CharsCount = s1Chars.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0Chars.count
let s1CharsCount = s1Chars.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}
```if s0CharsSet!= s1CharsSet { // cannot force unwrap value of non-optional type 'Set<String.Element>' (aka 'Set<Character>')if s0CharsSet!= s1CharsSet { // '=' must have consistent whitespace on both sidesif s0CharsSet!= s1CharsSet { // use of '=' in a boolean context, did you mean '=='?if s0CharsCount!= s1CharsCount { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // cannot force unwrap value of non-optional type 'Int'if s0CharsCount!= s1CharsCount { // use of '=' in a boolean context, did you mean '=='?func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0Chars.count
let s1CharsCount = s1Chars.count
if s0CharsCount!= s1CharsCount {
return false
}
for i in 0..<s0CharsCount {
if s0Chars[i]!= s1Chars[i] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0Chars.count
let s1CharsCount = s1Chars.count
if s0CharsCount!= s1CharsCount {
return false
}
for i in 0..<s0CharsCount {
if s0Chars[i]!= s1Chars[i] {
return false
}
}
return true
}
```if s0CharsSet!= s1CharsSet { // cannot force unwrap value of non-optional type 'Set<String.Element>' (aka 'Set<Character>')if s0CharsSet!= s1CharsSet { // '=' must have consistent whitespace on both sidesif s0CharsSet!= s1CharsSet { // use of '=' in a boolean context, did you mean '=='?if s0CharsCount!= s1CharsCount { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // cannot force unwrap value of non-optional type 'Int'if s0CharsCount!= s1CharsCount { // use of '=' in a boolean context, did you mean '=='?if s0Chars[i]!= s1Chars[i] { // '=' must have consistent whitespace on both sidesif s0Chars[i]!= s1Chars[i] { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')if s0Chars[i]!= s1Chars[i] { // use of '=' in a boolean context, did you mean '=='?func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0.lowercased())
let s1Chars = Array(s1.lowercased())
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0.lowercased())
let s1Chars = Array(s1.lowercased())
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}
```if s0CharsSet!= s1CharsSet { // cannot force unwrap value of non-optional type 'Set<String.Element>' (aka 'Set<Character>')if s0CharsSet!= s1CharsSet { // use of '=' in a boolean context, did you mean '=='?if s0CharsSet!= s1CharsSet { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // use of '=' in a boolean context, did you mean '=='?if s0CharsCount!= s1CharsCount { // cannot force unwrap value of non-optional type 'Int'if s0CharsCount!= s1CharsCount { // '=' must have consistent whitespace on both sidesfunc sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0.count
let s1CharsCount = s1.count
if s0CharsCount!= s1CharsCount {
return false
}
return true
}
```if s0CharsSet!= s1CharsSet { // cannot force unwrap value of non-optional type 'Set<String.Element>' (aka 'Set<Character>')if s0CharsSet!= s1CharsSet { // '=' must have consistent whitespace on both sidesif s0CharsSet!= s1CharsSet { // use of '=' in a boolean context, did you mean '=='?if s0CharsCount!= s1CharsCount { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // cannot force unwrap value of non-optional type 'Int'if s0CharsCount!= s1CharsCount { // use of '=' in a boolean context, did you mean '=='?func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0Chars.count
let s1CharsCount = s1Chars.count
if s0CharsCount!= s1CharsCount {
return false
}
for i in 0..<s0CharsCount {
if s0Chars[i]!= s1Chars[i] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet!= s1CharsSet {
return false
}
let s0CharsCount = s0Chars.count
let s1CharsCount = s1Chars.count
if s0CharsCount!= s1CharsCount {
return false
}
for i in 0..<s0CharsCount {
if s0Chars[i]!= s1Chars[i] {
return false
}
}
return true
}
```if s0CharsSet!= s1CharsSet { // cannot force unwrap value of non-optional type 'Set<String.Element>' (aka 'Set<Character>')if s0CharsSet!= s1CharsSet { // '=' must have consistent whitespace on both sidesif s0CharsSet!= s1CharsSet { // use of '=' in a boolean context, did you mean '=='?if s0CharsCount!= s1CharsCount { // '=' must have consistent whitespace on both sidesif s0CharsCount!= s1CharsCount { // cannot force unwrap value of non-optional type 'Int'if s0CharsCount!= s1CharsCount { // use of '=' in a boolean context, did you mean '=='?if s0Chars[i]!= s1Chars[i] { // '=' must have consistent whitespace on both sidesif s0Chars[i]!= s1Chars[i] { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')if s0Chars[i]!= s1Chars[i] { // use of '=' in a boolean context, did you mean '=='?func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet == s1CharsSet {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Check if two words have the same characters.
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddeddabc") == true
sameChars(s0: "abcd", s1: "dddddddabc") == true
sameChars(s0: "dddddddabc", s1: "abcd") == true
sameChars(s0: "eabcd", s1: "dddddddabc") == false
sameChars(s0: "abcd", s1: "dddddddabce") == false
sameChars(s0: "eabcdzzzz", s1: "dddzzzzzzzddddabc") == false
Answer:
```swift
func sameChars(s0: String, s1: String) -> Bool {
let s0Chars = Array(s0)
let s1Chars = Array(s1)
let s0CharsSet = Set(s0Chars)
let s1CharsSet = Set(s1Chars)
if s0CharsSet == s1CharsSet {
return true
}
return false
}
```func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}
```func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
if n == 1 || n == 2 { return 1 }
return fib(n: n - 1) + fib(n: n - 2)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
if n == 1 || n == 2 { return 1 }
return fib(n: n - 1) + fib(n: n - 2)
}
```func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}
```func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}
```func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}
```func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
if n == 1 || n == 2 { return 1 }
return fib(n: n - 1) + fib(n: n - 2)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
if n == 1 || n == 2 { return 1 }
return fib(n: n - 1) + fib(n: n - 2)
}
```func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}
```func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}
```func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
if n <= 1 {
return n
}
var a = 0
var b = 1
for _ in 2...n {
let c = a + b
a = b
b = c
}
return b
}
```func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
if n == 1 || n == 2 { return 1 }
return fib(n: n - 1) + fib(n: n - 2)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return n-th Fibonacci number.
fib(n: 10) == 55
fib(n: 1) == 1
fib(n: 8) == 21
Answer:
```swift
func fib(n: Int) -> Int {
guard n > 0 else { return 0 }
if n == 1 || n == 2 { return 1 }
return fib(n: n - 1) + fib(n: n - 2)
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty || stack.last!= "<" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty || stack.last!= "<" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "<" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "<" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "<" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "<" { // cannot convert value of type 'Character' to expected argument type 'Bool'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty || stack.last!= "<" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty || stack.last!= "<" {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```if stack.isEmpty || stack.last!= "<" { // use of '=' in a boolean context, did you mean '=='?if stack.isEmpty || stack.last!= "<" { // '=' must have consistent whitespace on both sidesif stack.isEmpty || stack.last!= "<" { // expression is not assignable: '||' returns immutable valueif stack.isEmpty || stack.last!= "<" { // cannot convert value of type 'Character' to expected argument type 'Bool'func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for bracket in brackets {
if bracket == "<" {
stack.append(bracket)
} else if bracket == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "<" and ">".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "<") == false
correctBracketing(brackets: "<>") == true
correctBracketing(brackets: "<<><>>") == true
correctBracketing(brackets: "><<>") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "<" {
stack.append(char)
} else if char == ">" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count - 1 {
if l[i] > l[i + 1] {
increasing = false
}
if l[i] < l[i + 1] {
decreasing = false
}
}
return increasing || decreasing
}
```func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return true is array elements are monotonically increasing or decreasing.
monotonic(l: [1, 2, 4, 20]) == true
monotonic(l: [1, 20, 4, 10]) == false
monotonic(l: [4, 1, 0, -10]) == true
Answer:
```swift
func monotonic(l: [Int]) -> Bool {
var increasing = true
var decreasing = true
for i in 0..<l.count-1 {
if l[i] > l[i+1] {
increasing = false
}
if l[i] < l[i+1] {
decreasing = false
}
}
return increasing || decreasing
}
```func common(l1: [Int], l2: [Int]) -> [Int] {
var set = Set(l1)
set.intersect(l2)
return Array(set).sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var set = Set(l1)
set.intersect(l2)
return Array(set).sorted()
}
```set.intersect(l2) // value of type 'Set<Int>' has no member 'intersect'func common(l1: [Int], l2: [Int]) -> [Int] {
var set = Set(l1)
set.intersection(l2)
return Array(set).sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var set = Set(l1)
set.intersection(l2)
return Array(set).sorted()
}
```var set = Set(l1) // variable 'set' was never mutated; consider changing to 'let' constantset.intersection(l2) // result of call to 'intersection' is unused // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
var l1 = l1
var l2 = l2
l1.sort()
l2.sort()
var result: [Int] = []
var i = 0
var j = 0
while i < l1.count && j < l2.count {
if l1[i] < l2[j] {
i += 1
} else if l1[i] > l2[j] {
j += 1
} else {
result.append(l1[i])
i += 1
j += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var l1 = l1
var l2 = l2
l1.sort()
l2.sort()
var result: [Int] = []
var i = 0
var j = 0
while i < l1.count && j < l2.count {
if l1[i] < l2[j] {
i += 1
} else if l1[i] > l2[j] {
j += 1
} else {
result.append(l1[i])
i += 1
j += 1
}
}
return result
}
```func common(l1: [Int], l2: [Int]) -> [Int] {
let set1 = Set(l1)
let set2 = Set(l2)
return set1.intersection(set2).sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let set1 = Set(l1)
let set2 = Set(l2)
return set1.intersection(set2).sorted()
}
```func common(l1: [Int], l2: [Int]) -> [Int] {
var set = Set(l1)
set.intersection(l2)
return Array(set).sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var set = Set(l1)
set.intersection(l2)
return Array(set).sorted()
}
```var set = Set(l1) // variable 'set' was never mutated; consider changing to 'let' constantset.intersection(l2) // result of call to 'intersection' is unused // XCTAssertTrue failedfunc common(l1: [Int], l2: [Int]) -> [Int] {
let set1 = Set(l1)
let set2 = Set(l2)
let common = set1.intersection(set2)
return Array(common).sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let set1 = Set(l1)
let set2 = Set(l2)
let common = set1.intersection(set2)
return Array(common).sorted()
}
```func common(l1: [Int], l2: [Int]) -> [Int] {
var l1 = l1
var l2 = l2
l1.sort()
l2.sort()
var result: [Int] = []
var i = 0
var j = 0
while i < l1.count && j < l2.count {
if l1[i] == l2[j] {
result.append(l1[i])
i += 1
j += 1
} else if l1[i] < l2[j] {
i += 1
} else {
j += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var l1 = l1
var l2 = l2
l1.sort()
l2.sort()
var result: [Int] = []
var i = 0
var j = 0
while i < l1.count && j < l2.count {
if l1[i] == l2[j] {
result.append(l1[i])
i += 1
j += 1
} else if l1[i] < l2[j] {
i += 1
} else {
j += 1
}
}
return result
}
```func common(l1: [Int], l2: [Int]) -> [Int] {
var l1 = l1
var l2 = l2
l1.sort()
l2.sort()
var result: [Int] = []
var i = 0
var j = 0
while i < l1.count && j < l2.count {
if l1[i] == l2[j] {
result.append(l1[i])
i += 1
j += 1
} else if l1[i] < l2[j] {
i += 1
} else {
j += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
var l1 = l1
var l2 = l2
l1.sort()
l2.sort()
var result: [Int] = []
var i = 0
var j = 0
while i < l1.count && j < l2.count {
if l1[i] == l2[j] {
result.append(l1[i])
i += 1
j += 1
} else if l1[i] < l2[j] {
i += 1
} else {
j += 1
}
}
return result
}
```func common(l1: [Int], l2: [Int]) -> [Int] {
let set1 = Set(l1)
let set2 = Set(l2)
let common = set1.intersection(set2)
return Array(common).sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let set1 = Set(l1)
let set2 = Set(l2)
let common = set1.intersection(set2)
return Array(common).sorted()
}
```func common(l1: [Int], l2: [Int]) -> [Int] {
let set1 = Set(l1)
let set2 = Set(l2)
let common = set1.intersection(set2)
return Array(common).sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return sorted unique common elements for two arrays.
common(l1: [1, 4, 3, 34, 653, 2, 5], l2: [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
common(l1: [5, 3, 2, 8], l2: [3, 2]) == [2, 3]
Answer:
```swift
func common(l1: [Int], l2: [Int]) -> [Int] {
let set1 = Set(l1)
let set2 = Set(l2)
let common = set1.intersection(set2)
return Array(common).sorted()
}
```func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while n % factor!= 0 {
factor += 1
}
return factor
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while n % factor!= 0 {
factor += 1
}
return factor
}
```while n % factor!= 0 { // cannot force unwrap value of non-optional type 'Int'while n % factor!= 0 { // '=' must have consistent whitespace on both sideswhile n % factor!= 0 { // use of '=' in a boolean context, did you mean '=='?func largestPrimeFactor(n: Int) -> Int {
var factor = 2
var number = n
while number > 1 {
while number % factor == 0 {
number /= factor
}
factor += 1
}
return factor - 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var factor = 2
var number = n
while number > 1 {
while number % factor == 0 {
number /= factor
}
factor += 1
}
return factor - 1
}
```func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestFactor = 1
for i in 2..<n {
while number % i == 0 {
number /= i
largestFactor = i
}
}
return largestFactor
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestFactor = 1
for i in 2..<n {
while number % i == 0 {
number /= i
largestFactor = i
}
}
return largestFactor
}
```func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}
```func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}
```func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}
```func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}
```func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var factor = 2
while factor * factor <= n {
if n % factor == 0 {
return largestPrimeFactor(n: n / factor)
}
factor += 1
}
return n
}
```func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestFactor = 1
for i in 2..<n {
while number % i == 0 {
number /= i
largestFactor = i
}
}
return largestFactor
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var number = n
var largestFactor = 1
for i in 2..<n {
while number % i == 0 {
number /= i
largestFactor = i
}
}
return largestFactor
}
```func largestPrimeFactor(n: Int) -> Int {
var factor = 2
var number = n
while number > 1 {
while number % factor == 0 {
number /= factor
}
factor += 1
}
return factor - 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Return the largest prime factor of n. Assume n > 1 and is not a prime.
largestPrimeFactor(n: 13195) == 29
largestPrimeFactor(n: 2048) == 2
Answer:
```swift
func largestPrimeFactor(n: Int) -> Int {
var factor = 2
var number = n
while number > 1 {
while number % factor == 0 {
number /= factor
}
factor += 1
}
return factor - 1
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
sum_to_n is a function that sums numbers from 1 to n.
sumToN(n: 30) == 465
sumToN(n: 100) == 5050
sumToN(n: 5) == 15
sumToN(n: 10) == 55
sumToN(n: 1) == 1
Answer:
```swift
func sumToN(n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
brackets is a string of "(" and ")".
return true if every opening bracket has a corresponding closing bracket.
correctBracketing(brackets: "(") == false
correctBracketing(brackets: "()") == true
correctBracketing(brackets: "(()())") == true
correctBracketing(brackets: ")(()") == false
Answer:
```swift
func correctBracketing(brackets: String) -> Bool {
var stack = [Character]()
for char in brackets {
if char == "(" {
stack.append(char)
} else if char == ")" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs, stride(from: xs.count - 1, through: 1, by: -1)).map { $0 * $1 })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs, stride(from: xs.count - 1, through: 1, by: -1)).map { $0 * $1 })
}
``` // XCTAssertTrue failedfunc derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
var result = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
result[i - 1] = i * xs[i]
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
var result = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
result[i - 1] = i * xs[i]
}
return result
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
var result = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
result[i - 1] = i * xs[i]
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
var result = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
result[i - 1] = i * xs[i]
}
return result
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
var result = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
result[i - 1] = i * xs[i]
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
var result = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
result[i - 1] = i * xs[i]
}
return result
}
```func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for (index, value) in xs.enumerated() {
if index == 0 {
continue
}
result.append(value * index)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
var result = [Int]()
for (index, value) in xs.enumerated() {
if index == 0 {
continue
}
result.append(value * index)
}
return result
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs, stride(from: xs.count - 1, to: 1, by: -1)).map { $0 * $1 })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs, stride(from: xs.count - 1, to: 1, by: -1)).map { $0 * $1 })
}
``` // XCTAssertTrue failedfunc derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
var result = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
result[i - 1] = i * xs[i]
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
var result = [Int](repeating: 0, count: xs.count - 1)
for i in 1..<xs.count {
result[i - 1] = i * xs[i]
}
return result
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs.dropFirst(), xs.indices.dropFirst()).map { $0 * $1 })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs.dropFirst(), xs.indices.dropFirst()).map { $0 * $1 })
}
```func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs, stride(from: xs.count - 1, through: 1, by: -1)).map { $0 * $1 })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs, stride(from: xs.count - 1, through: 1, by: -1)).map { $0 * $1 })
}
``` // XCTAssertTrue failedfunc derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs.dropFirst(), xs.indices.dropFirst()).map { $0 * $1 })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 +....
Return derivative of this polynomial in the same form.
derivative(xs: [3, 1, 2, 4, 5]) == [1, 4, 12, 20]
derivative(xs: [1, 2, 3]) == [2, 6]
Answer:
```swift
func derivative(xs: [Int]) -> [Int] {
guard xs.count > 1 else { return [] }
return Array(zip(xs.dropFirst(), xs.indices.dropFirst()).map { $0 * $1 })
}
```func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 {
return memo[n]
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 {
return memo[n]
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}
```if memo[n]!= 0 { // cannot force unwrap value of non-optional type 'Int'if memo[n]!= 0 { // use of '=' in a boolean context, did you mean '=='?if memo[n]!= 0 { // '=' must have consistent whitespace on both sidesfunc fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 {
return memo[n]
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 {
return memo[n]
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}
```if memo[n]!= 0 { // '=' must have consistent whitespace on both sidesif memo[n]!= 0 { // cannot force unwrap value of non-optional type 'Int'if memo[n]!= 0 { // use of '=' in a boolean context, did you mean '=='?func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 {
return memo[n]
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 {
return memo[n]
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}
```if memo[n]!= 0 { // cannot force unwrap value of non-optional type 'Int'if memo[n]!= 0 { // use of '=' in a boolean context, did you mean '=='?if memo[n]!= 0 { // '=' must have consistent whitespace on both sidesfunc fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = Array(repeating: -1, count: n)
memo[0] = 0
memo[1] = 0
return fibfibHelper(n, &memo)
}
func fibfibHelper(_ n: Int, _ memo: inout [Int]) -> Int {
if memo[n]!= -1 { return memo[n] }
let result = fibfibHelper(n-1, &memo) + fibfibHelper(n-2, &memo) + fibfibHelper(n-3, &memo)
memo[n] = result
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = Array(repeating: -1, count: n)
memo[0] = 0
memo[1] = 0
return fibfibHelper(n, &memo)
}
func fibfibHelper(_ n: Int, _ memo: inout [Int]) -> Int {
if memo[n]!= -1 { return memo[n] }
let result = fibfibHelper(n-1, &memo) + fibfibHelper(n-2, &memo) + fibfibHelper(n-3, &memo)
memo[n] = result
return result
}
```if memo[n]!= -1 { return memo[n] } // '=' must have consistent whitespace on both sidesif memo[n]!= -1 { return memo[n] } // cannot force unwrap value of non-optional type 'Int'if memo[n]!= -1 { return memo[n] } // use of '=' in a boolean context, did you mean '=='?func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 { return memo[n] }
memo[n] = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
return memo[n]
}
return calculateFibFib(n)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 { return memo[n] }
memo[n] = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
return memo[n]
}
return calculateFibFib(n)
}
```if memo[n]!= 0 { return memo[n] } // '=' must have consistent whitespace on both sidesif memo[n]!= 0 { return memo[n] } // cannot force unwrap value of non-optional type 'Int'if memo[n]!= 0 { return memo[n] } // use of '=' in a boolean context, did you mean '=='?func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 { return memo[n] }
memo[n] = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
return memo[n]
}
return calculateFibFib(n)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 { return memo[n] }
memo[n] = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
return memo[n]
}
return calculateFibFib(n)
}
```if memo[n]!= 0 { return memo[n] } // '=' must have consistent whitespace on both sidesif memo[n]!= 0 { return memo[n] } // cannot force unwrap value of non-optional type 'Int'if memo[n]!= 0 { return memo[n] } // use of '=' in a boolean context, did you mean '=='?func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [Int: Int]()
memo[0] = 0
memo[1] = 0
memo[2] = 1
func calculateFibFib(_ n: Int) -> Int {
if let result = memo[n] {
return result
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [Int: Int]()
memo[0] = 0
memo[1] = 0
memo[2] = 1
func calculateFibFib(_ n: Int) -> Int {
if let result = memo[n] {
return result
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}
```func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [Int: Int]()
memo[0] = 0
memo[1] = 0
memo[2] = 1
func calculateFibFib(_ n: Int) -> Int {
if let value = memo[n] {
return value
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [Int: Int]()
memo[0] = 0
memo[1] = 0
memo[2] = 1
func calculateFibFib(_ n: Int) -> Int {
if let value = memo[n] {
return value
}
let result = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
memo[n] = result
return result
}
return calculateFibFib(n)
}
```func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 {
return memo[n]
}
memo[n] = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
return memo[n]
}
return calculateFibFib(n)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func calculateFibFib(_ n: Int) -> Int {
if memo[n]!= 0 {
return memo[n]
}
memo[n] = calculateFibFib(n - 1) + calculateFibFib(n - 2) + calculateFibFib(n - 3)
return memo[n]
}
return calculateFibFib(n)
}
```if memo[n]!= 0 { // cannot force unwrap value of non-optional type 'Int'if memo[n]!= 0 { // use of '=' in a boolean context, did you mean '=='?if memo[n]!= 0 { // '=' must have consistent whitespace on both sidesfunc fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func fibfib(_ n: Int) -> Int {
if memo.count > n {
return memo[n]
}
let result = fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)
memo.append(result)
return result
}
return fibfib(n)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
fibfib(n: 1) == 0
fibfib(n: 5) == 4
fibfib(n: 8) == 24
Answer:
```swift
func fibfib(n: Int) -> Int {
guard n > 1 else { return 0 }
var memo = [0, 0, 1]
func fibfib(_ n: Int) -> Int {
if memo.count > n {
return memo[n]
}
let result = fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)
memo.append(result)
return result
}
return fibfib(n)
}
```func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s.lowercased() {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s.lowercased() {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s.lowercased() {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s.lowercased() {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.hasSuffix("y") && vowels.contains(s.last!) {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s.lowercased() {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s.lowercased() {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s.lowercased() {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
vowelsCount(s: "abcde") == 2
vowelsCount(s: "ACEDY") == 3
Answer:
```swift
func vowelsCount(s: String) -> Int {
let vowels: Set<Character> = ["a", "e", "i", "o", "u", "y"]
var count = 0
for char in s.lowercased() {
if vowels.contains(char) {
count += 1
}
}
if s.lowercased().hasSuffix("y") {
count += 1
}
return count
}
``` // XCTAssertTrue failedfunc circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifts = shift % digits.count
let result = reversed.suffix(digits.count - shifts) + reversed.prefix(digits.count - shifts)
return String(result)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifts = shift % digits.count
let result = reversed.suffix(digits.count - shifts) + reversed.prefix(digits.count - shifts)
return String(result)
}
```return String(result) // no exact matches in call to initializerfunc circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted)
}
```let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expected expressionlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expression of type 'ReversedCollection<[String]>' is unusedlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // cannot use optional chaining on non-optional value of type 'Int'func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted)
}
```let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expected expressionlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expression of type 'ReversedCollection<[String]>' is unusedlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // cannot use optional chaining on non-optional value of type 'Int'func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { Int(String($0))! }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted.map { String($0) })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { Int(String($0))! }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted.map { String($0) })
}
```let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expected expressionlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expression of type 'ReversedCollection<[Int]>' is unusedlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // cannot use optional chaining on non-optional value of type 'Int'func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = reversed.dropFirst(shift).append(reversed.prefix(shift))
return String(shifted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = reversed.dropFirst(shift).append(reversed.prefix(shift))
return String(shifted)
}
```let shifted = reversed.dropFirst(shift).append(reversed.prefix(shift)) // value of type 'DropFirstSequence<ReversedCollection<[String]>>' has no member 'append'func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted)
}
```let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expected expressionlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expression of type 'ReversedCollection<[String]>' is unusedlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // cannot use optional chaining on non-optional value of type 'Int'func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifts = shift % digits.count
let result = reversed.suffix(digits.count - shifts) + reversed.prefix(digits.count - shifts)
return String(result)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifts = shift % digits.count
let result = reversed.suffix(digits.count - shifts) + reversed.prefix(digits.count - shifts)
return String(result)
}
```return String(result) // no exact matches in call to initializerfunc circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift])
return String(shifted)
}
```let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expected expressionlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // expression of type 'ReversedCollection<[String]>' is unusedlet shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift >= digits.count? reversed : Array(reversed[shift..<digits.count] + reversed[0..<shift]) // cannot use optional chaining on non-optional value of type 'Int'func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { Int(String($0))! }
let reversed = digits.reversed()
let shifted = shift > digits.count? reversed : Array(reversed[shift..<reversed.count] + reversed[0..<shift])
return String(shifted.map { String($0) })
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { Int(String($0))! }
let reversed = digits.reversed()
let shifted = shift > digits.count? reversed : Array(reversed[shift..<reversed.count] + reversed[0..<shift])
return String(shifted.map { String($0) })
}
```let shifted = shift > digits.count? reversed : Array(reversed[shift..<reversed.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift > digits.count? reversed : Array(reversed[shift..<reversed.count] + reversed[0..<shift]) // consecutive statements on a line must be separated by ';'let shifted = shift > digits.count? reversed : Array(reversed[shift..<reversed.count] + reversed[0..<shift]) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let shifted = shift > digits.count? reversed : Array(reversed[shift..<reversed.count] + reversed[0..<shift]) // expected expressionlet shifted = shift > digits.count? reversed : Array(reversed[shift..<reversed.count] + reversed[0..<shift]) // expression of type 'ReversedCollection<[Int]>' is unusedlet shifted = shift > digits.count? reversed : Array(reversed[shift..<reversed.count] + reversed[0..<shift]) // cannot use optional chaining on non-optional value of type 'Int'func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = Array(reversed[shift..<reversed.count] + reversed[0..<shift])
let result = String(shifted.joined())
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
circularShift(x: 12, shift: 1) == "21"
circularShift(x: 12, shift: 2) == "12"
Answer:
```swift
func circularShift(x: Int, shift: Int) -> String {
let digits = String(x).map { String($0) }
let reversed = digits.reversed()
let shifted = Array(reversed[shift..<reversed.count] + reversed[0..<shift])
let result = String(shifted.joined())
return result
}
```let shifted = Array(reversed[shift..<reversed.count] + reversed[0..<shift]) // no exact matches in call to subscriptlet shifted = Array(reversed[shift..<reversed.count] + reversed[0..<shift]) // binary operator '+' cannot be applied to two 'String' operandslet shifted = Array(reversed[shift..<reversed.count] + reversed[0..<shift]) // no exact matches in call to subscriptfunc digitSum(s: String) -> Int {
let upperCased = s.filter { $0.isUppercase }
let asciiValues = upperCased.map { $0.asciiValue! }
return asciiValues.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
let upperCased = s.filter { $0.isUppercase }
let asciiValues = upperCased.map { $0.asciiValue! }
return asciiValues.reduce(0, +)
}
```return asciiValues.reduce(0, +) // cannot convert value of type '(Int) -> Int' to expected argument type '(Int, UInt8) throws -> Int'func digitSum(s: String) -> Int {
return s.unicodeScalars.filter { $0.isASCII && $0.isUppercase }.reduce(0) { $0 + $1.value }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
return s.unicodeScalars.filter { $0.isASCII && $0.isUppercase }.reduce(0) { $0 + $1.value }
}
```return s.unicodeScalars.filter { $0.isASCII && $0.isUppercase }.reduce(0) { $0 + $1.value } // cannot convert return expression of type 'UInt32' to return type 'Int'return s.unicodeScalars.filter { $0.isASCII && $0.isUppercase }.reduce(0) { $0 + $1.value } // trailing closure passed to parameter of type 'Predicate<String.UnicodeScalarView.Element>' (aka 'Predicate<Unicode.Scalar>') that does not accept a closurefunc digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}
```func digitSum(s: String) -> Int {
return s.filter { $0.isUppercase }.reduce(0) { $0 + Int($1.asciiValue!) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
return s.filter { $0.isUppercase }.reduce(0) { $0 + Int($1.asciiValue!) }
}
```func digitSum(s: String) -> Int {
let upperCaseLetters = s.filter { $0.isUppercase }
let asciiValues = upperCaseLetters.map { Int($0.asciiValue!) }
let sum = asciiValues.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
let upperCaseLetters = s.filter { $0.isUppercase }
let asciiValues = upperCaseLetters.map { Int($0.asciiValue!) }
let sum = asciiValues.reduce(0, +)
return sum
}
```func digitSum(s: String) -> Int {
let upperCaseLetters = s.filter { $0.isUppercase }
let asciiValues = upperCaseLetters.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
let upperCaseLetters = s.filter { $0.isUppercase }
let asciiValues = upperCaseLetters.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}
```func digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}
```func digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
let sum = asciiValues.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
let sum = asciiValues.reduce(0, +)
return sum
}
```func digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}
```func digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum(s: "") == 0
digitSum(s: "abAB") == 131
digitSum(s: "abcCd") == 67
digitSum(s: "helloE") == 69
digitSum(s: "woArBld") == 131
digitSum(s: "aAaaaXa") == 153
Answer:
```swift
func digitSum(s: String) -> Int {
let upperCaseChars = s.filter { $0.isUppercase }
let asciiValues = upperCaseChars.map { Int($0.asciiValue!) }
return asciiValues.reduce(0, +)
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = Int(apples)! + Int(oranges)!
let mangoes = n - totalFruits
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = Int(apples)! + Int(oranges)!
let mangoes = n - totalFruits
return mangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].components(separatedBy: " ")[0].replacingOccurrences(of: "apples", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let oranges = fruits[1].components(separatedBy: " ")[0].replacingOccurrences(of: "oranges", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let totalFruits = n
let mangoes = totalFruits - Int(apples)! - Int(oranges)!
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].components(separatedBy: " ")[0].replacingOccurrences(of: "apples", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let oranges = fruits[1].components(separatedBy: " ")[0].replacingOccurrences(of: "oranges", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let totalFruits = n
let mangoes = totalFruits - Int(apples)! - Int(oranges)!
return mangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = n - Int(apples)! - Int(oranges)!
return totalFruits
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = n - Int(apples)! - Int(oranges)!
return totalFruits
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = n
let mangoes = totalFruits - (Int(apples)! + Int(oranges)!)
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = n
let mangoes = totalFruits - (Int(apples)! + Int(oranges)!)
return mangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = n
let totalApples = Int(apples)!
let totalOranges = Int(oranges)!
let totalMangoes = totalFruits - (totalApples + totalOranges)
return totalMangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = n
let totalApples = Int(apples)!
let totalOranges = Int(oranges)!
let totalMangoes = totalFruits - (totalApples + totalOranges)
return totalMangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].components(separatedBy: " ")[0].replacingOccurrences(of: "apples", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let oranges = fruits[1].components(separatedBy: " ")[0].replacingOccurrences(of: "oranges", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
return n - (Int(apples)! + Int(oranges)!)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].components(separatedBy: " ")[0].replacingOccurrences(of: "apples", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let oranges = fruits[1].components(separatedBy: " ")[0].replacingOccurrences(of: "oranges", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
return n - (Int(apples)! + Int(oranges)!)
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].components(separatedBy: " ")[0].replacingOccurrences(of: "apples", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let oranges = fruits[1].components(separatedBy: " ")[0].replacingOccurrences(of: "oranges", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let totalFruits = n
let mangoes = totalFruits - (Int(apples)! + Int(oranges)!)
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].components(separatedBy: " ")[0].replacingOccurrences(of: "apples", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let oranges = fruits[1].components(separatedBy: " ")[0].replacingOccurrences(of: "oranges", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let totalFruits = n
let mangoes = totalFruits - (Int(apples)! + Int(oranges)!)
return mangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = n
let mangoes = totalFruits - (Int(apples)! + Int(oranges)!)
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = n
let mangoes = totalFruits - (Int(apples)! + Int(oranges)!)
return mangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = Int(apples)! + Int(oranges)!
let mangoes = n - totalFruits
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].replacingOccurrences(of: " apples", with: "").trimmingCharacters(in:.whitespaces)
let oranges = fruits[1].replacingOccurrences(of: " oranges", with: "").trimmingCharacters(in:.whitespaces)
let totalFruits = Int(apples)! + Int(oranges)!
let mangoes = n - totalFruits
return mangoes
}
```func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].components(separatedBy: " ")[0].replacingOccurrences(of: "apples", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let oranges = fruits[1].components(separatedBy: " ")[0].replacingOccurrences(of: "oranges", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let totalFruits = n
let mangoes = totalFruits - Int(apples)! - Int(oranges)!
return mangoes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruitDistribution(s: "5 apples and 6 oranges", n: 19) == 8
fruitDistribution(s: "0 apples and 1 oranges", n: 3) == 2
fruitDistribution(s: "2 apples and 3 oranges", n: 100) == 95
fruitDistribution(s: "100 apples and 1 oranges", n: 120) == 19
Answer:
```swift
func fruitDistribution(s: String, n: Int) -> Int {
let fruits = s.components(separatedBy: " and ")
let apples = fruits[0].components(separatedBy: " ")[0].replacingOccurrences(of: "apples", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let oranges = fruits[1].components(separatedBy: " ")[0].replacingOccurrences(of: "oranges", with: "").trimmingCharacters(in:.whitespacesAndNewlines)
let totalFruits = n
let mangoes = totalFruits - Int(apples)! - Int(oranges)!
return mangoes
}
```func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
var minEven: (value: Int, index: Int)?
for (index, value) in arr.enumerated() {
if value % 2 == 0 {
if minEven == nil || value < minEven!.value || (value == minEven!.value && index < minEven!.index) {
minEven = (value, index)
}
}
}
return minEven.map { [$0.value, $0.index] }?? []
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
var minEven: (value: Int, index: Int)?
for (index, value) in arr.enumerated() {
if value % 2 == 0 {
if minEven == nil || value < minEven!.value || (value == minEven!.value && index < minEven!.index) {
minEven = (value, index)
}
}
}
return minEven.map { [$0.value, $0.index] }?? []
}
```guard!arr.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionreturn minEven.map { [$0.value, $0.index] }?? [] // cannot use optional chaining on non-optional value of type '[_]'return minEven.map { [$0.value, $0.index] }?? [] // missing argument for parameter #1 in subscriptfunc pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}
```guard!arr.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionguard!evenNumbers.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionfunc pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}
```guard!arr.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionguard!evenNumbers.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionfunc pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}
```guard!arr.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionguard!evenNumbers.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionfunc pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}
```guard!arr.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionguard!evenNumbers.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionfunc pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard!evenNumbers.isEmpty else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let index = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, index]
}
```guard!arr.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionguard!evenNumbers.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionfunc pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
var minEven: (value: Int, index: Int)?
for (index, value) in arr.enumerated() {
if value % 2 == 0, (minEven == nil || value < minEven!.value || (value == minEven!.value && index < minEven!.index)) {
minEven = (value, index)
}
}
return minEven.map { [$0.value, $0.index] }?? []
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
var minEven: (value: Int, index: Int)?
for (index, value) in arr.enumerated() {
if value % 2 == 0, (minEven == nil || value < minEven!.value || (value == minEven!.value && index < minEven!.index)) {
minEven = (value, index)
}
}
return minEven.map { [$0.value, $0.index] }?? []
}
```guard!arr.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionreturn minEven.map { [$0.value, $0.index] }?? [] // missing argument for parameter #1 in subscriptreturn minEven.map { [$0.value, $0.index] }?? [] // cannot use optional chaining on non-optional value of type '[_]'func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
var minEven: (value: Int, index: Int)?
for (index, value) in arr.enumerated() {
if value % 2 == 0, (minEven == nil || value < minEven!.value || (value == minEven!.value && index < minEven!.index)) {
minEven = (value, index)
}
}
return minEven.map { [$0.value, $0.index] }?? []
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard!arr.isEmpty else { return [] }
var minEven: (value: Int, index: Int)?
for (index, value) in arr.enumerated() {
if value % 2 == 0, (minEven == nil || value < minEven!.value || (value == minEven!.value && index < minEven!.index)) {
minEven = (value, index)
}
}
return minEven.map { [$0.value, $0.index] }?? []
}
```guard!arr.isEmpty else { return [] } // expected expression, var, let or case in 'guard' conditionreturn minEven.map { [$0.value, $0.index] }?? [] // missing argument for parameter #1 in subscriptreturn minEven.map { [$0.value, $0.index] }?? [] // cannot use optional chaining on non-optional value of type '[_]'func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else { return [] }
var evenValues = arr.filter { $0 % 2 == 0 }
if evenValues.isEmpty { return [] }
let smallestEvenValue = evenValues.min()!
let index = arr.firstIndex(of: smallestEvenValue)!
return [smallestEvenValue, index]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else { return [] }
var evenValues = arr.filter { $0 % 2 == 0 }
if evenValues.isEmpty { return [] }
let smallestEvenValue = evenValues.min()!
let index = arr.firstIndex(of: smallestEvenValue)!
return [smallestEvenValue, index]
}
```var evenValues = arr.filter { $0 % 2 == 0 } // variable 'evenValues' was never mutated; consider changing to 'let' constantfunc pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard evenNumbers.count > 0 else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let smallestEvenNumberIndex = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, smallestEvenNumberIndex]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in an array, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Example 4:
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
pluck(arr: [4, 2, 3]) == [2, 1]
pluck(arr: [1, 2, 3]) == [2, 1]
pluck(arr: [] as [Int]) == [] as [Int]
pluck(arr: [5, 0, 3, 0, 4, 2]) == [0, 1]
Answer:
```swift
func pluck(arr: [Int]) -> [Int] {
guard arr.count > 0 else { return [] }
let evenNumbers = arr.filter { $0 % 2 == 0 }
guard evenNumbers.count > 0 else { return [] }
let smallestEvenNumber = evenNumbers.min()!
let smallestEvenNumberIndex = arr.firstIndex(of: smallestEvenNumber)!
return [smallestEvenNumber, smallestEvenNumberIndex]
}
```func search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
map[num, default: 0] += 1
}
for num in lst {
if num > 0, map[num]! >= num {
return num
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
map[num, default: 0] += 1
}
for num in lst {
if num > 0, map[num]! >= num {
return num
}
}
return -1
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
if num > 0 {
map[num, default: 0] += 1
}
}
for (num, freq) in map {
if freq >= num {
return num
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
if num > 0 {
map[num, default: 0] += 1
}
}
for (num, freq) in map {
if freq >= num {
return num
}
}
return -1
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
if num > 0 {
map[num, default: 0] += 1
}
}
for (num, freq) in map {
if freq >= num {
return num
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
if num > 0 {
map[num, default: 0] += 1
}
}
for (num, freq) in map {
if freq >= num {
return num
}
}
return -1
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
if num > 0 {
map[num, default: 0] += 1
}
}
for (num, count) in map {
if count >= num {
return num
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
if num > 0 {
map[num, default: 0] += 1
}
}
for (num, count) in map {
if count >= num {
return num
}
}
return -1
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var maxFrequency = 0
var result = -1
for num in lst {
if num > 0 {
let frequency = lst.filter { $0 == num }.count
if frequency >= num, frequency > maxFrequency {
maxFrequency = frequency
result = num
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var maxFrequency = 0
var result = -1
for num in lst {
if num > 0 {
let frequency = lst.filter { $0 == num }.count
if frequency >= num, frequency > maxFrequency {
maxFrequency = frequency
result = num
}
}
}
return result
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var maxFrequency = 0
var result = -1
for num in lst {
if num > 0 {
let frequency = lst.filter { $0 == num }.count
if frequency >= num, frequency >= maxFrequency {
maxFrequency = frequency
result = num
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var maxFrequency = 0
var result = -1
for num in lst {
if num > 0 {
let frequency = lst.filter { $0 == num }.count
if frequency >= num, frequency >= maxFrequency {
maxFrequency = frequency
result = num
}
}
}
return result
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
for (num, freq) in dict {
if num > 0 && freq >= num {
return num
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
for (num, freq) in dict {
if num > 0 && freq >= num {
return num
}
}
return -1
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
if num > 0 {
dict[num, default: 0] += 1
}
}
for (num, count) in dict {
if count >= num {
return num
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
if num > 0 {
dict[num, default: 0] += 1
}
}
for (num, count) in dict {
if count >= num {
return num
}
}
return -1
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
if num > 0 {
map[num, default: 0] += 1
}
}
for (num, count) in map {
if count >= num {
return num
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var map = [Int: Int]()
for num in lst {
if num > 0 {
map[num, default: 0] += 1
}
}
for (num, count) in map {
if count >= num {
return num
}
}
return -1
}
``` // XCTAssertTrue failedfunc search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
for (num, count) in dict {
if num > 0 && count >= num {
return num
}
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a non-empty array of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the array.
If no such a value exist, return -1.
Examples:
search(lst: [4, 1, 2, 2, 3, 1]) == 2
search(lst: [1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search(lst: [5, 5, 4, 4, 4]) == -1
Answer:
```swift
func search(lst: [Int]) -> Int {
var dict = [Int: Int]()
for num in lst {
dict[num, default: 0] += 1
}
for (num, count) in dict {
if num > 0 && count >= num {
return num
}
}
return -1
}
``` // XCTAssertTrue failedfunc strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var sortedList = lst.sorted()
var isMax = true
while!sortedList.isEmpty {
if isMax {
result.append(sortedList.removeLast())
} else {
result.append(sortedList.removeFirst())
}
isMax.toggle()
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var sortedList = lst.sorted()
var isMax = true
while!sortedList.isEmpty {
if isMax {
result.append(sortedList.removeLast())
} else {
result.append(sortedList.removeFirst())
}
isMax.toggle()
}
return result
}
```guard!lst.isEmpty else { return lst } // expected expression, var, let or case in 'guard' conditionwhile!sortedList.isEmpty { // expected expression, var, or let in 'while' conditionfunc strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var left = lst
let min = left.min()!
let max = left.max()!
while!left.isEmpty {
result.append(min)
left = left.filter { $0!= min }
if!left.isEmpty {
result.append(max)
left = left.filter { $0!= max }
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var left = lst
let min = left.min()!
let max = left.max()!
while!left.isEmpty {
result.append(min)
left = left.filter { $0!= min }
if!left.isEmpty {
result.append(max)
left = left.filter { $0!= max }
}
}
return result
}
```guard!lst.isEmpty else { return lst } // expected expression, var, let or case in 'guard' conditionwhile!left.isEmpty { // expected expression, var, or let in 'while' conditionleft = left.filter { $0!= min } // '=' must have consistent whitespace on both sidesleft = left.filter { $0!= max } // '=' must have consistent whitespace on both sidesfunc strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var sortedList = lst.sorted()
var isMax = true
while!sortedList.isEmpty {
if isMax {
result.append(sortedList.removeLast())
} else {
result.append(sortedList.removeFirst())
}
isMax =!isMax
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var sortedList = lst.sorted()
var isMax = true
while!sortedList.isEmpty {
if isMax {
result.append(sortedList.removeLast())
} else {
result.append(sortedList.removeFirst())
}
isMax =!isMax
}
return result
}
```guard!lst.isEmpty else { return lst } // expected expression, var, let or case in 'guard' conditionwhile!sortedList.isEmpty { // expected expression, var, or let in 'while' conditionfunc strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var remaining = lst
var isMax = true
while!remaining.isEmpty {
if isMax {
result.append(remaining.max()!)
remaining.remove(at: remaining.firstIndex(of: remaining.max()!)!)
} else {
result.append(remaining.min()!)
remaining.remove(at: remaining.firstIndex(of: remaining.min()!)!)
}
isMax.toggle()
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var remaining = lst
var isMax = true
while!remaining.isEmpty {
if isMax {
result.append(remaining.max()!)
remaining.remove(at: remaining.firstIndex(of: remaining.max()!)!)
} else {
result.append(remaining.min()!)
remaining.remove(at: remaining.firstIndex(of: remaining.min()!)!)
}
isMax.toggle()
}
return result
}
```guard!lst.isEmpty else { return lst } // expected expression, var, let or case in 'guard' conditionwhile!remaining.isEmpty { // expected expression, var, or let in 'while' conditionfunc strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result: [Int] = []
var sortedList = lst.sorted()
var isMax = true
while!sortedList.isEmpty {
if isMax {
result.append(sortedList.removeLast())
} else {
result.append(sortedList.removeFirst())
}
isMax =!isMax
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result: [Int] = []
var sortedList = lst.sorted()
var isMax = true
while!sortedList.isEmpty {
if isMax {
result.append(sortedList.removeLast())
} else {
result.append(sortedList.removeFirst())
}
isMax =!isMax
}
return result
}
```guard!lst.isEmpty else { return lst } // expected expression, var, let or case in 'guard' conditionwhile!sortedList.isEmpty { // expected expression, var, or let in 'while' conditionfunc strangeSortList(lst: [Int]) -> [Int] {
if lst.count <= 1 {
return lst
}
var result = [Int]()
var left = lst
let min = left.min()!
let max = left.max()!
while!left.isEmpty {
result.append(min)
left.remove(at: left.firstIndex(of: min)!)
if!left.isEmpty {
result.append(max)
left.remove(at: left.firstIndex(of: max)!)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
if lst.count <= 1 {
return lst
}
var result = [Int]()
var left = lst
let min = left.min()!
let max = left.max()!
while!left.isEmpty {
result.append(min)
left.remove(at: left.firstIndex(of: min)!)
if!left.isEmpty {
result.append(max)
left.remove(at: left.firstIndex(of: max)!)
}
}
return result
}
```while!left.isEmpty { // expected expression, var, or let in 'while' conditionfunc strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result: [Int] = []
var sortedList = lst.sorted()
while!sortedList.isEmpty {
result.append(sortedList.removeFirst())
if!sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result: [Int] = []
var sortedList = lst.sorted()
while!sortedList.isEmpty {
result.append(sortedList.removeFirst())
if!sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```guard!lst.isEmpty else { return lst } // expected expression, var, let or case in 'guard' conditionwhile!sortedList.isEmpty { // expected expression, var, or let in 'while' conditionfunc strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var unsorted = lst
while!unsorted.isEmpty {
result.append(unsorted.min()!)
unsorted.remove(at: unsorted.firstIndex(of: unsorted.min()!)!)
if!unsorted.isEmpty {
result.append(unsorted.max()!)
unsorted.remove(at: unsorted.firstIndex(of: unsorted.max()!)!)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var unsorted = lst
while!unsorted.isEmpty {
result.append(unsorted.min()!)
unsorted.remove(at: unsorted.firstIndex(of: unsorted.min()!)!)
if!unsorted.isEmpty {
result.append(unsorted.max()!)
unsorted.remove(at: unsorted.firstIndex(of: unsorted.max()!)!)
}
}
return result
}
```guard!lst.isEmpty else { return lst } // expected expression, var, let or case in 'guard' conditionwhile!unsorted.isEmpty { // expected expression, var, or let in 'while' conditionfunc strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result: [Int] = []
var remaining = lst
var current = remaining.min()!
while!remaining.isEmpty {
result.append(current)
remaining.remove(at: remaining.firstIndex(of: current)!)
if remaining.isEmpty {
break
}
current = remaining.max()?? current
remaining.remove(at: remaining.firstIndex(of: current)!)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result: [Int] = []
var remaining = lst
var current = remaining.min()!
while!remaining.isEmpty {
result.append(current)
remaining.remove(at: remaining.firstIndex(of: current)!)
if remaining.isEmpty {
break
}
current = remaining.max()?? current
remaining.remove(at: remaining.firstIndex(of: current)!)
}
return result
}
```guard!lst.isEmpty else { return lst } // expected expression, var, let or case in 'guard' conditionwhile!remaining.isEmpty { // expected expression, var, or let in 'while' conditionfunc strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var sortedList = lst.sorted()
while!sortedList.isEmpty {
result.append(sortedList.removeFirst())
if!sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given array of integers, return array in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strangeSortList(lst: [1, 2, 3, 4]) == [1, 4, 2, 3]
strangeSortList(lst: [5, 5, 5, 5]) == [5, 5, 5, 5]
strangeSortList(lst: [] as [Int]) == [] as [Int]
Answer:
```swift
func strangeSortList(lst: [Int]) -> [Int] {
guard!lst.isEmpty else { return lst }
var result = [Int]()
var sortedList = lst.sorted()
while!sortedList.isEmpty {
result.append(sortedList.removeFirst())
if!sortedList.isEmpty {
result.append(sortedList.removeLast())
}
}
return result
}
```guard!lst.isEmpty else { return lst } // expected expression, var, let or case in 'guard' conditionwhile!sortedList.isEmpty { // expected expression, var, or let in 'while' conditionfunc triangleArea(a: Int, b: Int, c: Int) -> Double {
let sides = [a, b, c]
let sortedSides = sides.sorted()
let (shortest, _, longest) = (sortedSides[0], sortedSides[1], sortedSides[2])
if shortest + longest > longest {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return Double(round(area * 100)) / 100
} else {
return -1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let sides = [a, b, c]
let sortedSides = sides.sorted()
let (shortest, _, longest) = (sortedSides[0], sortedSides[1], sortedSides[2])
if shortest + longest > longest {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return Double(round(area * 100)) / 100
} else {
return -1
}
}
``` // XCTAssertTrue failedfunc triangleArea(a: Int, b: Int, c: Int) -> Double {
let sides = [a, b, c]
let sortedSides = sides.sorted()
let (shortest, _, longest) = (sortedSides[0], sortedSides[1], sortedSides[2])
if shortest + longest > longest {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return Double(round(area * 100)) / 100
} else {
return -1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let sides = [a, b, c]
let sortedSides = sides.sorted()
let (shortest, _, longest) = (sortedSides[0], sortedSides[1], sortedSides[2])
if shortest + longest > longest {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return Double(round(area * 100)) / 100
} else {
return -1
}
}
``` // XCTAssertTrue failedfunc triangleArea(a: Int, b: Int, c: Int) -> Double {
let sides = [a, b, c]
let sortedSides = sides.sorted()
let (shortest, _, longest) = (sortedSides[0], sortedSides[1], sortedSides[2])
if shortest + longest > longest {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let sides = [a, b, c]
let sortedSides = sides.sorted()
let (shortest, _, longest) = (sortedSides[0], sortedSides[1], sortedSides[2])
if shortest + longest > longest {
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - Double(a)) * (s - Double(b)) * (s - Double(c)))
return round(area * 100) / 100
}
return -1
}
``` // XCTAssertTrue failedfunc triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return area
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return area
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if (a + b <= c) || (a + c <= b) || (b + c <= a) {
return -1
}
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return round(area * 100) / 100
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if (a + b <= c) || (a + c <= b) || (b + c <= a) {
return -1
}
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return round(area * 100) / 100
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return area
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return area
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = pow(s * (s - a) * (s - b) * (s - c), 0.5)
return area
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = pow(s * (s - a) * (s - b) * (s - c), 0.5)
return area
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b <= c || a + c <= b || b + c <= a {
return -1
}
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return Double(round(area * 100)) / 100
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
if a + b <= c || a + c <= b || b + c <= a {
return -1
}
let s = Double(a + b + c) / 2
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return Double(round(area * 100)) / 100
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
if area == 0 {
return -1
} else {
return round(area * 100) / 100
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
if area == 0 {
return -1
} else {
return round(area * 100) / 100
}
}
```func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return area
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangleArea(a: 3, b: 4, c: 5) == 6.0
triangleArea(a: 1, b: 2, c: 10) == -1
Answer:
```swift
func triangleArea(a: Int, b: Int, c: Int) -> Double {
let s = (a + b + c) / 2.0
let area = sqrt(s * (s - a) * (s - b) * (s - c))
return area
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balance = q == q.reversed()
return balance && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balance = q == q.reversed()
return balance && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balance = q == q.reversed()
return balance && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balance = q == q.reversed()
return balance && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
if sum > w {
return false
}
let sorted = q.sorted()
let reversed = Array(sorted.reversed())
return sorted == reversed
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
if sum > w {
return false
}
let sorted = q.sorted()
let reversed = Array(sorted.reversed())
return sorted == reversed
}
``` // XCTAssertTrue failedfunc willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balance = q == q.reversed()
return balance && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balance = q == q.reversed()
return balance && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let isBalanced = q == q.reversed()
return isBalanced && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
if sum > w {
return false
}
let sortedQ = q.sorted()
let reversedQ = Array(sortedQ.reversed())
return sortedQ == reversedQ
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
if sum > w {
return false
}
let sortedQ = q.sorted()
let reversedQ = Array(sortedQ.reversed())
return sortedQ == reversedQ
}
``` // XCTAssertTrue failedfunc willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balance = q == q.reversed()
return balance && sum <= w
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
let balance = q == q.reversed()
return balance && sum <= w
}
```func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
if sum > w {
return false
}
let sortedQ = q.sorted()
let reversedQ = Array(sortedQ.reversed())
return sortedQ == reversedQ
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the object q will fly, and false otherwise.
The object q will fly if it's balanced (it is a palindromic array) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
# 1+2 is less than the maximum possible weight, but it's unbalanced.
# it's balanced, but 3+2+3 is more than the maximum possible weight.
# 3+2+3 is less than the maximum possible weight, and it's balanced.
# 3 is less than the maximum possible weight, and it's balanced.
willItFly(q: [1, 2], w: 5) == false
willItFly(q: [3, 2, 3], w: 1) == false
willItFly(q: [3, 2, 3], w: 9) == true
willItFly(q: [3], w: 5) == true
Answer:
```swift
func willItFly(q: [Int], w: Int) -> Bool {
let sum = q.reduce(0, +)
if sum > w {
return false
}
let sortedQ = q.sorted()
let reversedQ = Array(sortedQ.reversed())
return sortedQ == reversedQ
}
``` // XCTAssertTrue failedfunc smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for count in frequency.values {
if count % 2!= 0 {
oddCount += 1
}
}
return arr.count - oddCount / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for count in frequency.values {
if count % 2!= 0 {
oddCount += 1
}
}
return arr.count - oddCount / 2
}
```if count % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif count % 2!= 0 { // '=' must have consistent whitespace on both sidesif count % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if count % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for value in frequency.values {
if value % 2!= 0 {
oddCount += 1
}
}
return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for value in frequency.values {
if value % 2!= 0 {
oddCount += 1
}
}
return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1
}
```if value % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if value % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif value % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if value % 2!= 0 { // '=' must have consistent whitespace on both sidesreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // result of operator '-' is unusedreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // consecutive statements on a line must be separated by ';'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // cannot use optional chaining on non-optional value of type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // expected expressionreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // cannot convert return expression of type 'Bool' to return type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // consecutive statements on a line must be separated by ';'func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for count in frequency.values {
if count % 2!= 0 {
oddCount += 1
}
}
return arr.count - oddCount / 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for count in frequency.values {
if count % 2!= 0 {
oddCount += 1
}
}
return arr.count - oddCount / 2
}
```if count % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif count % 2!= 0 { // '=' must have consistent whitespace on both sidesif count % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if count % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for value in frequency.values {
if value % 2!= 0 {
oddCount += 1
}
}
return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for value in frequency.values {
if value % 2!= 0 {
oddCount += 1
}
}
return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1
}
```if value % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if value % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif value % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if value % 2!= 0 { // '=' must have consistent whitespace on both sidesreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // result of operator '-' is unusedreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // consecutive statements on a line must be separated by ';'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // cannot use optional chaining on non-optional value of type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // expected expressionreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // cannot convert return expression of type 'Bool' to return type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // consecutive statements on a line must be separated by ';'func smallestChange(arr: [Int]) -> Int {
var odds = [Int: Int]()
for num in arr {
odds[num, default: 0] += 1
}
var count = 0
for value in odds.values {
if value % 2!= 0 {
count += 1
}
}
return count <= 1? 0 : count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var odds = [Int: Int]()
for num in arr {
odds[num, default: 0] += 1
}
var count = 0
for value in odds.values {
if value % 2!= 0 {
count += 1
}
}
return count <= 1? 0 : count
}
```if value % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif value % 2!= 0 { // '=' must have consistent whitespace on both sidesif value % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if value % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'return count <= 1? 0 : count // consecutive statements on a line must be separated by ';'return count <= 1? 0 : count // integer literal is unusedreturn count <= 1? 0 : count // expected expressionreturn count <= 1? 0 : count // cannot use optional chaining on non-optional value of type 'Int'return count <= 1? 0 : count // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return count <= 1? 0 : count // consecutive statements on a line must be separated by ';'return count <= 1? 0 : count // cannot convert return expression of type 'Bool' to return type 'Int'func smallestChange(arr: [Int]) -> Int {
var odds = [Int: Int]()
for num in arr {
odds[num, default: 0] += 1
}
var count = 0
for value in odds.values {
if value % 2 == 1 {
count += 1
}
}
return count <= 1? 0 : count - 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var odds = [Int: Int]()
for num in arr {
odds[num, default: 0] += 1
}
var count = 0
for value in odds.values {
if value % 2 == 1 {
count += 1
}
}
return count <= 1? 0 : count - 1
}
```return count <= 1? 0 : count - 1 // integer literal is unusedreturn count <= 1? 0 : count - 1 // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return count <= 1? 0 : count - 1 // cannot use optional chaining on non-optional value of type 'Int'return count <= 1? 0 : count - 1 // consecutive statements on a line must be separated by ';'return count <= 1? 0 : count - 1 // consecutive statements on a line must be separated by ';'return count <= 1? 0 : count - 1 // cannot convert return expression of type 'Bool' to return type 'Int'return count <= 1? 0 : count - 1 // expected expressionfunc smallestChange(arr: [Int]) -> Int {
var odds = [Int: Int]()
for num in arr {
odds[num, default: 0] += 1
}
var result = 0
for (num, count) in odds {
if count % 2!= 0 {
result += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var odds = [Int: Int]()
for num in arr {
odds[num, default: 0] += 1
}
var result = 0
for (num, count) in odds {
if count % 2!= 0 {
result += 1
}
}
return result
}
```if count % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if count % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif count % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if count % 2!= 0 { // '=' must have consistent whitespace on both sidesfunc smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for value in frequency.values {
if value % 2!= 0 {
oddCount += 1
}
}
return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for value in frequency.values {
if value % 2!= 0 {
oddCount += 1
}
}
return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1
}
```if value % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if value % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif value % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if value % 2!= 0 { // '=' must have consistent whitespace on both sidesreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // result of operator '-' is unusedreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // consecutive statements on a line must be separated by ';'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // cannot use optional chaining on non-optional value of type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // expected expressionreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // cannot convert return expression of type 'Bool' to return type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // consecutive statements on a line must be separated by ';'func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for value in frequency.values {
if value % 2!= 0 {
oddCount += 1
}
}
return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var oddCount = 0
var frequency = [Int: Int]()
for num in arr {
frequency[num, default: 0] += 1
}
for value in frequency.values {
if value % 2!= 0 {
oddCount += 1
}
}
return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1
}
```if value % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if value % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif value % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if value % 2!= 0 { // '=' must have consistent whitespace on both sidesreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // result of operator '-' is unusedreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // consecutive statements on a line must be separated by ';'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // cannot use optional chaining on non-optional value of type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // expected expressionreturn oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // cannot convert return expression of type 'Bool' to return type 'Int'return oddCount > 1? arr.count - oddCount : arr.count - oddCount + 1 // consecutive statements on a line must be separated by ';'func smallestChange(arr: [Int]) -> Int {
var odds = [Int: Int]()
for num in arr {
odds[num, default: 0] += 1
}
var result = 0
for (_, count) in odds {
if count % 2 == 1 {
result += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallestChange(arr: [1, 2, 3, 5, 4, 7, 9, 6]) == 4
smallestChange(arr: [1, 2, 3, 4, 3, 2, 2]) == 1
smallestChange(arr: [1, 2, 3, 2, 1]) == 0
Answer:
```swift
func smallestChange(arr: [Int]) -> Int {
var odds = [Int: Int]()
for num in arr {
odds[num, default: 0] += 1
}
var result = 0
for (_, count) in odds {
if count % 2 == 1 {
result += 1
}
}
return result
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalChars1 = lst1.reduce(0) { $0 + $1.count }
let totalChars2 = lst2.reduce(0) { $0 + $1.count }
if totalChars1 < totalChars2 {
return lst2
} else if totalChars2 < totalChars1 {
return lst1
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalChars1 = lst1.reduce(0) { $0 + $1.count }
let totalChars2 = lst2.reduce(0) { $0 + $1.count }
if totalChars1 < totalChars2 {
return lst2
} else if totalChars2 < totalChars1 {
return lst1
} else {
return lst1
}
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count1 > count2 {
return lst2
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count1 > count2 {
return lst2
} else {
return lst1
}
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst2
} else if count1 > count2 {
return lst1
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst2
} else if count1 > count2 {
return lst1
} else {
return lst1
}
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count1 > count2 {
return lst2
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count1 > count2 {
return lst2
} else {
return lst1
}
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalChars1 = lst1.reduce(0) { $0 + $1.count }
let totalChars2 = lst2.reduce(0) { $0 + $1.count }
if totalChars1 < totalChars2 {
return lst2
} else if totalChars2 < totalChars1 {
return lst1
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let totalChars1 = lst1.reduce(0) { $0 + $1.count }
let totalChars2 = lst2.reduce(0) { $0 + $1.count }
if totalChars1 < totalChars2 {
return lst2
} else if totalChars2 < totalChars1 {
return lst1
} else {
return lst1
}
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst2
} else if count1 > count2 {
return lst1
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst2
} else if count1 > count2 {
return lst1
} else {
return lst1
}
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count2 < count1 {
return lst2
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count2 < count1 {
return lst2
} else {
return lst1
}
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count1 > count2 {
return lst2
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count1 > count2 {
return lst2
} else {
return lst1
}
}
```func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst2
} else if count1 > count2 {
return lst1
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst2
} else if count1 > count2 {
return lst1
} else {
return lst1
}
}
``` // XCTAssertTrue failedfunc totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count1 > count2 {
return lst2
} else {
return lst1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts two arrays of strings and returns the array that has
total number of chars in the all strings of the array less than the other array.
if the two arrays have the same number of chars, return the first array.
Examples
totalMatch(lst1: [] as [String], lst2: [] as [String]) == [] as [String]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "Hi"]) == ["hI", "Hi"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hi", "hi", "admin", "project"]) == ["hi", "admin"]
totalMatch(lst1: ["hi", "admin"], lst2: ["hI", "hi", "hi"]) == ["hI", "hi", "hi"]
totalMatch(lst1: ["4"], lst2: ["1", "2", "3", "4", "5"]) == ["4"]
Answer:
```swift
func totalMatch(lst1: [String], lst2: [String]) -> [String] {
let count1 = lst1.reduce(0) { $0 + $1.count }
let count2 = lst2.reduce(0) { $0 + $1.count }
if count1 < count2 {
return lst1
} else if count1 > count2 {
return lst2
} else {
return lst1
}
}
```func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
var factors = [Int]()
var number = a
for i in 2...a {
while number % i == 0 {
factors.append(i)
number /= i
}
}
if factors.count < 3 {
return false
}
for factor in factors {
if!isPrime(factor) {
return false
}
}
return true
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
var factors = [Int]()
var number = a
for i in 2...a {
while number % i == 0 {
factors.append(i)
number /= i
}
}
if factors.count < 3 {
return false
}
for factor in factors {
if!isPrime(factor) {
return false
}
}
return true
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```if!isPrime(factor) { // expected expression, var, or let in 'if' conditionfunc isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
if a == 2 {
return true
}
if a % 2 == 0 {
return false
}
for i in stride(from: 3, to: a, by: 2) {
if a % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
if a == 2 {
return true
}
if a % 2 == 0 {
return false
}
for i in stride(from: 3, to: a, by: 2) {
if a % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
var b = 2
while b * b <= a {
if a % b == 0 {
if isPrime(b) && isPrime(a / b) {
return true
}
}
b += 1
}
return false
}
func isPrime(_ a: Int) -> Bool {
if a < 2 {
return false
}
var b = 2
while b * b <= a {
if a % b == 0 {
return false
}
b += 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
var b = 2
while b * b <= a {
if a % b == 0 {
if isPrime(b) && isPrime(a / b) {
return true
}
}
b += 1
}
return false
}
func isPrime(_ a: Int) -> Bool {
if a < 2 {
return false
}
var b = 2
while b * b <= a {
if a % b == 0 {
return false
}
b += 1
}
return true
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
if a <= 1 {
return false
}
if a == 2 || a == 3 {
return true
}
if a % 2 == 0 || a % 3 == 0 {
return false
}
var i = 5
while i * i <= a {
if a % i == 0 || a % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a <= 1 {
return false
}
if a == 2 || a == 3 {
return true
}
if a % 2 == 0 || a % 3 == 0 {
return false
}
var i = 5
while i * i <= a {
if a % i == 0 || a % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
if a == 2 {
return true
}
if a % 2 == 0 {
return false
}
for i in stride(from: 3, to: a, by: 2) {
if a % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
if a == 2 {
return true
}
if a % 2 == 0 {
return false
}
for i in stride(from: 3, to: a, by: 2) {
if a % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
if a <= 1 {
return false
}
if a == 2 || a == 3 {
return true
}
if a % 2 == 0 || a % 3 == 0 {
return false
}
var i = 5
while i * i <= a {
if a % i == 0 || a % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a <= 1 {
return false
}
if a == 2 || a == 3 {
return true
}
if a % 2 == 0 || a % 3 == 0 {
return false
}
var i = 5
while i * i <= a {
if a % i == 0 || a % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
if a == 2 {
return true
}
if a % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(a))), by: 2) {
if a % i == 0 {
return false
}
}
return true
}
func isMultiplyOf3Primes(a: Int) -> Bool {
if a < 6 {
return false
}
if isMultiplyPrime(a: a) {
return true
}
for i in stride(from: 2, through: a / 2, by: 1) {
if isMultiplyPrime(a: i) && isMultiplyPrime(a: a - i) {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
if a == 2 {
return true
}
if a % 2 == 0 {
return false
}
for i in stride(from: 3, through: Int(sqrt(Double(a))), by: 2) {
if a % i == 0 {
return false
}
}
return true
}
func isMultiplyOf3Primes(a: Int) -> Bool {
if a < 6 {
return false
}
if isMultiplyPrime(a: a) {
return true
}
for i in stride(from: 2, through: a / 2, by: 1) {
if isMultiplyPrime(a: i) && isMultiplyPrime(a: a - i) {
return true
}
}
return false
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
if a == 2 {
return true
}
if a % 2 == 0 {
return false
}
var i = 3
while i * i <= a {
if a % i == 0 {
return false
}
i += 2
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
if a == 2 {
return true
}
if a % 2 == 0 {
return false
}
var i = 3
while i * i <= a {
if a % i == 0 {
return false
}
i += 2
}
return true
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
var b = 2
while b * b <= a {
if a % b == 0 {
if isPrime(b) && isPrime(a / b) {
return true
}
}
b += 1
}
return false
}
func isPrime(_ a: Int) -> Bool {
if a < 2 {
return false
}
var b = 2
while b * b <= a {
if a % b == 0 {
return false
}
b += 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
var b = 2
while b * b <= a {
if a % b == 0 {
if isPrime(b) && isPrime(a / b) {
return true
}
}
b += 1
}
return false
}
func isPrime(_ a: Int) -> Bool {
if a < 2 {
return false
}
var b = 2
while b * b <= a {
if a % b == 0 {
return false
}
b += 1
}
return true
}
``` // XCTAssertTrue failedfunc isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
var primeNumbers = [2]
var number = 3
while primeNumbers.count < 3 && number < a {
if isPrime(number) {
primeNumbers.append(number)
}
number += 1
}
if primeNumbers.count < 3 {
return false
}
return primeNumbers.reduce(1, *) == a
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
30 = 2 * 3 * 5
isMultiplyPrime(a: 30) == true
Answer:
```swift
func isMultiplyPrime(a: Int) -> Bool {
if a < 2 {
return false
}
var primeNumbers = [2]
var number = 3
while primeNumbers.count < 3 && number < a {
if isPrime(number) {
primeNumbers.append(number)
}
number += 1
}
if primeNumbers.count < 3 {
return false
}
return primeNumbers.reduce(1, *) == a
}
func isPrime(_ number: Int) -> Bool {
if number < 2 {
return false
}
if number == 2 {
return true
}
if number % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(number))), by: 2) {
if number % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}
```if x % n!= 0 { // use of '=' in a boolean context, did you mean '=='?if x % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if x % n!= 0 { // '=' must have consistent whitespace on both sidesfunc isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
if y == 1 {
return true
}
if y % n!= 0 {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
if y == 1 {
return true
}
if y % n!= 0 {
return false
}
return true
}
```if x % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if x % n!= 0 { // '=' must have consistent whitespace on both sidesif x % n!= 0 { // use of '=' in a boolean context, did you mean '=='?if y % n!= 0 { // '=' must have consistent whitespace on both sidesif y % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if y % n!= 0 { // use of '=' in a boolean context, did you mean '=='?func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}
```if x % n!= 0 { // use of '=' in a boolean context, did you mean '=='?if x % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if x % n!= 0 { // '=' must have consistent whitespace on both sidesfunc isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}
```if x % n!= 0 { // use of '=' in a boolean context, did you mean '=='?if x % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if x % n!= 0 { // '=' must have consistent whitespace on both sidesfunc isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}
```if x % n!= 0 { // use of '=' in a boolean context, did you mean '=='?if x % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if x % n!= 0 { // '=' must have consistent whitespace on both sidesfunc isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
return y == 1
}
```if x % n!= 0 { // use of '=' in a boolean context, did you mean '=='?if x % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if x % n!= 0 { // '=' must have consistent whitespace on both sidesfunc isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
if y == 1 {
return true
}
if y % n!= 0 {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
if y == 1 {
return true
}
if y % n!= 0 {
return false
}
return true
}
```if x % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if x % n!= 0 { // '=' must have consistent whitespace on both sidesif x % n!= 0 { // use of '=' in a boolean context, did you mean '=='?if y % n!= 0 { // '=' must have consistent whitespace on both sidesif y % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if y % n!= 0 { // use of '=' in a boolean context, did you mean '=='?func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
if y == 1 {
return true
}
if y % n!= 0 {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
if y == 1 {
return true
}
if y % n!= 0 {
return false
}
return true
}
```if x % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if x % n!= 0 { // '=' must have consistent whitespace on both sidesif x % n!= 0 { // use of '=' in a boolean context, did you mean '=='?if y % n!= 0 { // '=' must have consistent whitespace on both sidesif y % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if y % n!= 0 { // use of '=' in a boolean context, did you mean '=='?func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
if y == 1 {
return true
}
if y % n!= 0 {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x % n!= 0 {
return false
}
let y = x / n
if y == 1 {
return true
}
if y % n!= 0 {
return false
}
return true
}
```if x % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if x % n!= 0 { // '=' must have consistent whitespace on both sidesif x % n!= 0 { // use of '=' in a boolean context, did you mean '=='?if y % n!= 0 { // '=' must have consistent whitespace on both sidesif y % n!= 0 { // cannot force unwrap value of non-optional type 'Int'if y % n!= 0 { // use of '=' in a boolean context, did you mean '=='?func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x < 1 || n < 1 {
return false
}
var power = n
while power < x {
power *= n
}
return power == x
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
isSimplePower(x: 1, n: 4) == true
isSimplePower(x: 2, n: 2) == true
isSimplePower(x: 8, n: 2) == true
isSimplePower(x: 3, n: 2) == false
isSimplePower(x: 3, n: 1) == false
isSimplePower(x: 5, n: 3) == false
Answer:
```swift
func isSimplePower(x: Int, n: Int) -> Bool {
if x == 1 {
return true
}
if x < 1 || n < 1 {
return false
}
var power = n
while power < x {
power *= n
}
return power == x
}
```func iscube(a: Int) -> Bool {
let result = pow(Double(a), 1.0/3.0)
return result == Int(result)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let result = pow(Double(a), 1.0/3.0)
return result == Int(result)
}
```return result == Int(result) // binary operator '==' cannot be applied to operands of type 'Double' and 'Int'func iscube(a: Int) -> Bool {
let result = pow(Double(a), 1.0/3.0)
return result == Int(result)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let result = pow(Double(a), 1.0/3.0)
return result == Int(result)
}
```return result == Int(result) // binary operator '==' cannot be applied to operands of type 'Double' and 'Int'func iscube(a: Int) -> Bool {
let cubeRoot = Int(pow(Double(abs(a)), 1.0/3.0))
return cubeRoot * cubeRoot * cubeRoot == abs(a)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let cubeRoot = Int(pow(Double(abs(a)), 1.0/3.0))
return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
``` // XCTAssertTrue failedfunc iscube(a: Int) -> Bool {
let result = pow(Double(a), 1.0/3.0)
return result == Int(result)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let result = pow(Double(a), 1.0/3.0)
return result == Int(result)
}
```return result == Int(result) // binary operator '==' cannot be applied to operands of type 'Double' and 'Int'func iscube(a: Int) -> Bool {
if a == 0 {
return true
}
let absA = abs(a)
let cubeRoot = Int(pow(Double(absA), 1.0/3.0))
return cubeRoot * cubeRoot * cubeRoot == absA
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
if a == 0 {
return true
}
let absA = abs(a)
let cubeRoot = Int(pow(Double(absA), 1.0/3.0))
return cubeRoot * cubeRoot * cubeRoot == absA
}
``` // XCTAssertTrue failedfunc iscube(a: Int) -> Bool {
let cbrt = a > 0? pow(Double(a), 1.0/3.0) : -pow(Double(-a), 1.0/3.0)
return cbrt == Int(cbrt)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let cbrt = a > 0? pow(Double(a), 1.0/3.0) : -pow(Double(-a), 1.0/3.0)
return cbrt == Int(cbrt)
}
```let cbrt = a > 0? pow(Double(a), 1.0/3.0) : -pow(Double(-a), 1.0/3.0) // expected expressionlet cbrt = a > 0? pow(Double(a), 1.0/3.0) : -pow(Double(-a), 1.0/3.0) // consecutive statements on a line must be separated by ';'let cbrt = a > 0? pow(Double(a), 1.0/3.0) : -pow(Double(-a), 1.0/3.0) // value of optional type 'Int?' must be unwrapped to a value of type 'Int'let cbrt = a > 0? pow(Double(a), 1.0/3.0) : -pow(Double(-a), 1.0/3.0) // consecutive statements on a line must be separated by ';'let cbrt = a > 0? pow(Double(a), 1.0/3.0) : -pow(Double(-a), 1.0/3.0) // cannot use optional chaining on non-optional value of type 'Int'func iscube(a: Int) -> Bool {
let x = Double(a)
let y = pow(x, 1.0/3.0)
return y == y.rounded()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let x = Double(a)
let y = pow(x, 1.0/3.0)
return y == y.rounded()
}
``` // XCTAssertTrue failedfunc iscube(a: Int) -> Bool {
let cubeRoot = Int(pow(Double(abs(a)), 1.0/3.0))
return cubeRoot * cubeRoot * cubeRoot == abs(a)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let cubeRoot = Int(pow(Double(abs(a)), 1.0/3.0))
return cubeRoot * cubeRoot * cubeRoot == abs(a)
}
``` // XCTAssertTrue failedfunc iscube(a: Int) -> Bool {
let x = Double(a)
let y = pow(x, 1.0/3.0)
return y == y.rounded()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let x = Double(a)
let y = pow(x, 1.0/3.0)
return y == y.rounded()
}
``` // XCTAssertTrue failedfunc iscube(a: Int) -> Bool {
let absA = abs(a)
let cubeRoot = Int(pow(Double(absA), 1.0/3.0))
return cubeRoot * cubeRoot * cubeRoot == absA
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an integer a and returns true
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(a: 1) == true
iscube(a: 2) == false
iscube(a: -1) == true
iscube(a: 64) == true
iscube(a: 0) == true
iscube(a: 180) == false
Answer:
```swift
func iscube(a: Int) -> Bool {
let absA = abs(a)
let cubeRoot = Int(pow(Double(absA), 1.0/3.0))
return cubeRoot * cubeRoot * cubeRoot == absA
}
``` // XCTAssertTrue failedfunc hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if hexDigits.contains(char) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if hexDigits.contains(char) {
count += 1
}
}
return count
}
```func hexKey(num: String) -> Int {
let hexDigits: [Character: Int] = [
"0": 0, "1": 1, "2": 2, "3": 3, "4": 4, "5": 5, "6": 6, "7": 7, "8": 8, "9": 9,
"A": 10, "B": 11, "C": 12, "D": 13, "E": 14, "F": 15
]
let primeHexDigits: [Int] = [2, 3, 5, 7, 11, 13]
var count = 0
for char in num {
if let digit = hexDigits[char], primeHexDigits.contains(digit) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character: Int] = [
"0": 0, "1": 1, "2": 2, "3": 3, "4": 4, "5": 5, "6": 6, "7": 7, "8": 8, "9": 9,
"A": 10, "B": 11, "C": 12, "D": 13, "E": 14, "F": 15
]
let primeHexDigits: [Int] = [2, 3, 5, 7, 11, 13]
var count = 0
for char in num {
if let digit = hexDigits[char], primeHexDigits.contains(digit) {
count += 1
}
}
return count
}
```func hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16), hexDigits.contains(String(digit)) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16), hexDigits.contains(String(digit)) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16), hexDigits.contains(String(digit)) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16), hexDigits.contains(String(digit)) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16), hexDigits.contains(String(digit)) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16), hexDigits.contains(String(digit)) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16) {
if hexDigits.contains(String(char).uppercased()) {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16) {
if hexDigits.contains(String(char).uppercased()) {
count += 1
}
}
}
return count
}
```if let digit = Int(String(char), radix: 16) { // value 'digit' was defined but never used; consider replacing with boolean testfunc hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if hexDigits.contains(char) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if hexDigits.contains(char) {
count += 1
}
}
return count
}
```func hexKey(num: String) -> Int {
let hexDigits: [Character: Bool] = [
"2": true, "3": true, "5": true, "7": true, "B": true, "D": true
]
var count = 0
for char in num {
if let value = hexDigits[char], value {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character: Bool] = [
"2": true, "3": true, "5": true, "7": true, "B": true, "D": true
]
var count = 0
for char in num {
if let value = hexDigits[char], value {
count += 1
}
}
return count
}
```func hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16) {
if hexDigits.contains(String(char).uppercased()) {
count += 1
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character] = ["2", "3", "5", "7", "B", "D"]
var count = 0
for char in num {
if let digit = Int(String(char), radix: 16) {
if hexDigits.contains(String(char).uppercased()) {
count += 1
}
}
}
return count
}
```if let digit = Int(String(char), radix: 16) { // value 'digit' was defined but never used; consider replacing with boolean testfunc hexKey(num: String) -> Int {
let hexDigits: [Character: Bool] = [
"2": true, "3": true, "5": true, "7": true,
"B": true, "D": true
]
var count = 0
for char in num {
if let value = hexDigits[char], value {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
hexKey(num: "AB") == 1
hexKey(num: "1077E") == 2
hexKey(num: "ABED1A33") == 4
hexKey(num: "123456789ABCDEF0") == 6
hexKey(num: "2020") == 2
Answer:
```swift
func hexKey(num: String) -> Int {
let hexDigits: [Character: Bool] = [
"2": true, "3": true, "5": true, "7": true,
"B": true, "D": true
]
var count = 0
for char in num {
if let value = hexDigits[char], value {
count += 1
}
}
return count
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimalToBinary(decimal: 15) == "db1111db"
decimalToBinary(decimal: 32) == "db100000db"
Answer:
```swift
func decimalToBinary(decimal: Int) -> String {
let binary = String(decimal, radix: 2)
return "db\(binary)db"
}
```func isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}
```func isHappy(s: String) -> Bool {
guard s.count >= 3 else {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 1) {
let substring = s[s.index(s.startIndex, offsetBy: i)..<s.index(s.startIndex, offsetBy: i + 3)]
if substring.count!= Array(substring).count {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
guard s.count >= 3 else {
return false
}
for i in stride(from: 0, to: s.count - 2, by: 1) {
let substring = s[s.index(s.startIndex, offsetBy: i)..<s.index(s.startIndex, offsetBy: i + 3)]
if substring.count!= Array(substring).count {
return false
}
}
return true
}
```if substring.count!= Array(substring).count { // cannot force unwrap value of non-optional type 'Int'if substring.count!= Array(substring).count { // '=' must have consistent whitespace on both sidesif substring.count!= Array(substring).count { // use of '=' in a boolean context, did you mean '=='?func isHappy(s: String) -> Bool {
guard s.count >= 3 else { return false }
for i in stride(from: 0, to: s.count - 2, by: 3) {
let slice = s[s.index(s.startIndex, offsetBy: i)..<s.index(s.startIndex, offsetBy: i + 3)]
if slice.count!= slice.reduce(into: Set<Character>()) { $0.insert($1) }.count {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
guard s.count >= 3 else { return false }
for i in stride(from: 0, to: s.count - 2, by: 3) {
let slice = s[s.index(s.startIndex, offsetBy: i)..<s.index(s.startIndex, offsetBy: i + 3)]
if slice.count!= slice.reduce(into: Set<Character>()) { $0.insert($1) }.count {
return false
}
}
return true
}
```if slice.count!= slice.reduce(into: Set<Character>()) { $0.insert($1) }.count { // cannot force unwrap value of non-optional type 'Int'if slice.count!= slice.reduce(into: Set<Character>()) { $0.insert($1) }.count { // use of '=' in a boolean context, did you mean '=='?if slice.count!= slice.reduce(into: Set<Character>()) { $0.insert($1) }.count { // '=' must have consistent whitespace on both sidesfunc isHappy(s: String) -> Bool {
guard s.count >= 3 else { return false }
for i in stride(from: 0, to: s.count - 2, by: 3) {
let substring = String(s[s.index(s.startIndex, offsetBy: i)..<s.index(s.startIndex, offsetBy: i + 3)])
if substring.contains(where: { substring.count(of: $0) > 1 }) {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
guard s.count >= 3 else { return false }
for i in stride(from: 0, to: s.count - 2, by: 3) {
let substring = String(s[s.index(s.startIndex, offsetBy: i)..<s.index(s.startIndex, offsetBy: i + 3)])
if substring.contains(where: { substring.count(of: $0) > 1 }) {
return false
}
}
return true
}
```if substring.contains(where: { substring.count(of: $0) > 1 }) { // cannot call value of non-function type 'Int'func isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}
```func isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}
```func isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}
```func isHappy(s: String) -> Bool {
guard s.count >= 3 else { return false }
let chars = Array(s)
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] && chars[i] == chars[i+2] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
guard s.count >= 3 else { return false }
let chars = Array(s)
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] && chars[i] == chars[i+2] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isHappy(s: String) -> Bool {
guard s.count >= 3 else { return false }
let array = Array(s)
for i in 0..<array.count-2 {
if array[i] == array[i+1] && array[i] == array[i+2] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
guard s.count >= 3 else { return false }
let array = Array(s)
for i in 0..<array.count-2 {
if array[i] == array[i+1] && array[i] == array[i+2] {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
Your task is to check if the string is hapswift or not.
A string is hapswift if its length is at least 3 and every 3 consecutive letters are distinct
For example:
isHappy(s: "a") == false
isHappy(s: "aa") == false
isHappy(s: "abcd") == true
isHappy(s: "aabb") == false
isHappy(s: "adb") == true
isHappy(s: "xyy") == false
Answer:
```swift
func isHappy(s: String) -> Bool {
let chars = Array(s)
if chars.count < 3 {
return false
}
for i in 0..<chars.count-2 {
if chars[i] == chars[i+1] || chars[i] == chars[i+2] || chars[i+1] == chars[i+2] {
return false
}
}
return true
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGrades.append("A+")
} else if gpa > 3.7 {
letterGrades.append("A")
} else if gpa > 3.3 {
letterGrades.append("A-")
} else if gpa > 3.0 {
letterGrades.append("B+")
} else if gpa > 2.7 {
letterGrades.append("B")
} else if gpa > 2.3 {
letterGrades.append("B-")
} else if gpa > 2.0 {
letterGrades.append("C+")
} else if gpa > 1.7 {
letterGrades.append("C")
} else if gpa > 1.3 {
letterGrades.append("C-")
} else if gpa > 1.0 {
letterGrades.append("D+")
} else if gpa > 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGrades.append("A+")
} else if gpa > 3.7 {
letterGrades.append("A")
} else if gpa > 3.3 {
letterGrades.append("A-")
} else if gpa > 3.0 {
letterGrades.append("B+")
} else if gpa > 2.7 {
letterGrades.append("B")
} else if gpa > 2.3 {
letterGrades.append("B-")
} else if gpa > 2.0 {
letterGrades.append("C+")
} else if gpa > 1.7 {
letterGrades.append("C")
} else if gpa > 1.3 {
letterGrades.append("C-")
} else if gpa > 1.0 {
letterGrades.append("D+")
} else if gpa > 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
let gradesCopy = grades.sorted()
var letterGrades: [String] = []
for grade in gradesCopy {
if grade >= 4.0 {
letterGrades.append("A+")
} else if grade >= 3.7 {
letterGrades.append("A")
} else if grade >= 3.3 {
letterGrades.append("A-")
} else if grade >= 3.0 {
letterGrades.append("B+")
} else if grade >= 2.7 {
letterGrades.append("B")
} else if grade >= 2.3 {
letterGrades.append("B-")
} else if grade >= 2.0 {
letterGrades.append("C+")
} else if grade >= 1.7 {
letterGrades.append("C")
} else if grade >= 1.3 {
letterGrades.append("C-")
} else if grade >= 1.0 {
letterGrades.append("D+")
} else if grade >= 0.7 {
letterGrades.append("D")
} else if grade >= 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
let gradesCopy = grades.sorted()
var letterGrades: [String] = []
for grade in gradesCopy {
if grade >= 4.0 {
letterGrades.append("A+")
} else if grade >= 3.7 {
letterGrades.append("A")
} else if grade >= 3.3 {
letterGrades.append("A-")
} else if grade >= 3.0 {
letterGrades.append("B+")
} else if grade >= 2.7 {
letterGrades.append("B")
} else if grade >= 2.3 {
letterGrades.append("B-")
} else if grade >= 2.0 {
letterGrades.append("C+")
} else if grade >= 1.7 {
letterGrades.append("C")
} else if grade >= 1.3 {
letterGrades.append("C-")
} else if grade >= 1.0 {
letterGrades.append("D+")
} else if grade >= 0.7 {
letterGrades.append("D")
} else if grade >= 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
let letterGrades = ["A+", "A", "A-", "B+", "B", "B-", "C+", "C", "C-", "D+", "D", "D-", "E"]
let minGPA = [4.0, 3.7, 3.3, 3.0, 2.7, 2.3, 2.0, 1.7, 1.3, 1.0, 0.7, 0.0, 0.0]
var letterGradeResults: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGradeResults.append(letterGrades[0])
} else {
for i in 0..<minGPA.count {
if gpa > minGPA[i] {
letterGradeResults.append(letterGrades[i])
break
}
}
}
}
return letterGradeResults
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
let letterGrades = ["A+", "A", "A-", "B+", "B", "B-", "C+", "C", "C-", "D+", "D", "D-", "E"]
let minGPA = [4.0, 3.7, 3.3, 3.0, 2.7, 2.3, 2.0, 1.7, 1.3, 1.0, 0.7, 0.0, 0.0]
var letterGradeResults: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGradeResults.append(letterGrades[0])
} else {
for i in 0..<minGPA.count {
if gpa > minGPA[i] {
letterGradeResults.append(letterGrades[i])
break
}
}
}
}
return letterGradeResults
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
let letterGrades = ["A+", "A", "A-", "B+", "B", "B-", "C+", "C", "C-", "D+", "D", "D-", "E"]
var letterGradeResults: [String] = []
for grade in grades {
if grade >= 4.0 {
letterGradeResults.append(letterGrades[0])
} else if grade >= 3.7 {
letterGradeResults.append(letterGrades[1])
} else if grade >= 3.3 {
letterGradeResults.append(letterGrades[2])
} else if grade >= 3.0 {
letterGradeResults.append(letterGrades[3])
} else if grade >= 2.7 {
letterGradeResults.append(letterGrades[4])
} else if grade >= 2.3 {
letterGradeResults.append(letterGrades[5])
} else if grade >= 2.0 {
letterGradeResults.append(letterGrades[6])
} else if grade >= 1.7 {
letterGradeResults.append(letterGrades[7])
} else if grade >= 1.3 {
letterGradeResults.append(letterGrades[8])
} else if grade >= 1.0 {
letterGradeResults.append(letterGrades[9])
} else if grade >= 0.7 {
letterGradeResults.append(letterGrades[10])
} else if grade >= 0.0 {
letterGradeResults.append(letterGrades[11])
} else {
letterGradeResults.append(letterGrades[12])
}
}
return letterGradeResults
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
let letterGrades = ["A+", "A", "A-", "B+", "B", "B-", "C+", "C", "C-", "D+", "D", "D-", "E"]
var letterGradeResults: [String] = []
for grade in grades {
if grade >= 4.0 {
letterGradeResults.append(letterGrades[0])
} else if grade >= 3.7 {
letterGradeResults.append(letterGrades[1])
} else if grade >= 3.3 {
letterGradeResults.append(letterGrades[2])
} else if grade >= 3.0 {
letterGradeResults.append(letterGrades[3])
} else if grade >= 2.7 {
letterGradeResults.append(letterGrades[4])
} else if grade >= 2.3 {
letterGradeResults.append(letterGrades[5])
} else if grade >= 2.0 {
letterGradeResults.append(letterGrades[6])
} else if grade >= 1.7 {
letterGradeResults.append(letterGrades[7])
} else if grade >= 1.3 {
letterGradeResults.append(letterGrades[8])
} else if grade >= 1.0 {
letterGradeResults.append(letterGrades[9])
} else if grade >= 0.7 {
letterGradeResults.append(letterGrades[10])
} else if grade >= 0.0 {
letterGradeResults.append(letterGrades[11])
} else {
letterGradeResults.append(letterGrades[12])
}
}
return letterGradeResults
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGrades.append("A+")
} else if gpa > 3.7 {
letterGrades.append("A")
} else if gpa > 3.3 {
letterGrades.append("A-")
} else if gpa > 3.0 {
letterGrades.append("B+")
} else if gpa > 2.7 {
letterGrades.append("B")
} else if gpa > 2.3 {
letterGrades.append("B-")
} else if gpa > 2.0 {
letterGrades.append("C+")
} else if gpa > 1.7 {
letterGrades.append("C")
} else if gpa > 1.3 {
letterGrades.append("C-")
} else if gpa > 1.0 {
letterGrades.append("D+")
} else if gpa > 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGrades.append("A+")
} else if gpa > 3.7 {
letterGrades.append("A")
} else if gpa > 3.3 {
letterGrades.append("A-")
} else if gpa > 3.0 {
letterGrades.append("B+")
} else if gpa > 2.7 {
letterGrades.append("B")
} else if gpa > 2.3 {
letterGrades.append("B-")
} else if gpa > 2.0 {
letterGrades.append("C+")
} else if gpa > 1.7 {
letterGrades.append("C")
} else if gpa > 1.3 {
letterGrades.append("C-")
} else if gpa > 1.0 {
letterGrades.append("D+")
} else if gpa > 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGrades.append("A+")
} else if gpa > 3.7 {
letterGrades.append("A")
} else if gpa > 3.3 {
letterGrades.append("A-")
} else if gpa > 3.0 {
letterGrades.append("B+")
} else if gpa > 2.7 {
letterGrades.append("B")
} else if gpa > 2.3 {
letterGrades.append("B-")
} else if gpa > 2.0 {
letterGrades.append("C+")
} else if gpa > 1.7 {
letterGrades.append("C")
} else if gpa > 1.3 {
letterGrades.append("C-")
} else if gpa > 1.0 {
letterGrades.append("D+")
} else if gpa > 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGrades.append("A+")
} else if gpa > 3.7 {
letterGrades.append("A")
} else if gpa > 3.3 {
letterGrades.append("A-")
} else if gpa > 3.0 {
letterGrades.append("B+")
} else if gpa > 2.7 {
letterGrades.append("B")
} else if gpa > 2.3 {
letterGrades.append("B-")
} else if gpa > 2.0 {
letterGrades.append("C+")
} else if gpa > 1.7 {
letterGrades.append("C")
} else if gpa > 1.3 {
letterGrades.append("C-")
} else if gpa > 1.0 {
letterGrades.append("D+")
} else if gpa > 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGrades.append("A+")
} else if gpa > 3.7 {
letterGrades.append("A")
} else if gpa > 3.3 {
letterGrades.append("A-")
} else if gpa > 3.0 {
letterGrades.append("B+")
} else if gpa > 2.7 {
letterGrades.append("B")
} else if gpa > 2.3 {
letterGrades.append("B-")
} else if gpa > 2.0 {
letterGrades.append("C+")
} else if gpa > 1.7 {
letterGrades.append("C")
} else if gpa > 1.3 {
letterGrades.append("C-")
} else if gpa > 1.0 {
letterGrades.append("D+")
} else if gpa > 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa == 4.0 {
letterGrades.append("A+")
} else if gpa > 3.7 {
letterGrades.append("A")
} else if gpa > 3.3 {
letterGrades.append("A-")
} else if gpa > 3.0 {
letterGrades.append("B+")
} else if gpa > 2.7 {
letterGrades.append("B")
} else if gpa > 2.3 {
letterGrades.append("B-")
} else if gpa > 2.0 {
letterGrades.append("C+")
} else if gpa > 1.7 {
letterGrades.append("C")
} else if gpa > 1.3 {
letterGrades.append("C-")
} else if gpa > 1.0 {
letterGrades.append("D+")
} else if gpa > 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
```func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else if gpa >= 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else if gpa >= 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
var letterGrades: [String] = []
for gpa in grades {
if gpa >= 4.0 {
letterGrades.append("A+")
} else if gpa >= 3.7 {
letterGrades.append("A")
} else if gpa >= 3.3 {
letterGrades.append("A-")
} else if gpa >= 3.0 {
letterGrades.append("B+")
} else if gpa >= 2.7 {
letterGrades.append("B")
} else if gpa >= 2.3 {
letterGrades.append("B-")
} else if gpa >= 2.0 {
letterGrades.append("C+")
} else if gpa >= 1.7 {
letterGrades.append("C")
} else if gpa >= 1.3 {
letterGrades.append("C-")
} else if gpa >= 1.0 {
letterGrades.append("D+")
} else if gpa >= 0.7 {
letterGrades.append("D")
} else if gpa > 0.0 {
letterGrades.append("D-")
} else {
letterGrades.append("E")
}
}
return letterGrades
}
``` // XCTAssertTrue failedfunc numericalLetterGrade(grades: [Double]) -> [String] {
let letterGrades = ["A+", "A", "A-", "B+", "B", "B-", "C+", "C", "C-", "D+", "D", "D-", "E"]
var letterGradeResults: [String] = []
for grade in grades {
if grade >= 4.0 {
letterGradeResults.append(letterGrades[0])
} else if grade >= 3.7 {
letterGradeResults.append(letterGrades[1])
} else if grade >= 3.3 {
letterGradeResults.append(letterGrades[2])
} else if grade >= 3.0 {
letterGradeResults.append(letterGrades[3])
} else if grade >= 2.7 {
letterGradeResults.append(letterGrades[4])
} else if grade >= 2.3 {
letterGradeResults.append(letterGrades[5])
} else if grade >= 2.0 {
letterGradeResults.append(letterGrades[6])
} else if grade >= 1.7 {
letterGradeResults.append(letterGrades[7])
} else if grade >= 1.3 {
letterGradeResults.append(letterGrades[8])
} else if grade >= 1.0 {
letterGradeResults.append(letterGrades[9])
} else if grade >= 0.7 {
letterGradeResults.append(letterGrades[10])
} else if grade >= 0.0 {
letterGradeResults.append(letterGrades[11])
} else {
letterGradeResults.append(letterGrades[12])
}
}
return letterGradeResults
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you an array of GPAs for some students and you have to write
a function that can output an array of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
numericalLetterGrade(grades: [4.0, 3, 1.7, 2, 3.5]) == ["A+", "B", "C-", "C", "A-"]
Answer:
```swift
func numericalLetterGrade(grades: [Double]) -> [String] {
let letterGrades = ["A+", "A", "A-", "B+", "B", "B-", "C+", "C", "C-", "D+", "D", "D-", "E"]
var letterGradeResults: [String] = []
for grade in grades {
if grade >= 4.0 {
letterGradeResults.append(letterGrades[0])
} else if grade >= 3.7 {
letterGradeResults.append(letterGrades[1])
} else if grade >= 3.3 {
letterGradeResults.append(letterGrades[2])
} else if grade >= 3.0 {
letterGradeResults.append(letterGrades[3])
} else if grade >= 2.7 {
letterGradeResults.append(letterGrades[4])
} else if grade >= 2.3 {
letterGradeResults.append(letterGrades[5])
} else if grade >= 2.0 {
letterGradeResults.append(letterGrades[6])
} else if grade >= 1.7 {
letterGradeResults.append(letterGrades[7])
} else if grade >= 1.3 {
letterGradeResults.append(letterGrades[8])
} else if grade >= 1.0 {
letterGradeResults.append(letterGrades[9])
} else if grade >= 0.7 {
letterGradeResults.append(letterGrades[10])
} else if grade >= 0.0 {
letterGradeResults.append(letterGrades[11])
} else {
letterGradeResults.append(letterGrades[12])
}
}
return letterGradeResults
}
``` // XCTAssertTrue failedfunc primeLength(string: String) -> Bool {
let length = string.count
if length == 2 {
return true
}
if length < 2 || length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length == 2 {
return true
}
if length < 2 || length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc primeLength(string: String) -> Bool {
let length = string.count
if length == 2 {
return true
}
if length < 2 || length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length == 2 {
return true
}
if length < 2 || length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length == 2 {
return true
}
if length < 2 || length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length == 2 {
return true
}
if length < 2 || length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
if length == 2 {
return true
}
if length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
if length == 2 {
return true
}
if length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
for i in 2..<length {
if length % i == 0 {
return false
}
}
return true
}
```func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
if length == 2 {
return true
}
if length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns true if the string
length is a prime number or false otherwise
Examples
primeLength(string: "Hello") == true
primeLength(string: "abcdcba") == true
primeLength(string: "kittens") == true
primeLength(string: "orange") == false
Answer:
```swift
func primeLength(string: String) -> Bool {
let length = string.count
if length <= 1 {
return false
}
if length == 2 {
return true
}
if length % 2 == 0 {
return false
}
for i in stride(from: 3, to: Int(sqrt(Double(length))), by: 2) {
if length % i == 0 {
return false
}
}
return true
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
var count = 0
for i in 1...9 {
count += pow(10, n - 1)
}
for i in 2...9 {
count += pow(10, n - 2)
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
var count = 0
for i in 1...9 {
count += pow(10, n - 1)
}
for i in 2...9 {
count += pow(10, n - 2)
}
return count
}
```count += pow(10, n - 1) // cannot convert value of type 'Decimal' to expected argument type 'Int'count += pow(10, n - 2) // cannot convert value of type 'Decimal' to expected argument type 'Int'func startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * (10 ^ (n - 2)) * 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * (10 ^ (n - 2)) * 10
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 10 * (9 - 1) + 9 * (9 - 1)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 10 * (9 - 1) + 9 * (9 - 1)
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
var count = 0
for i in 1...9 {
count += countHelper(n - 1, i)
}
return count
}
func countHelper(_ n: Int, _ last: Int) -> Int {
if n == 0 {
return 1
}
var count = 0
for i in 0...9 {
if i!= last {
count += countHelper(n - 1, i)
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
var count = 0
for i in 1...9 {
count += countHelper(n - 1, i)
}
return count
}
func countHelper(_ n: Int, _ last: Int) -> Int {
if n == 0 {
return 1
}
var count = 0
for i in 0...9 {
if i!= last {
count += countHelper(n - 1, i)
}
}
return count
}
```if i!= last { // cannot force unwrap value of non-optional type 'Int'if i!= last { // '=' must have consistent whitespace on both sidesif i!= last { // use of '=' in a boolean context, did you mean '=='?func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 10
}
if n == 2 {
return 90
}
return 9 * (10 ^ (n - 2)) * 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 10
}
if n == 2 {
return 90
}
return 9 * (10 ^ (n - 2)) * 10
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * (10 ^ (n - 2)) * 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * (10 ^ (n - 2)) * 10
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 {
return 10
}
if n == 2 {
return 90
}
return 9 * (10 ^ (n - 2)) * 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 {
return 10
}
if n == 2 {
return 90
}
return 9 * (10 ^ (n - 2)) * 10
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * (10 ^ (n - 2)) * 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * (10 ^ (n - 2)) * 10
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * 10^(n-2)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * 10^(n-2)
}
``` // XCTAssertTrue failedfunc startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * (10 ^ (n - 2)) * 10
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
Answer:
```swift
func startsOneEnds(n: Int) -> Int {
if n == 1 { return 10 }
if n == 2 { return 90 }
return 9 * (10 ^ (n - 2)) * 10
}
``` // XCTAssertTrue failed@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let sum = binaryString.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let sum = binaryString.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let sum = binaryString.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binaryString = String(N, radix: 2)
let sum = binaryString.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int(String($1))! }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scope@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int($1.description) }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int($1.description) }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopelet sum = binary.reduce(0) { $0 + Int($1.description) } // value of optional type 'Int?' must be unwrapped to a value of type 'Int'@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int($1.description) }
return String(sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer N, return the total sum of its digits in binary.
Example
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
solve(N: 1000) == "1"
solve(N: 150) == "110"
solve(N: 147) == "1100"
Answer:
```swift
func solve(N: Int) -> String {
let binary = String(N, radix: 2)
let sum = binary.reduce(0) { $0 + Int($1.description) }
return String(sum)
}
```@N integer // cannot find type 'integer' in scope@N integer // unknown attribute 'N'Constraints: 0 ≤ N ≤ 10000. // expected member name following '.'Constraints: 0 ≤ N ≤ 10000. // expected expressionConstraints: 0 ≤ N ≤ 10000. // consecutive statements on a line must be separated by ';'Constraints: 0 ≤ N ≤ 10000. // cannot find 'Constraints' in scopelet sum = binary.reduce(0) { $0 + Int($1.description) } // value of optional type 'Int?' must be unwrapped to a value of type 'Int'func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```func add(lst: [Int]) -> Int {
return lst.enumerated().reduce(0) { (result, element) in
guard element.offset % 2 == 1, element.element % 2 == 0 else {
return result
}
return result + element.element
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().reduce(0) { (result, element) in
guard element.offset % 2 == 1, element.element % 2 == 0 else {
return result
}
return result + element.element
}
}
```func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 1 && $0.element % 2 == 0 }.map { $0.element }.reduce(0, +)
}
```func add(lst: [Int]) -> Int {
return lst.enumerated().reduce(0) { (result, element) in
guard element.offset % 2 == 1, element.element % 2 == 0 else { return result }
return result + element.element
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().reduce(0) { (result, element) in
guard element.offset % 2 == 1, element.element % 2 == 0 else { return result }
return result + element.element
}
}
```func add(lst: [Int]) -> Int {
return lst.enumerated().reduce(0) { (result, element) in
guard element.offset % 2 == 1, element.element % 2 == 0 else { return result }
return result + element.element
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers lst. add the even elements that are at odd indices..
Examples:
add(lst: [4, 2, 6, 7]) == 2
Answer:
```swift
func add(lst: [Int]) -> Int {
return lst.enumerated().reduce(0) { (result, element) in
guard element.offset % 2 == 1, element.element % 2 == 0 else { return result }
return result + element.element
}
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
antiShuffle(s: "Hi") == "Hi"
antiShuffle(s: "hello") == "ehllo"
antiShuffle(s: "Hello World!!!") == "Hello!!!Wdlor"
Answer:
```swift
func antiShuffle(s: String) -> String {
let words = s.components(separatedBy: " ")
var result = ""
for word in words {
let sortedWord = String(word.sorted())
result += "\(sortedWord) "
}
return String(result.dropLast())
}
```func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 }
result.sort(by: { $0.1 > $1.1 })
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 }
result.sort(by: { $0.1 > $1.1 })
return result
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let index = row.firstIndex(of: x) {
result.append((i, index))
}
}
result.sort { $0.0 < $1.0 }
result.sort(by: { $0.1 > $1.1 })
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let index = row.firstIndex(of: x) {
result.append((i, index))
}
}
result.sort { $0.0 < $1.0 }
result.sort(by: { $0.1 > $1.1 })
return result
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let index = row.firstIndex(of: x) {
result.append((i, index))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let index = row.firstIndex(of: x) {
result.append((i, index))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let j = row.firstIndex(of: x) {
result.append((i, j))
}
}
result.sort { $0.0 < $1.0 || ($0.0 == $1.0 && $0.1 > $1.1) }
return result
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let index = row.firstIndex(of: x) {
result.append((i, index))
}
}
result.sort { $0.0 < $1.0 }
result.sort(by: { $0.1 > $1.1 })
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let index = row.firstIndex(of: x) {
result.append((i, index))
}
}
result.sort { $0.0 < $1.0 }
result.sort(by: { $0.1 > $1.1 })
return result
}
``` // XCTAssertTrue failedfunc getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let index = row.firstIndex(of: x) {
result.append((i, index))
}
}
result.sort { $0.0 < $1.0 }
result.sort { $0.1 > $1.1 }
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a 2 dimensional data, as a nested arrays,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the array,
and return array of tuples, [(x1, y1), (x2, y2)...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
getRow(lst: [[1, 2, 3, 4, 5, 6], [1, 2, 3, 4, 1, 6], [1, 2, 3, 4, 5, 1]], x: 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
getRow(lst: [] as [[Int]], x: 1) == [] as [(Int, Int)]
getRow(lst: [[] as [Int], [1], [1, 2, 3]], x: 3) == [(2, 2)]
Answer:
```swift
func getRow(lst: [[Int]], x: Int) -> [(Int, Int)] {
var result: [(Int, Int)] = []
for (i, row) in lst.enumerated() {
if let index = row.firstIndex(of: x) {
result.append((i, index))
}
}
result.sort { $0.0 < $1.0 }
result.sort { $0.1 > $1.1 }
return result
}
``` // XCTAssertTrue failedfunc sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc sortArray(array: [Int]) -> [Int] {
if array.count <= 1 {
return array
}
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
if array.count <= 1 {
return array
}
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
```func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of non-negative integers, return a coswift of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
sortArray(array: [] as [Int]) == [] as [Int]
sortArray(array: [5]) == [5]
sortArray(array: [2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5]
sortArray(array: [2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0]
Answer:
```swift
func sortArray(array: [Int]) -> [Int] {
let sum = array.first! + array.last!
if sum % 2 == 0 {
return array.sorted(by: >)
} else {
return array.sorted()
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
guard let index = alphabet.firstIndex(of: char.lowercased()) else { return char }
let newIndex = (index + 2 * 2) % alphabet.count
return alphabet[newIndex]
}
return String(encrypted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
guard let index = alphabet.firstIndex(of: char.lowercased()) else { return char }
let newIndex = (index + 2 * 2) % alphabet.count
return alphabet[newIndex]
}
return String(encrypted)
}
```guard let index = alphabet.firstIndex(of: char.lowercased()) else { return char } // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % 26
return alphabet[newIndex]
}
return String(encrypted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % 26
return alphabet[newIndex]
}
return String(encrypted)
}
```let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot use optional chaining on non-optional value of type 'String.Index'let index = alphabet.firstIndex(of: char.lowercased())?? 0 // consecutive statements on a line must be separated by ';'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % 26
return alphabet[alphabet.index(alphabet.startIndex, offsetBy: newIndex)]
}
return String(encrypted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % 26
return alphabet[alphabet.index(alphabet.startIndex, offsetBy: newIndex)]
}
return String(encrypted)
}
```let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot use optional chaining on non-optional value of type 'String.Index'let index = alphabet.firstIndex(of: char.lowercased())?? 0 // consecutive statements on a line must be separated by ';'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % alphabet.count
return alphabet[alphabet.index(alphabet.startIndex, offsetBy: newIndex)]
}
return String(encrypted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % alphabet.count
return alphabet[alphabet.index(alphabet.startIndex, offsetBy: newIndex)]
}
return String(encrypted)
}
```let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot use optional chaining on non-optional value of type 'String.Index'let index = alphabet.firstIndex(of: char.lowercased())?? 0 // consecutive statements on a line must be separated by ';'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % 26
return alphabet[alphabet.index(alphabet.startIndex, offsetBy: newIndex)]
}
return String(encrypted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % 26
return alphabet[alphabet.index(alphabet.startIndex, offsetBy: newIndex)]
}
return String(encrypted)
}
```let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot use optional chaining on non-optional value of type 'String.Index'let index = alphabet.firstIndex(of: char.lowercased())?? 0 // consecutive statements on a line must be separated by ';'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = String(s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % alphabet.count
return alphabet[alphabet.index(alphabet.startIndex, offsetBy: newIndex)]
})
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = String(s.map { char in
let index = alphabet.firstIndex(of: char.lowercased())?? 0
let newIndex = (index + 2 * 2) % alphabet.count
return alphabet[alphabet.index(alphabet.startIndex, offsetBy: newIndex)]
})
return encrypted
}
```let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')let index = alphabet.firstIndex(of: char.lowercased())?? 0 // cannot use optional chaining on non-optional value of type 'String.Index'let index = alphabet.firstIndex(of: char.lowercased())?? 0 // consecutive statements on a line must be separated by ';'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
guard let index = alphabet.firstIndex(of: char.lowercased()) else { return char }
let newIndex = (index + 2 * 2) % alphabet.count
return alphabet[newIndex]
}
return String(encrypted)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
let encrypted = s.map { char in
guard let index = alphabet.firstIndex(of: char.lowercased()) else { return char }
let newIndex = (index + 2 * 2) % alphabet.count
return alphabet[newIndex]
}
return String(encrypted)
}
```guard let index = alphabet.firstIndex(of: char.lowercased()) else { return char } // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let newIndex = (index + 2 * 2) % alphabet.count
encrypted.append(alphabet[newIndex])
}
}
return encrypted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encrypted = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let newIndex = (index + 2 * 2) % alphabet.count
encrypted.append(alphabet[newIndex])
}
}
return encrypted
}
```let newIndex = (index + 2 * 2) % alphabet.count // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let newIndex = (index + 2 * 2) % alphabet.count
encryptedString.append(alphabet[newIndex])
}
}
return encryptedString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let newIndex = (index + 2 * 2) % alphabet.count
encryptedString.append(alphabet[newIndex])
}
}
return encryptedString
}
```let newIndex = (index + 2 * 2) % alphabet.count // cannot convert value of type 'String.Index' to expected argument type 'Int'func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let newIndex = (index + 2 * 2) % alphabet.count
encryptedString.append(alphabet[newIndex])
}
}
return encryptedString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt(s: "hi") == "lm"
encrypt(s: "asdfghjkl") == "ewhjklnop"
encrypt(s: "gf") == "kj"
encrypt(s: "et") == "ix"
Answer:
```swift
func encrypt(s: String) -> String {
let alphabet = "abcdefghijklmnopqrstuvwxyz"
var encryptedString = ""
for char in s {
if let index = alphabet.firstIndex(of: char) {
let newIndex = (index + 2 * 2) % alphabet.count
encryptedString.append(alphabet[newIndex])
}
}
return encryptedString
}
```let newIndex = (index + 2 * 2) % alphabet.count // cannot convert value of type 'String.Index' to expected argument type 'Int'func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}
```} else if num < min2 && num!= min1 { // type 'Int' cannot be used as a boolean; test for '!= 0' instead} else if num < min2 && num!= min1 { // cannot force unwrap value of non-optional type 'Int'} else if num < min2 && num!= min1 { // use of '=' in a boolean context, did you mean '=='?} else if num < min2 && num!= min1 { // '=' must have consistent whitespace on both sidesreturn min2 == Int.max? nil : min2 // cannot use optional chaining on non-optional value of type 'Int'return min2 == Int.max? nil : min2 // 'nil' requires a contextual typereturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'return min2 == Int.max? nil : min2 // cannot convert return expression of type 'Bool' to return type 'Int?'return min2 == Int.max? nil : min2 // expected expressionreturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}
```} else if num < min2 && num!= min1 { // type 'Int' cannot be used as a boolean; test for '!= 0' instead} else if num < min2 && num!= min1 { // cannot force unwrap value of non-optional type 'Int'} else if num < min2 && num!= min1 { // use of '=' in a boolean context, did you mean '=='?} else if num < min2 && num!= min1 { // '=' must have consistent whitespace on both sidesreturn min2 == Int.max? nil : min2 // cannot use optional chaining on non-optional value of type 'Int'return min2 == Int.max? nil : min2 // 'nil' requires a contextual typereturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'return min2 == Int.max? nil : min2 // cannot convert return expression of type 'Bool' to return type 'Int?'return min2 == Int.max? nil : min2 // expected expressionreturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}
```} else if num < min2 && num!= min1 { // type 'Int' cannot be used as a boolean; test for '!= 0' instead} else if num < min2 && num!= min1 { // cannot force unwrap value of non-optional type 'Int'} else if num < min2 && num!= min1 { // use of '=' in a boolean context, did you mean '=='?} else if num < min2 && num!= min1 { // '=' must have consistent whitespace on both sidesreturn min2 == Int.max? nil : min2 // cannot use optional chaining on non-optional value of type 'Int'return min2 == Int.max? nil : min2 // 'nil' requires a contextual typereturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'return min2 == Int.max? nil : min2 // cannot convert return expression of type 'Bool' to return type 'Int?'return min2 == Int.max? nil : min2 // expected expressionreturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}
```} else if num < min2 && num!= min1 { // type 'Int' cannot be used as a boolean; test for '!= 0' instead} else if num < min2 && num!= min1 { // cannot force unwrap value of non-optional type 'Int'} else if num < min2 && num!= min1 { // use of '=' in a boolean context, did you mean '=='?} else if num < min2 && num!= min1 { // '=' must have consistent whitespace on both sidesreturn min2 == Int.max? nil : min2 // cannot use optional chaining on non-optional value of type 'Int'return min2 == Int.max? nil : min2 // 'nil' requires a contextual typereturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'return min2 == Int.max? nil : min2 // cannot convert return expression of type 'Bool' to return type 'Int?'return min2 == Int.max? nil : min2 // expected expressionreturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var min1 = lst[0]
var min2 = lst[1]
if min2 < min1 {
min1 = min2
min2 = lst[2]
} else {
min2 = min1
min1 = lst[2]
}
for i in 3..<lst.count {
if lst[i] < min1 {
min2 = min1
min1 = lst[i]
} else if lst[i] < min2 {
min2 = lst[i]
}
}
return min2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
var min1 = lst[0]
var min2 = lst[1]
if min2 < min1 {
min1 = min2
min2 = lst[2]
} else {
min2 = min1
min1 = lst[2]
}
for i in 3..<lst.count {
if lst[i] < min1 {
min2 = min1
min1 = lst[i]
} else if lst[i] < min2 {
min2 = lst[i]
}
}
return min2
}
``` // XCTAssertTrue failedfunc nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}
```} else if num < min2 && num!= min1 { // type 'Int' cannot be used as a boolean; test for '!= 0' instead} else if num < min2 && num!= min1 { // cannot force unwrap value of non-optional type 'Int'} else if num < min2 && num!= min1 { // use of '=' in a boolean context, did you mean '=='?} else if num < min2 && num!= min1 { // '=' must have consistent whitespace on both sidesreturn min2 == Int.max? nil : min2 // cannot use optional chaining on non-optional value of type 'Int'return min2 == Int.max? nil : min2 // 'nil' requires a contextual typereturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'return min2 == Int.max? nil : min2 // cannot convert return expression of type 'Bool' to return type 'Int?'return min2 == Int.max? nil : min2 // expected expressionreturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
let sortedList = lst.sorted()
for i in 0..<sortedList.count - 1 {
if sortedList[i] < sortedList[i + 1] {
return sortedList[i + 1]
}
}
return nil
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
if lst.count < 2 {
return nil
}
let sortedList = lst.sorted()
for i in 0..<sortedList.count - 1 {
if sortedList[i] < sortedList[i + 1] {
return sortedList[i + 1]
}
}
return nil
}
```func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
var min1 = Int.max
var min2 = Int.max
for num in lst {
if num < min1 {
min2 = min1
min1 = num
} else if num < min2 && num!= min1 {
min2 = num
}
}
return min2 == Int.max? nil : min2
}
```} else if num < min2 && num!= min1 { // type 'Int' cannot be used as a boolean; test for '!= 0' instead} else if num < min2 && num!= min1 { // cannot force unwrap value of non-optional type 'Int'} else if num < min2 && num!= min1 { // use of '=' in a boolean context, did you mean '=='?} else if num < min2 && num!= min1 { // '=' must have consistent whitespace on both sidesreturn min2 == Int.max? nil : min2 // cannot use optional chaining on non-optional value of type 'Int'return min2 == Int.max? nil : min2 // 'nil' requires a contextual typereturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'return min2 == Int.max? nil : min2 // cannot convert return expression of type 'Bool' to return type 'Int?'return min2 == Int.max? nil : min2 // expected expressionreturn min2 == Int.max? nil : min2 // consecutive statements on a line must be separated by ';'func nextSmallest(lst: [Int]) -> Int? {
var min1: Int? = nil
var min2: Int? = nil
for num in lst {
if min1 == nil || num <= min1! {
min2 = min1
min1 = num
} else if min2 == nil || num < min2! {
min2 = num
}
}
return min2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
var min1: Int? = nil
var min2: Int? = nil
for num in lst {
if min1 == nil || num <= min1! {
min2 = min1
min1 = num
} else if min2 == nil || num < min2! {
min2 = num
}
}
return min2
}
``` // XCTAssertTrue failedfunc nextSmallest(lst: [Int]) -> Int? {
var min1: Int?
var min2: Int?
for num in lst {
if min1 == nil || num <= min1! {
min2 = min1
min1 = num
} else if min2 == nil || num < min2! {
min2 = num
}
}
return min2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
Write a function next_smallest() that returns the 2nd smallest element of the array.
Return nil if there is no such element.
nextSmallest(lst: [1, 2, 3, 4, 5]) == 2
nextSmallest(lst: [5, 1, 4, 3, 2]) == 2
nextSmallest(lst: [] as [Int]) == nil
nextSmallest(lst: [1, 1]) == nil
Answer:
```swift
func nextSmallest(lst: [Int]) -> Int? {
var min1: Int?
var min2: Int?
for num in lst {
if min1 == nil || num <= min1! {
min2 = min1
min1 = num
} else if min2 == nil || num < min2! {
min2 = num
}
}
return min2
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
```var sentences = S.components(separatedBy: [".", "!", "?"]) // variable 'sentences' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
```var sentences = S.components(separatedBy: [".", "!", "?"]) // variable 'sentences' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc isBored(S: String) -> Int {
var sentences = S.components(separatedBy: [".", "!", "?"])
var boredoms = 0
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
var sentences = S.components(separatedBy: [".", "!", "?"])
var boredoms = 0
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
```var sentences = S.components(separatedBy: [".", "!", "?"]) // variable 'sentences' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "!", "?"])
return sentences.filter { $0.trimmingCharacters(in:.whitespaces).hasPrefix("I") }.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "!", "?"])
return sentences.filter { $0.trimmingCharacters(in:.whitespaces).hasPrefix("I") }.count
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "!", "?"])
return sentences.filter { $0.trimmingCharacters(in:.whitespacesAndNewlines).hasPrefix("I") }.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "!", "?"])
return sentences.filter { $0.trimmingCharacters(in:.whitespacesAndNewlines).hasPrefix("I") }.count
}
``` // XCTAssertTrue failedfunc isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
```var sentences = S.components(separatedBy: [".", "!", "?"]) // variable 'sentences' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
```var sentences = S.components(separatedBy: [".", "!", "?"]) // variable 'sentences' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
```var sentences = S.components(separatedBy: [".", "!", "?"]) // variable 'sentences' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
var boredoms = 0
var sentences = S.components(separatedBy: [".", "!", "?"])
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
```var sentences = S.components(separatedBy: [".", "!", "?"]) // variable 'sentences' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "!", "?"])
var boredoms = 0
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
isBored(S: "Hello world") == 0
isBored(S: "The sky is blue. The sun is shining. I love this weather") == 1
Answer:
```swift
func isBored(S: String) -> Int {
let sentences = S.components(separatedBy: [".", "!", "?"])
var boredoms = 0
for sentence in sentences {
let trimmedSentence = sentence.trimmingCharacters(in:.whitespacesAndNewlines)
if trimmedSentence.hasPrefix("I") {
boredoms += 1
}
}
return boredoms
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
} else {
return false
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
} else {
return false
}
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}
``` // XCTAssertTrue failedfunc anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
anyInt(x: 5, y: 2, z: 7) == true
anyInt(x: 3, y: 2, z: 2) == false
anyInt(x: 3, y: -2, z: 1) == true
anyInt(x: 3.6, y: -2.2, z: 2) == false
Answer:
```swift
func anyInt(x: Double, y: Double, z: Double) -> Bool {
let sum = x + y
if sum == z || sum == x || sum == y {
return true
}
let sum2 = x + z
if sum2 == y || sum2 == x || sum2 == z {
return true
}
let sum3 = y + z
if sum3 == x || sum3 == y || sum3 == z {
return true
}
return false
}
``` // XCTAssertTrue failedfunc encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let uppercase = character.isUppercase
let shiftedCharacter = character.shifted(by: uppercase? 26 : 0)
if vowels.contains(character) {
encodedMessage.append(shiftedCharacter.shifted(by: 2))
} else {
encodedMessage.append(shiftedCharacter)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let uppercase = character.isUppercase
let shiftedCharacter = character.shifted(by: uppercase? 26 : 0)
if vowels.contains(character) {
encodedMessage.append(shiftedCharacter.shifted(by: 2))
} else {
encodedMessage.append(shiftedCharacter)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```let shiftedCharacter = character.shifted(by: uppercase? 26 : 0) // value of type 'Character' has no member 'shifted'let shiftedCharacter = character.shifted(by: uppercase? 26 : 0) // cannot use optional chaining on non-optional value of type 'Bool'let shiftedCharacter = character.shifted(by: uppercase? 26 : 0) // expected ',' separatorfunc encode(message: String) -> String {
let vowels = "aeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercasedCharacter = character.lowercased()
let uppercasedCharacter = character.uppercased()
if vowels.contains(lowercasedCharacter) {
let vowelIndex = vowels.firstIndex(of: lowercasedCharacter)!
let encodedVowel = vowels[(vowelIndex + 2) % vowels.count]
encodedMessage.append(encodedVowel.uppercased())
} else {
encodedMessage.append(uppercasedCharacter)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "aeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercasedCharacter = character.lowercased()
let uppercasedCharacter = character.uppercased()
if vowels.contains(lowercasedCharacter) {
let vowelIndex = vowels.firstIndex(of: lowercasedCharacter)!
let encodedVowel = vowels[(vowelIndex + 2) % vowels.count]
encodedMessage.append(encodedVowel.uppercased())
} else {
encodedMessage.append(uppercasedCharacter)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```let vowelIndex = vowels.firstIndex(of: lowercasedCharacter)! // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercased = character.lowercased()
let uppercased = character.uppercased()
if vowels.contains(lowercased) {
let index = vowels.firstIndex(of: lowercased)!
let newIndex = index + 2
let newCharacter = vowels[newIndex]
encodedMessage.append(newCharacter.uppercased())
} else {
encodedMessage.append(uppercased)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercased = character.lowercased()
let uppercased = character.uppercased()
if vowels.contains(lowercased) {
let index = vowels.firstIndex(of: lowercased)!
let newIndex = index + 2
let newCharacter = vowels[newIndex]
encodedMessage.append(newCharacter.uppercased())
} else {
encodedMessage.append(uppercased)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```let index = vowels.firstIndex(of: lowercased)! // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercasedCharacter = character.lowercased()
let uppercasedCharacter = character.uppercased()
if vowels.contains(lowercasedCharacter) {
let vowelIndex = vowels.firstIndex(of: lowercasedCharacter)!
let encodedVowel = vowels[(vowelIndex + 2) % vowels.count]
encodedMessage.append(encodedVowel.uppercased())
} else {
encodedMessage.append(uppercasedCharacter)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercasedCharacter = character.lowercased()
let uppercasedCharacter = character.uppercased()
if vowels.contains(lowercasedCharacter) {
let vowelIndex = vowels.firstIndex(of: lowercasedCharacter)!
let encodedVowel = vowels[(vowelIndex + 2) % vowels.count]
encodedMessage.append(encodedVowel.uppercased())
} else {
encodedMessage.append(uppercasedCharacter)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```let vowelIndex = vowels.firstIndex(of: lowercasedCharacter)! // cannot convert value of type 'String' to expected argument type 'Character'func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercasedCharacter = character.lowercased()
let uppercasedCharacter = character.uppercased()
if vowels.contains(lowercasedCharacter) {
let index = vowels.firstIndex(of: lowercasedCharacter)!
let encodedVowel = vowels[(index + 2) % vowels.count]
encodedMessage.append(encodedVowel.uppercased())
} else {
encodedMessage.append(uppercasedCharacter)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels: [Character] = ["a", "e", "i", "o", "u"]
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercasedCharacter = character.lowercased()
let uppercasedCharacter = character.uppercased()
if vowels.contains(lowercasedCharacter) {
let index = vowels.firstIndex(of: lowercasedCharacter)!
let encodedVowel = vowels[(index + 2) % vowels.count]
encodedMessage.append(encodedVowel.uppercased())
} else {
encodedMessage.append(uppercasedCharacter)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```let index = vowels.firstIndex(of: lowercasedCharacter)! // cannot convert value of type 'String' to expected argument type 'Character'func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let uppercase = character.isUppercase
let shiftedCharacter: Character
if vowels.contains(character) {
shiftedCharacter = vowels[(vowels.firstIndex(of: character)! + 2) % vowels.count]
} else {
shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased()
}
encodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased())
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let uppercase = character.isUppercase
let shiftedCharacter: Character
if vowels.contains(character) {
shiftedCharacter = vowels[(vowels.firstIndex(of: character)! + 2) % vowels.count]
} else {
shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased()
}
encodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased())
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```shiftedCharacter = vowels[(vowels.firstIndex(of: character)! + 2) % vowels.count] // cannot convert value of type 'String.Index' to expected argument type 'Int'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // consecutive statements on a line must be separated by ';'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // binary operator '==' cannot be applied to operands of type 'String' and 'Character?'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // cannot use optional chaining on non-optional value of type 'Character'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // cannot assign value of type 'Bool' to type 'Character'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // consecutive statements on a line must be separated by ';'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // result of call to 'uppercased()' is unusedshiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // expected expressionencodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased()) // cannot use optional chaining on non-optional value of type 'Bool'encodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased()) // no exact matches in call to instance method 'append'encodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased()) // expected ',' separatorfunc encode(message: String) -> String {
let vowels = "aeiouAEIOU"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercased = character.lowercased()
let uppercased = character.uppercased()
if vowels.contains(lowercased) {
let index = vowels.firstIndex(of: lowercased)!
let encodedVowel = vowels[vowels.index(index, offsetBy: 2)]
encodedMessage.append(encodedVowel.uppercased())
} else if let index = vowels.firstIndex(of: uppercased) {
let encodedVowel = vowels[vowels.index(index, offsetBy: 2)]
encodedMessage.append(encodedVowel.lowercased())
} else {
encodedMessage.append(character)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "aeiouAEIOU"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercased = character.lowercased()
let uppercased = character.uppercased()
if vowels.contains(lowercased) {
let index = vowels.firstIndex(of: lowercased)!
let encodedVowel = vowels[vowels.index(index, offsetBy: 2)]
encodedMessage.append(encodedVowel.uppercased())
} else if let index = vowels.firstIndex(of: uppercased) {
let encodedVowel = vowels[vowels.index(index, offsetBy: 2)]
encodedMessage.append(encodedVowel.lowercased())
} else {
encodedMessage.append(character)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```let index = vowels.firstIndex(of: lowercased)! // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')} else if let index = vowels.firstIndex(of: uppercased) { // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercased = character.lowercased()
let uppercased = character.uppercased()
if vowels.contains(lowercased) {
let index = vowels.firstIndex(of: lowercased)!
let newIndex = index + 2
let newCharacter = vowels[newIndex]
encodedMessage.append(newCharacter.uppercased())
} else {
encodedMessage.append(uppercased)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercased = character.lowercased()
let uppercased = character.uppercased()
if vowels.contains(lowercased) {
let index = vowels.firstIndex(of: lowercased)!
let newIndex = index + 2
let newCharacter = vowels[newIndex]
encodedMessage.append(newCharacter.uppercased())
} else {
encodedMessage.append(uppercased)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```let index = vowels.firstIndex(of: lowercased)! // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercased = character.lowercased()
let uppercased = character.uppercased()
if vowels.contains(lowercased) {
let index = vowels.firstIndex(of: lowercased)!
let encodedVowel = vowels[vowels.index(index, offsetBy: 2)]
encodedMessage.append(encodedVowel.uppercased())
} else {
encodedMessage.append(uppercased)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let lowercased = character.lowercased()
let uppercased = character.uppercased()
if vowels.contains(lowercased) {
let index = vowels.firstIndex(of: lowercased)!
let encodedVowel = vowels[vowels.index(index, offsetBy: 2)]
encodedMessage.append(encodedVowel.uppercased())
} else {
encodedMessage.append(uppercased)
}
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```let index = vowels.firstIndex(of: lowercased)! // cannot convert value of type 'String' to expected argument type 'String.Element' (aka 'Character')func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let uppercase = character.isUppercase
let shiftedCharacter: Character
if vowels.contains(character) {
shiftedCharacter = vowels[(vowels.firstIndex(of: character)! + 2) % vowels.count]
} else {
shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased()
}
encodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased())
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
encode(message: "test") == "TGST"
encode(message: "This is a message") == "tHKS KS C MGSSCGG"
Answer:
```swift
func encode(message: String) -> String {
let vowels = "AEIOUaeiou"
var encodedMessage = ""
for character in message {
if character.isLetter {
let uppercase = character.isUppercase
let shiftedCharacter: Character
if vowels.contains(character) {
shiftedCharacter = vowels[(vowels.firstIndex(of: character)! + 2) % vowels.count]
} else {
shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased()
}
encodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased())
} else {
encodedMessage.append(character)
}
}
return encodedMessage
}
```shiftedCharacter = vowels[(vowels.firstIndex(of: character)! + 2) % vowels.count] // cannot convert value of type 'String.Index' to expected argument type 'Int'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // consecutive statements on a line must be separated by ';'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // binary operator '==' cannot be applied to operands of type 'String' and 'Character?'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // cannot use optional chaining on non-optional value of type 'Character'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // cannot assign value of type 'Bool' to type 'Character'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // consecutive statements on a line must be separated by ';'shiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // result of call to 'uppercased()' is unusedshiftedCharacter = character.lowercased() == character? character.uppercased() : character.lowercased() // expected expressionencodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased()) // cannot use optional chaining on non-optional value of type 'Bool'encodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased()) // no exact matches in call to instance method 'append'encodedMessage.append(uppercase? shiftedCharacter.uppercased() : shiftedCharacter.lowercased()) // expected ',' separatorfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var largestPrime = 0
for num in lst {
if primes.contains(num) && num > largestPrime {
largestPrime = num
}
}
var sum = 0
while largestPrime > 0 {
sum += largestPrime % 10
largestPrime /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var largestPrime = 0
for num in lst {
if primes.contains(num) && num > largestPrime {
largestPrime = num
}
}
var sum = 0
while largestPrime > 0 {
sum += largestPrime % 10
largestPrime /= 10
}
return sum
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
var largestPrime = 0
for num in lst {
if primes.contains(num) && num > largestPrime {
largestPrime = num
}
}
let sumOfDigits = largestPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
var largestPrime = 0
for num in lst {
if primes.contains(num) && num > largestPrime {
largestPrime = num
}
}
let sumOfDigits = largestPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
let sumOfDigits = maxPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
let sumOfDigits = maxPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
let sumOfDigits = maxPrime.description.map { Int(String($0))! }.reduce(0, +)
return sumOfDigits
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
let sumOfDigits = maxPrime.description.map { Int(String($0))! }.reduce(0, +)
return sumOfDigits
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
let sumOfDigits = maxPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
let sumOfDigits = maxPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
var sum = 0
while maxPrime > 0 {
sum += maxPrime % 10
maxPrime /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
var sum = 0
while maxPrime > 0 {
sum += maxPrime % 10
maxPrime /= 10
}
return sum
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var largestPrime = 0
for num in lst {
if primes.contains(num) && num > largestPrime {
largestPrime = num
}
}
var sumOfDigits = 0
var temp = largestPrime
while temp > 0 {
sumOfDigits += temp % 10
temp /= 10
}
return sumOfDigits
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var largestPrime = 0
for num in lst {
if primes.contains(num) && num > largestPrime {
largestPrime = num
}
}
var sumOfDigits = 0
var temp = largestPrime
while temp > 0 {
sumOfDigits += temp % 10
temp /= 10
}
return sumOfDigits
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
let sumOfDigits = maxPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var maxPrime = 0
for num in lst {
if primes.contains(num) && num > maxPrime {
maxPrime = num
}
}
let sumOfDigits = maxPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var largestPrime = 0
for num in lst {
if primes.contains(num) && num > largestPrime {
largestPrime = num
}
}
let sumOfDigits = largestPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var largestPrime = 0
for num in lst {
if primes.contains(num) && num > largestPrime {
largestPrime = num
}
}
let sumOfDigits = largestPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}
``` // XCTAssertTrue failedfunc skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var largestPrime = 0
for number in lst {
if primes.contains(number) && number > largestPrime {
largestPrime = number
}
}
let sumOfDigits = largestPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
skjkasdkd(lst: [0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) == 10
skjkasdkd(lst: [1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) == 25
skjkasdkd(lst: [1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) == 13
skjkasdkd(lst: [0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) == 11
skjkasdkd(lst: [0, 81, 12, 3, 1, 21]) == 3
skjkasdkd(lst: [0, 8, 1, 2, 1, 7]) == 7
Answer:
```swift
func skjkasdkd(lst: [Int]) -> Int {
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997]
var largestPrime = 0
for number in lst {
if primes.contains(number) && number > largestPrime {
largestPrime = number
}
}
let sumOfDigits = largestPrime.description.reduce(0) { $0 + Int(String($1))! }
return sumOfDigits
}
``` // XCTAssertTrue failedfunc countUpTo(n: Int) -> [Int] {
var primes: [Int] = []
for i in 0..<n {
if isPrime(i) {
primes.append(i)
}
}
return primes
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes: [Int] = []
for i in 0..<n {
if isPrime(i) {
primes.append(i)
}
}
return primes
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while numbers.count > 0 {
let current = numbers.first!
primes.append(current)
numbers = numbers.filter { $0 % current!= 0 }
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while numbers.count > 0 {
let current = numbers.first!
primes.append(current)
numbers = numbers.filter { $0 % current!= 0 }
}
return primes
}
```numbers = numbers.filter { $0 % current!= 0 } // cannot convert value of type '()' to closure result type 'Bool'numbers = numbers.filter { $0 % current!= 0 } // cannot force unwrap value of non-optional type 'Int'numbers = numbers.filter { $0 % current!= 0 } // '=' must have consistent whitespace on both sidesfunc countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while numbers.count > 0 {
let prime = numbers.first!
primes.append(prime)
numbers = numbers.filter { $0 % prime!= 0 }
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while numbers.count > 0 {
let prime = numbers.first!
primes.append(prime)
numbers = numbers.filter { $0 % prime!= 0 }
}
return primes
}
```numbers = numbers.filter { $0 % prime!= 0 } // '=' must have consistent whitespace on both sidesnumbers = numbers.filter { $0 % prime!= 0 } // cannot convert value of type '()' to closure result type 'Bool'numbers = numbers.filter { $0 % prime!= 0 } // cannot force unwrap value of non-optional type 'Int'func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while!numbers.isEmpty {
let smallest = numbers.first!
primes.append(smallest)
numbers = numbers.filter { $0 % smallest!= 0 }
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while!numbers.isEmpty {
let smallest = numbers.first!
primes.append(smallest)
numbers = numbers.filter { $0 % smallest!= 0 }
}
return primes
}
```while!numbers.isEmpty { // expected expression, var, or let in 'while' conditionnumbers = numbers.filter { $0 % smallest!= 0 } // '=' must have consistent whitespace on both sidesfunc countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while numbers.count > 0 {
let prime = numbers.first!
primes.append(prime)
numbers = numbers.filter { $0 % prime!= 0 }
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while numbers.count > 0 {
let prime = numbers.first!
primes.append(prime)
numbers = numbers.filter { $0 % prime!= 0 }
}
return primes
}
```numbers = numbers.filter { $0 % prime!= 0 } // '=' must have consistent whitespace on both sidesnumbers = numbers.filter { $0 % prime!= 0 } // cannot convert value of type '()' to closure result type 'Bool'numbers = numbers.filter { $0 % prime!= 0 } // cannot force unwrap value of non-optional type 'Int'func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while!numbers.isEmpty {
let prime = numbers.removeFirst()
primes.append(prime)
numbers = numbers.filter { $0 % prime!= 0 }
}
return primes
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
var numbers = Array(2..<n)
while!numbers.isEmpty {
let prime = numbers.removeFirst()
primes.append(prime)
numbers = numbers.filter { $0 % prime!= 0 }
}
return primes
}
```while!numbers.isEmpty { // expected expression, var, or let in 'while' conditionnumbers = numbers.filter { $0 % prime!= 0 } // '=' must have consistent whitespace on both sidesfunc countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var numbers = Array(2...n)
for i in 2..<n {
if numbers[i] == 0 { continue }
for j in stride(from: i*i, through: n, by: i) {
numbers[j] = 0
}
}
return numbers.compactMap { $0 }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var numbers = Array(2...n)
for i in 2..<n {
if numbers[i] == 0 { continue }
for j in stride(from: i*i, through: n, by: i) {
numbers[j] = 0
}
}
return numbers.compactMap { $0 }
}
``` // Fatal error: Index out of rangefunc countUpTo(n: Int) -> [Int] {
var primes: [Int] = []
var number = 2
while number < n {
if isPrime(number) {
primes.append(number)
}
number += 1
}
return primes
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes: [Int] = []
var number = 2
while number < n {
if isPrime(number) {
primes.append(number)
}
number += 1
}
return primes
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
if number <= 3 {
return true
}
if number % 2 == 0 || number % 3 == 0 {
return false
}
var i = 5
while i * i <= number {
if number % i == 0 || number % (i + 2) == 0 {
return false
}
i += 6
}
return true
}
```func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
for i in 2..<n {
if isPrime(i) {
primes.append(i)
}
}
return primes
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
guard n > 1 else { return [] }
var primes: [Int] = []
for i in 2..<n {
if isPrime(i) {
primes.append(i)
}
}
return primes
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func countUpTo(n: Int) -> [Int] {
var primes: [Int] = []
for i in 2..<n {
if isPrime(i) {
primes.append(i)
}
}
return primes
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
countUpTo(n: 5) == [2, 3]
countUpTo(n: 11) == [2, 3, 5, 7]
countUpTo(n: 0) == [] as [Int]
countUpTo(n: 20) == [2, 3, 5, 7, 11, 13, 17, 19]
countUpTo(n: 1) == [] as [Int]
countUpTo(n: 18) == [2, 3, 5, 7, 11, 13, 17]
Answer:
```swift
func countUpTo(n: Int) -> [Int] {
var primes: [Int] = []
for i in 2..<n {
if isPrime(i) {
primes.append(i)
}
}
return primes
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(a: 148, b: 412) == 16
multiply(a: 19, b: 28) == 72
multiply(a: 2020, b: 1851) == 0
multiply(a: 14, b: -15) == 20
Answer:
```swift
func multiply(a: Int, b: Int) -> Int {
let unitDigitA = a % 10
let unitDigitB = b % 10
return unitDigitA * unitDigitB
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && vowels.contains(character.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && vowels.contains(character.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels = "AEIOU"
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels = "AEIOU"
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels = "AEIOU"
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels = "AEIOU"
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && vowels.contains(character.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, character) in s.enumerated() {
if index % 2 == 0 && vowels.contains(character.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s, count the number of uppercase vowels in even indices.
For example:
countUpper(s: "aBCdEf") == 1
countUpper(s: "abcdefg") == 0
countUpper(s: "dBBE") == 0
Answer:
```swift
func countUpper(s: String) -> Int {
let vowels: Set<Character> = ["A", "E", "I", "O", "U"]
var count = 0
for (index, char) in s.enumerated() {
if index % 2 == 0 && vowels.contains(char.uppercased()) {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
let roundedInt = Int(rounded)
return roundedInt
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
let roundedInt = Int(rounded)
return roundedInt
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
let roundedInt = Int(rounded)
return roundedInt
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
let roundedInt = Int(rounded)
return roundedInt
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
return Int(rounded)
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
let roundedInt = Int(rounded)
return roundedInt
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
closestInteger(value: "10") == 10
closestInteger(value: "15.3") == 15
Answer:
```swift
func closestInteger(value: String) -> Int {
let number = Double(value)?? 0.0
let rounded = round(number)
let roundedInt = Int(rounded)
return roundedInt
}
```let number = Double(value)?? 0.0 // floating-point literal is unusedlet number = Double(value)?? 0.0 // consecutive statements on a line must be separated by ';'let number = Double(value)?? 0.0 // cannot use optional chaining on non-optional value of type 'Double'func makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}
```current = current % 2 == 0? current - 2 : current - 1 // result of operator '-' is unusedcurrent = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 2 : current - 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 2 : current - 1 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 1 : current + 1
result.append(current)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 1 : current + 1
result.append(current)
}
return result
}
```current = current % 2 == 0? current - 1 : current + 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 1 : current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 1 : current + 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 1 : current + 1 // expected expressioncurrent = current % 2 == 0? current - 1 : current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 1 : current + 1 // result of operator '-' is unusedfunc makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 1 : current + 1
result.append(current)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 1 : current + 1
result.append(current)
}
return result
}
```current = current % 2 == 0? current - 1 : current + 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 1 : current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 1 : current + 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 1 : current + 1 // expected expressioncurrent = current % 2 == 0? current - 1 : current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 1 : current + 1 // result of operator '-' is unusedfunc makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}
```current = current % 2 == 0? current - 2 : current - 1 // result of operator '-' is unusedcurrent = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 2 : current - 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 2 : current - 1 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}
```current = current % 2 == 0? current - 2 : current - 1 // result of operator '-' is unusedcurrent = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 2 : current - 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 2 : current - 1 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var piles = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 1 : current + 1
piles.append(current)
}
return piles
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var piles = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 1 : current + 1
piles.append(current)
}
return piles
}
```current = current % 2 == 0? current - 1 : current + 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 1 : current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 1 : current + 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 1 : current + 1 // expected expressioncurrent = current % 2 == 0? current - 1 : current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 1 : current + 1 // result of operator '-' is unusedfunc makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}
```current = current % 2 == 0? current - 2 : current - 1 // result of operator '-' is unusedcurrent = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 2 : current - 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 2 : current - 1 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
result.append(current)
}
return result
}
```current = current % 2 == 0? current - 2 : current - 1 // result of operator '-' is unusedcurrent = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 2 : current - 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 2 : current - 1 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var piles = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
piles.append(current)
}
return piles
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var piles = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 2 : current - 1
piles.append(current)
}
return piles
}
```current = current % 2 == 0? current - 2 : current - 1 // result of operator '-' is unusedcurrent = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 2 : current - 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 2 : current - 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 2 : current - 1 // expected expressionfunc makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 1 : current + 1
result.append(current)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in an array, where element at index
i represents the number of stones in the level (i+1).
Examples:
makeAPile(n: 3) == [3, 5, 7]
Answer:
```swift
func makeAPile(n: Int) -> [Int] {
var result = [n]
var current = n
while current > 1 {
current = current % 2 == 0? current - 1 : current + 1
result.append(current)
}
return result
}
```current = current % 2 == 0? current - 1 : current + 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current - 1 : current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 1 : current + 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current - 1 : current + 1 // expected expressioncurrent = current % 2 == 0? current - 1 : current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current - 1 : current + 1 // result of operator '-' is unusedfunc wordsString(s: String) -> [String] {
return s.split(separator: ",").map { String($0.split(separator: " ")) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.split(separator: ",").map { String($0.split(separator: " ")) }
}
```return s.split(separator: ",").map { String($0.split(separator: " ")) } // no exact matches in call to initializerfunc wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
return s.split(separator: ",").map { String($0.split(separator: " ")) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.split(separator: ",").map { String($0.split(separator: " ")) }
}
```return s.split(separator: ",").map { String($0.split(separator: " ")) } // no exact matches in call to initializerfunc wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
return s.split(separator: ",").map { String($0.trimmingCharacters(in:.whitespaces)) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.split(separator: ",").map { String($0.trimmingCharacters(in:.whitespaces)) }
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.components(separatedBy: ", ")
}
``` // XCTAssertTrue failedfunc wordsString(s: String) -> [String] {
return s.split(separator: ",").flatMap { $0.trimmingCharacters(in:.whitespaces).split(separator: " ") }.map(String.init)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.split(separator: ",").flatMap { $0.trimmingCharacters(in:.whitespaces).split(separator: " ") }.map(String.init)
}
```func wordsString(s: String) -> [String] {
return s.split(separator: ",").map { String($0.trimmingCharacters(in:.whitespaces)) }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
wordsString(s: "Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
wordsString(s: "One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
Answer:
```swift
func wordsString(s: String) -> [String] {
return s.split(separator: ",").map { String($0.trimmingCharacters(in:.whitespaces)) }
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
for i in stride(from: y, through: x, by: -2) {
return i
}
return -1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
for i in stride(from: y, through: x, by: -2) {
return i
}
return -1
}
``` // XCTAssertTrue failedfunc chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 && i > result {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 && i > result {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 && i > result {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 && i > result {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
chooseNum(x: 12, y: 15) == 14
chooseNum(x: 13, y: 12) == -1
Answer:
```swift
func chooseNum(x: Int, y: Int) -> Int {
var result = -1
for i in x...y {
if i % 2 == 0 {
result = i
}
}
return result
}
``` // Fatal error: Range requires lowerBound <= upperBoundextension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let sum = Int(Double(n + m) * 0.5)
let binary = String(format: "0b%08d", sum)
return.success(binary)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let sum = Int(Double(n + m) * 0.5)
let binary = String(format: "0b%08d", sum)
return.success(binary)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let sum = (n...m).reduce(0, +)
let avg = sum / (m - n + 1)
let rounded = Int(round(Double(avg)))
return.success("0b\(String(rounded, radix: 2))")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let sum = (n...m).reduce(0, +)
let avg = sum / (m - n + 1)
let rounded = Int(round(Double(avg)))
return.success("0b\(String(rounded, radix: 2))")
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let sum = (n...m).reduce(0, +)
let avg = sum / (m - n + 1)
let rounded = Int(round(Double(avg)))
return.success("0b\(String(rounded, radix: 2))")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let sum = (n...m).reduce(0, +)
let avg = sum / (m - n + 1)
let rounded = Int(round(Double(avg)))
return.success("0b\(String(rounded, radix: 2))")
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let sum = Int(Double(n + m) / 2.0).rounded(.toNearestOrEven)
return.success(String(format: "0b%064b", sum))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let sum = Int(Double(n + m) / 2.0).rounded(.toNearestOrEven)
return.success(String(format: "0b%064b", sum))
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let sum = Int(Double(n + m) / 2.0).rounded(.toNearestOrEven) // value of type 'Int' has no member 'rounded'let sum = Int(Double(n + m) / 2.0).rounded(.toNearestOrEven) // cannot infer contextual base in reference to member 'toNearestOrEven'extension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = Int(round(avg))
return.success(String(rounded, radix: 2))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = Int(round(avg))
return.success(String(rounded, radix: 2))
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // no exact matches in call to initializerlet avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // reference to member 'reduce' cannot be resolved without a contextual typeextension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = round(avg)
return.success(String(rounded, radix: 2))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = round(avg)
return.success(String(rounded, radix: 2))
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // no exact matches in call to initializerlet avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // reference to member 'reduce' cannot be resolved without a contextual typeextension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = Int(round(avg))
return.success(String(rounded, radix: 2))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = Int(round(avg))
return.success(String(rounded, radix: 2))
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // no exact matches in call to initializerlet avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // reference to member 'reduce' cannot be resolved without a contextual typeextension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = Int(round(avg))
return.success(String(rounded, radix: 2))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = Int(round(avg))
return.success(String(rounded, radix: 2))
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // no exact matches in call to initializerlet avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // reference to member 'reduce' cannot be resolved without a contextual typeextension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = Int(round(avg))
return.success(String(rounded, radix: 2))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, +) / Double(m - n + 1)
let rounded = Int(round(avg))
return.success(String(rounded, radix: 2))
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // no exact matches in call to initializerlet avg = Double(n...m).reduce(0, +) / Double(m - n + 1) // reference to member 'reduce' cannot be resolved without a contextual typeextension Int: Error {
}
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, { $0 + Double($1) }) / Double(m - n + 1)
let rounded = round(avg)
return.success(String(format: "0b%01d", rounded))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
roundedAvg(n: 1, m: 5) ==.success("0b11")
roundedAvg(n: 7, m: 5) ==.failure(-1)
roundedAvg(n: 10, m: 20) ==.success("0b1111")
roundedAvg(n: 20, m: 33) ==.success("0b11010")
Answer:
```swift
extension Int: Error {}
func roundedAvg(n: Int, m: Int) -> Result<String, Int> {
guard n <= m else { return.failure(n) }
let avg = Double(n...m).reduce(0, { $0 + Double($1) }) / Double(m - n + 1)
let rounded = round(avg)
return.success(String(format: "0b%01d", rounded))
}
```func uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for i in 0..<sorted.count {
let number = sorted[i]
if String(number).contains(where: { $0 == "2" || $0 == "4" || $0 == "6" || $0 == "8" }) {
continue
}
result.append(number)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for i in 0..<sorted.count {
let number = sorted[i]
if String(number).contains(where: { $0 == "2" || $0 == "4" || $0 == "6" || $0 == "8" }) {
continue
}
result.append(number)
}
return result
}
``` // XCTAssertTrue failedfunc uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for num in sorted {
if String(num).contains(where: "02468".contains) { continue }
result.append(num)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for num in sorted {
if String(num).contains(where: "02468".contains) { continue }
result.append(num)
}
return result
}
```func uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for num in sorted {
if String(num).contains(where: { $0.wholeNumberValue! % 2 == 0 }) {
continue
}
result.append(num)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for num in sorted {
if String(num).contains(where: { $0.wholeNumberValue! % 2 == 0 }) {
continue
}
result.append(num)
}
return result
}
```func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
if String(num).filter("02468".contains).isEmpty {
result.append(num)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
var result = [Int]()
for num in x {
if String(num).filter("02468".contains).isEmpty {
result.append(num)
}
}
return result.sorted()
}
```func uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for number in sorted {
if String(number).filter("02468".contains).isEmpty {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for number in sorted {
if String(number).filter("02468".contains).isEmpty {
result.append(number)
}
}
return result
}
```func uniqueDigits(x: [Int]) -> [Int] {
let evenDigits = Set("02468")
return x.filter { number in
let digits = String(number).compactMap { Int(String($0)) }
return digits.contains(where: {!evenDigits.contains(String($0)) })
}.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let evenDigits = Set("02468")
return x.filter { number in
let digits = String(number).compactMap { Int(String($0)) }
return digits.contains(where: {!evenDigits.contains(String($0)) })
}.sorted()
}
``` // XCTAssertTrue failedfunc uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for number in sorted {
if String(number).filter("02468".contains).isEmpty {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for number in sorted {
if String(number).filter("02468".contains).isEmpty {
result.append(number)
}
}
return result
}
```func uniqueDigits(x: [Int]) -> [Int] {
let evenDigits = Set("02468")
return x.filter { number in
let digits = String(number).compactMap { Int(String($0)) }
return digits.contains(where: {!evenDigits.contains(String($0)) })
}.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let evenDigits = Set("02468")
return x.filter { number in
let digits = String(number).compactMap { Int(String($0)) }
return digits.contains(where: {!evenDigits.contains(String($0)) })
}.sorted()
}
``` // XCTAssertTrue failedfunc uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for number in sorted {
if String(number).filter("02468".contains).isEmpty {
result.append(number)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let sorted = x.sorted()
var result: [Int] = []
for number in sorted {
if String(number).filter("02468".contains).isEmpty {
result.append(number)
}
}
return result
}
```func uniqueDigits(x: [Int]) -> [Int] {
let evenDigits = Set("02468")
return x.filter { number in
let digits = String(number).compactMap { Int(String($0)) }
return digits.contains(where: {!evenDigits.contains(String($0)) })
}.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of positive integers x. return a sorted array of all
elements that hasn't any even digit.
Note: Returned array should be sorted in increasing order.
For example:
uniqueDigits(x: [15, 33, 1422, 1]) == [1, 15, 33]
uniqueDigits(x: [152, 323, 1422, 10]) == [] as [Int]
Answer:
```swift
func uniqueDigits(x: [Int]) -> [Int] {
let evenDigits = Set("02468")
return x.filter { number in
let digits = String(number).compactMap { Int(String($0)) }
return digits.contains(where: {!evenDigits.contains(String($0)) })
}.sorted()
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let between1and9 = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = between1and9.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0 - 1] }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let between1and9 = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = between1and9.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0 - 1] }
return named
}
```func byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let between1and9 = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = between1and9.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let between1and9 = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = between1and9.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let between1And9 = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = between1And9.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0 - 1] }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let between1And9 = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = between1And9.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0 - 1] }
return named
}
```func byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0 - 1] }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = ["One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0 - 1] }
return named
}
```func byLength(arr: [Int]) -> [String] {
let numbers = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0]! }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = [1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0]! }
return named
}
```func byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}
``` // XCTAssertTrue failedfunc byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
If the array is empty, return an empty array:
If the array has any strange number ignore it:
byLength(arr: [2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]
byLength(arr: [] as [Int]) == [] as [String]
byLength(arr: [1, -1, 55]) == ["One"]
Answer:
```swift
func byLength(arr: [Int]) -> [String] {
let numbers = ["", "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"]
let filtered = arr.filter { $0 >= 1 && $0 <= 9 }
let sorted = filtered.sorted()
let reversed = sorted.reversed()
let named = reversed.map { numbers[$0] }
return named
}
``` // XCTAssertTrue failedfunc f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i + 1)
} else {
result[i] = sum(1...(i + 1))
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ range: CountableRange<Int>) -> Int {
return range.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i + 1)
} else {
result[i] = sum(1...(i + 1))
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ range: CountableRange<Int>) -> Int {
return range.reduce(0, +)
}
```result[i] = sum(1...(i + 1)) // cannot convert value of type 'ClosedRange<Int>' to expected argument type 'CountableRange<Int>' (aka 'Range<Int>')func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i - 1] = factorial(i)
} else {
result[i - 1] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
var result = 0
for i in 1...n {
result += i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i - 1] = factorial(i)
} else {
result[i - 1] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
var result = 0
for i in 1...n {
result += i
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i)
} else {
result[i] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
var result = 0
for i in 1...n {
result += i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i)
} else {
result[i] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
var result = 0
for i in 1...n {
result += i
}
return result
}
``` // XCTAssertTrue failedfunc f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i + 1)
} else {
result[i] = sum(1...(i + 1))
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ range: CountableRange<Int>) -> Int {
var sum = 0
for i in range {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i + 1)
} else {
result[i] = sum(1...(i + 1))
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ range: CountableRange<Int>) -> Int {
var sum = 0
for i in range {
sum += i
}
return sum
}
```result[i] = sum(1...(i + 1)) // cannot convert value of type 'ClosedRange<Int>' to expected argument type 'CountableRange<Int>' (aka 'Range<Int>')func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i + 1)
} else {
result[i] = (1...(i + 1)).reduce(0, +)
}
}
return result
}
func factorial(_ n: Int) -> Int {
return n == 0? 1 : n * factorial(n - 1)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i + 1)
} else {
result[i] = (1...(i + 1)).reduce(0, +)
}
}
return result
}
func factorial(_ n: Int) -> Int {
return n == 0? 1 : n * factorial(n - 1)
}
```return n == 0? 1 : n * factorial(n - 1) // consecutive statements on a line must be separated by ';'return n == 0? 1 : n * factorial(n - 1) // integer literal is unusedreturn n == 0? 1 : n * factorial(n - 1) // consecutive statements on a line must be separated by ';'return n == 0? 1 : n * factorial(n - 1) // cannot use optional chaining on non-optional value of type 'Int'return n == 0? 1 : n * factorial(n - 1) // expected expressionreturn n == 0? 1 : n * factorial(n - 1) // cannot convert return expression of type 'Bool' to return type 'Int'func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i - 1] = factorial(i)
} else {
result[i - 1] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 1 {
return 1
} else {
return n * factorial(n - 1)
}
}
func sum(_ n: Int) -> Int {
var result = 0
for i in 1...n {
result += i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i - 1] = factorial(i)
} else {
result[i - 1] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 1 {
return 1
} else {
return n * factorial(n - 1)
}
}
func sum(_ n: Int) -> Int {
var result = 0
for i in 1...n {
result += i
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i - 1] = factorial(i)
} else {
result[i - 1] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 1 {
return 1
} else {
return n * factorial(n - 1)
}
}
func sum(_ n: Int) -> Int {
var result = 0
for i in 1...n {
result += i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i - 1] = factorial(i)
} else {
result[i - 1] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 1 {
return 1
} else {
return n * factorial(n - 1)
}
}
func sum(_ n: Int) -> Int {
var result = 0
for i in 1...n {
result += i
}
return result
}
```func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i - 1] = factorial(of: i)
} else {
result[i - 1] = sum(from: 1, to: i)
}
}
return result
}
func factorial(of n: Int) -> Int {
if n == 1 {
return 1
}
return n * factorial(of: n - 1)
}
func sum(from start: Int, to end: Int) -> Int {
var sum = 0
for i in start...end {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 1...n {
if i % 2 == 0 {
result[i - 1] = factorial(of: i)
} else {
result[i - 1] = sum(from: 1, to: i)
}
}
return result
}
func factorial(of n: Int) -> Int {
if n == 1 {
return 1
}
return n * factorial(of: n - 1)
}
func sum(from start: Int, to end: Int) -> Int {
var sum = 0
for i in start...end {
sum += i
}
return sum
}
```func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i)
} else {
result[i] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i)
} else {
result[i] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
``` // XCTAssertTrue failedfunc f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i)
} else {
result[i] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Implement the function f that takes n as a parameter,
and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 *... * i).
Example:
f(n: 5) == [1, 2, 6, 24, 15]
Answer:
```swift
func f(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n)
for i in 0..<n {
if i % 2 == 0 {
result[i] = factorial(i)
} else {
result[i] = sum(i)
}
}
return result
}
func factorial(_ n: Int) -> Int {
if n == 0 {
return 1
}
return n * factorial(n - 1)
}
func sum(_ n: Int) -> Int {
var sum = 0
for i in 1...n {
sum += i
}
return sum
}
``` // XCTAssertTrue failedfunc evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
``` // XCTAssertTrue failedfunc evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
``` // XCTAssertTrue failedfunc evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let string = String(i)
let isPalindrome = string == String(string.reversed())
if isPalindrome {
if string.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let string = String(i)
let isPalindrome = string == String(string.reversed())
if isPalindrome {
if string.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
``` // XCTAssertTrue failedfunc evenOddPalindrome(n: Int) -> (Int, Int) {
var countEven = 0
var countOdd = 0
for i in 1...n {
let str = String(i)
let isPalindrome = str == String(str.reversed())
if isPalindrome {
if str.count % 2 == 0 {
countEven += 1
} else {
countOdd += 1
}
}
}
return (countEven, countOdd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var countEven = 0
var countOdd = 0
for i in 1...n {
let str = String(i)
let isPalindrome = str == String(str.reversed())
if isPalindrome {
if str.count % 2 == 0 {
countEven += 1
} else {
countOdd += 1
}
}
}
return (countEven, countOdd)
}
``` // XCTAssertTrue failedfunc evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
if isPalindrome(i) {
if i % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
func isPalindrome(_ x: Int) -> Bool {
let str = String(x)
let reversed = String(str.reversed())
return str == reversed
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
if isPalindrome(i) {
if i % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
func isPalindrome(_ x: Int) -> Bool {
let str = String(x)
let reversed = String(str.reversed())
return str == reversed
}
```func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
``` // XCTAssertTrue failedfunc evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
if isPalindrome(i) {
if i % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
func isPalindrome(_ x: Int) -> Bool {
let str = String(x)
let length = str.count
for i in 0..<length/2 {
if str[str.index(str.startIndex, offsetBy: i)]!= str[str.index(str.endIndex, offsetBy: -i - 1)] {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
if isPalindrome(i) {
if i % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
func isPalindrome(_ x: Int) -> Bool {
let str = String(x)
let length = str.count
for i in 0..<length/2 {
if str[str.index(str.startIndex, offsetBy: i)]!= str[str.index(str.endIndex, offsetBy: -i - 1)] {
return false
}
}
return true
}
```if str[str.index(str.startIndex, offsetBy: i)]!= str[str.index(str.endIndex, offsetBy: -i - 1)] { // '=' must have consistent whitespace on both sidesif str[str.index(str.startIndex, offsetBy: i)]!= str[str.index(str.endIndex, offsetBy: -i - 1)] { // use of '=' in a boolean context, did you mean '=='?if str[str.index(str.startIndex, offsetBy: i)]!= str[str.index(str.endIndex, offsetBy: -i - 1)] { // cannot force unwrap value of non-optional type 'Character'func evenOddPalindrome(n: Int) -> (Int, Int) {
var countEven = 0
var countOdd = 0
for i in 1...n {
let string = String(i)
let isPalindrome = string == String(string.reversed())
if isPalindrome {
if string.count % 2 == 0 {
countEven += 1
} else {
countOdd += 1
}
}
}
return (countEven, countOdd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var countEven = 0
var countOdd = 0
for i in 1...n {
let string = String(i)
let isPalindrome = string == String(string.reversed())
if isPalindrome {
if string.count % 2 == 0 {
countEven += 1
} else {
countOdd += 1
}
}
}
return (countEven, countOdd)
}
``` // XCTAssertTrue failedfunc evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
``` // XCTAssertTrue failedfunc evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Explanation:
Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.
Note:
1. 1 <= n <= 10^3
2. returned tuple has the number of even and odd integer palindromes respectively.
evenOddPalindrome(n: 3) == (1, 2)
evenOddPalindrome(n: 12) == (4, 6)
Answer:
```swift
func evenOddPalindrome(n: Int) -> (Int, Int) {
var even = 0
var odd = 0
for i in 1...n {
let s = String(i)
let isPalindrome = s == String(s.reversed())
if isPalindrome {
if s.count % 2 == 0 {
even += 1
} else {
odd += 1
}
}
}
return (even, odd)
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
if num > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
countNums(arr: [] as [Int]) == 0
countNums(arr: [-1, 11, -11]) == 1
countNums(arr: [1, 1, 2]) == 3
Answer:
```swift
func countNums(arr: [Int]) -> Int {
var count = 0
for num in arr {
var sum = 0
var n = abs(num)
while n > 0 {
sum += n % 10
n /= 10
}
if sum > 0 {
count += 1
}
}
return count
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard!arr.isEmpty else { return true }
var count = 0
for i in 0..<arr.count - 1 {
if arr[i] > arr[i + 1] {
count += 1
}
}
return count <= 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard!arr.isEmpty else { return true }
var count = 0
for i in 0..<arr.count - 1 {
if arr[i] > arr[i + 1] {
count += 1
}
}
return count <= 1
}
```guard!arr.isEmpty else { return true } // expected expression, var, let or case in 'guard' conditionfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > left {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
return left == right
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > left {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
return left == right
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > 0 {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
return left >= right
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > 0 {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
return left >= right
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > 0 {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
return left >= right
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > 0 {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
return left >= right
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var count = 0
for i in 0..<arr.count-1 {
if arr[i] > arr[i+1] {
count += 1
}
}
return count <= 1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var count = 0
for i in 0..<arr.count-1 {
if arr[i] > arr[i+1] {
count += 1
}
}
return count <= 1
}
```func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > left {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
while left < right {
if arr[left] > arr[left + 1] || arr[right] < arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > left {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
while left < right {
if arr[left] > arr[left + 1] || arr[right] < arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
return false
}
if arr[right] > arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
return false
}
if arr[right] > arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > left {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
while left < right {
if arr[left] > arr[left + 1] || arr[right] < arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > left {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
while left < right {
if arr[left] > arr[left + 1] || arr[right] < arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > left {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
while left < right {
if arr[left] > arr[left + 1] || arr[right] < arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else {
return true
}
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
break
}
left += 1
}
while right > left {
if arr[right] < arr[right - 1] {
break
}
right -= 1
}
while left < right {
if arr[left] > arr[left + 1] || arr[right] < arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}
``` // XCTAssertTrue failedfunc moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
return false
}
if arr[right] < arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
We have an array 'arr' of N integers arr[1], arr[2],..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation any number of times.
One right shift operation means shifting all elements of the array by one
position in the right direction. The last element of the array will be moved to
the starting position in the array i.e. 0th index.
If it is possible to obtain the sorted array by performing the above operation
then return true else return false.
If the given array is empty then return true.
Note: The given array is guaranteed to have unique elements.
For Example:
Explanation: By performin 2 right shift operations, non-decreasing order can
be achieved for the given array.
Explanation:It is not possible to get non-decreasing order for the given
array by performing any number of right shift operations.
moveOneBall(arr: [3, 4, 5, 1, 2]) == true
moveOneBall(arr: [3, 5, 4, 1, 2]) == false
Answer:
```swift
func moveOneBall(arr: [Int]) -> Bool {
guard arr.count > 0 else { return true }
var left = 0
var right = arr.count - 1
while left < right {
if arr[left] > arr[left + 1] {
return false
}
if arr[right] < arr[right - 1] {
return false
}
left += 1
right -= 1
}
return true
}
``` // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2!= 0 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count
if evenCount + lst2EvenCount >= oddCount {
return "YES"
} else {
return "NO"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2!= 0 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count
if evenCount + lst2EvenCount >= oddCount {
return "YES"
} else {
return "NO"
}
}
```let oddCount = lst1.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'let oddCount = lst1.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = lst1.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = lst1.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet lst2OddCount = lst2.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuefunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2!= 0 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count
if evenCount == lst1.count || (oddCount == lst1.count && lst2OddCount >= oddCount) {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2!= 0 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count
if evenCount == lst1.count || (oddCount == lst1.count && lst2OddCount >= oddCount) {
return "YES"
}
return "NO"
}
```let oddCount = lst1.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'let oddCount = lst1.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = lst1.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = lst1.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'let lst2OddCount = lst2.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet lst2OddCount = lst2.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuefunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count || oddCount == 0 {
return "YES"
}
if lst2EvenCount >= oddCount {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count || oddCount == 0 {
return "YES"
}
if lst2EvenCount >= oddCount {
return "YES"
}
return "NO"
}
```let lst2OddCount = lst2.filter { $0 % 2 == 1 }.count // initialization of immutable value 'lst2OddCount' was never used; consider replacing with assignment to '_' or removing itfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let evenCount2 = lst2.filter { $0 % 2 == 0 }.count
let oddCount2 = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count {
return "YES"
}
if oddCount == 0 {
return "NO"
}
let diff = abs(oddCount - evenCount)
let oddCount2Diff = abs(oddCount2 - evenCount2)
if oddCount2Diff < diff {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let evenCount2 = lst2.filter { $0 % 2 == 0 }.count
let oddCount2 = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count {
return "YES"
}
if oddCount == 0 {
return "NO"
}
let diff = abs(oddCount - evenCount)
let oddCount2Diff = abs(oddCount2 - evenCount2)
if oddCount2Diff < diff {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2 == 1 }.count
if evenCount + lst2EvenCount >= lst1.count && oddCount <= lst2OddCount {
return "YES"
} else {
return "NO"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2 == 1 }.count
if evenCount + lst2EvenCount >= lst1.count && oddCount <= lst2OddCount {
return "YES"
} else {
return "NO"
}
}
``` // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count || (oddCount == lst1.count && lst2OddCount >= oddCount) {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count || (oddCount == lst1.count && lst2OddCount >= oddCount) {
return "YES"
}
return "NO"
}
```let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count // initialization of immutable value 'lst2EvenCount' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let even1 = lst1.filter { $0 % 2 == 0 }
let odd1 = lst1.filter { $0 % 2 == 1 }
let even2 = lst2.filter { $0 % 2 == 0 }
let odd2 = lst2.filter { $0 % 2 == 1 }
let count1 = even1.count + odd2.count
let count2 = odd1.count + even2.count
return count1 == count2? "YES" : "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let even1 = lst1.filter { $0 % 2 == 0 }
let odd1 = lst1.filter { $0 % 2 == 1 }
let even2 = lst2.filter { $0 % 2 == 0 }
let odd2 = lst2.filter { $0 % 2 == 1 }
let count1 = even1.count + odd2.count
let count2 = odd1.count + even2.count
return count1 == count2? "YES" : "NO"
}
```return count1 == count2? "YES" : "NO" // string literal is unusedreturn count1 == count2? "YES" : "NO" // consecutive statements on a line must be separated by ';'return count1 == count2? "YES" : "NO" // cannot use optional chaining on non-optional value of type 'Int'return count1 == count2? "YES" : "NO" // consecutive statements on a line must be separated by ';'return count1 == count2? "YES" : "NO" // expected expressionreturn count1 == count2? "YES" : "NO" // cannot convert return expression of type 'Bool' to return type 'String'func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let evenCount2 = lst2.filter { $0 % 2 == 0 }.count
let oddCount2 = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count {
return "YES"
}
if oddCount == 0 {
return "NO"
}
let diff = abs(evenCount - oddCount)
let oddDiff = abs(oddCount2 - evenCount2)
if oddDiff < diff {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let evenCount2 = lst2.filter { $0 % 2 == 0 }.count
let oddCount2 = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count {
return "YES"
}
if oddCount == 0 {
return "NO"
}
let diff = abs(evenCount - oddCount)
let oddDiff = abs(oddCount2 - evenCount2)
if oddDiff < diff {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2 == 1 }.count
if evenCount + lst2EvenCount >= lst1.count && oddCount <= lst2OddCount {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let lst2EvenCount = lst2.filter { $0 % 2 == 0 }.count
let lst2OddCount = lst2.filter { $0 % 2 == 1 }.count
if evenCount + lst2EvenCount >= lst1.count && oddCount <= lst2OddCount {
return "YES"
}
return "NO"
}
``` // XCTAssertTrue failedfunc exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let evenCount2 = lst2.filter { $0 % 2 == 0 }.count
let oddCount2 = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count || (oddCount == lst1.count && evenCount2 >= oddCount) {
return "YES"
}
return "NO"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this problem, you will implement a function that takes two arrays of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 an array of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange elements between the lst1 and lst2 to make
all the elements of lst1 to be even, return "YES".
Otherwise, return "NO".
For example:
It is assumed that the input arrays will be non-empty.
exchange(lst1: [1, 2, 3, 4], lst2: [1, 2, 3, 4]) == "YES"
exchange(lst1: [1, 2, 3, 4], lst2: [1, 5, 3, 4]) == "NO"
Answer:
```swift
func exchange(lst1: [Int], lst2: [Int]) -> String {
let evenCount = lst1.filter { $0 % 2 == 0 }.count
let oddCount = lst1.filter { $0 % 2 == 1 }.count
let evenCount2 = lst2.filter { $0 % 2 == 0 }.count
let oddCount2 = lst2.filter { $0 % 2 == 1 }.count
if evenCount == lst1.count || (oddCount == lst1.count && evenCount2 >= oddCount) {
return "YES"
}
return "NO"
}
```let oddCount2 = lst2.filter { $0 % 2 == 1 }.count // initialization of immutable value 'oddCount2' was never used; consider replacing with assignment to '_' or removing it // XCTAssertTrue failedfunc histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter]!= nil {
result[letter]! += 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter]!= nil {
result[letter]! += 1
} else {
result[letter] = 1
}
}
return result
}
```if result[letter]!= nil { // use of '=' in a boolean context, did you mean '=='?if result[letter]!= nil { // 'nil' cannot be assigned to type 'Int'if result[letter]!= nil { // '=' must have consistent whitespace on both sidesfunc histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter]!= nil {
result[letter]! += 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter]!= nil {
result[letter]! += 1
} else {
result[letter] = 1
}
}
return result
}
```if result[letter]!= nil { // use of '=' in a boolean context, did you mean '=='?if result[letter]!= nil { // 'nil' cannot be assigned to type 'Int'if result[letter]!= nil { // '=' must have consistent whitespace on both sidesfunc histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter]!= nil {
result[letter]! += 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter]!= nil {
result[letter]! += 1
} else {
result[letter] = 1
}
}
return result
}
```if result[letter]!= nil { // use of '=' in a boolean context, did you mean '=='?if result[letter]!= nil { // 'nil' cannot be assigned to type 'Int'if result[letter]!= nil { // '=' must have consistent whitespace on both sidesfunc histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter]!= nil {
result[letter]! += 1
} else {
result[letter] = 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter]!= nil {
result[letter]! += 1
} else {
result[letter] = 1
}
}
return result
}
```if result[letter]!= nil { // use of '=' in a boolean context, did you mean '=='?if result[letter]!= nil { // 'nil' cannot be assigned to type 'Int'if result[letter]!= nil { // '=' must have consistent whitespace on both sidesfunc histogram(test: String) -> [String : Int] {
var result: [String : Int] = [:]
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter] == nil {
result[letter] = 1
} else {
result[letter]! += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result: [String : Int] = [:]
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter] == nil {
result[letter] = 1
} else {
result[letter]! += 1
}
}
return result
}
``` // XCTAssertTrue failedfunc histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter] == nil {
result[letter] = 1
} else {
result[letter]! += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter] == nil {
result[letter] = 1
} else {
result[letter]! += 1
}
}
return result
}
``` // XCTAssertTrue failedfunc histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter] == nil {
result[letter] = 1
} else {
result[letter]! += 1
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var result = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if result[letter] == nil {
result[letter] = 1
} else {
result[letter]! += 1
}
}
return result
}
``` // XCTAssertTrue failedfunc histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if let count = dict[letter] {
dict[letter] = count + 1
} else {
dict[letter] = 1
}
}
return dict
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if let count = dict[letter] {
dict[letter] = count + 1
} else {
dict[letter] = 1
}
}
return dict
}
``` // XCTAssertTrue failedfunc histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if let count = dict[letter] {
dict[letter] = count + 1
} else {
dict[letter] = 1
}
}
return dict
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if let count = dict[letter] {
dict[letter] = count + 1
} else {
dict[letter] = 1
}
}
return dict
}
``` // XCTAssertTrue failedfunc histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if let count = dict[letter] {
dict[letter] = count + 1
} else {
dict[letter] = 1
}
}
return dict
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram(test: "a b c") == ["a" : 1, "b" : 1, "c" : 1]
histogram(test: "a b b a") == ["a" : 2, "b" : 2]
histogram(test: "a b c a b") == ["a" : 2, "b" : 2]
histogram(test: "b b b b a") == ["b" : 4]
histogram(test: "") == [:] as [String : Int]
Answer:
```swift
func histogram(test: String) -> [String : Int] {
var dict = [String : Int]()
let letters = test.components(separatedBy: " ")
for letter in letters {
if let count = dict[letter] {
dict[letter] = count + 1
} else {
dict[letter] = 1
}
}
return dict
}
``` // XCTAssertTrue failedfunc reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and true/false for the check.
Example
reverseDelete(s: "abcde", c: "ae") == ("bcd", false)
reverseDelete(s: "abcdef", c: "b") == ("acdef", false)
reverseDelete(s: "abcdedcba", c: "ab") == ("cdedc", true)
Answer:
```swift
func reverseDelete(s: String, c: String) -> (String, Bool) {
let set = Set(c)
let result = String(s.filter {!set.contains($0) })
let isPalindrome = result == String(result.reversed())
return (result, isPalindrome)
}
```func oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count
let newString = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(newString)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count
let newString = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(newString)
}
return result
}
```let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // 'nil' is not compatible with expected argument type 'Bool'let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // cannot assign value of type 'Bool' to type 'Int'let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // cannot convert value of type '()' to closure result type 'Bool'let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // '=' must have consistent whitespace on both sideslet count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // cannot assign through '!': 'wholeNumberValue' is a get-only propertyfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for string in lst {
let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
result.append("the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for string in lst {
let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
result.append("the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput.")
}
return result
}
```let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // optional type 'Int?' cannot be used as a boolean; test for '!= nil' insteadlet count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // consecutive statements on a line must be separated by ';'let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // cannot use optional chaining on non-optional value of type 'Int'let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
result.append("the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
result.append("the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput.")
}
return result
}
```let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // optional type 'Int?' cannot be used as a boolean; test for '!= nil' insteadlet count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // consecutive statements on a line must be separated by ';'let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // cannot use optional chaining on non-optional value of type 'Int'let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count
let newString = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(newString)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count
let newString = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(newString)
}
return result
}
```let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // 'nil' is not compatible with expected argument type 'Bool'let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // cannot assign value of type 'Bool' to type 'Int'let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // cannot convert value of type '()' to closure result type 'Bool'let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // '=' must have consistent whitespace on both sideslet count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // cannot assign through '!': 'wholeNumberValue' is a get-only propertyfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for string in lst {
let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(output)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for string in lst {
let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(output)
}
return result
}
```let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // optional type 'Int?' cannot be used as a boolean; test for '!= nil' insteadlet count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // consecutive statements on a line must be separated by ';'let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // cannot use optional chaining on non-optional value of type 'Int'let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for string in lst {
let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
result.append("the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for string in lst {
let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
result.append("the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput.")
}
return result
}
```let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // optional type 'Int?' cannot be used as a boolean; test for '!= nil' insteadlet count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // consecutive statements on a line must be separated by ';'let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // cannot use optional chaining on non-optional value of type 'Int'let count = string.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurefunc oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count
let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(output)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count
let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(output)
}
return result
}
```let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // 'nil' is not compatible with expected argument type 'Bool'let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // cannot assign value of type 'Bool' to type 'Int'let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // cannot convert value of type '()' to closure result type 'Bool'let count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // '=' must have consistent whitespace on both sideslet count = string.filter { $0.wholeNumberValue!= nil && $0.wholeNumberValue! % 2 == 1 }.count // cannot assign through '!': 'wholeNumberValue' is a get-only propertyfunc oddCount(lst: [String]) -> [String] {
var result = [String]()
for str in lst {
let count = str.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
let replaced = str.replacingOccurrences(of: "1", with: "\(count)")
result.append("the number of odd elements \(replaced)n the str\(replaced)ng \(replaced) of the \(replaced)nput.")
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result = [String]()
for str in lst {
let count = str.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count
let replaced = str.replacingOccurrences(of: "1", with: "\(count)")
result.append("the number of odd elements \(replaced)n the str\(replaced)ng \(replaced) of the \(replaced)nput.")
}
return result
}
```let count = str.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // cannot use optional chaining on non-optional value of type 'Int'let count = str.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // consecutive statements on a line must be separated by ';'let count = str.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // trailing closure passed to parameter of type 'Predicate<String.Element>' (aka 'Predicate<Character>') that does not accept a closurelet count = str.filter { $0.isdigit && Int($0)?? 0 % 2 == 1 }.count // optional type 'Int?' cannot be used as a boolean; test for '!= nil' insteadfunc oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter("13579".contains).count
let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(output)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter("13579".contains).count
let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(output)
}
return result
}
```func oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter("13579".contains).count
let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(output)
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of strings, where each string consists of only digits, return an array.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
oddCount(lst: ["1234567"]) == ["the number of odd elements 4n the str4ng 4 of the 4nput."]
oddCount(lst: ["3", "11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput."]
Answer:
```swift
func oddCount(lst: [String]) -> [String] {
var result: [String] = []
for string in lst {
let count = string.filter("13579".contains).count
let output = "the number of odd elements \(count)n the str\(count)ng \(count) of the \(count)nput."
result.append(output)
}
return result
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for num in nums.dropFirst() {
currentSum = min(num, currentSum + num)
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for num in nums.dropFirst() {
currentSum = min(num, currentSum + num)
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum(nums: [2, 3, 4, 1, 2, 4]) == 1
minSubArraySum(nums: [-1, -2, -3]) == -6
Answer:
```swift
func minSubArraySum(nums: [Int]) -> Int {
var minSum = nums[0]
var currentSum = nums[0]
for i in 1..<nums.count {
currentSum = min(nums[i], currentSum + nums[i])
minSum = min(minSum, currentSum)
}
return minSum
}
```func maxFill(grid: [[Int]], capacity: Int) -> Int {
var max = 0
var count = 0
var row = 0
var col = grid[0].count - 1
while row < grid.count && col >= 0 {
if grid[row][col] == 1 {
count += 1
max = max > count? max : count
} else {
count = 0
}
if count == capacity {
count = 0
col -= 1
} else {
row += 1
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var max = 0
var count = 0
var row = 0
var col = grid[0].count - 1
while row < grid.count && col >= 0 {
if grid[row][col] == 1 {
count += 1
max = max > count? max : count
} else {
count = 0
}
if count == capacity {
count = 0
col -= 1
} else {
row += 1
}
}
return max
}
```max = max > count? max : count // expected expressionmax = max > count? max : count // variable is unusedmax = max > count? max : count // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max > count? max : count // consecutive statements on a line must be separated by ';'max = max > count? max : count // cannot use optional chaining on non-optional value of type 'Int'max = max > count? max : count // cannot assign value of type 'Bool' to type 'Int'max = max > count? max : count // consecutive statements on a line must be separated by ';'func maxFill(grid: [[Int]], capacity: Int) -> Int {
var max = 0
var count = 0
for row in grid {
max = 0
count = 0
for well in row {
if well == 1 {
count += 1
} else {
max = max > count? max : count
count = 0
}
}
max = max > count? max : count
print(max)
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var max = 0
var count = 0
for row in grid {
max = 0
count = 0
for well in row {
if well == 1 {
count += 1
} else {
max = max > count? max : count
count = 0
}
}
max = max > count? max : count
print(max)
}
return max
}
```max = max > count? max : count // consecutive statements on a line must be separated by ';'max = max > count? max : count // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max > count? max : count // cannot use optional chaining on non-optional value of type 'Int'max = max > count? max : count // expected expressionmax = max > count? max : count // variable is unusedmax = max > count? max : count // consecutive statements on a line must be separated by ';'max = max > count? max : count // cannot assign value of type 'Bool' to type 'Int'max = max > count? max : count // expected expressionmax = max > count? max : count // consecutive statements on a line must be separated by ';'max = max > count? max : count // variable is unusedmax = max > count? max : count // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max > count? max : count // cannot use optional chaining on non-optional value of type 'Int'max = max > count? max : count // cannot assign value of type 'Bool' to type 'Int'max = max > count? max : count // consecutive statements on a line must be separated by ';'func maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var wells = grid.map { $0.map { $0 == 1 } }
var water = Array(repeating: Array(repeating: 0, count: grid[0].count), count: grid.count)
var empty = Array(repeating: Array(repeating: 0, count: grid[0].count), count: grid.count)
var q = [(r: 0, c: 0)]
while!q.isEmpty {
let (r, c) = q.removeFirst()
if wells[r][c] {
water[r][c] = capacity
empty[r][c] = 0
} else {
water[r][c] = 0
empty[r][c] = capacity
}
maxFill = max(maxFill, water[r][c])
if r > 0 {
q.append((r - 1, c))
}
if r + 1 < grid.count {
q.append((r + 1, c))
}
if c > 0 {
q.append((r, c - 1))
}
if c + 1 < grid[0].count {
q.append((r, c + 1))
}
}
return maxFill
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var wells = grid.map { $0.map { $0 == 1 } }
var water = Array(repeating: Array(repeating: 0, count: grid[0].count), count: grid.count)
var empty = Array(repeating: Array(repeating: 0, count: grid[0].count), count: grid.count)
var q = [(r: 0, c: 0)]
while!q.isEmpty {
let (r, c) = q.removeFirst()
if wells[r][c] {
water[r][c] = capacity
empty[r][c] = 0
} else {
water[r][c] = 0
empty[r][c] = capacity
}
maxFill = max(maxFill, water[r][c])
if r > 0 {
q.append((r - 1, c))
}
if r + 1 < grid.count {
q.append((r + 1, c))
}
if c > 0 {
q.append((r, c - 1))
}
if c + 1 < grid[0].count {
q.append((r, c + 1))
}
}
return maxFill
}
```while!q.isEmpty { // expected expression, var, or let in 'while' conditionfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var wells = grid.count
var columns = grid[0].count
var waterLevel = capacity
while wells > 0 {
var currentWells = 0
for row in 0..<grid.count {
for column in 0..<columns {
if grid[row][column] == 0 {
continue
}
if grid[row][column] <= waterLevel {
currentWells += 1
waterLevel -= grid[row][column]
grid[row][column] = 0
}
}
}
maxFill += currentWells
wells -= currentWells
}
return maxFill
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var wells = grid.count
var columns = grid[0].count
var waterLevel = capacity
while wells > 0 {
var currentWells = 0
for row in 0..<grid.count {
for column in 0..<columns {
if grid[row][column] == 0 {
continue
}
if grid[row][column] <= waterLevel {
currentWells += 1
waterLevel -= grid[row][column]
grid[row][column] = 0
}
}
}
maxFill += currentWells
wells -= currentWells
}
return maxFill
}
```grid[row][column] = 0 // cannot assign through subscript: 'grid' is a 'let' constantfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var rows = grid.count
var cols = grid[0].count
var waterLevel = 0
var waterVolume = 0
while rows > 0 {
waterLevel = 0
waterVolume = 0
for i in 0..<cols {
waterLevel = 0
for j in 0..<rows {
waterLevel = max(waterLevel, grid[j][i])
}
waterVolume += waterLevel
}
maxFill = max(maxFill, waterVolume)
capacity -= waterVolume
if capacity <= 0 {
break
}
for i in 0..<cols {
for j in 0..<rows {
grid[j][i] -= waterLevel
}
}
rows = grid.count(where: { $0.contains(where: { $0 > 0 }) })
}
return maxFill
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var rows = grid.count
var cols = grid[0].count
var waterLevel = 0
var waterVolume = 0
while rows > 0 {
waterLevel = 0
waterVolume = 0
for i in 0..<cols {
waterLevel = 0
for j in 0..<rows {
waterLevel = max(waterLevel, grid[j][i])
}
waterVolume += waterLevel
}
maxFill = max(maxFill, waterVolume)
capacity -= waterVolume
if capacity <= 0 {
break
}
for i in 0..<cols {
for j in 0..<rows {
grid[j][i] -= waterLevel
}
}
rows = grid.count(where: { $0.contains(where: { $0 > 0 }) })
}
return maxFill
}
```capacity -= waterVolume // left side of mutating operator isn't mutable: 'capacity' is a 'let' constantgrid[j][i] -= waterLevel // left side of mutating operator isn't mutable: 'grid' is a 'let' constantrows = grid.count(where: { $0.contains(where: { $0 > 0 }) }) // cannot call value of non-function type 'Int'func maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var wells = grid.count
var columns = grid[0].count
var waterLevel = capacity
var water = 0
var level = 0
var row = 0
var column = 0
while wells > 0 {
while row < wells {
column = 0
while column < columns {
if grid[row][column] == 1 {
water = min(waterLevel, 1)
level = waterLevel - water
waterLevel -= water
grid[row][column] = level
}
column += 1
}
row += 1
}
maxFill += 1
wells = 0
row = 0
while row < grid.count {
column = 0
while column < columns {
if grid[row][column] > 0 {
wells += 1
}
column += 1
}
row += 1
}
}
return maxFill
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var wells = grid.count
var columns = grid[0].count
var waterLevel = capacity
var water = 0
var level = 0
var row = 0
var column = 0
while wells > 0 {
while row < wells {
column = 0
while column < columns {
if grid[row][column] == 1 {
water = min(waterLevel, 1)
level = waterLevel - water
waterLevel -= water
grid[row][column] = level
}
column += 1
}
row += 1
}
maxFill += 1
wells = 0
row = 0
while row < grid.count {
column = 0
while column < columns {
if grid[row][column] > 0 {
wells += 1
}
column += 1
}
row += 1
}
}
return maxFill
}
```grid[row][column] = level // cannot assign through subscript: 'grid' is a 'let' constantfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var max = 0
var wells = grid.count
var columns = grid[0].count
var water = Array(repeating: Array(repeating: 0, count: columns), count: wells)
var result = 0
while wells > 0 {
for i in 0..<wells {
for j in 0..<columns {
if water[i][j] < capacity && grid[i][j] == 1 {
water[i][j] += 1
result += 1
max = max > result? max : result
}
}
}
wells -= 1
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var max = 0
var wells = grid.count
var columns = grid[0].count
var water = Array(repeating: Array(repeating: 0, count: columns), count: wells)
var result = 0
while wells > 0 {
for i in 0..<wells {
for j in 0..<columns {
if water[i][j] < capacity && grid[i][j] == 1 {
water[i][j] += 1
result += 1
max = max > result? max : result
}
}
}
wells -= 1
}
return max
}
```max = max > result? max : result // cannot use optional chaining on non-optional value of type 'Int'max = max > result? max : result // consecutive statements on a line must be separated by ';'max = max > result? max : result // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max > result? max : result // cannot assign value of type 'Bool' to type 'Int'max = max > result? max : result // consecutive statements on a line must be separated by ';'max = max > result? max : result // expected expressionmax = max > result? max : result // variable is unusedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var max = 0
var count = 0
for row in grid {
max = 0
count = 0
for well in row {
if well == 0 {
max = max < count? count : max
count = 0
} else {
count += 1
}
}
max = max < count? count : max
if max < capacity {
return 0
}
}
return max
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var max = 0
var count = 0
for row in grid {
max = 0
count = 0
for well in row {
if well == 0 {
max = max < count? count : max
count = 0
} else {
count += 1
}
}
max = max < count? count : max
if max < capacity {
return 0
}
}
return max
}
```max = max < count? count : max // consecutive statements on a line must be separated by ';'max = max < count? count : max // cannot assign value of type 'Bool' to type 'Int'max = max < count? count : max // variable is unusedmax = max < count? count : max // consecutive statements on a line must be separated by ';'max = max < count? count : max // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max < count? count : max // expected expressionmax = max < count? count : max // cannot use optional chaining on non-optional value of type 'Int'max = max < count? count : max // consecutive statements on a line must be separated by ';'max = max < count? count : max // variable is unusedmax = max < count? count : max // value of optional type 'Int?' must be unwrapped to a value of type 'Int'max = max < count? count : max // cannot assign value of type 'Bool' to type 'Int'max = max < count? count : max // expected expressionmax = max < count? count : max // consecutive statements on a line must be separated by ';'max = max < count? count : max // cannot use optional chaining on non-optional value of type 'Int'func maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var wells = grid.count
var columns = grid[0].count
var waterLevel = capacity
var waterLevelIndex = 0
while wells > 0 {
var waterLevelCount = 0
for i in 0..<columns {
if grid[waterLevelIndex][i] == 1 {
waterLevelCount += 1
}
}
if waterLevelCount > 0 {
maxFill += waterLevelCount
wells -= waterLevelCount
if waterLevelCount <= waterLevel {
waterLevel -= waterLevelCount
} else {
waterLevel = capacity
waterLevelIndex += 1
}
} else {
waterLevelIndex += 1
}
}
return maxFill
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var maxFill = 0
var wells = grid.count
var columns = grid[0].count
var waterLevel = capacity
var waterLevelIndex = 0
while wells > 0 {
var waterLevelCount = 0
for i in 0..<columns {
if grid[waterLevelIndex][i] == 1 {
waterLevelCount += 1
}
}
if waterLevelCount > 0 {
maxFill += waterLevelCount
wells -= waterLevelCount
if waterLevelCount <= waterLevel {
waterLevel -= waterLevelCount
} else {
waterLevel = capacity
waterLevelIndex += 1
}
} else {
waterLevelIndex += 1
}
}
return maxFill
}
```var columns = grid[0].count // variable 'columns' was never mutated; consider changing to 'let' constant // XCTAssertTrue failedfunc maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var wells = Array(repeating: capacity, count: grid[0].count)
for row in grid {
var available = capacity
for i in 0..<row.count {
if row[i] == 1 {
available = min(available, wells[i])
}
}
result += available
for i in 0..<row.count {
if row[i] == 1 {
wells[i] -= available
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the number of times you need to lower the buckets.
Example 1:
Example 2:
Example 3:
Constraints:
* all wells have the same length
* 1 <= grid.length <= 10^2
* 1 <= grid[:,1].length <= 10^2
* grid[i][j] -> 0 | 1
* 1 <= capacity <= 10
maxFill(grid: [[0, 0, 1, 0], [0, 1, 0, 0], [1, 1, 1, 1]], capacity: 1) == 6
maxFill(grid: [[0, 0, 1, 1], [0, 0, 0, 0], [1, 1, 1, 1], [0, 1, 1, 1]], capacity: 2) == 5
maxFill(grid: [[0, 0, 0], [0, 0, 0]], capacity: 5) == 0
Answer:
```swift
func maxFill(grid: [[Int]], capacity: Int) -> Int {
var result = 0
var wells = Array(repeating: capacity, count: grid[0].count)
for row in grid {
var available = capacity
for i in 0..<row.count {
if row[i] == 1 {
available = min(available, wells[i])
}
}
result += available
for i in 0..<row.count {
if row[i] == 1 {
wells[i] -= available
}
}
}
return result
}
``` // XCTAssertTrue failedfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}
```func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
if binaryA.count!= binaryB.count {
return binaryA.count < binaryB.count
} else {
return a < b
}
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
if binaryA.count!= binaryB.count {
return binaryA.count < binaryB.count
} else {
return a < b
}
}
return sorted
}
```if binaryA.count!= binaryB.count { // cannot force unwrap value of non-optional type 'Int'if binaryA.count!= binaryB.count { // '=' must have consistent whitespace on both sidesif binaryA.count!= binaryB.count { // use of '=' in a boolean context, did you mean '=='?func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}
```func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}
```func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}
```func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}
```func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}
```func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}
```func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
if binaryA.count == binaryB.count {
return a < b
}
return binaryA.count < binaryB.count
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
if binaryA.count == binaryB.count {
return a < b
}
return binaryA.count < binaryB.count
}
return sorted
}
``` // XCTAssertTrue failedfunc sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
sortArray(arr: [1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
sortArray(arr: [-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
sortArray(arr: [1, 0, 2, 3, 4]) == [0, 1, 2, 3, 4]
Answer:
```swift
func sortArray(arr: [Int]) -> [Int] {
let sorted = arr.sorted { (a, b) -> Bool in
let binaryA = String(a, radix: 2)
let binaryB = String(b, radix: 2)
let countA = binaryA.filter { $0 == "1" }.count
let countB = binaryB.filter { $0 == "1" }.count
if countA == countB {
return a < b
}
return countA < countB
}
return sorted
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for letter in word {
if letter.isConsonant {
consonantsCount += 1
}
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
extension Character {
var isConsonant: Bool {
let vowels = "aeiou"
return!vowels.contains(String(self).lowercased())
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for letter in word {
if letter.isConsonant {
consonantsCount += 1
}
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
extension Character {
var isConsonant: Bool {
let vowels = "aeiou"
return!vowels.contains(String(self).lowercased())
}
}
```return!vowels.contains(String(self).lowercased()) // expected expression in 'return' statementfunc selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "aeiouAEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "aeiouAEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
```func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string s and a natural number n, you have been tasked to implement
a function that returns an array of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty array.
Note: you may assume the input string contains only letters and spaces.
Examples:
selectWords(s: "Mary had a little lamb", n: 4) == ["little"]
selectWords(s: "Mary had a little lamb", n: 3) == ["Mary", "lamb"]
selectWords(s: "simple white space", n: 2) == [] as [String]
selectWords(s: "Hello world", n: 4) == ["world"]
selectWords(s: "Uncle sam", n: 3) == ["Uncle"]
Answer:
```swift
func selectWords(s: String, n: Int) -> [String] {
let words = s.components(separatedBy: " ")
var result: [String] = []
for word in words {
var consonantsCount = 0
for character in word {
if "AEIOU".contains(character) {
continue
}
consonantsCount += 1
}
if consonantsCount == n {
result.append(word)
}
}
return result
}
``` // XCTAssertTrue failedfunc getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}
```if lastConsonantIndex!= -1 { // use of '=' in a boolean context, did you mean '=='?if lastConsonantIndex!= -1 { // '=' must have consistent whitespace on both sidesif lastConsonantIndex!= -1 { // cannot force unwrap value of non-optional type 'Int'func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}
```if lastConsonantIndex!= -1 { // use of '=' in a boolean context, did you mean '=='?if lastConsonantIndex!= -1 { // '=' must have consistent whitespace on both sidesif lastConsonantIndex!= -1 { // cannot force unwrap value of non-optional type 'Int'func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}
```if lastConsonantIndex!= -1 { // use of '=' in a boolean context, did you mean '=='?if lastConsonantIndex!= -1 { // '=' must have consistent whitespace on both sidesif lastConsonantIndex!= -1 { // cannot force unwrap value of non-optional type 'Int'func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}
```if lastConsonantIndex!= -1 { // use of '=' in a boolean context, did you mean '=='?if lastConsonantIndex!= -1 { // '=' must have consistent whitespace on both sidesif lastConsonantIndex!= -1 { // cannot force unwrap value of non-optional type 'Int'func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}
```if lastConsonantIndex!= -1 { // use of '=' in a boolean context, did you mean '=='?if lastConsonantIndex!= -1 { // '=' must have consistent whitespace on both sidesif lastConsonantIndex!= -1 { // cannot force unwrap value of non-optional type 'Int'func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}
```if lastConsonantIndex!= -1 { // use of '=' in a boolean context, did you mean '=='?if lastConsonantIndex!= -1 { // '=' must have consistent whitespace on both sidesif lastConsonantIndex!= -1 { // cannot force unwrap value of non-optional type 'Int'func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let closestDistance = word.count - lastConsonantIndex
if distance < closestDistance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}
```if lastConsonantIndex!= -1 { // use of '=' in a boolean context, did you mean '=='?if lastConsonantIndex!= -1 { // '=' must have consistent whitespace on both sidesif lastConsonantIndex!= -1 { // cannot force unwrap value of non-optional type 'Int'func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let lastConsonantDistance = word.count - lastConsonantIndex
if lastConsonantDistance > distance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
let lastConsonantDistance = word.count - lastConsonantIndex
if lastConsonantDistance > distance {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}
```if lastConsonantIndex!= -1 { // use of '=' in a boolean context, did you mean '=='?if lastConsonantIndex!= -1 { // '=' must have consistent whitespace on both sidesif lastConsonantIndex!= -1 { // cannot force unwrap value of non-optional type 'Int'func getClosestVowel(word: String) -> String {
let vowels = "aeiou"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
if distance < word.count - lastConsonantIndex {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiou"
var closestVowel = ""
var lastConsonantIndex = -1
for (index, character) in word.enumerated() {
if vowels.contains(character) {
if lastConsonantIndex!= -1 {
let distance = word.count - index
if distance < word.count - lastConsonantIndex {
closestVowel = String(character)
}
}
} else if character.isLetter {
lastConsonantIndex = index
}
}
return closestVowel
}
```if lastConsonantIndex!= -1 { // use of '=' in a boolean context, did you mean '=='?if lastConsonantIndex!= -1 { // '=' must have consistent whitespace on both sidesif lastConsonantIndex!= -1 { // cannot force unwrap value of non-optional type 'Int'func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var isVowelFound = false
for char in word.reversed() {
if vowels.contains(char) {
if isVowelFound {
return closestVowel
}
isVowelFound = true
} else if isVowelFound {
return closestVowel
} else {
closestVowel = String(char)
}
}
return ""
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
Example:
getClosestVowel(word: "yogurt") == "u"
getClosestVowel(word: "FULL") == "U"
getClosestVowel(word: "quick") == ""
getClosestVowel(word: "ab") == ""
Answer:
```swift
func getClosestVowel(word: String) -> String {
let vowels = "aeiouAEIOU"
var closestVowel = ""
var isVowelFound = false
for char in word.reversed() {
if vowels.contains(char) {
if isVowelFound {
return closestVowel
}
isVowelFound = true
} else if isVowelFound {
return closestVowel
} else {
closestVowel = String(char)
}
}
return ""
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var count = 0
for char in lst.joined() {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
return count == 0? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var count = 0
for char in lst.joined() {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
return count == 0? "Yes" : "No"
}
```return count == 0? "Yes" : "No" // consecutive statements on a line must be separated by ';'return count == 0? "Yes" : "No" // cannot convert return expression of type 'Bool' to return type 'String'return count == 0? "Yes" : "No" // string literal is unusedreturn count == 0? "Yes" : "No" // consecutive statements on a line must be separated by ';'return count == 0? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Int'return count == 0? "Yes" : "No" // expected expressionfunc matchParens(lst: [String]) -> String {
var count = 0
for char in lst[0] {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for char in lst[1] {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var count = 0
for char in lst[0] {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for char in lst[1] {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var left = 0
var right = 0
for char in lst[0] {
if char == "(" {
left += 1
} else {
right += 1
}
}
for char in lst[1] {
if char == "(" {
left += 1
} else {
right += 1
}
}
if left == right {
return "Yes"
} else {
return "No"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var left = 0
var right = 0
for char in lst[0] {
if char == "(" {
left += 1
} else {
right += 1
}
}
for char in lst[1] {
if char == "(" {
left += 1
} else {
right += 1
}
}
if left == right {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var left = 0
var right = 0
for char in lst[0] {
if char == "(" {
left += 1
} else {
right += 1
}
}
for char in lst[1] {
if char == "(" {
left += 1
} else {
right += 1
}
}
if left == right {
return "Yes"
} else {
return "No"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var left = 0
var right = 0
for char in lst[0] {
if char == "(" {
left += 1
} else {
right += 1
}
}
for char in lst[1] {
if char == "(" {
left += 1
} else {
right += 1
}
}
if left == right {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var count = 0
for c in lst[0] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for c in lst[1] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var count = 0
for c in lst[0] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for c in lst[1] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var count = 0
for c in lst.joined() {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
return count == 0? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var count = 0
for c in lst.joined() {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
return count == 0? "Yes" : "No"
}
```return count == 0? "Yes" : "No" // consecutive statements on a line must be separated by ';'return count == 0? "Yes" : "No" // cannot convert return expression of type 'Bool' to return type 'String'return count == 0? "Yes" : "No" // string literal is unusedreturn count == 0? "Yes" : "No" // consecutive statements on a line must be separated by ';'return count == 0? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Int'return count == 0? "Yes" : "No" // expected expressionfunc matchParens(lst: [String]) -> String {
var count = 0
for c in lst.joined() {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
return count == 0? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var count = 0
for c in lst.joined() {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
return count == 0? "Yes" : "No"
}
```return count == 0? "Yes" : "No" // consecutive statements on a line must be separated by ';'return count == 0? "Yes" : "No" // cannot convert return expression of type 'Bool' to return type 'String'return count == 0? "Yes" : "No" // string literal is unusedreturn count == 0? "Yes" : "No" // consecutive statements on a line must be separated by ';'return count == 0? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Int'return count == 0? "Yes" : "No" // expected expressionfunc matchParens(lst: [String]) -> String {
var count = 0
for c in lst[0] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for c in lst[1] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var count = 0
for c in lst[0] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for c in lst[1] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var count = 0
for c in lst[0] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for c in lst[1] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var count = 0
for c in lst[0] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for c in lst[1] {
if c == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc matchParens(lst: [String]) -> String {
var count = 0
for char in lst[0] {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for char in lst[1] {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
Examples:
matchParens(lst: ["()(", ")"]) == "Yes"
matchParens(lst: [")", ")"]) == "No"
Answer:
```swift
func matchParens(lst: [String]) -> String {
var count = 0
for char in lst[0] {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
count = 0
for char in lst[1] {
if char == "(" {
count += 1
} else {
count -= 1
}
if count < 0 {
return "No"
}
}
if count == 0 {
return "Yes"
} else {
return "No"
}
}
``` // XCTAssertTrue failedfunc maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array arr of integers and a positive integer k, return a sorted array
of length k with the maximum k numbers in arr.
Example 1:
Example 2:
Example 3:
Note:
1. The length of the array will be in the range of [1, 1000].
2. The elements in the array will be in the range of [-1000, 1000].
3. 0 <= k <= len(arr)
maximum(arr: [-3, -4, 5], k: 3) == [-4, -3, 5]
maximum(arr: [4, -4, 4], k: 2) == [4, 4]
maximum(arr: [-3, 2, 1, 2, -1, -2, 1], k: 1) == [2]
Answer:
```swift
func maximum(arr: [Int], k: Int) -> [Int] {
var arr = arr
arr.sort()
return Array(arr.suffix(k))
}
```func solution(lst: [Int]) -> Int {
var sum = 0
for (index, value) in lst.enumerated() {
if index % 2 == 0 && value % 2!= 0 {
sum += value
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, value) in lst.enumerated() {
if index % 2 == 0 && value % 2!= 0 {
sum += value
}
}
return sum
}
```if index % 2 == 0 && value % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif index % 2 == 0 && value % 2!= 0 { // '=' must have consistent whitespace on both sidesif index % 2 == 0 && value % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if index % 2 == 0 && value % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif index % 2 == 0 && value % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { (index, _) in index % 2 == 0 }.reduce(0) { sum, element in
let (_, value) = element
return sum + value
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { (index, _) in index % 2 == 0 }.reduce(0) { sum, element in
let (_, value) = element
return sum + value
}
}
``` // XCTAssertTrue failedfunc solution(lst: [Int]) -> Int {
return lst.enumerated().filter { (index, _) in index % 2 == 1 }.reduce(0) { sum, element in sum + element.element }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { (index, _) in index % 2 == 1 }.reduce(0) { sum, element in sum + element.element }
}
``` // XCTAssertTrue failedfunc solution(lst: [Int]) -> Int {
var sum = 0
for (index, num) in lst.enumerated() {
if index % 2 == 0 && num % 2!= 0 {
sum += num
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
var sum = 0
for (index, num) in lst.enumerated() {
if index % 2 == 0 && num % 2!= 0 {
sum += num
}
}
return sum
}
```if index % 2 == 0 && num % 2!= 0 { // '=' must have consistent whitespace on both sidesif index % 2 == 0 && num % 2!= 0 { // expression is not assignable: '&&' returns immutable valueif index % 2 == 0 && num % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'if index % 2 == 0 && num % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if index % 2 == 0 && num % 2!= 0 { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc solution(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { (index, _) in index % 2 == 1 }.reduce(0) { sum, element in sum + element.element }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { (index, _) in index % 2 == 1 }.reduce(0) { sum, element in sum + element.element }
}
``` // XCTAssertTrue failedfunc solution(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { (index, _) in index % 2 == 1 }.reduce(0) { sum, element in sum + element.element }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { (index, _) in index % 2 == 1 }.reduce(0) { sum, element in sum + element.element }
}
``` // XCTAssertTrue failedfunc solution(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution(lst: [5, 8, 7, 1]) == 12
solution(lst: [3, 3, 3, 3, 3]) == 9
solution(lst: [30, 13, 24, 321]) == 0
Answer:
```swift
func solution(lst: [Int]) -> Int {
return lst.enumerated().filter { $0.offset % 2 == 0 && $0.element % 2 == 1 }.map { $0.element }.reduce(0, +)
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] >= 100 {
sum += arr[i] % 100
} else {
sum += arr[i]
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] >= 100 {
sum += arr[i] % 100
} else {
sum += arr[i]
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
var count = 0
for num in arr {
if count == k {
break
}
if num < 100 {
sum += num
}
count += 1
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
var count = 0
for num in arr {
if count == k {
break
}
if num < 100 {
sum += num
}
count += 1
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
var count = 0
for num in arr {
if count == k {
break
}
if num < 100 {
sum += num
}
count += 1
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
var count = 0
for num in arr {
if count == k {
break
}
if num < 100 {
sum += num
}
count += 1
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] >= 100 {
sum += arr[i] % 100
} else {
sum += arr[i]
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] >= 100 {
sum += arr[i] % 100
} else {
sum += arr[i]
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] >= 100 {
sum += arr[i] % 100
} else {
sum += arr[i]
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] >= 100 {
sum += arr[i] % 100
} else {
sum += arr[i]
}
}
return sum
}
``` // XCTAssertTrue failedfunc addElements(arr: [Int], k: Int) -> Int {
var sum = 0
var count = 0
for num in arr {
if count == k {
break
}
if num < 100 {
sum += num
}
count += 1
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
var count = 0
for num in arr {
if count == k {
break
}
if num < 100 {
sum += num
}
count += 1
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
for i in 0..<k {
if arr[i] < 100 {
sum += arr[i]
}
}
return sum
}
```func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
var count = 0
for num in arr {
if count == k {
break
}
if num < 100 {
sum += num
}
count += 1
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr)
addElements(arr: [111, 21, 3, 4000, 5, 6, 7, 8, 9], k: 4) == 24
Answer:
```swift
func addElements(arr: [Int], k: Int) -> Int {
var sum = 0
var count = 0
for num in arr {
if count == k {
break
}
if num < 100 {
sum += num
}
count += 1
}
return sum
}
```func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = (3 * number) + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = (3 * number) + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
```while number!= 1 { // cannot force unwrap value of non-optional type 'Int'while number!= 1 { // use of '=' in a boolean context, did you mean '=='?while number!= 1 { // '=' must have consistent whitespace on both sidesif number % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if number % 2!= 0 { // '=' must have consistent whitespace on both sidesif number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
```while number!= 1 { // cannot force unwrap value of non-optional type 'Int'while number!= 1 { // use of '=' in a boolean context, did you mean '=='?while number!= 1 { // '=' must have consistent whitespace on both sidesif number % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if number % 2!= 0 { // '=' must have consistent whitespace on both sidesif number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
```while number!= 1 { // cannot force unwrap value of non-optional type 'Int'while number!= 1 { // use of '=' in a boolean context, did you mean '=='?while number!= 1 { // '=' must have consistent whitespace on both sidesif number % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if number % 2!= 0 { // '=' must have consistent whitespace on both sidesif number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
result.append(num)
}
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var num = n
while num!= 1 {
if num % 2 == 0 {
num /= 2
} else {
num = 3 * num + 1
}
if num % 2 == 1 {
result.append(num)
}
}
result.append(1)
return result.sorted()
}
```while num!= 1 { // cannot force unwrap value of non-optional type 'Int'while num!= 1 { // use of '=' in a boolean context, did you mean '=='?while num!= 1 { // '=' must have consistent whitespace on both sidesfunc getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 0 {
number /= 2
} else {
number = 3 * number + 1
}
if number % 2!= 0 {
result.append(number)
}
}
result.append(1)
return result.sorted()
}
```while number!= 1 { // cannot force unwrap value of non-optional type 'Int'while number!= 1 { // use of '=' in a boolean context, did you mean '=='?while number!= 1 { // '=' must have consistent whitespace on both sidesif number % 2!= 0 { // expression is not assignable: binary operator returns immutable valueif number % 2!= 0 { // use of '=' in a boolean context, did you mean '=='?if number % 2!= 0 { // '=' must have consistent whitespace on both sidesif number % 2!= 0 { // cannot force unwrap value of non-optional type 'Int'func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
```while number!= 1 { // cannot force unwrap value of non-optional type 'Int'while number!= 1 { // use of '=' in a boolean context, did you mean '=='?while number!= 1 { // '=' must have consistent whitespace on both sidesnumber = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot assign value of type 'Bool' to type 'Int'number = number % 2 == 0? number / 2 : 3 * number + 1 // expected expressionnumber = number % 2 == 0? number / 2 : 3 * number + 1 // cannot use optional chaining on non-optional value of type 'Int'number = number % 2 == 0? number / 2 : 3 * number + 1 // result of operator '/' is unusedfunc getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var current = n
while current!= 1 {
if current % 2 == 1 {
result.append(current)
}
current = current % 2 == 0? current / 2 : 3 * current + 1
}
result.append(1)
return result.sorted()
}
```while current!= 1 { // cannot force unwrap value of non-optional type 'Int'while current!= 1 { // use of '=' in a boolean context, did you mean '=='?while current!= 1 { // '=' must have consistent whitespace on both sidescurrent = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot assign value of type 'Bool' to type 'Int'current = current % 2 == 0? current / 2 : 3 * current + 1 // result of operator '/' is unusedcurrent = current % 2 == 0? current / 2 : 3 * current + 1 // consecutive statements on a line must be separated by ';'current = current % 2 == 0? current / 2 : 3 * current + 1 // cannot use optional chaining on non-optional value of type 'Int'current = current % 2 == 0? current / 2 : 3 * current + 1 // expected expressionfunc getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
```while number!= 1 { // cannot force unwrap value of non-optional type 'Int'while number!= 1 { // use of '=' in a boolean context, did you mean '=='?while number!= 1 { // '=' must have consistent whitespace on both sidesnumber = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot assign value of type 'Bool' to type 'Int'number = number % 2 == 0? number / 2 : 3 * number + 1 // expected expressionnumber = number % 2 == 0? number / 2 : 3 * number + 1 // cannot use optional chaining on non-optional value of type 'Int'number = number % 2 == 0? number / 2 : 3 * number + 1 // result of operator '/' is unusedfunc getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result: [Int] = []
var number = n
while number!= 1 {
if number % 2 == 1 {
result.append(number)
}
number = number % 2 == 0? number / 2 : 3 * number + 1
}
result.append(1)
return result.sorted()
}
```while number!= 1 { // cannot force unwrap value of non-optional type 'Int'while number!= 1 { // use of '=' in a boolean context, did you mean '=='?while number!= 1 { // '=' must have consistent whitespace on both sidesnumber = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'number = number % 2 == 0? number / 2 : 3 * number + 1 // consecutive statements on a line must be separated by ';'number = number % 2 == 0? number / 2 : 3 * number + 1 // cannot assign value of type 'Bool' to type 'Int'number = number % 2 == 0? number / 2 : 3 * number + 1 // expected expressionnumber = number % 2 == 0? number / 2 : 3 * number + 1 // cannot use optional chaining on non-optional value of type 'Int'number = number % 2 == 0? number / 2 : 3 * number + 1 // result of operator '/' is unusedfunc getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is even, the next term is one half of
the previous term. If the previous term is odd, the next term is 3 times the previous
term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.
Note:
1. Collatz(1) is [1].
2. returned array sorted in increasing order.
For example:
get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
getOddCollatz(n: 5) == [1, 5]
Answer:
```swift
func getOddCollatz(n: Int) -> [Int] {
var result = [Int]()
var num = n
while num!= 1 {
if num % 2 == 1 {
result.append(num)
}
num = num % 2 == 0? num / 2 : num * 3 + 1
}
result.append(1)
return result.sorted()
}
```while num!= 1 { // cannot force unwrap value of non-optional type 'Int'while num!= 1 { // '=' must have consistent whitespace on both sideswhile num!= 1 { // use of '=' in a boolean context, did you mean '=='?num = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'num = num % 2 == 0? num / 2 : num * 3 + 1 // cannot use optional chaining on non-optional value of type 'Int'num = num % 2 == 0? num / 2 : num * 3 + 1 // result of operator '/' is unusednum = num % 2 == 0? num / 2 : num * 3 + 1 // cannot assign value of type 'Bool' to type 'Int'num = num % 2 == 0? num / 2 : num * 3 + 1 // expected expressionnum = num % 2 == 0? num / 2 : num * 3 + 1 // consecutive statements on a line must be separated by ';'func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30)
return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30)
return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12
}
```let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // expected expressionlet validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // integer literal is unusedlet validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // consecutive statements on a line must be separated by ';'let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // consecutive statements on a line must be separated by ';'let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // cannot use optional chaining on non-optional value of type 'Int'return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // 'nil' is not compatible with expected argument type 'Bool'return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // use of '=' in a boolean context, did you mean '=='?return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // '=' must have consistent whitespace on both sidesreturn date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // cannot assign value of type 'Bool' to type 'Date'return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // cannot assign through '!': 'date' is a 'let' constantfunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let year = components.year!
let month = components.month!
let day = components.day!
if month == 2 {
return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0)
} else if [1, 3, 5, 7, 8, 10, 12].contains(month) {
return day >= 1 && day <= 31
} else {
return day >= 1 && day <= 30
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let year = components.year!
let month = components.month!
let day = components.day!
if month == 2 {
return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0)
} else if [1, 3, 5, 7, 8, 10, 12].contains(month) {
return day >= 1 && day <= 31
} else {
return day >= 1 && day <= 30
}
}
```return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // expression is not assignable: binary operator returns immutable valuereturn day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // '=' must have consistent whitespace on both sidesreturn day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // use of '=' in a boolean context, did you mean '=='?return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // cannot force unwrap value of non-optional type 'Int'return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // integer literal value '0' cannot be used as a boolean; did you mean 'false'?func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30)
return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30)
return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12
}
```let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // expected expressionlet validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // integer literal is unusedlet validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // consecutive statements on a line must be separated by ';'let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // consecutive statements on a line must be separated by ';'let validDays = components.month == 2? 29 : ([1, 3, 5, 7, 8, 10, 12].contains(components.month!)? 31 : 30) // cannot use optional chaining on non-optional value of type 'Int'return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // 'nil' is not compatible with expected argument type 'Bool'return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // use of '=' in a boolean context, did you mean '=='?return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // '=' must have consistent whitespace on both sidesreturn date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // cannot assign value of type 'Bool' to type 'Date'return date!= nil && components.day! > 0 && components.day! <= validDays && components.month! > 0 && components.month! <= 12 // cannot assign through '!': 'date' is a 'let' constantfunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let year = components.year!
let month = components.month!
let day = components.day!
if month == 2 {
return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0)
} else if [1, 3, 5, 7, 8, 10, 12].contains(month) {
return day >= 1 && day <= 31
} else {
return day >= 1 && day <= 30
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let year = components.year!
let month = components.month!
let day = components.day!
if month == 2 {
return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0)
} else if [1, 3, 5, 7, 8, 10, 12].contains(month) {
return day >= 1 && day <= 31
} else {
return day >= 1 && day <= 30
}
}
```return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // expression is not assignable: binary operator returns immutable valuereturn day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // '=' must have consistent whitespace on both sidesreturn day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // use of '=' in a boolean context, did you mean '=='?return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // cannot force unwrap value of non-optional type 'Int'return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // integer literal value '0' cannot be used as a boolean; did you mean 'false'?func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
guard let date = dateFormatter.date(from: date) else {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date)
let year = components.year!
let month = components.month!
let day = components.day!
if month == 2 {
return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0)
} else if [1, 3, 5, 7, 8, 10, 12].contains(month) {
return day >= 1 && day <= 31
} else {
return day >= 1 && day <= 30
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
guard let date = dateFormatter.date(from: date) else {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date)
let year = components.year!
let month = components.month!
let day = components.day!
if month == 2 {
return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0)
} else if [1, 3, 5, 7, 8, 10, 12].contains(month) {
return day >= 1 && day <= 31
} else {
return day >= 1 && day <= 30
}
}
```return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // expression is not assignable: binary operator returns immutable valuereturn day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // integer literal value '0' cannot be used as a boolean; did you mean 'false'?return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // '=' must have consistent whitespace on both sidesreturn day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // cannot force unwrap value of non-optional type 'Int'return day >= 1 && day <= 29 && year % 4 == 0 && (year % 100!= 0 || year % 400 == 0) // use of '=' in a boolean context, did you mean '=='?func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
if components.day! < 1 || (components.month! == 2 && components.day! > 29) || (components.month! == 4 || components.month! == 6 || components.month! == 9 || components.month! == 11) && components.day! > 30 || (components.month! == 1 || components.month! == 3 || components.month! == 5 || components.month! == 7 || components.month! == 8 || components.month! == 10 || components.month! == 12) && components.day! > 31 || components.month! < 1 || components.month! > 12 {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
if components.day! < 1 || (components.month! == 2 && components.day! > 29) || (components.month! == 4 || components.month! == 6 || components.month! == 9 || components.month! == 11) && components.day! > 30 || (components.month! == 1 || components.month! == 3 || components.month! == 5 || components.month! == 7 || components.month! == 8 || components.month! == 10 || components.month! == 12) && components.day! > 31 || components.month! < 1 || components.month! > 12 {
return false
}
return true
}
```func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let month = components.month!
let day = components.day!
if month == 2 {
return day >= 1 && day <= 29
} else if month == 4 || month == 6 || month == 9 || month == 11 {
return day >= 1 && day <= 30
} else {
return day >= 1 && day <= 31
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let month = components.month!
let day = components.day!
if month == 2 {
return day >= 1 && day <= 29
} else if month == 4 || month == 6 || month == 9 || month == 11 {
return day >= 1 && day <= 30
} else {
return day >= 1 && day <= 31
}
}
```func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let daysInMonth = calendar.range(of:.day, in:.month, for: date!)!.count
if components.month == 2 {
return components.day! >= 1 && components.day! <= 29
} else if [1, 3, 5, 7, 8, 10, 12].contains(components.month!) {
return components.day! >= 1 && components.day! <= 31
} else {
return components.day! >= 1 && components.day! <= 30
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
let daysInMonth = calendar.range(of:.day, in:.month, for: date!)!.count
if components.month == 2 {
return components.day! >= 1 && components.day! <= 29
} else if [1, 3, 5, 7, 8, 10, 12].contains(components.month!) {
return components.day! >= 1 && components.day! <= 31
} else {
return components.day! >= 1 && components.day! <= 30
}
}
```let daysInMonth = calendar.range(of:.day, in:.month, for: date!)!.count // initialization of immutable value 'daysInMonth' was never used; consider replacing with assignment to '_' or removing it // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US_POSIX")
dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
guard let date = dateFormatter.date(from: date) else {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date)
if components.month == 2 {
return components.day! >= 1 && components.day! <= 29
} else if [1, 3, 5, 7, 8, 10, 12].contains(components.month!) {
return components.day! >= 1 && components.day! <= 31
} else {
return components.day! >= 1 && components.day! <= 30
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
dateFormatter.locale = Locale(identifier: "en_US_POSIX")
dateFormatter.timeZone = TimeZone(secondsFromGMT: 0)
guard let date = dateFormatter.date(from: date) else {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date)
if components.month == 2 {
return components.day! >= 1 && components.day! <= 29
} else if [1, 3, 5, 7, 8, 10, 12].contains(components.month!) {
return components.day! >= 1 && components.day! <= 31
} else {
return components.day! >= 1 && components.day! <= 30
}
}
```func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
if components.day! < 1 || (components.month! == 2 && components.day! > 29) || (components.month! == 4 || components.month! == 6 || components.month! == 9 || components.month! == 11) && components.day! > 30 || (components.month! == 1 || components.month! == 3 || components.month! == 5 || components.month! == 7 || components.month! == 8 || components.month! == 10 || components.month! == 12) && components.day! > 31 || components.month! < 1 || components.month! > 12 {
return false
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You have to write a function which validates a given date string and
returns true if the date is valid otherwise false.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
3. The months should not be less than 1 or higher than 12.
4. The date should be in the format: mm-dd-yyyy
validDate(date: "03-11-2000") == true
validDate(date: "15-01-2012") == false
validDate(date: "04-0-2040") == false
validDate(date: "06-04-2020") == true
validDate(date: "06/04/2020") == false
Answer:
```swift
func validDate(date: String) -> Bool {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "MM-dd-yyyy"
let date = dateFormatter.date(from: date)
if date == nil {
return false
}
let calendar = Calendar.current
let components = calendar.dateComponents([.year,.month,.day], from: date!)
if components.day! < 1 || (components.month! == 2 && components.day! > 29) || (components.month! == 4 || components.month! == 6 || components.month! == 9 || components.month! == 11) && components.day! > 30 || (components.month! == 1 || components.month! == 3 || components.month! == 5 || components.month! == 7 || components.month! == 8 || components.month! == 10 || components.month! == 12) && components.day! > 31 || components.month! < 1 || components.month! > 12 {
return false
}
return true
}
```extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
if let words = txt.split(separator: " ") {
return.success(Array(words))
} else if let words = txt.split(separator: ",") {
return.success(Array(words))
} else {
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
if let words = txt.split(separator: " ") {
return.success(Array(words))
} else if let words = txt.split(separator: ",") {
return.success(Array(words))
} else {
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'if let words = txt.split(separator: " ") { // initializer for conditional binding must have Optional type, not '[String.SubSequence]' (aka 'Array<Substring>')return.success(Array(words)) // cannot convert value of type 'Array<String.SubSequence>' (aka 'Array<Substring>') to expected argument type '[String]'} else if let words = txt.split(separator: ",") { // initializer for conditional binding must have Optional type, not '[String.SubSequence]' (aka 'Array<Substring>')return.success(Array(words)) // cannot convert value of type 'Array<String.SubSequence>' (aka 'Array<Substring>') to expected argument type '[String]'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return.success(txt.split(separator: " ").map(String.init))
} else if txt.contains(",") {
return.success(txt.split(separator: ",").map(String.init))
} else {
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return.success(txt.split(separator: " ").map(String.init))
} else if txt.contains(",") {
return.success(txt.split(separator: ",").map(String.init))
} else {
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let words = txt.split(separator: ",") // invalid redeclaration of 'words'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let words = txt.split(separator: ",") // invalid redeclaration of 'words'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let words = txt.split(separator: ",") // invalid redeclaration of 'words'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let words = txt.split(separator: ",") // invalid redeclaration of 'words'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let words = txt.split(separator: ",") // invalid redeclaration of 'words'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return.success(txt.split(separator: " ").map(String.init))
} else if txt.contains(",") {
return.success(txt.split(separator: ",").map(String.init))
} else {
let count = txt.filter { "abcdefghijklmnopqrstuvwxyz".contains($0) && $0.asciiValue! % 2 == 1 }.count
return.failure(count)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
if txt.contains(" ") {
return.success(txt.split(separator: " ").map(String.init))
} else if txt.contains(",") {
return.success(txt.split(separator: ",").map(String.init))
} else {
let count = txt.filter { "abcdefghijklmnopqrstuvwxyz".contains($0) && $0.asciiValue! % 2 == 1 }.count
return.failure(count)
}
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
let words = txt.split(separator: " ")
if words.count > 1 {
return.success(words.map(String.init))
}
let words = txt.split(separator: ",")
if words.count > 1 {
return.success(words.map(String.init))
}
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'let words = txt.split(separator: ",") // invalid redeclaration of 'words'extension Int: Error {
}
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
if let words = txt.split(separator: " ") {
return.success(words.map(String.init))
} else if let words = txt.split(separator: ",") {
return.success(words.map(String.init))
} else {
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1,... ord('z') = 25
Examples
splitWords(txt: "Hello world!") ==.success(["Hello", "world!"])
splitWords(txt: "Hello,world!") ==.success(["Hello", "world!"])
splitWords(txt: "abcdef") ==.failure(3)
Answer:
```swift
extension Int: Error {}
func splitWords(txt: String) -> Result<[String], Int> {
if let words = txt.split(separator: " ") {
return.success(words.map(String.init))
} else if let words = txt.split(separator: ",") {
return.success(words.map(String.init))
} else {
var count = 0
for (index, _) in txt.enumerated() {
if index % 2 == 0 {
count += 1
}
}
return.failure(count)
}
}
```extension Int: Error {} // redundant conformance of 'Int' to protocol 'Error'if let words = txt.split(separator: " ") { // initializer for conditional binding must have Optional type, not '[String.SubSequence]' (aka 'Array<Substring>')} else if let words = txt.split(separator: ",") { // initializer for conditional binding must have Optional type, not '[String.SubSequence]' (aka 'Array<Substring>')func isSorted(lst: [Int]) -> Bool {
var previous: Int?
var hasDuplicate = false
for number in lst {
if let previous = previous {
if number < previous {
return false
} else if number == previous {
hasDuplicate = true
}
}
previous = number
}
return!hasDuplicate
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous: Int?
var hasDuplicate = false
for number in lst {
if let previous = previous {
if number < previous {
return false
} else if number == previous {
hasDuplicate = true
}
}
previous = number
}
return!hasDuplicate
}
```return!hasDuplicate // expected expression in 'return' statementfunc isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for current in lst[1..<lst.count] {
if current < previous {
return false
}
if current == previous {
hasDuplicate = true
}
previous = current
}
return!hasDuplicate
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for current in lst[1..<lst.count] {
if current < previous {
return false
}
if current == previous {
hasDuplicate = true
}
previous = current
}
return!hasDuplicate
}
```return!hasDuplicate // expected expression in 'return' statementfunc isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for num in lst[1..<lst.count] {
if num < previous {
return false
}
if num == previous {
hasDuplicate = true
}
previous = num
}
return!hasDuplicate
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for num in lst[1..<lst.count] {
if num < previous {
return false
}
if num == previous {
hasDuplicate = true
}
previous = num
}
return!hasDuplicate
}
```return!hasDuplicate // expected expression in 'return' statementfunc isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for number in lst[1..<lst.count] {
if number < previous {
return false
}
if number == previous {
hasDuplicate = true
}
previous = number
}
return!hasDuplicate
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for number in lst[1..<lst.count] {
if number < previous {
return false
}
if number == previous {
hasDuplicate = true
}
previous = number
}
return!hasDuplicate
}
```return!hasDuplicate // expected expression in 'return' statementfunc isSorted(lst: [Int]) -> Bool {
var previous: Int?
var hasDuplicate = false
for num in lst {
if let previous = previous {
if num < previous {
return false
} else if num == previous {
hasDuplicate = true
}
}
previous = num
}
return!hasDuplicate
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous: Int?
var hasDuplicate = false
for num in lst {
if let previous = previous {
if num < previous {
return false
} else if num == previous {
hasDuplicate = true
}
}
previous = num
}
return!hasDuplicate
}
```return!hasDuplicate // expected expression in 'return' statementfunc isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for current in lst[1..<lst.count] {
if current < previous {
return false
}
if current == previous {
hasDuplicate = true
}
previous = current
}
return!hasDuplicate
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for current in lst[1..<lst.count] {
if current < previous {
return false
}
if current == previous {
hasDuplicate = true
}
previous = current
}
return!hasDuplicate
}
```return!hasDuplicate // expected expression in 'return' statementfunc isSorted(lst: [Int]) -> Bool {
var previous: Int?
var hasDuplicate = false
for num in lst {
if let previous = previous {
if num < previous {
return false
} else if num == previous {
hasDuplicate = true
}
}
previous = num
}
return!hasDuplicate
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous: Int?
var hasDuplicate = false
for num in lst {
if let previous = previous {
if num < previous {
return false
} else if num == previous {
hasDuplicate = true
}
}
previous = num
}
return!hasDuplicate
}
```return!hasDuplicate // expected expression in 'return' statementfunc isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for i in 0..<lst.count {
if lst[i] < previous {
return false
}
if lst[i] == previous {
hasDuplicate = true
}
previous = lst[i]
}
return!hasDuplicate
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous = lst[0]
var hasDuplicate = false
for i in 0..<lst.count {
if lst[i] < previous {
return false
}
if lst[i] == previous {
hasDuplicate = true
}
previous = lst[i]
}
return!hasDuplicate
}
```return!hasDuplicate // expected expression in 'return' statementfunc isSorted(lst: [Int]) -> Bool {
var previous: Int?
for num in lst {
if let previous = previous {
if num < previous {
return false
}
}
previous = num
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous: Int?
for num in lst {
if let previous = previous {
if num < previous {
return false
}
}
previous = num
}
return true
}
``` // XCTAssertTrue failedfunc isSorted(lst: [Int]) -> Bool {
var previous: Int?
for number in lst {
if let previous = previous {
if number < previous {
return false
}
}
previous = number
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return whether or not they are sorted
in ascending order. If array has more than 1 duplicate of the same
number, return false. Assume no negative numbers and only integers.
Examples
isSorted(lst: [5]) == true
isSorted(lst: [1, 2, 3, 4, 5]) == true
isSorted(lst: [1, 3, 2, 4, 5]) == false
isSorted(lst: [1, 2, 3, 4, 5, 6]) == true
isSorted(lst: [1, 2, 3, 4, 5, 6, 7]) == true
isSorted(lst: [1, 3, 2, 4, 5, 6, 7]) == false
isSorted(lst: [1, 2, 2, 3, 3, 4]) == true
isSorted(lst: [1, 2, 2, 2, 3, 4]) == false
Answer:
```swift
func isSorted(lst: [Int]) -> Bool {
var previous: Int?
for number in lst {
if let previous = previous {
if number < previous {
return false
}
}
previous = number
}
return true
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length <= 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 1 {
return "NO"
}
for i in 2..<length {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // XCTAssertTrue failedfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to determine whether the length of intersection of these two
intervals is a prime number.
Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
which its length is 1, which not a prime number.
If the length of the intersection is a prime number, return "YES",
otherwise, return "NO".
If the two intervals don't intersect, return "NO".
[input/output] samples:
intersection(interval1: (1, 2), interval2: (2, 3)) == "NO"
intersection(interval1: (-1, 1), interval2: (0, 4)) == "NO"
intersection(interval1: (-3, -1), interval2: (-5, 5)) == "YES"
Answer:
```swift
func intersection(interval1: (Int, Int), interval2: (Int, Int)) -> String {
let start = max(interval1.0, interval2.0)
let end = min(interval1.1, interval2.1)
if start > end {
return "NO"
}
let length = end - start + 1
if length == 2 || length == 3 {
return "YES"
}
if length % 2 == 0 || length % 3 == 0 {
return "NO"
}
for i in 5...Int(sqrt(Double(length))) {
if length % i == 0 {
return "NO"
}
}
return "YES"
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
var product = 1
var sum = 0
for num in arr {
switch num {
case 0:
return 0
case let n where n > 0:
product *= n
default:
product *= -1
}
sum += abs(num)
}
return product * sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
var product = 1
var sum = 0
for num in arr {
switch num {
case 0:
return 0
case let n where n > 0:
product *= n
default:
product *= -1
}
sum += abs(num)
}
return product * sum
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
var product = 1
var sum = 0
for num in arr {
if num == 0 {
return 0
} else if num < 0 {
product *= -1
}
sum += abs(num)
}
return product * sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
var product = 1
var sum = 0
for num in arr {
if num == 0 {
return 0
} else if num < 0 {
product *= -1
}
sum += abs(num)
}
return product * sum
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
var product = 1
var sum = 0
for num in arr {
switch num {
case 0:
return 0
case let n where n > 0:
product *= n
case let n where n < 0:
product *= -1
default:
break
}
sum += abs(num)
}
return product * sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
var product = 1
var sum = 0
for num in arr {
switch num {
case 0:
return 0
case let n where n > 0:
product *= n
case let n where n < 0:
product *= -1
default:
break
}
sum += abs(num)
}
return product * sum
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // cannot use optional chaining on non-optional value of type 'Int'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // expected expressionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // cannot use optional chaining on non-optional value of type 'Int'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // expected expressionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // cannot use optional chaining on non-optional value of type 'Int'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // expected expressionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // cannot use optional chaining on non-optional value of type 'Int'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // expected expressionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // cannot use optional chaining on non-optional value of type 'Int'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // expected expressionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // cannot use optional chaining on non-optional value of type 'Int'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // expected expressionfunc prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return nil for empty arr.
Example:
prodSigns(arr: [1, 2, 2, -4]) == 9
prodSigns(arr: [0, 1]) == 0
prodSigns(arr: [] as [Int]) == nil
Answer:
```swift
func prodSigns(arr: [Int]) -> Int? {
guard!arr.isEmpty else { return nil }
let signs = arr.map { $0 == 0? 0 : $0 / abs($0) }
let magnitudes = arr.map { abs($0) }
return magnitudes.reduce(1, *) * signs.reduce(1, *)
}
```guard!arr.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // cannot use optional chaining on non-optional value of type 'Int'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // consecutive statements on a line must be separated by ';'let signs = arr.map { $0 == 0? 0 : $0 / abs($0) } // expected expressionfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n {
for j in 0..<n {
for l in 0..<k {
if l == 0 {
dp[i * n + j][l] = grid[i][j]
} else {
dp[i * n + j][l] = Int.max
for x in max(0, i - 1)... min(n - 1, i + 1) {
for y in max(0, j - 1)... min(n - 1, j + 1) {
if x == i && y == j {
continue
}
dp[i * n + j][l] = min(dp[i * n + j][l], dp[x * n + y][l - 1])
}
}
dp[i * n + j][l] += grid[i][j]
}
}
}
}
var minValue = Int.max
var minIndex = 0
for i in 0..<n * n {
if dp[i][k - 1] < minValue {
minValue = dp[i][k - 1]
minIndex = i
}
}
var cur = minIndex
for i in (0..<k).reversed() {
path[i] = grid[cur / n][cur % n]
var minValue = Int.max
for x in max(0, cur / n - 1)... min(n - 1, cur / n + 1) {
for y in max(0, cur % n - 1)... min(n - 1, cur % n + 1) {
if x == cur / n && y == cur % n {
continue
}
if dp[x * n + y][i - 1] < minValue {
minValue = dp[x * n + y][i - 1]
cur = x * n + y
}
}
}
}
return path
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n {
for j in 0..<n {
for l in 0..<k {
if l == 0 {
dp[i * n + j][l] = grid[i][j]
} else {
dp[i * n + j][l] = Int.max
for x in max(0, i - 1)... min(n - 1, i + 1) {
for y in max(0, j - 1)... min(n - 1, j + 1) {
if x == i && y == j {
continue
}
dp[i * n + j][l] = min(dp[i * n + j][l], dp[x * n + y][l - 1])
}
}
dp[i * n + j][l] += grid[i][j]
}
}
}
}
var minValue = Int.max
var minIndex = 0
for i in 0..<n * n {
if dp[i][k - 1] < minValue {
minValue = dp[i][k - 1]
minIndex = i
}
}
var cur = minIndex
for i in (0..<k).reversed() {
path[i] = grid[cur / n][cur % n]
var minValue = Int.max
for x in max(0, cur / n - 1)... min(n - 1, cur / n + 1) {
for y in max(0, cur % n - 1)... min(n - 1, cur % n + 1) {
if x == cur / n && y == cur % n {
continue
}
if dp[x * n + y][i - 1] < minValue {
minValue = dp[x * n + y][i - 1]
cur = x * n + y
}
}
}
}
return path
}
```for x in max(0, i - 1)... min(n - 1, i + 1) { // expected '{' to start the body of for-each loopfor y in max(0, j - 1)... min(n - 1, j + 1) { // expected '{' to start the body of for-each loopfor x in max(0, cur / n - 1)... min(n - 1, cur / n + 1) { // expected '{' to start the body of for-each loopfor y in max(0, cur % n - 1)... min(n - 1, cur % n + 1) { // expected '{' to start the body of for-each loopfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
for i in 0..<n * n {
for j in 0...k {
if j == 0 {
dp[i][j] = 0
path[i][j] = -1
} else {
dp[i][j] = Int.max
path[i][j] = -1
}
}
}
for i in 0..<n {
for j in 0..<n {
let index = i * n + j
for l in 0...k {
if l == 1 {
dp[index][l] = grid[i][j]
} else {
for m in 0..<n * n {
if m!= index && dp[m][l - 1]!= Int.max {
if dp[index][l] > dp[m][l - 1] + grid[i][j] {
dp[index][l] = dp[m][l - 1] + grid[i][j]
path[index][l] = m
}
}
}
}
}
}
}
var result = [Int]()
var current = 0
for i in 0...k {
if dp[current][i] == Int.max {
break
}
result.append(grid[current / n][current % n])
current = path[current][i]
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
for i in 0..<n * n {
for j in 0...k {
if j == 0 {
dp[i][j] = 0
path[i][j] = -1
} else {
dp[i][j] = Int.max
path[i][j] = -1
}
}
}
for i in 0..<n {
for j in 0..<n {
let index = i * n + j
for l in 0...k {
if l == 1 {
dp[index][l] = grid[i][j]
} else {
for m in 0..<n * n {
if m!= index && dp[m][l - 1]!= Int.max {
if dp[index][l] > dp[m][l - 1] + grid[i][j] {
dp[index][l] = dp[m][l - 1] + grid[i][j]
path[index][l] = m
}
}
}
}
}
}
}
var result = [Int]()
var current = 0
for i in 0...k {
if dp[current][i] == Int.max {
break
}
result.append(grid[current / n][current % n])
current = path[current][i]
}
return result
}
```if m!= index && dp[m][l - 1]!= Int.max { // use of '=' in a boolean context, did you mean '=='?if m!= index && dp[m][l - 1]!= Int.max { // cannot force unwrap value of non-optional type 'Int'if m!= index && dp[m][l - 1]!= Int.max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif m!= index && dp[m][l - 1]!= Int.max { // '=' must have consistent whitespace on both sidesif m!= index && dp[m][l - 1]!= Int.max { // cannot force unwrap value of non-optional type 'Int'if m!= index && dp[m][l - 1]!= Int.max { // '=' must have consistent whitespace on both sidesif m!= index && dp[m][l - 1]!= Int.max { // cannot assign value of type '()' to type 'Int'if m!= index && dp[m][l - 1]!= Int.max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
var dirs = [[-1, 0], [1, 0], [0, -1], [0, 1]]
var q = [(0, 0, 0)]
var res = [Int]()
while!q.isEmpty {
let (x, y, d) = q.removeFirst()
let val = grid[x][y]
if d > 0 {
for i in 0..<dirs.count {
let (nx, ny) = (x + dirs[i][0], y + dirs[i][1])
if nx >= 0 && nx < n && ny >= 0 && ny < n && dp[nx * n + ny][d - 1] == 0 {
dp[nx * n + ny][d - 1] = val
q.append((nx, ny, d - 1))
}
}
}
if d == k {
if res.isEmpty || val < res[0] {
res = [val]
} else if val == res[0] {
res.append(val)
}
}
}
return res
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
var dirs = [[-1, 0], [1, 0], [0, -1], [0, 1]]
var q = [(0, 0, 0)]
var res = [Int]()
while!q.isEmpty {
let (x, y, d) = q.removeFirst()
let val = grid[x][y]
if d > 0 {
for i in 0..<dirs.count {
let (nx, ny) = (x + dirs[i][0], y + dirs[i][1])
if nx >= 0 && nx < n && ny >= 0 && ny < n && dp[nx * n + ny][d - 1] == 0 {
dp[nx * n + ny][d - 1] = val
q.append((nx, ny, d - 1))
}
}
}
if d == k {
if res.isEmpty || val < res[0] {
res = [val]
} else if val == res[0] {
res.append(val)
}
}
}
return res
}
```while!q.isEmpty { // expected expression, var, or let in 'while' conditionfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n * n {
for j in 0...k {
if j == 0 {
dp[i][j] = grid[i / n][i % n]
} else {
dp[i][j] = Int.max
for (x, y) in [(i - 1, i - n), (i + 1, i + n)] {
if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1] + grid[i / n][i % n] < dp[i][j] {
dp[i][j] = dp[x][j - 1] + grid[i / n][i % n]
path[j - 1] = grid[i / n][i % n]
}
}
}
}
}
return path
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n * n {
for j in 0...k {
if j == 0 {
dp[i][j] = grid[i / n][i % n]
} else {
dp[i][j] = Int.max
for (x, y) in [(i - 1, i - n), (i + 1, i + n)] {
if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1] + grid[i / n][i % n] < dp[i][j] {
dp[i][j] = dp[x][j - 1] + grid[i / n][i % n]
path[j - 1] = grid[i / n][i % n]
}
}
}
}
}
return path
}
``` // XCTAssertTrue failedfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var parent = Array(repeating: Array(repeating: -1, count: k + 1), count: n * n)
for i in 0..<n * n {
for j in 0...k {
dp[i][j] = Int.max
}
}
for i in 0..<n * n {
dp[i][1] = grid[i / n][i % n]
}
for len in 3...k + 1 {
for i in 0..<n * n {
let x = i / n
let y = i % n
for j in max(0, i - n)..<min(n * n, i + n) {
if j == i { continue }
let newLen = len - (grid[j / n][j % n]!= grid[x][y])
if newLen > 0 && dp[j][newLen] > dp[i][len] + grid[j / n][j % n] {
dp[j][newLen] = dp[i][len] + grid[j / n][j % n]
parent[j][newLen] = i
}
}
}
}
var result = [Int]()
var x = (n * n) - 1
var y = k
while y > 1 {
result.append(grid[x / n][x % n])
let newX = parent[x][y]
y -= (grid[x / n][x % n]!= grid[newX / n][newX % n])
x = newX
}
result.append(grid[x / n][x % n])
return result.reversed()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var parent = Array(repeating: Array(repeating: -1, count: k + 1), count: n * n)
for i in 0..<n * n {
for j in 0...k {
dp[i][j] = Int.max
}
}
for i in 0..<n * n {
dp[i][1] = grid[i / n][i % n]
}
for len in 3...k + 1 {
for i in 0..<n * n {
let x = i / n
let y = i % n
for j in max(0, i - n)..<min(n * n, i + n) {
if j == i { continue }
let newLen = len - (grid[j / n][j % n]!= grid[x][y])
if newLen > 0 && dp[j][newLen] > dp[i][len] + grid[j / n][j % n] {
dp[j][newLen] = dp[i][len] + grid[j / n][j % n]
parent[j][newLen] = i
}
}
}
}
var result = [Int]()
var x = (n * n) - 1
var y = k
while y > 1 {
result.append(grid[x / n][x % n])
let newX = parent[x][y]
y -= (grid[x / n][x % n]!= grid[newX / n][newX % n])
x = newX
}
result.append(grid[x / n][x % n])
return result.reversed()
}
```let newLen = len - (grid[j / n][j % n]!= grid[x][y]) // cannot force unwrap value of non-optional type 'Int'let newLen = len - (grid[j / n][j % n]!= grid[x][y]) // cannot convert value of type '()' to expected argument type 'Int'let newLen = len - (grid[j / n][j % n]!= grid[x][y]) // '=' must have consistent whitespace on both sidesy -= (grid[x / n][x % n]!= grid[newX / n][newX % n]) // cannot convert value of type '()' to expected argument type 'Int'y -= (grid[x / n][x % n]!= grid[newX / n][newX % n]) // '=' must have consistent whitespace on both sidesy -= (grid[x / n][x % n]!= grid[newX / n][newX % n]) // cannot force unwrap value of non-optional type 'Int'func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n * n {
for j in 0...k {
if j == 0 {
dp[i][j] = grid[i / n][i % n]
} else {
dp[i][j] = Int.max
for (x, y) in [(i - 1, i - n), (i + 1, i + n)] {
if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max {
dp[i][j] = min(dp[i][j], dp[x][j - 1] + grid[i / n][i % n])
}
}
}
}
}
var i = (n * n) - 1
var j = k
while j > 0 {
path[j - 1] = grid[i / n][i % n]
for (x, y) in [(i - 1, i - n), (i + 1, i + n)] {
if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max && dp[x][j - 1] + grid[i / n][i % n] == dp[i][j] {
i = x
break
}
}
j -= 1
}
return path
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n * n {
for j in 0...k {
if j == 0 {
dp[i][j] = grid[i / n][i % n]
} else {
dp[i][j] = Int.max
for (x, y) in [(i - 1, i - n), (i + 1, i + n)] {
if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max {
dp[i][j] = min(dp[i][j], dp[x][j - 1] + grid[i / n][i % n])
}
}
}
}
}
var i = (n * n) - 1
var j = k
while j > 0 {
path[j - 1] = grid[i / n][i % n]
for (x, y) in [(i - 1, i - n), (i + 1, i + n)] {
if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max && dp[x][j - 1] + grid[i / n][i % n] == dp[i][j] {
i = x
break
}
}
j -= 1
}
return path
}
```if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max { // '=' must have consistent whitespace on both sidesif x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max { // expression is not assignable: '&&' returns immutable valueif x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max { // use of '=' in a boolean context, did you mean '=='?if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max { // cannot force unwrap value of non-optional type 'Int'if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max && dp[x][j - 1] + grid[i / n][i % n] == dp[i][j] { // expression is not assignable: '&&' returns immutable valueif x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max && dp[x][j - 1] + grid[i / n][i % n] == dp[i][j] { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max && dp[x][j - 1] + grid[i / n][i % n] == dp[i][j] { // '=' must have consistent whitespace on both sidesif x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max && dp[x][j - 1] + grid[i / n][i % n] == dp[i][j] { // cannot force unwrap value of non-optional type 'Int'if x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max && dp[x][j - 1] + grid[i / n][i % n] == dp[i][j] { // type 'Int' cannot be used as a boolean; test for '!= 0' insteadif x >= 0 && x < n * n && y >= 0 && y < n * n && dp[x][j - 1]!= Int.max && dp[x][j - 1] + grid[i / n][i % n] == dp[i][j] { // use of '=' in a boolean context, did you mean '=='?func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n {
for j in 0..<n {
for l in (0..<k).reversed() {
let index = i * n + j
if l == 0 {
dp[index][l] = grid[i][j]
} else {
dp[index][l] = Int.max
for (x, y) in [(i - 1, j), (i + 1, j), (i, j - 1), (i, j + 1)] {
if x >= 0 && x < n && y >= 0 && y < n {
let nextIndex = x * n + y
dp[index][l] = min(dp[index][l], dp[nextIndex][l - 1] + grid[i][j])
}
}
}
}
}
}
var index = 0
for i in 0..<n {
for j in 0..<n {
if dp[i * n + j][k - 1] < dp[index][k - 1] {
index = i * n + j
}
}
}
var l = k - 1
while l >= 0 {
path[l] = grid[index / n][index % n]
for (x, y) in [(index / n - 1, index % n), (index / n + 1, index % n), (index / n, index % n - 1), (index / n, index % n + 1)] {
if x >= 0 && x < n && y >= 0 && y < n && dp[x * n + y][l - 1] + grid[index / n][index % n] < dp[index][l] {
index = x * n + y
break
}
}
l -= 1
}
return path
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n {
for j in 0..<n {
for l in (0..<k).reversed() {
let index = i * n + j
if l == 0 {
dp[index][l] = grid[i][j]
} else {
dp[index][l] = Int.max
for (x, y) in [(i - 1, j), (i + 1, j), (i, j - 1), (i, j + 1)] {
if x >= 0 && x < n && y >= 0 && y < n {
let nextIndex = x * n + y
dp[index][l] = min(dp[index][l], dp[nextIndex][l - 1] + grid[i][j])
}
}
}
}
}
}
var index = 0
for i in 0..<n {
for j in 0..<n {
if dp[i * n + j][k - 1] < dp[index][k - 1] {
index = i * n + j
}
}
}
var l = k - 1
while l >= 0 {
path[l] = grid[index / n][index % n]
for (x, y) in [(index / n - 1, index % n), (index / n + 1, index % n), (index / n, index % n - 1), (index / n, index % n + 1)] {
if x >= 0 && x < n && y >= 0 && y < n && dp[x * n + y][l - 1] + grid[index / n][index % n] < dp[index][l] {
index = x * n + y
break
}
}
l -= 1
}
return path
}
``` // Fatal error: Index out of rangefunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
for i in 0..<n * n {
for j in 0..<k + 1 {
dp[i][j] = Int.max
path[i][j] = -1
}
}
for i in 0..<n * n {
dp[i][1] = grid[i / n][i % n]
}
for len in 2...k {
for i in 0..<n * n {
for j in 0..<n * n {
if abs(i - j) == 1 || abs(i - j) == n {
if dp[i][len - 1] + grid[j / n][j % n] < dp[j][len] {
dp[j][len] = dp[i][len - 1] + grid[j / n][j % n]
path[j][len] = i
}
}
}
}
}
var res = [Int]()
var cur = dp.indices.filter { dp[$0][k] == dp.map { $0[k] }.min()! }.first!
for _ in 1...k {
res.append(grid[cur / n][cur % n])
cur = path[cur][k]
}
return res.reversed()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
for i in 0..<n * n {
for j in 0..<k + 1 {
dp[i][j] = Int.max
path[i][j] = -1
}
}
for i in 0..<n * n {
dp[i][1] = grid[i / n][i % n]
}
for len in 2...k {
for i in 0..<n * n {
for j in 0..<n * n {
if abs(i - j) == 1 || abs(i - j) == n {
if dp[i][len - 1] + grid[j / n][j % n] < dp[j][len] {
dp[j][len] = dp[i][len - 1] + grid[j / n][j % n]
path[j][len] = i
}
}
}
}
}
var res = [Int]()
var cur = dp.indices.filter { dp[$0][k] == dp.map { $0[k] }.min()! }.first!
for _ in 1...k {
res.append(grid[cur / n][cur % n])
cur = path[cur][k]
}
return res.reversed()
}
``` // Fatal error: Range requires lowerBound <= upperBoundfunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
for i in 0..<n * n {
for j in 0..<k + 1 {
dp[i][j] = Int.max
path[i][j] = -1
}
}
dp[0][0] = 0
for i in 0..<n {
for j in 0..<n {
let index = i * n + j
for l in 0..<k {
if dp[index][l] == Int.max { continue }
let val = dp[index][l] + grid[i][j]
if val < dp[index][l + 1] {
dp[index][l + 1] = val
path[index][l + 1] = index
}
if i > 0 {
let val = dp[index][l] + grid[i - 1][j]
if val < dp[index - n][l + 1] {
dp[index - n][l + 1] = val
path[index - n][l + 1] = index
}
}
if j > 0 {
let val = dp[index][l] + grid[i][j - 1]
if val < dp[index - 1][l + 1] {
dp[index - 1][l + 1] = val
path[index - 1][l + 1] = index
}
}
}
}
}
var result = [Int]()
var index = (n - 1) * n + (n - 1)
var count = k
while count > 0 {
result.append(grid[index / n][index % n])
index = path[index][count]
count -= 1
}
return result.reversed()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
for i in 0..<n * n {
for j in 0..<k + 1 {
dp[i][j] = Int.max
path[i][j] = -1
}
}
dp[0][0] = 0
for i in 0..<n {
for j in 0..<n {
let index = i * n + j
for l in 0..<k {
if dp[index][l] == Int.max { continue }
let val = dp[index][l] + grid[i][j]
if val < dp[index][l + 1] {
dp[index][l + 1] = val
path[index][l + 1] = index
}
if i > 0 {
let val = dp[index][l] + grid[i - 1][j]
if val < dp[index - n][l + 1] {
dp[index - n][l + 1] = val
path[index - n][l + 1] = index
}
}
if j > 0 {
let val = dp[index][l] + grid[i][j - 1]
if val < dp[index - 1][l + 1] {
dp[index - 1][l + 1] = val
path[index - 1][l + 1] = index
}
}
}
}
}
var result = [Int]()
var index = (n - 1) * n + (n - 1)
var count = k
while count > 0 {
result.append(grid[index / n][index % n])
index = path[index][count]
count -= 1
}
return result.reversed()
}
``` // Fatal error: Index out of rangefunc minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1] = grid[i][j]
}
}
for length in 2...k {
for i in 0..<n {
for j in 0..<n {
for x in max(0, i - 1)..<min(n, i + 2) {
for y in max(0, j - 1)..<min(n, j + 2) {
if x == i && y == j { continue }
dp[i * n + j][length] = min(dp[i * n + j][length], dp[x * n + y][length - 1])
}
}
dp[i * n + j][length] += grid[i][j]
}
}
}
var minValue = Int.max
var minIndex = 0
for i in 0..<n * n {
if dp[i][k] < minValue {
minValue = dp[i][k]
minIndex = i
}
}
var length = k
var x = minIndex / n
var y = minIndex % n
while length > 0 {
path[k - length] = grid[x][y]
for i in max(0, x - 1)..<min(n, x + 2) {
for j in max(0, y - 1)..<min(n, y + 2) {
if i == x && j == y { continue }
if dp[i * n + j][length - 1] + grid[x][y] == dp[x * n + y][length] {
x = i
y = j
break
}
}
}
length -= 1
}
return path
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered arrays of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered array of the values on the cells that the minimum path go through.
Examples:
minPath(grid: [[1, 2, 3], [4, 5, 6], [7, 8, 9]], k: 3) == [1, 2, 1]
minPath(grid: [[5, 9, 3], [4, 1, 6], [7, 8, 2]], k: 1) == [1]
Answer:
```swift
func minPath(grid: [[Int]], k: Int) -> [Int] {
let n = grid.count
var dp = Array(repeating: Array(repeating: 0, count: k + 1), count: n * n)
var path = Array(repeating: 0, count: k)
for i in 0..<n {
for j in 0..<n {
dp[i * n + j][1] = grid[i][j]
}
}
for length in 2...k {
for i in 0..<n {
for j in 0..<n {
for x in max(0, i - 1)..<min(n, i + 2) {
for y in max(0, j - 1)..<min(n, j + 2) {
if x == i && y == j { continue }
dp[i * n + j][length] = min(dp[i * n + j][length], dp[x * n + y][length - 1])
}
}
dp[i * n + j][length] += grid[i][j]
}
}
}
var minValue = Int.max
var minIndex = 0
for i in 0..<n * n {
if dp[i][k] < minValue {
minValue = dp[i][k]
minIndex = i
}
}
var length = k
var x = minIndex / n
var y = minIndex % n
while length > 0 {
path[k - length] = grid[x][y]
for i in max(0, x - 1)..<min(n, x + 2) {
for j in max(0, y - 1)..<min(n, y + 2) {
if i == x && j == y { continue }
if dp[i * n + j][length - 1] + grid[x][y] == dp[x * n + y][length] {
x = i
y = j
break
}
}
}
length -= 1
}
return path
}
``` // XCTAssertTrue failedfunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
if n > 1 {
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
if n > 1 {
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var tribonacci = [1, 3]
for i in 3...n {
if i % 2 == 0 {
tribonacci.append(1 + i / 2)
} else {
tribonacci.append(tribonacci[i - 1] + tribonacci[i - 2] + tribonacci[i + 1])
}
}
return tribonacci
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var tribonacci = [1, 3]
for i in 3...n {
if i % 2 == 0 {
tribonacci.append(1 + i / 2)
} else {
tribonacci.append(tribonacci[i - 1] + tribonacci[i - 2] + tribonacci[i + 1])
}
}
return tribonacci
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
if n > 1 {
result[2] = 2
}
for i in 3...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
if n > 1 {
result[2] = 2
}
for i in 3...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var tribonacci = [1, 3]
for i in 2...n {
if i % 2 == 0 {
tribonacci.append(1 + i / 2)
} else {
tribonacci.append(tribonacci[i - 1] + tribonacci[i - 2] + tribonacci[i + 1])
}
}
return tribonacci
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var tribonacci = [1, 3]
for i in 2...n {
if i % 2 == 0 {
tribonacci.append(1 + i / 2)
} else {
tribonacci.append(tribonacci[i - 1] + tribonacci[i - 2] + tribonacci[i + 1])
}
}
return tribonacci
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var tribonacci = [Int](repeating: 1, count: n + 3)
tribonacci[1] = 3
tribonacci[2] = 2
for i in 3...n {
if i % 2 == 0 {
tribonacci[i] = 1 + i / 2
} else {
tribonacci[i] = tribonacci[i - 1] + tribonacci[i - 2] + tribonacci[i + 1]
}
}
return Array(tribonacci[0...n])
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var tribonacci = [Int](repeating: 1, count: n + 3)
tribonacci[1] = 3
tribonacci[2] = 2
for i in 3...n {
if i % 2 == 0 {
tribonacci[i] = 1 + i / 2
} else {
tribonacci[i] = tribonacci[i - 1] + tribonacci[i - 2] + tribonacci[i + 1]
}
}
return Array(tribonacci[0...n])
}
``` // XCTAssertTrue failedfunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
if n > 1 {
result[2] = 2
}
for i in 3...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
if n > 1 {
result[2] = 2
}
for i in 3...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return result
}
``` // Fatal error: Index out of rangefunc tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
if n < 1 {
return Array(result)
}
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return Array(result)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
For example:
tri(2) = 1 + (2 / 2) = 2
tri(4) = 3
tri(3) = tri(2) + tri(1) + tri(4)
= 2 + 3 + 3 = 8
You are given a non-negative integer number n, you have to a return an array of the
first n + 1 numbers of the Tribonacci sequence.
Examples:
tri(n: 3) == [1, 3, 2, 8]
Answer:
```swift
func tri(n: Int) -> [Int] {
var result = [Int](repeating: 0, count: n + 1)
result[0] = 1
result[1] = 3
if n < 1 {
return Array(result)
}
for i in 2...n {
if i % 2 == 0 {
result[i] = 1 + i / 2
} else {
result[i] = result[i - 1] + result[i - 2] + result[i + 1]
}
}
return Array(result)
}
``` // Fatal error: Index out of rangefunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(n: 1) == 1
digits(n: 4) == 0
digits(n: 235) == 15
Answer:
```swift
func digits(n: Int) -> Int {
var product = 1
var number = n
while number > 0 {
let digit = number % 10
if digit % 2 == 1 {
product *= digit
}
number /= 10
}
return product
}
``` // XCTAssertTrue failedfunc isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes a string as input which contains only square brackets.
The function should return true if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
isNested(string: "[[]]") == true
isNested(string: "[]]]]]]][[[[[]") == false
isNested(string: "[][]") == false
isNested(string: "[]") == false
isNested(string: "[[][]]") == true
isNested(string: "[[]][[") == true
Answer:
```swift
func isNested(string: String) -> Bool {
var stack = [Character]()
for char in string {
if char == "[" {
stack.append(char)
} else if char == "]" {
if stack.isEmpty {
return false
}
stack.removeLast()
}
}
return stack.isEmpty? false : true
}
```return stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // expected expressionreturn stack.isEmpty? false : true // boolean literal is unusedreturn stack.isEmpty? false : true // consecutive statements on a line must be separated by ';'return stack.isEmpty? false : true // cannot use optional chaining on non-optional value of type 'Bool'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given an array of numbers.
You need to return the sum of squared numbers in the given array,
round each element in the array to the upper int(Ceiling) first.
Examples:
sumSquares(lst: [1.0, 2.0, 3.0]) == 14
sumSquares(lst: [1.0, 4.0, 9.0]) == 98
sumSquares(lst: [1.0, 3.0, 5.0, 7.0]) == 84
sumSquares(lst: [1.4, 4.2, 0.0]) == 29
sumSquares(lst: [-2.4, 1.0, 1.0]) == 6
Answer:
```swift
func sumSquares(lst: [Double]) -> Int {
let squaredNumbers = lst.map { ceil($0 * $0) }
let sum = squaredNumbers.reduce(0, +)
return sum
}
```return sum // cannot convert return expression of type 'Double' to return type 'Int'func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
let isLetter = lastChar?.isLetter?? false
let isNotPartOfWord = txt.suffix(from: txt.index(before: txt.endIndex)).trimmingCharacters(in:.whitespacesAndNewlines).isEmpty
return isLetter && isNotPartOfWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
let isLetter = lastChar?.isLetter?? false
let isNotPartOfWord = txt.suffix(from: txt.index(before: txt.endIndex)).trimmingCharacters(in:.whitespacesAndNewlines).isEmpty
return isLetter && isNotPartOfWord
}
```let isLetter = lastChar?.isLetter?? false // cannot use optional chaining on non-optional value of type 'Bool'let isLetter = lastChar?.isLetter?? false // cannot use optional chaining on non-optional value of type 'Bool'let isLetter = lastChar?.isLetter?? false // boolean literal is unusedlet isLetter = lastChar?.isLetter?? false // consecutive statements on a line must be separated by ';'func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
let isLetter = lastChar?.isLetter?? false
let isNotPartOfWord = txt.dropLast().rangeOfCharacter(from:.alphanumerics, options:.fortranForm)!= nil
return isLetter && isNotPartOfWord
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
let isLetter = lastChar?.isLetter?? false
let isNotPartOfWord = txt.dropLast().rangeOfCharacter(from:.alphanumerics, options:.fortranForm)!= nil
return isLetter && isNotPartOfWord
}
```let isLetter = lastChar?.isLetter?? false // cannot use optional chaining on non-optional value of type 'Bool'let isLetter = lastChar?.isLetter?? false // cannot use optional chaining on non-optional value of type 'Bool'let isLetter = lastChar?.isLetter?? false // boolean literal is unusedlet isLetter = lastChar?.isLetter?? false // consecutive statements on a line must be separated by ';'let isNotPartOfWord = txt.dropLast().rangeOfCharacter(from:.alphanumerics, options:.fortranForm)!= nil // '=' must have consistent whitespace on both sideslet isNotPartOfWord = txt.dropLast().rangeOfCharacter(from:.alphanumerics, options:.fortranForm)!= nil // cannot infer contextual base in reference to member 'alphanumerics'let isNotPartOfWord = txt.dropLast().rangeOfCharacter(from:.alphanumerics, options:.fortranForm)!= nil // value of type '[String.Element]' (aka 'Array<Character>') has no member 'rangeOfCharacter'let isNotPartOfWord = txt.dropLast().rangeOfCharacter(from:.alphanumerics, options:.fortranForm)!= nil // cannot infer contextual base in reference to member 'fortranForm'func checkIfLastCharIsALetter(txt: String) -> Bool {
let characters = Array(txt)
let lastCharacter = characters.last
if let lastCharacter = lastCharacter {
if lastCharacter.isLetter {
let reversedCharacters = characters.reversed()
if reversedCharacters.contains(" ") {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let characters = Array(txt)
let lastCharacter = characters.last
if let lastCharacter = lastCharacter {
if lastCharacter.isLetter {
let reversedCharacters = characters.reversed()
if reversedCharacters.contains(" ") {
return true
}
}
}
return false
}
``` // XCTAssertTrue failedfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -1)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return false
} else {
return true
}
} else {
return false
}
} else {
return false
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -1)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return false
} else {
return true
}
} else {
return false
}
} else {
return false
}
}
``` // XCTAssertTrue failedfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let characters = Array(txt)
let lastCharacter = characters.last
if let lastCharacter = lastCharacter {
if lastCharacter.isLetter {
let reversedCharacters = characters.reversed()
if reversedCharacters.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let characters = Array(txt)
let lastCharacter = characters.last
if let lastCharacter = lastCharacter {
if lastCharacter.isLetter {
let reversedCharacters = characters.reversed()
if reversedCharacters.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}
``` // XCTAssertTrue failedfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
}
}
}
return false
}
``` // Fatal error: String index is out of boundsfunc checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns true if the last character
of a given string is an alphabetical character and is not
a part of a word, and false otherwise.
Note: "word" is a group of characters separated by space.
Examples:
checkIfLastCharIsALetter(txt: "apple pie") == false
checkIfLastCharIsALetter(txt: "apple pi e") == true
checkIfLastCharIsALetter(txt: "apple pi e ") == false
checkIfLastCharIsALetter(txt: "") == false
Answer:
```swift
func checkIfLastCharIsALetter(txt: String) -> Bool {
let lastChar = txt.last
if let lastChar = lastChar {
if lastChar.isLetter {
let range = txt.index(txt.endIndex, offsetBy: -2)..<txt.endIndex
let substring = txt[range]
if substring.contains(" ") {
return true
} else {
return false
}
} else {
return false
}
} else {
return false
}
}
``` // Fatal error: String index is out of boundsfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 {
continue
}
if value >= arr[index - 1] {
continue
}
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 {
continue
}
if value >= arr[index - 1] {
continue
}
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (i, num) in arr.enumerated() {
if i == 0 {
continue
}
if num < arr[i - 1] {
maxIndex = i - 1
break
}
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (i, num) in arr.enumerated() {
if i == 0 {
continue
}
if num < arr[i - 1] {
maxIndex = i - 1
break
}
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 {
continue
}
if value >= arr[index - 1] {
continue
}
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 {
continue
}
if value >= arr[index - 1] {
continue
}
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 {
continue
}
if value >= arr[index - 1] {
continue
}
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 {
continue
}
if value >= arr[index - 1] {
continue
}
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (i, num) in arr.enumerated() {
if i == 0 || num >= arr[i - 1] {
maxIndex = i
}
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (i, num) in arr.enumerated() {
if i == 0 || num >= arr[i - 1] {
maxIndex = i
}
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (i, num) in arr.enumerated() {
if i == 0 {
continue
}
if num < arr[i - 1] {
maxIndex = i - 1
}
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (i, num) in arr.enumerated() {
if i == 0 {
continue
}
if num < arr[i - 1] {
maxIndex = i - 1
}
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 { continue }
if value >= arr[index - 1] { continue }
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 { continue }
if value >= arr[index - 1] { continue }
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 {
continue
}
if value >= arr[index - 1] {
continue
}
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 {
continue
}
if value >= arr[index - 1] {
continue
}
maxIndex = max(maxIndex, index - 1)
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 || value < arr[index - 1] {
maxIndex = index
}
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
for (index, value) in arr.enumerated() {
if index == 0 || value < arr[index - 1] {
maxIndex = index
}
}
return maxIndex
}
``` // XCTAssertTrue failedfunc canArrange(arr: [Int]) -> Int {
var maxIndex = -1
var max = Int.min
for (index, num) in arr.enumerated() {
if num >= max {
max = num
maxIndex = index
}
}
return maxIndex
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
canArrange(arr: [1, 2, 4, 3, 5]) == 3
canArrange(arr: [1, 2, 3]) == -1
Answer:
```swift
func canArrange(arr: [Int]) -> Int {
var maxIndex = -1
var max = Int.min
for (index, num) in arr.enumerated() {
if num >= max {
max = num
maxIndex = index
}
}
return maxIndex
}
``` // XCTAssertTrue failedfunc largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for number in lst {
if number < 0 {
if largestNegative == nil || number > largestNegative! {
largestNegative = number
}
} else if number > 0 {
if smallestPositive == nil || number < smallestPositive! {
smallestPositive = number
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for number in lst {
if number < 0 {
if largestNegative == nil || number > largestNegative! {
largestNegative = number
}
} else if number > 0 {
if smallestPositive == nil || number < smallestPositive! {
smallestPositive = number
}
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}
```func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in an array.
If there is no negative or positive integers, return them as nil.
Examples:
largestSmallestIntegers(lst: [2, 4, 1, 3, 5, 7]) == (nil, 1)
largestSmallestIntegers(lst: [] as [Int]) == (nil, nil)
largestSmallestIntegers(lst: [0]) == (nil, nil)
Answer:
```swift
func largestSmallestIntegers(lst: [Int]) -> (Int?, Int?) {
var largestNegative: Int?
var smallestPositive: Int?
for num in lst {
if num < 0 {
if largestNegative == nil || num > largestNegative! {
largestNegative = num
}
} else if num > 0 {
if smallestPositive == nil || num < smallestPositive! {
smallestPositive = num
}
}
}
return (largestNegative, smallestPositive)
}
```enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Double' is unusedreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Double' is unusedreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b)?? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a) > Double(b)?? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a) > b?? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b)?? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a) > Double(b)?? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a) > b?? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b)?? a : b // expected expressionreturn Double(a) > Double(b)?? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b)?? a : b // expression of type 'Double' is unusedreturn a > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)?? a : b // expected expressionreturn a > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // no exact matches in call to initializerreturn Double(a) > Double(b)?? a : b // expression of type 'String' is unusedreturn Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // no exact matches in call to initializerreturn Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b)?? a : b // expected expressionreturn Double(a) > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b?? a : b // no exact matches in call to initializerreturn Double(a) > b?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > b?? a : b // expected expressionreturn Double(a) > b?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b?? a : b // expression of type 'String' is unusedreturn Double(a) > b?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // expression of type 'String' is unusedreturn Double(a) > Double(b)?? a : b // expected expressionreturn Double(a) > Double(b)?? a : b // no exact matches in call to initializerreturn Double(a) > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Double' is unusedreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Double' is unusedreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Double' is unusedreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b)?? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a) > Double(b)?? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a) > b?? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b)?? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a) > Double(b)?? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a) > b?? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b)?? a : b // expected expressionreturn Double(a) > Double(b)?? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b)?? a : b // expression of type 'Double' is unusedreturn a > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)?? a : b // expected expressionreturn a > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // no exact matches in call to initializerreturn Double(a) > Double(b)?? a : b // expression of type 'String' is unusedreturn Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // no exact matches in call to initializerreturn Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b)?? a : b // expected expressionreturn Double(a) > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b?? a : b // no exact matches in call to initializerreturn Double(a) > b?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > b?? a : b // expected expressionreturn Double(a) > b?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b?? a : b // expression of type 'String' is unusedreturn Double(a) > b?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // expression of type 'String' is unusedreturn Double(a) > Double(b)?? a : b // expected expressionreturn Double(a) > Double(b)?? a : b // no exact matches in call to initializerreturn Double(a) > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b)?? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a) > Double(b)?? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b)?? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a) > Double(b)?? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a) > Double(b)?? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b)?? a : b // expected expressionreturn Double(a) > Double(b)?? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b)?? a : b // expression of type 'Double' is unusedreturn a > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)?? a : b // expected expressionreturn a > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // no exact matches in call to initializerreturn Double(a) > Double(b)?? a : b // expression of type 'String' is unusedreturn Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // no exact matches in call to initializerreturn Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b)?? a : b // expected expressionreturn Double(a) > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // no exact matches in call to initializerreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // expression of type 'String' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // expression of type 'String' is unusedreturn Double(a) > Double(b)?? a : b // expected expressionreturn Double(a) > Double(b)?? a : b // no exact matches in call to initializerreturn Double(a) > Double(b)?? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b)?? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b)?? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b)?? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Double' is unusedreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return nil if the values are equal.
Note: If a real number is represented as a string, the floating point might be. or,
compareOne(a:.intValue(1), b:.doubleValue(2.5)) ==.doubleValue(2.5)
compareOne(a:.intValue(1), b:.stringValue("2,3")) ==.stringValue("2,3")
compareOne(a:.stringValue("5,1"), b:.stringValue("6")) ==.stringValue("6")
compareOne(a:.stringValue("1"), b:.intValue(1)) == nil
Answer:
```swift
enum Value: Equatable, Hashable {
case intValue(Int)
case doubleValue(Double)
case stringValue(String)
}
func compareOne(a: Value, b: Value) -> Value? {
switch (a, b) {
case (.intValue(let a),.intValue(let b)):
return a > b? a : b
case (.intValue(let a),.doubleValue(let b)):
return Double(a) > b? a : b
case (.intValue(let a),.stringValue(let b)):
return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.doubleValue(let a),.intValue(let b)):
return a > Double(b)? a : b
case (.doubleValue(let a),.doubleValue(let b)):
return a > b? a : b
case (.doubleValue(let a),.stringValue(let b)):
return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
case (.stringValue(let a),.intValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b
case (.stringValue(let a),.doubleValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b
case (.stringValue(let a),.stringValue(let b)):
return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b
}
}
```return a > b? a : b // expression of type 'Int' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Int'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn Double(a) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // expected expressionreturn Double(a) > b? a : b // expression of type 'Int' is unusedreturn Double(a) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Int' is unusedreturn Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b)? a : b // no exact matches in call to initializerreturn a > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b)? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > Double(b)? a : b // expected expressionreturn a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // consecutive statements on a line must be separated by ';'return a > Double(b)? a : b // expression of type 'Double' is unusedreturn a > b? a : b // expression of type 'Double' is unusedreturn a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return a > b? a : b // consecutive statements on a line must be separated by ';'return a > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return a > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > b? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'Double' is unusedreturn a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return a > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b)? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // value of optional type 'Double?' must be unwrapped to a value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // cannot use optional chaining on non-optional value of type 'Double'return Double(a.replacingOccurrences(of: ",", with: ".")) > b? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // cannot convert return expression of type 'Bool' to return type 'Value?'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // no exact matches in call to initializerreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expected expressionreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // consecutive statements on a line must be separated by ';'return Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // expression of type 'String' is unusedreturn Double(a.replacingOccurrences(of: ",", with: ".")) > Double(b.replacingOccurrences(of: ",", with: "."))? a : b // binary operator '>' cannot be applied to operands of type 'Double' and 'Double?'func isEqualToSumEven(n: Int) -> Bool {
if n <= 8 {
return false
}
for i in 2...(n/2) {
let remaining = n - i
if remaining % 2 == 0 {
let numEven = remaining / 2
if numEven % 2 == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
if n <= 8 {
return false
}
for i in 2...(n/2) {
let remaining = n - i
if remaining % 2 == 0 {
let numEven = remaining / 2
if numEven % 2 == 0 {
return true
}
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
if n <= 8 {
return false
}
for i in 2...n/2 {
let remaining = n - i
if remaining % 2 == 0 && remaining / 2 % 2 == 0 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
if n <= 8 {
return false
}
for i in 2...n/2 {
let remaining = n - i
if remaining % 2 == 0 && remaining / 2 % 2 == 0 {
return true
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
if sum == n && count == 4 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
if sum == n && count == 4 {
return true
}
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
if sum == n && count == 4 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
if sum == n && count == 4 {
return true
}
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
let evenNumbers = [2, 4, 6, 8, 10, 12, 14, 16, 18, 20]
var sum = 0
var count = 0
for number in evenNumbers {
if sum + number > n {
break
}
sum += number
count += 1
if sum == n && count == 4 {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let evenNumbers = [2, 4, 6, 8, 10, 12, 14, 16, 18, 20]
var sum = 0
var count = 0
for number in evenNumbers {
if sum + number > n {
break
}
sum += number
count += 1
if sum == n && count == 4 {
return true
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
for i in 2...n/2 {
let j = i + 2
let k = j + 2
let l = k + 2
if i + j + k + l == n {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
for i in 2...n/2 {
let j = i + 2
let k = j + 2
let l = k + 2
if i + j + k + l == n {
return true
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
let evenNumbers = [2, 4, 6, 8, 10, 12, 14, 16, 18, 20]
var sum = 0
var count = 0
for number in evenNumbers {
sum += number
count += 1
if sum == n {
return true
}
if sum > n {
break
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
let evenNumbers = [2, 4, 6, 8, 10, 12, 14, 16, 18, 20]
var sum = 0
var count = 0
for number in evenNumbers {
sum += number
count += 1
if sum == n {
return true
}
if sum > n {
break
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
if sum == n && count == 4 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
if sum == n && count == 4 {
return true
}
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
if n <= 8 {
return false
}
for i in 2...(n/2) {
let remaining = n - i
if remaining % 2 == 0 {
let count = remaining / 2
if count % 2 == 0 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
if n <= 8 {
return false
}
for i in 2...(n/2) {
let remaining = n - i
if remaining % 2 == 0 {
let count = remaining / 2
if count % 2 == 0 {
return true
}
}
}
return false
}
``` // XCTAssertTrue failedfunc isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
if sum == n && count == 4 {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
isEqualToSumEven(n: 4) == false
isEqualToSumEven(n: 6) == false
isEqualToSumEven(n: 8) == true
Answer:
```swift
func isEqualToSumEven(n: Int) -> Bool {
var sum = 0
var count = 0
for i in 2...n {
if i % 2 == 0 {
sum += i
count += 1
if sum == n && count == 4 {
return true
}
}
}
return false
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
}
var result = 1
for i in 1...n {
result *= i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
}
var result = 1
for i in 1...n {
result *= i
}
return result
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
}
var result = 1
for i in 1...n {
result *= i
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
}
var result = 1
for i in 1...n {
result *= i
}
return result
}
``` // XCTAssertTrue failedfunc specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! *... * 1!
where n > 0
For example:
The function will receive an integer as input and should return the special
factorial of this integer.
specialFactorial(n: 4) == 288
Answer:
```swift
func specialFactorial(n: Int) -> Int {
if n == 0 {
return 1
} else {
return n * specialFactorial(n: n - 1)
}
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let result = text.replacingOccurrences(of: " {2,}", with: "-", options:.regularExpression)
return result.replacingOccurrences(of: " ", with: "_")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let result = text.replacingOccurrences(of: " {2,}", with: "-", options:.regularExpression)
return result.replacingOccurrences(of: " ", with: "_")
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let result = text.replacingOccurrences(of: " {2,}", with: "-", options:.regularExpression)
return result.replacingOccurrences(of: " ", with: "_")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let result = text.replacingOccurrences(of: " {2,}", with: "-", options:.regularExpression)
return result.replacingOccurrences(of: " ", with: "_")
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = ""
for (index, word) in words.enumerated() {
if index == 0 {
result += String(word)
} else if word.count > 2 {
result += "-\(word)"
} else {
result += "_\(word)"
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = ""
for (index, word) in words.enumerated() {
if index == 0 {
result += String(word)
} else if word.count > 2 {
result += "-\(word)"
} else {
result += "_\(word)"
}
}
return result
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = [String]()
for component in components {
if component.count > 2 {
result.append(component.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(component.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let components = text.components(separatedBy: " ")
var result = [String]()
for component in components {
if component.count > 2 {
result.append(component.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(component.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let components = text.split(separator: " ")
var result = [String]()
for component in components {
if component.count > 2 {
result.append(component.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(component.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: "")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let components = text.split(separator: " ")
var result = [String]()
for component in components {
if component.count > 2 {
result.append(component.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(component.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: "")
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: "")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: "")
}
``` // XCTAssertTrue failedfunc fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fixSpaces(text: " Example") == "Example"
fixSpaces(text: " Example 1") == "Example_1"
fixSpaces(text: " Example 2") == "_Example_2"
fixSpaces(text: " Example 3") == "_Example-3"
Answer:
```swift
func fixSpaces(text: String) -> String {
let words = text.split(separator: " ")
var result = [String]()
for word in words {
if word.count > 2 {
result.append(word.replacingOccurrences(of: " ", with: "-"))
} else {
result.append(word.replacingOccurrences(of: " ", with: "_"))
}
}
return result.joined(separator: " ")
}
``` // XCTAssertTrue failedfunc fileNameCheck(fileName: String) -> String {
let name = fileName.lowercased()
let components = name.split(separator: ".")
guard components.count == 2,
let firstComponent = components.first,
let lastComponent = components.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
lastComponent.count <= 3,
lastComponent.allSatisfy({ $0.isdigit }) else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
return validExtensions.contains(lastComponent)? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let name = fileName.lowercased()
let components = name.split(separator: ".")
guard components.count == 2,
let firstComponent = components.first,
let lastComponent = components.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
lastComponent.count <= 3,
lastComponent.allSatisfy({ $0.isdigit }) else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
return validExtensions.contains(lastComponent)? "Yes" : "No"
}
```lastComponent.allSatisfy({ $0.isdigit }) else { // value of type 'Substring.Element' (aka 'Character') has no member 'isdigit'return validExtensions.contains(lastComponent)? "Yes" : "No" // consecutive statements on a line must be separated by ';'return validExtensions.contains(lastComponent)? "Yes" : "No" // expected expressionreturn validExtensions.contains(lastComponent)? "Yes" : "No" // string literal is unusedreturn validExtensions.contains(lastComponent)? "Yes" : "No" // instance method 'contains' requires the types 'String' and 'Substring.Element' (aka 'Character') be equivalentreturn validExtensions.contains(lastComponent)? "Yes" : "No" // consecutive statements on a line must be separated by ';'return validExtensions.contains(lastComponent)? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
guard fileNameComponents.count == 2,
let firstComponent = fileNameComponents.first,
let lastComponent = fileNameComponents.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
lastComponent.count <= 3,
lastComponent.allSatisfy({ $0.isDigit }) else {
return "No"
}
let validFileExtensions = ["txt", "exe", "dll"]
guard validFileExtensions.contains(lastComponent) else {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
guard fileNameComponents.count == 2,
let firstComponent = fileNameComponents.first,
let lastComponent = fileNameComponents.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
lastComponent.count <= 3,
lastComponent.allSatisfy({ $0.isDigit }) else {
return "No"
}
let validFileExtensions = ["txt", "exe", "dll"]
guard validFileExtensions.contains(lastComponent) else {
return "No"
}
return "Yes"
}
```lastComponent.allSatisfy({ $0.isDigit }) else { // value of type 'Substring.Element' (aka 'Character') has no member 'isDigit'guard validFileExtensions.contains(lastComponent) else { // instance method 'contains' requires the types 'String' and 'Substring.Element' (aka 'Character') be equivalentfunc fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
guard fileNameComponents.count == 2 else {
return "No"
}
let fileNameWithoutExtension = String(fileNameComponents[0])
let fileExtension = String(fileNameComponents[1])
let containsOnlyDigits = fileNameWithoutExtension.rangeOfCharacter(from:.decimalDigits) == nil
guard!containsOnlyDigits else {
return "No"
}
let firstCharacter = fileNameWithoutExtension.first
guard let firstCharacter = firstCharacter, firstCharacter.isLetter else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
guard validExtensions.contains(fileExtension) else {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
guard fileNameComponents.count == 2 else {
return "No"
}
let fileNameWithoutExtension = String(fileNameComponents[0])
let fileExtension = String(fileNameComponents[1])
let containsOnlyDigits = fileNameWithoutExtension.rangeOfCharacter(from:.decimalDigits) == nil
guard!containsOnlyDigits else {
return "No"
}
let firstCharacter = fileNameWithoutExtension.first
guard let firstCharacter = firstCharacter, firstCharacter.isLetter else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
guard validExtensions.contains(fileExtension) else {
return "No"
}
return "Yes"
}
```guard!containsOnlyDigits else { // expected expression, var, let or case in 'guard' conditionfunc fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
if fileNameComponents.count!= 2 {
return "No"
}
let fileNameWithoutExtension = String(fileNameComponents[0])
let fileExtension = String(fileNameComponents[1])
if fileNameWithoutExtension.count == 0 ||!fileNameWithoutExtension.first!.isLetter {
return "No"
}
let allowedFileExtensions = ["txt", "exe", "dll"]
if!allowedFileExtensions.contains(fileExtension) {
return "No"
}
let digitCount = fileNameWithoutExtension.filter { $0.isDigit }.count
if digitCount > 3 {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
if fileNameComponents.count!= 2 {
return "No"
}
let fileNameWithoutExtension = String(fileNameComponents[0])
let fileExtension = String(fileNameComponents[1])
if fileNameWithoutExtension.count == 0 ||!fileNameWithoutExtension.first!.isLetter {
return "No"
}
let allowedFileExtensions = ["txt", "exe", "dll"]
if!allowedFileExtensions.contains(fileExtension) {
return "No"
}
let digitCount = fileNameWithoutExtension.filter { $0.isDigit }.count
if digitCount > 3 {
return "No"
}
return "Yes"
}
```if fileNameComponents.count!= 2 { // cannot force unwrap value of non-optional type 'Int'if fileNameComponents.count!= 2 { // use of '=' in a boolean context, did you mean '=='?if fileNameComponents.count!= 2 { // '=' must have consistent whitespace on both sidesif fileNameWithoutExtension.count == 0 ||!fileNameWithoutExtension.first!.isLetter { // expected '{' after 'if' conditionif!allowedFileExtensions.contains(fileExtension) { // expected expression, var, or let in 'if' conditionlet digitCount = fileNameWithoutExtension.filter { $0.isDigit }.count // value of type 'String.Element' (aka 'Character') has no member 'isDigit'func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
if fileNameComponents.count!= 2 {
return "No"
}
let name = String(fileNameComponents[0])
let extension = String(fileNameComponents[1])
let nameCharacters = Array(name)
if nameCharacters.count == 0 ||!isLetter(nameCharacters[0]) {
return "No"
}
if extension!= "txt" && extension!= "exe" && extension!= "dll" {
return "No"
}
var digitCount = 0
for character in nameCharacters {
if isDigit(character) {
digitCount += 1
if digitCount > 3 {
return "No"
}
}
}
return "Yes"
}
func isLetter(_ character: Character) -> Bool {
return (character >= "a" && character <= "z") || (character >= "A" && character <= "Z")
}
func isDigit(_ character: Character) -> Bool {
return character >= "0" && character <= "9"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
if fileNameComponents.count!= 2 {
return "No"
}
let name = String(fileNameComponents[0])
let extension = String(fileNameComponents[1])
let nameCharacters = Array(name)
if nameCharacters.count == 0 ||!isLetter(nameCharacters[0]) {
return "No"
}
if extension!= "txt" && extension!= "exe" && extension!= "dll" {
return "No"
}
var digitCount = 0
for character in nameCharacters {
if isDigit(character) {
digitCount += 1
if digitCount > 3 {
return "No"
}
}
}
return "Yes"
}
func isLetter(_ character: Character) -> Bool {
return (character >= "a" && character <= "z") || (character >= "A" && character <= "Z")
}
func isDigit(_ character: Character) -> Bool {
return character >= "0" && character <= "9"
}
```if fileNameComponents.count!= 2 { // cannot force unwrap value of non-optional type 'Int'if fileNameComponents.count!= 2 { // use of '=' in a boolean context, did you mean '=='?if fileNameComponents.count!= 2 { // '=' must have consistent whitespace on both sideslet extension = String(fileNameComponents[1]) // keyword 'extension' cannot be used as an identifier hereif nameCharacters.count == 0 ||!isLetter(nameCharacters[0]) { // expected '{' after 'if' conditionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected '{' in extensionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected type name in extension declarationif extension!= "txt" && extension!= "exe" && extension!= "dll" { // '=' must have consistent whitespace on both sidesif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected '{' in extensionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // '=' must have consistent whitespace on both sidesif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected type name in extension declarationif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected expression, var, or let in 'if' conditionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected type name in extension declarationif extension!= "txt" && extension!= "exe" && extension!= "dll" { // declaration is only valid at file scopeif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected '{' in extensionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // declaration is only valid at file scopeif extension!= "txt" && extension!= "exe" && extension!= "dll" { // declaration is only valid at file scopeif extension!= "txt" && extension!= "exe" && extension!= "dll" { // '=' must have consistent whitespace on both sidesfunc fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
guard fileNameComponents.count == 2,
let firstComponent = fileNameComponents.first,
let lastComponent = fileNameComponents.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
lastComponent.count <= 3,
lastComponent.allSatisfy({ $0.isDigit }) else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
guard validExtensions.contains(lastComponent) else {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
guard fileNameComponents.count == 2,
let firstComponent = fileNameComponents.first,
let lastComponent = fileNameComponents.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
lastComponent.count <= 3,
lastComponent.allSatisfy({ $0.isDigit }) else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
guard validExtensions.contains(lastComponent) else {
return "No"
}
return "Yes"
}
```lastComponent.allSatisfy({ $0.isDigit }) else { // value of type 'Substring.Element' (aka 'Character') has no member 'isDigit'guard validExtensions.contains(lastComponent) else { // instance method 'contains' requires the types 'String' and 'Substring.Element' (aka 'Character') be equivalentfunc fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
if fileNameComponents.count!= 2 {
return "No"
}
let name = String(fileNameComponents[0])
let extension = String(fileNameComponents[1])
if name.count == 0 || name.contains(where: CharacterSet.decimalDigits.contains) {
return "No"
}
if extension!= "txt" && extension!= "exe" && extension!= "dll" {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
if fileNameComponents.count!= 2 {
return "No"
}
let name = String(fileNameComponents[0])
let extension = String(fileNameComponents[1])
if name.count == 0 || name.contains(where: CharacterSet.decimalDigits.contains) {
return "No"
}
if extension!= "txt" && extension!= "exe" && extension!= "dll" {
return "No"
}
return "Yes"
}
```if fileNameComponents.count!= 2 { // cannot force unwrap value of non-optional type 'Int'if fileNameComponents.count!= 2 { // use of '=' in a boolean context, did you mean '=='?if fileNameComponents.count!= 2 { // '=' must have consistent whitespace on both sideslet extension = String(fileNameComponents[1]) // keyword 'extension' cannot be used as an identifier hereif name.count == 0 || name.contains(where: CharacterSet.decimalDigits.contains) { // cannot convert value of type '(Unicode.Scalar) -> Bool' to expected argument type '(String.Element) throws -> Bool' (aka '(Character) throws -> Bool')if extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected type name in extension declarationif extension!= "txt" && extension!= "exe" && extension!= "dll" { // '=' must have consistent whitespace on both sidesif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected type name in extension declarationif extension!= "txt" && extension!= "exe" && extension!= "dll" { // '=' must have consistent whitespace on both sidesif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected type name in extension declarationif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected '{' in extensionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // declaration is only valid at file scopeif extension!= "txt" && extension!= "exe" && extension!= "dll" { // declaration is only valid at file scopeif extension!= "txt" && extension!= "exe" && extension!= "dll" { // '=' must have consistent whitespace on both sidesif extension!= "txt" && extension!= "exe" && extension!= "dll" { // declaration is only valid at file scopeif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected '{' in extensionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected expression, var, or let in 'if' conditionif extension!= "txt" && extension!= "exe" && extension!= "dll" { // expected '{' in extensionfunc fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.split(separator: ".")
guard nameComponents.count == 2,
let firstComponent = nameComponents.first,
let lastComponent = nameComponents.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
let _ = Int(String(firstComponent.dropFirst())) else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
return validExtensions.contains(lastComponent)? "Yes" : "No"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let nameComponents = fileName.split(separator: ".")
guard nameComponents.count == 2,
let firstComponent = nameComponents.first,
let lastComponent = nameComponents.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
let _ = Int(String(firstComponent.dropFirst())) else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
return validExtensions.contains(lastComponent)? "Yes" : "No"
}
```return validExtensions.contains(lastComponent)? "Yes" : "No" // cannot use optional chaining on non-optional value of type 'Bool'return validExtensions.contains(lastComponent)? "Yes" : "No" // consecutive statements on a line must be separated by ';'return validExtensions.contains(lastComponent)? "Yes" : "No" // instance method 'contains' requires the types 'String' and 'Substring.Element' (aka 'Character') be equivalentreturn validExtensions.contains(lastComponent)? "Yes" : "No" // string literal is unusedreturn validExtensions.contains(lastComponent)? "Yes" : "No" // consecutive statements on a line must be separated by ';'return validExtensions.contains(lastComponent)? "Yes" : "No" // expected expressionfunc fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
if fileNameComponents.count!= 2 {
return "No"
}
let fileNameWithoutExtension = String(fileNameComponents[0])
let fileExtension = String(fileNameComponents[1])
let allowedFileExtensions = ["txt", "exe", "dll"]
if fileNameWithoutExtension.count == 0 ||!fileNameWithoutExtension.first!.isLetter {
return "No"
}
if fileExtension.count > 3 ||!allowedFileExtensions.contains(fileExtension) {
return "No"
}
let digitRange = "0"..."9"
if fileNameWithoutExtension.contains(where: { digitRange.contains($0) }) {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
if fileNameComponents.count!= 2 {
return "No"
}
let fileNameWithoutExtension = String(fileNameComponents[0])
let fileExtension = String(fileNameComponents[1])
let allowedFileExtensions = ["txt", "exe", "dll"]
if fileNameWithoutExtension.count == 0 ||!fileNameWithoutExtension.first!.isLetter {
return "No"
}
if fileExtension.count > 3 ||!allowedFileExtensions.contains(fileExtension) {
return "No"
}
let digitRange = "0"..."9"
if fileNameWithoutExtension.contains(where: { digitRange.contains($0) }) {
return "No"
}
return "Yes"
}
```if fileNameComponents.count!= 2 { // cannot force unwrap value of non-optional type 'Int'if fileNameComponents.count!= 2 { // use of '=' in a boolean context, did you mean '=='?if fileNameComponents.count!= 2 { // '=' must have consistent whitespace on both sidesif fileNameWithoutExtension.count == 0 ||!fileNameWithoutExtension.first!.isLetter { // expected '{' after 'if' conditionif fileExtension.count > 3 ||!allowedFileExtensions.contains(fileExtension) { // expected '{' after 'if' conditionif fileNameWithoutExtension.contains(where: { digitRange.contains($0) }) { // cannot convert value of type 'String.Element' (aka 'Character') to expected argument type 'String'func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
guard fileNameComponents.count == 2,
let firstComponent = fileNameComponents.first,
let lastComponent = fileNameComponents.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
lastComponent.count <= 3,
lastComponent.allSatisfy({ $0.isDigit }) else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
guard validExtensions.contains(lastComponent) else {
return "No"
}
return "Yes"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The file's name contains exactly one dot '.'
- The substring before the dot should not be empty, and it starts with a letter from
the latin alphapet ('a'-'z' and 'A'-'Z').
- The substring after the dot should be one of these: ['txt', 'exe', 'dll']
Examples:
fileNameCheck(fileName: "example.txt") == "Yes"
fileNameCheck(fileName: "1example.dll") == "No"
Answer:
```swift
func fileNameCheck(fileName: String) -> String {
let fileNameComponents = fileName.split(separator: ".")
guard fileNameComponents.count == 2,
let firstComponent = fileNameComponents.first,
let lastComponent = fileNameComponents.last,
let firstChar = firstComponent.first,
firstChar.isLetter,
lastComponent.count <= 3,
lastComponent.allSatisfy({ $0.isDigit }) else {
return "No"
}
let validExtensions = ["txt", "exe", "dll"]
guard validExtensions.contains(lastComponent) else {
return "No"
}
return "Yes"
}
```lastComponent.allSatisfy({ $0.isDigit }) else { // value of type 'Substring.Element' (aka 'Character') has no member 'isDigit'guard validExtensions.contains(lastComponent) else { // instance method 'contains' requires the types 'String' and 'Substring.Element' (aka 'Character') be equivalentfunc wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeLengthWords = [String]()
for word in words {
if isPrime(word.count) {
primeLengthWords.append(word)
}
}
return primeLengthWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeLengthWords = [String]()
for word in words {
if isPrime(word.count) {
primeLengthWords.append(word)
}
}
return primeLengthWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeWords = [String]()
for word in words {
if isPrime(word.count) {
primeWords.append(word)
}
}
return primeWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeWords = [String]()
for word in words {
if isPrime(word.count) {
primeWords.append(word)
}
}
return primeWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeLengthWords = [String]()
for word in words {
if isPrime(word.count) {
primeLengthWords.append(word)
}
}
return primeLengthWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeLengthWords = [String]()
for word in words {
if isPrime(word.count) {
primeLengthWords.append(word)
}
}
return primeLengthWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeWords = [String]()
for word in words {
if isPrime(word.count) {
primeWords.append(word)
}
}
return primeWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeWords = [String]()
for word in words {
if isPrime(word.count) {
primeWords.append(word)
}
}
return primeWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
let primeWordLengths = words.filter { isPrime(Int($0.count)) }
let primeWords = primeWordLengths.joined(separator: " ")
return primeWords
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
let primeWordLengths = words.filter { isPrime(Int($0.count)) }
let primeWords = primeWordLengths.joined(separator: " ")
return primeWords
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeWordCount = 0
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
primeWordCount += 1
}
}
if primeWordCount == 0 {
return ""
}
return String(result.dropLast())
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeWordCount = 0
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
primeWordCount += 1
}
}
if primeWordCount == 0 {
return ""
}
return String(result.dropLast())
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeWordCount = 0
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
primeWordCount += 1
}
}
if primeWordCount == 0 {
return ""
}
return String(result.dropLast())
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeWordCount = 0
var result = ""
for word in words {
if isPrime(word.count) {
result += word + " "
primeWordCount += 1
}
}
if primeWordCount == 0 {
return ""
}
return String(result.dropLast())
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeLengthWords = [String]()
for word in words {
if isPrime(word.count) {
primeLengthWords.append(word)
}
}
return primeLengthWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeLengthWords = [String]()
for word in words {
if isPrime(word.count) {
primeLengthWords.append(word)
}
}
return primeLengthWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeLengthWords = [String]()
for word in words {
if isPrime(word.count) {
primeLengthWords.append(word)
}
}
return primeLengthWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
var primeLengthWords = [String]()
for word in words {
if isPrime(word.count) {
primeLengthWords.append(word)
}
}
return primeLengthWords.joined(separator: " ")
}
func isPrime(_ number: Int) -> Bool {
if number <= 1 {
return false
}
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
let primeWordLengths = words.filter { isPrime(Int($0.count)) }
let primeWords = primeWordLengths.joined(separator: " ")
return primeWords
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Example 2:
Constraints:
* 1 <= len(sentence) <= 100
* sentence contains only letters
wordsInSentence(sentence: "This is a test") == "is"
wordsInSentence(sentence: "lets go for swimming") == "go for"
Answer:
```swift
func wordsInSentence(sentence: String) -> String {
let words = sentence.components(separatedBy: " ")
let primeWordLengths = words.filter { isPrime(Int($0.count)) }
let primeWords = primeWordLengths.joined(separator: " ")
return primeWords
}
func isPrime(_ number: Int) -> Bool {
guard number > 1 else { return false }
for i in 2..<number {
if number % i == 0 {
return false
}
}
return true
}
```func simplify(x: String, n: String) -> Bool {
let xValues = x.split(separator: "/").compactMap { Int($0) }
let nValues = n.split(separator: "/").compactMap { Int($0) }
let xNumerator = xValues[0]!
let xDenominator = xValues[1]!
let nNumerator = nValues[0]!
let nDenominator = nValues[1]!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: resultNumerator, b: resultDenominator)
let simplifiedNumerator = resultNumerator / gcd
let simplifiedDenominator = resultDenominator / gcd
return simplifiedNumerator == simplifiedDenominator
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xValues = x.split(separator: "/").compactMap { Int($0) }
let nValues = n.split(separator: "/").compactMap { Int($0) }
let xNumerator = xValues[0]!
let xDenominator = xValues[1]!
let nNumerator = nValues[0]!
let nDenominator = nValues[1]!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: resultNumerator, b: resultDenominator)
let simplifiedNumerator = resultNumerator / gcd
let simplifiedDenominator = resultDenominator / gcd
return simplifiedNumerator == simplifiedDenominator
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```let xNumerator = xValues[0]! // cannot force unwrap value of non-optional type 'Int'let xDenominator = xValues[1]! // cannot force unwrap value of non-optional type 'Int'let nNumerator = nValues[0]! // cannot force unwrap value of non-optional type 'Int'let nDenominator = nValues[1]! // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // use of '=' in a boolean context, did you mean '=='?while b!= 0 { // '=' must have consistent whitespace on both sideswhile b!= 0 { // cannot force unwrap value of non-optional type 'Int'func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: resultNumerator, b: resultDenominator)
let simplifiedNumerator = resultNumerator / gcd
let simplifiedDenominator = resultDenominator / gcd
return simplifiedNumerator % simplifiedDenominator == 0
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: resultNumerator, b: resultDenominator)
let simplifiedNumerator = resultNumerator / gcd
let simplifiedDenominator = resultDenominator / gcd
return simplifiedNumerator % simplifiedDenominator == 0
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```while b!= 0 { // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // '=' must have consistent whitespace on both sideswhile b!= 0 { // use of '=' in a boolean context, did you mean '=='?func simplify(x: String, n: String) -> Bool {
let xValues = x.split(separator: "/").compactMap { Int($0.trimmingCharacters(in:.whitespaces)) }
let nValues = n.split(separator: "/").compactMap { Int($0.trimmingCharacters(in:.whitespaces)) }
guard let xNumerator = xValues.first, let xDenominator = xValues.last,
let nNumerator = nValues.first, let nDenominator = nValues.last,
xDenominator!= 0, nDenominator!= 0 else { return false }
let xSimplified = simplifyFraction(numerator: xNumerator, denominator: xDenominator)
let nSimplified = simplifyFraction(numerator: nNumerator, denominator: nDenominator)
let resultNumerator = xSimplified.0 * nSimplified.0
let resultDenominator = xSimplified.1 * nSimplified.1
return resultNumerator % resultDenominator == 0
}
func simplifyFraction(numerator: Int, denominator: Int) -> (Int, Int) {
var (num, den) = (numerator, denominator)
while num % den!= 0 {
let remainder = num % den
num = den
den = remainder
}
return (numerator / den, denominator / den)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xValues = x.split(separator: "/").compactMap { Int($0.trimmingCharacters(in:.whitespaces)) }
let nValues = n.split(separator: "/").compactMap { Int($0.trimmingCharacters(in:.whitespaces)) }
guard let xNumerator = xValues.first, let xDenominator = xValues.last,
let nNumerator = nValues.first, let nDenominator = nValues.last,
xDenominator!= 0, nDenominator!= 0 else { return false }
let xSimplified = simplifyFraction(numerator: xNumerator, denominator: xDenominator)
let nSimplified = simplifyFraction(numerator: nNumerator, denominator: nDenominator)
let resultNumerator = xSimplified.0 * nSimplified.0
let resultDenominator = xSimplified.1 * nSimplified.1
return resultNumerator % resultDenominator == 0
}
func simplifyFraction(numerator: Int, denominator: Int) -> (Int, Int) {
var (num, den) = (numerator, denominator)
while num % den!= 0 {
let remainder = num % den
num = den
den = remainder
}
return (numerator / den, denominator / den)
}
```xDenominator!= 0, nDenominator!= 0 else { return false } // '=' must have consistent whitespace on both sidesxDenominator!= 0, nDenominator!= 0 else { return false } // use of '=' in a boolean context, did you mean '=='?xDenominator!= 0, nDenominator!= 0 else { return false } // cannot force unwrap value of non-optional type 'Int'xDenominator!= 0, nDenominator!= 0 else { return false } // '=' must have consistent whitespace on both sidesxDenominator!= 0, nDenominator!= 0 else { return false } // use of '=' in a boolean context, did you mean '=='?xDenominator!= 0, nDenominator!= 0 else { return false } // cannot force unwrap value of non-optional type 'Int'while num % den!= 0 { // '=' must have consistent whitespace on both sideswhile num % den!= 0 { // use of '=' in a boolean context, did you mean '=='?while num % den!= 0 { // cannot force unwrap value of non-optional type 'Int'func simplify(x: String, n: String) -> Bool {
let xValues = x.split(separator: "/").map { Int($0)! }
let nValues = n.split(separator: "/").map { Int($0)! }
let xNumerator = xValues[0]
let xDenominator = xValues[1]
let nNumerator = nValues[0]
let nDenominator = nValues[1]
let numerator = xNumerator * nNumerator
let denominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: numerator, b: denominator)
let simplifiedNumerator = numerator / gcd
let simplifiedDenominator = denominator / gcd
return simplifiedNumerator % simplifiedDenominator == 0
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xValues = x.split(separator: "/").map { Int($0)! }
let nValues = n.split(separator: "/").map { Int($0)! }
let xNumerator = xValues[0]
let xDenominator = xValues[1]
let nNumerator = nValues[0]
let nDenominator = nValues[1]
let numerator = xNumerator * nNumerator
let denominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: numerator, b: denominator)
let simplifiedNumerator = numerator / gcd
let simplifiedDenominator = denominator / gcd
return simplifiedNumerator % simplifiedDenominator == 0
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```while b!= 0 { // use of '=' in a boolean context, did you mean '=='?while b!= 0 { // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // '=' must have consistent whitespace on both sidesfunc simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let numerator = xNumerator * nNumerator
let denominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: numerator, b: denominator)
let simplifiedNumerator = numerator / gcd
let simplifiedDenominator = denominator / gcd
return simplifiedNumerator % simplifiedDenominator == 0
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let numerator = xNumerator * nNumerator
let denominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: numerator, b: denominator)
let simplifiedNumerator = numerator / gcd
let simplifiedDenominator = denominator / gcd
return simplifiedNumerator % simplifiedDenominator == 0
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```while b!= 0 { // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // '=' must have consistent whitespace on both sideswhile b!= 0 { // use of '=' in a boolean context, did you mean '=='?func simplify(x: String, n: String) -> Bool {
let xComponents = x.split(separator: "/")
let nComponents = n.split(separator: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: resultNumerator, b: resultDenominator)
let simplifiedNumerator = resultNumerator / gcd
let simplifiedDenominator = resultDenominator / gcd
return simplifiedNumerator == simplifiedDenominator
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xComponents = x.split(separator: "/")
let nComponents = n.split(separator: "/")
let xNumerator = Int(xComponents[0])!
let xDenominator = Int(xComponents[1])!
let nNumerator = Int(nComponents[0])!
let nDenominator = Int(nComponents[1])!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: resultNumerator, b: resultDenominator)
let simplifiedNumerator = resultNumerator / gcd
let simplifiedDenominator = resultDenominator / gcd
return simplifiedNumerator == simplifiedDenominator
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```while b!= 0 { // use of '=' in a boolean context, did you mean '=='?while b!= 0 { // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // '=' must have consistent whitespace on both sidesfunc simplify(x: String, n: String) -> Bool {
let xValues = x.split(separator: "/").compactMap { Int($0) }
let nValues = n.split(separator: "/").compactMap { Int($0) }
let xNumerator = xValues[0]!
let xDenominator = xValues[1]!
let nNumerator = nValues[0]!
let nDenominator = nValues[1]!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: resultNumerator, b: resultDenominator)
let simplifiedNumerator = resultNumerator / gcd
let simplifiedDenominator = resultDenominator / gcd
return simplifiedNumerator == simplifiedDenominator
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xValues = x.split(separator: "/").compactMap { Int($0) }
let nValues = n.split(separator: "/").compactMap { Int($0) }
let xNumerator = xValues[0]!
let xDenominator = xValues[1]!
let nNumerator = nValues[0]!
let nDenominator = nValues[1]!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
let gcd = greatestCommonDivisor(a: resultNumerator, b: resultDenominator)
let simplifiedNumerator = resultNumerator / gcd
let simplifiedDenominator = resultDenominator / gcd
return simplifiedNumerator == simplifiedDenominator
}
func greatestCommonDivisor(a: Int, b: Int) -> Int {
var a = a
var b = b
while b!= 0 {
let remainder = a % b
a = b
b = remainder
}
return a
}
```let xNumerator = xValues[0]! // cannot force unwrap value of non-optional type 'Int'let xDenominator = xValues[1]! // cannot force unwrap value of non-optional type 'Int'let nNumerator = nValues[0]! // cannot force unwrap value of non-optional type 'Int'let nDenominator = nValues[1]! // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // '=' must have consistent whitespace on both sideswhile b!= 0 { // cannot force unwrap value of non-optional type 'Int'while b!= 0 { // use of '=' in a boolean context, did you mean '=='?func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
return resultNumerator % resultDenominator == 0
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let resultNumerator = xNumerator * nNumerator
let resultDenominator = xDenominator * nDenominator
return resultNumerator % resultDenominator == 0
}
```func simplify(x: String, n: String) -> Bool {
let xNumerator: Int
let xDenominator: Int
let nNumerator: Int
let nDenominator: Int
let resultNumerator: Int
let resultDenominator: Int
let xSplit = x.split(separator: "/")
let nSplit = n.split(separator: "/")
xNumerator = Int(xSplit[0])!
xDenominator = Int(xSplit[1])!
nNumerator = Int(nSplit[0])!
nDenominator = Int(nSplit[1])!
resultNumerator = xNumerator * nNumerator
resultDenominator = xDenominator * nDenominator
return (resultNumerator % resultDenominator) == 0
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator: Int
let xDenominator: Int
let nNumerator: Int
let nDenominator: Int
let resultNumerator: Int
let resultDenominator: Int
let xSplit = x.split(separator: "/")
let nSplit = n.split(separator: "/")
xNumerator = Int(xSplit[0])!
xDenominator = Int(xSplit[1])!
nNumerator = Int(nSplit[0])!
nDenominator = Int(nSplit[1])!
resultNumerator = xNumerator * nNumerator
resultDenominator = xDenominator * nDenominator
return (resultNumerator % resultDenominator) == 0
}
```func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let simplifiedNumerator = xNumerator * nNumerator
let simplifiedDenominator = xDenominator * nDenominator
return simplifiedNumerator % simplifiedDenominator == 0
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Your task is to implement a function that will simplify the expression
x * n. The function returns true if x * n evaluates to a whole number and false
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are positive whole numbers.
You can assume that x, and n are valid fractions, and do not have zero as denominator.
simplify(x: "1/5", n: "5/1") == true
simplify(x: "1/6", n: "2/1") == false
simplify(x: "7/10", n: "10/2") == false
Answer:
```swift
func simplify(x: String, n: String) -> Bool {
let xNumerator = Int(x.components(separatedBy: "/")[0])!
let xDenominator = Int(x.components(separatedBy: "/")[1])!
let nNumerator = Int(n.components(separatedBy: "/")[0])!
let nDenominator = Int(n.components(separatedBy: "/")[1])!
let simplifiedNumerator = xNumerator * nNumerator
let simplifiedDenominator = xDenominator * nDenominator
return simplifiedNumerator % simplifiedDenominator == 0
}
```func orderByPoints(nums: [Int]) -> [Int] {
let getSum = { (num: Int) -> Int in
var sum = 0
var n = num
while n!= 0 {
sum += n % 10
n /= 10
}
return sum
}
return nums.sorted { (num1, num2) -> Bool in
let sum1 = getSum(num1)
let sum2 = getSum(num2)
if sum1 == sum2 {
return nums.firstIndex(of: num1)! < nums.firstIndex(of: num2)!
}
return sum1 < sum2
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let getSum = { (num: Int) -> Int in
var sum = 0
var n = num
while n!= 0 {
sum += n % 10
n /= 10
}
return sum
}
return nums.sorted { (num1, num2) -> Bool in
let sum1 = getSum(num1)
let sum2 = getSum(num2)
if sum1 == sum2 {
return nums.firstIndex(of: num1)! < nums.firstIndex(of: num2)!
}
return sum1 < sum2
}
}
```while n!= 0 { // cannot force unwrap value of non-optional type 'Int'while n!= 0 { // '=' must have consistent whitespace on both sideswhile n!= 0 { // use of '=' in a boolean context, did you mean '=='?func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.enumerated().sorted {
let sum1 = $0.element.absoluteValue.digits.reduce(0, +)
let sum2 = $1.element.absoluteValue.digits.reduce(0, +)
if sum1 == sum2 {
return $0.offset < $1.offset
}
return sum1 < sum2
}
return sorted.map { $0.element }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.enumerated().sorted {
let sum1 = $0.element.absoluteValue.digits.reduce(0, +)
let sum2 = $1.element.absoluteValue.digits.reduce(0, +)
if sum1 == sum2 {
return $0.offset < $1.offset
}
return sum1 < sum2
}
return sorted.map { $0.element }
}
```let sum1 = $0.element.absoluteValue.digits.reduce(0, +) // value of type 'Int' has no member 'absoluteValue'func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.enumerated().sorted {
let sum1 = $0.element.absoluteValue.digits.reduce(0, +)
let sum2 = $1.element.absoluteValue.digits.reduce(0, +)
if sum1 == sum2 {
return $0.offset < $1.offset
}
return sum1 < sum2
}
return sorted.map { $0.element }
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.enumerated().sorted {
let sum1 = $0.element.absoluteValue.digits.reduce(0, +)
let sum2 = $1.element.absoluteValue.digits.reduce(0, +)
if sum1 == sum2 {
return $0.offset < $1.offset
}
return sum1 < sum2
}
return sorted.map { $0.element }
}
```let sum1 = $0.element.absoluteValue.digits.reduce(0, +) // value of type 'Int' has no member 'absoluteValue'func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.enumerated().sorted {
let sum1 = getSum($0.element)
let sum2 = getSum($1.element)
if sum1 == sum2 {
return $0.offset < $1.offset
}
return sum1 < sum2
}
return sorted.map { $0.element }
}
func getSum(_ num: Int) -> Int {
var sum = 0
var n = num
while n!= 0 {
sum += n % 10
n /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.enumerated().sorted {
let sum1 = getSum($0.element)
let sum2 = getSum($1.element)
if sum1 == sum2 {
return $0.offset < $1.offset
}
return sum1 < sum2
}
return sorted.map { $0.element }
}
func getSum(_ num: Int) -> Int {
var sum = 0
var n = num
while n!= 0 {
sum += n % 10
n /= 10
}
return sum
}
```while n!= 0 { // cannot force unwrap value of non-optional type 'Int'while n!= 0 { // '=' must have consistent whitespace on both sideswhile n!= 0 { // use of '=' in a boolean context, did you mean '=='?func orderByPoints(nums: [Int]) -> [Int] {
let digitSums = nums.enumerated().map { ($0.offset, $0.element.digitSum) }
let sorted = digitSums.sorted { ($0.1, $0.0) < ($1.1, $1.0) }
return sorted.map { nums[$0.0] }
}
extension Int {
var digitSum: Int {
return String(self).reduce(0) { $0 + Int(String($1))! }
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let digitSums = nums.enumerated().map { ($0.offset, $0.element.digitSum) }
let sorted = digitSums.sorted { ($0.1, $0.0) < ($1.1, $1.0) }
return sorted.map { nums[$0.0] }
}
extension Int {
var digitSum: Int {
return String(self).reduce(0) { $0 + Int(String($1))! }
}
}
``` // Fatal error: Unexpectedly found nil while unwrapping an Optional valuefunc orderByPoints(nums: [Int]) -> [Int] {
let points = nums.map { abs($0).description.reduce(0) { $0 + Int(String($1))! } }
return nums.sorted { (num1, num2) -> Bool in
let point1 = points[abs(num1) - 1]
let point2 = points[abs(num2) - 1]
if point1 == point2 {
return num1 < num2
}
return point1 > point2
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let points = nums.map { abs($0).description.reduce(0) { $0 + Int(String($1))! } }
return nums.sorted { (num1, num2) -> Bool in
let point1 = points[abs(num1) - 1]
let point2 = points[abs(num2) - 1]
if point1 == point2 {
return num1 < num2
}
return point1 > point2
}
}
``` // Fatal error: Index out of rangefunc orderByPoints(nums: [Int]) -> [Int] {
let sums = nums.map { sumOfDigits(num: $0) }
let sortedIndices = sums.indices.sorted { sums[$0] < sums[$1] || (sums[$0] == sums[$1] && $0 > $1) }
return sortedIndices.map { nums[$0] }
}
func sumOfDigits(num: Int) -> Int {
var num = num
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sums = nums.map { sumOfDigits(num: $0) }
let sortedIndices = sums.indices.sorted { sums[$0] < sums[$1] || (sums[$0] == sums[$1] && $0 > $1) }
return sortedIndices.map { nums[$0] }
}
func sumOfDigits(num: Int) -> Int {
var num = num
var sum = 0
while num > 0 {
sum += num % 10
num /= 10
}
return sum
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
let points = nums.map { abs($0).description.reduce(0) { $0 + Int(String($1))! } }
return nums.sorted { (num1, num2) -> Bool in
let point1 = points[abs(num1) % points.count]
let point2 = points[abs(num2) % points.count]
if point1 == point2 {
return num1 < num2
}
return point1 < point2
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let points = nums.map { abs($0).description.reduce(0) { $0 + Int(String($1))! } }
return nums.sorted { (num1, num2) -> Bool in
let point1 = points[abs(num1) % points.count]
let point2 = points[abs(num2) % points.count]
if point1 == point2 {
return num1 < num2
}
return point1 < point2
}
}
``` // XCTAssertTrue failedfunc orderByPoints(nums: [Int]) -> [Int] {
let points = nums.map { abs($0).description.reduce(0) { $0 + Int(String($1))! } }
return nums.sorted { (num1, num2) -> Bool in
let point1 = points[abs(num1) - 1]
let point2 = points[abs(num2) - 1]
if point1 == point2 {
return num1 > num2
}
return point1 < point2
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let points = nums.map { abs($0).description.reduce(0) { $0 + Int(String($1))! } }
return nums.sorted { (num1, num2) -> Bool in
let point1 = points[abs(num1) - 1]
let point2 = points[abs(num2) - 1]
if point1 == point2 {
return num1 > num2
}
return point1 < point2
}
}
``` // Fatal error: Index out of rangefunc orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.enumerated().sorted {
let sum1 = getSumOfDigits(num: $0.element)
let sum2 = getSumOfDigits(num: $1.element)
if sum1 == sum2 {
return $0.offset < $1.offset
}
return sum1 < sum2
}
return sorted.map { $0.element }
}
func getSumOfDigits(num: Int) -> Int {
var absoluteNum = abs(num)
var sum = 0
while absoluteNum > 0 {
sum += absoluteNum % 10
absoluteNum /= 10
}
return sum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function which sorts the given array of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original array.
For example:
orderByPoints(nums: [1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
orderByPoints(nums: [] as [Int]) == [] as [Int]
Answer:
```swift
func orderByPoints(nums: [Int]) -> [Int] {
let sorted = nums.enumerated().sorted {
let sum1 = getSumOfDigits(num: $0.element)
let sum2 = getSumOfDigits(num: $1.element)
if sum1 == sum2 {
return $0.offset < $1.offset
}
return sum1 < sum2
}
return sorted.map { $0.element }
}
func getSumOfDigits(num: Int) -> Int {
var absoluteNum = abs(num)
var sum = 0
while absoluteNum > 0 {
sum += absoluteNum % 10
absoluteNum /= 10
}
return sum
}
``` // XCTAssertTrue failedfunc specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false
}
var lastDigitIsOdd: Bool {
return String(self).last(where: {!$0.isWhitespace })?.isOdd?? false
}
var isOdd: Bool {
return self % 2 == 1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false
}
var lastDigitIsOdd: Bool {
return String(self).last(where: {!$0.isWhitespace })?.isOdd?? false
}
var isOdd: Bool {
return self % 2 == 1
}
}
```return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false // boolean literal is unusedreturn String(self).first(where: {!$0.isWhitespace })?.isOdd?? false // consecutive statements on a line must be separated by ';'return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false // type of expression is ambiguous without a type annotationreturn String(self).last(where: {!$0.isWhitespace })?.isOdd?? false // boolean literal is unusedreturn String(self).last(where: {!$0.isWhitespace })?.isOdd?? false // type of expression is ambiguous without a type annotationreturn String(self).last(where: {!$0.isWhitespace })?.isOdd?? false // consecutive statements on a line must be separated by ';'func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first!.isOdd
}
var lastDigitIsOdd: Bool {
return String(self).last!.isOdd
}
}
extension String {
var first: Character? {
return self[safe: 0]
}
var last: Character? {
return self[safe: self.count - 1]
}
subscript (safe index: Int) -> Character? {
return index >= 0 && index < count? self[index] : nil
}
}
extension Character {
var isOdd: Bool {
return Int(String(self))! % 2 == 1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first!.isOdd
}
var lastDigitIsOdd: Bool {
return String(self).last!.isOdd
}
}
extension String {
var first: Character? {
return self[safe: 0]
}
var last: Character? {
return self[safe: self.count - 1]
}
subscript (safe index: Int) -> Character? {
return index >= 0 && index < count? self[index] : nil
}
}
extension Character {
var isOdd: Bool {
return Int(String(self))! % 2 == 1
}
}
```return index >= 0 && index < count? self[index] : nil // expression of type 'Character' is unusedreturn index >= 0 && index < count? self[index] : nil // 'subscript(_:)' is unavailable: cannot subscript String with an Int, use a String.Index instead.return index >= 0 && index < count? self[index] : nil // expected expressionreturn index >= 0 && index < count? self[index] : nil // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return index >= 0 && index < count? self[index] : nil // consecutive statements on a line must be separated by ';'return index >= 0 && index < count? self[index] : nil // consecutive statements on a line must be separated by ';'return index >= 0 && index < count? self[index] : nil // cannot convert return expression of type 'Bool' to return type 'Character?'return index >= 0 && index < count? self[index] : nil // cannot use optional chaining on non-optional value of type 'Int'func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first!.isOdd
}
var lastDigitIsOdd: Bool {
return String(self).last!.isOdd
}
}
extension String {
var first: Character? {
return self[self.startIndex]
}
var last: Character? {
return self[self.endIndex - 1]
}
}
extension Character {
var isOdd: Bool {
return Int(String(self))! % 2 == 1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first!.isOdd
}
var lastDigitIsOdd: Bool {
return String(self).last!.isOdd
}
}
extension String {
var first: Character? {
return self[self.startIndex]
}
var last: Character? {
return self[self.endIndex - 1]
}
}
extension Character {
var isOdd: Bool {
return Int(String(self))! % 2 == 1
}
}
```return self[self.endIndex - 1] // cannot convert value of type 'String.Index' to expected argument type 'Int'func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).firstDigitIsOdd
}
var lastDigitIsOdd: Bool {
return String(self).lastDigitIsOdd
}
}
extension String {
var firstDigitIsOdd: Bool {
return Int(String(self.prefix(1)))?.isOdd?? false
}
var lastDigitIsOdd: Bool {
return Int(String(self.suffix(1)))?.isOdd?? false
}
}
extension Int {
var isOdd: Bool {
return self % 2 == 1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).firstDigitIsOdd
}
var lastDigitIsOdd: Bool {
return String(self).lastDigitIsOdd
}
}
extension String {
var firstDigitIsOdd: Bool {
return Int(String(self.prefix(1)))?.isOdd?? false
}
var lastDigitIsOdd: Bool {
return Int(String(self.suffix(1)))?.isOdd?? false
}
}
extension Int {
var isOdd: Bool {
return self % 2 == 1
}
}
```return Int(String(self.prefix(1)))?.isOdd?? false // cannot use optional chaining on non-optional value of type 'Bool'return Int(String(self.prefix(1)))?.isOdd?? false // cannot use optional chaining on non-optional value of type 'Bool'return Int(String(self.prefix(1)))?.isOdd?? false // optional type 'Bool?' cannot be used as a boolean; test for '!= nil' insteadreturn Int(String(self.prefix(1)))?.isOdd?? false // boolean literal is unusedreturn Int(String(self.prefix(1)))?.isOdd?? false // consecutive statements on a line must be separated by ';'return Int(String(self.suffix(1)))?.isOdd?? false // boolean literal is unusedreturn Int(String(self.suffix(1)))?.isOdd?? false // consecutive statements on a line must be separated by ';'return Int(String(self.suffix(1)))?.isOdd?? false // cannot use optional chaining on non-optional value of type 'Bool'return Int(String(self.suffix(1)))?.isOdd?? false // cannot use optional chaining on non-optional value of type 'Bool'return Int(String(self.suffix(1)))?.isOdd?? false // optional type 'Bool?' cannot be used as a boolean; test for '!= nil' insteadfunc specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self)[String(self).index(before: String(self).endIndex)]!= "0"
}
var lastDigitIsOdd: Bool {
return String(self).last!= "0"
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self)[String(self).index(before: String(self).endIndex)]!= "0"
}
var lastDigitIsOdd: Bool {
return String(self).last!= "0"
}
}
```return String(self)[String(self).index(before: String(self).endIndex)]!= "0" // use of '=' in a boolean context, did you mean '=='?return String(self)[String(self).index(before: String(self).endIndex)]!= "0" // cannot force unwrap value of non-optional type 'Character'return String(self)[String(self).index(before: String(self).endIndex)]!= "0" // '=' must have consistent whitespace on both sidesreturn String(self).last!= "0" // '=' must have consistent whitespace on both sidesreturn String(self).last!= "0" // use of '=' in a boolean context, did you mean '=='?return String(self).last!= "0" // cannot assign through '!': 'last' is a get-only propertyfunc specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false
}
var lastDigitIsOdd: Bool {
return String(self).last(where: {!$0.isWhitespace })?.isOdd?? false
}
}
extension String {
var isOdd: Bool {
return Int(self)?? 0 % 2 == 1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false
}
var lastDigitIsOdd: Bool {
return String(self).last(where: {!$0.isWhitespace })?.isOdd?? false
}
}
extension String {
var isOdd: Bool {
return Int(self)?? 0 % 2 == 1
}
}
```return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false // boolean literal is unusedreturn String(self).first(where: {!$0.isWhitespace })?.isOdd?? false // consecutive statements on a line must be separated by ';'return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false // type of expression is ambiguous without a type annotationreturn String(self).last(where: {!$0.isWhitespace })?.isOdd?? false // boolean literal is unusedreturn String(self).last(where: {!$0.isWhitespace })?.isOdd?? false // type of expression is ambiguous without a type annotationreturn String(self).last(where: {!$0.isWhitespace })?.isOdd?? false // consecutive statements on a line must be separated by ';'return Int(self)?? 0 % 2 == 1 // result of operator '==' is unusedreturn Int(self)?? 0 % 2 == 1 // optional type 'Int?' cannot be used as a boolean; test for '!= nil' insteadreturn Int(self)?? 0 % 2 == 1 // consecutive statements on a line must be separated by ';'return Int(self)?? 0 % 2 == 1 // cannot use optional chaining on non-optional value of type 'Int'func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false
}
var lastDigitIsOdd: Bool {
return String(self).last(where: {!$0.isWhitespace })?.isOdd?? false
}
}
extension String {
var isOdd: Bool {
return Int(self)?? 0 % 2 == 1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false
}
var lastDigitIsOdd: Bool {
return String(self).last(where: {!$0.isWhitespace })?.isOdd?? false
}
}
extension String {
var isOdd: Bool {
return Int(self)?? 0 % 2 == 1
}
}
```return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false // boolean literal is unusedreturn String(self).first(where: {!$0.isWhitespace })?.isOdd?? false // consecutive statements on a line must be separated by ';'return String(self).first(where: {!$0.isWhitespace })?.isOdd?? false // type of expression is ambiguous without a type annotationreturn String(self).last(where: {!$0.isWhitespace })?.isOdd?? false // boolean literal is unusedreturn String(self).last(where: {!$0.isWhitespace })?.isOdd?? false // type of expression is ambiguous without a type annotationreturn String(self).last(where: {!$0.isWhitespace })?.isOdd?? false // consecutive statements on a line must be separated by ';'return Int(self)?? 0 % 2 == 1 // result of operator '==' is unusedreturn Int(self)?? 0 % 2 == 1 // optional type 'Int?' cannot be used as a boolean; test for '!= nil' insteadreturn Int(self)?? 0 % 2 == 1 // consecutive statements on a line must be separated by ';'return Int(self)?? 0 % 2 == 1 // cannot use optional chaining on non-optional value of type 'Int'func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first!.asciiValue! % 2 == 1
}
var lastDigitIsOdd: Bool {
return String(self).last!.asciiValue! % 2 == 1
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && $0.firstDigitIsOdd && $0.lastDigitIsOdd
}.count
}
extension Int {
var firstDigitIsOdd: Bool {
return String(self).first!.asciiValue! % 2 == 1
}
var lastDigitIsOdd: Bool {
return String(self).last!.asciiValue! % 2 == 1
}
}
```func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0
}.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0
}.count
}
```$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // type 'Int' cannot be used as a boolean; test for '!= 0' instead$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // '=' must have consistent whitespace on both sides$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // cannot force unwrap value of non-optional type 'Int'$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // cannot convert value of type '()' to closure result type 'Bool'$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // integer literal value '0' cannot be used as a boolean; did you mean 'false'?$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // '=' must have consistent whitespace on both sides$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // expression is not assignable: '&&' returns immutable value$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // cannot force unwrap value of non-optional type 'Int'$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // expression is not assignable: '&&' returns immutable value$0 > 10 && ($0 % 10) % 2!= 0 && $0 % 2!= 0 // type 'Int' cannot be used as a boolean; test for '!= 0' insteadfunc specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && ($0 % 10) % 2!= 0 && $0 / 10 % 2!= 0
}.count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter(nums: [15, -73, 14, -15]) == 1
specialFilter(nums: [33, -2, -3, 45, 21, 109]) == 2
Answer:
```swift
func specialFilter(nums: [Int]) -> Int {
return nums.filter {
$0 > 10 && ($0 % 10) % 2!= 0 && $0 / 10 % 2!= 0
}.count
}
```func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var count = 0
var a = Array(repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = Array(repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
for i in 0..<n - 2 {
for j in (i + 1)..<n - 1 {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
for i in 0..<n - 2 {
for j in (i + 1)..<n - 1 {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
for i in 0..<n - 2 {
for j in (i + 1)..<n - 1 {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
for i in 0..<n - 2 {
for j in (i + 1)..<n - 1 {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i-1] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 0..<n {
a[i] = i * i - i + 1
}
for i in 0..<n-2 {
for j in (i+1)..<n-1 {
for k in (j+1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
``` // XCTAssertTrue failedfunc getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
for i in 0..<n - 2 {
for j in (i + 1)..<n - 1 {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Explanation:
a = [1, 3, 7, 13, 21]
The only valid triple is (1, 7, 13).
getMaxTriples(n: 5) == 1
Answer:
```swift
func getMaxTriples(n: Int) -> Int {
var count = 0
var a = [Int](repeating: 0, count: n)
for i in 1...n {
a[i - 1] = i * i - i + 1
}
for i in 0..<n - 2 {
for j in (i + 1)..<n - 1 {
for k in (j + 1)..<n {
if (a[i] + a[j] + a[k]) % 3 == 0 {
count += 1
}
}
}
}
return count
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedEvenLengthStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedEvenLengthStrings
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedStrings
}
```func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedStrings
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted array with a sorted order,
The array is always an array of strings and never an array of numbers,
and it may contain duplicates.
The order of the array should be ascending by length of each word, and you
should return the array sorted by that rule.
If two words have the same length, sort the array alphabetically.
The function should return an array of strings in sorted order.
You may assume that all words will have the same length.
For example:
sortedListSum(lst: ["aa", "a", "aaa"]) == ["aa"]
sortedListSum(lst: ["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
Answer:
```swift
func sortedListSum(lst: [String]) -> [String] {
let evenLengthStrings = lst.filter { $0.count % 2 == 0 }
let sortedStrings = evenLengthStrings.sorted { $0.count < $1.count || ($0.count == $1.count && $0 < $1) }
return sortedStrings
}
```func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n <= 1 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n <= 1 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n <= 1 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n <= 1 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n <= 1 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n <= 1 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
xOrY(n: 7, x: 34, y: 12) == 34
xOrY(n: 15, x: 8, y: 5) == 5
Answer:
```swift
func xOrY(n: Int, x: Int, y: Int) -> Int {
var isPrime = true
if n < 2 {
isPrime = false
} else {
for i in 2..<n {
if n % i == 0 {
isPrime = false
break
}
}
}
return isPrime? x : y
}
```return isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expression of type 'Int' is unusedreturn isPrime? x : y // consecutive statements on a line must be separated by ';'return isPrime? x : y // expected expressionreturn isPrime? x : y // cannot use optional chaining on non-optional value of type 'Bool'func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Double($0.rounded()) }.map { $0 * $0 }
let sum = squares.reduce(0, +)
return sum * 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Double($0.rounded()) }.map { $0 * $0 }
let sum = squares.reduce(0, +)
return sum * 2
}
```return sum * 2 // cannot convert return expression of type 'Double' to return type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}
```let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) } // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}
```let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) } // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Double($0.rounded()) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Double($0.rounded()) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}
``` // XCTAssertTrue failedfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
var squareSum = 0
for num in lst {
if num > 0 && num % 1 == 0 {
sum += Int(num)
squareSum += Int(num * num)
}
}
return 2 * (squareSum - sum)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
var squareSum = 0
for num in lst {
if num > 0 && num % 1 == 0 {
sum += Int(num)
squareSum += Int(num * num)
}
}
return 2 * (squareSum - sum)
}
```if num > 0 && num % 1 == 0 { // '%' is unavailable: For floating point numbers use truncatingRemainder insteadfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
var difference = 0
for num in lst {
if num > 0 && num % 1 == 0 {
sum += Int(num * num)
}
difference += Int(num)
}
return sum + 2 * difference
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
var difference = 0
for num in lst {
if num > 0 && num % 1 == 0 {
sum += Int(num * num)
}
difference += Int(num)
}
return sum + 2 * difference
}
```if num > 0 && num % 1 == 0 { // '%' is unavailable: For floating point numbers use truncatingRemainder insteadfunc doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
var squareSum = 0
for num in lst {
if num > 0 && num % 1 == 0 {
sum += Int(num)
squareSum += Int(num * num)
}
}
return (sum * 2) - squareSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
var squareSum = 0
for num in lst {
if num > 0 && num % 1 == 0 {
sum += Int(num)
squareSum += Int(num * num)
}
}
return (sum * 2) - squareSum
}
```if num > 0 && num % 1 == 0 { // '%' is unavailable: For floating point numbers use truncatingRemainder insteadfunc doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}
```let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) } // cannot convert value of type 'Double' to expected argument type 'Int'func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
var squareSum = 0
for num in lst {
if num > 0 && num % 1 == 0 {
sum += Int(num)
squareSum += Int(num * num)
}
}
return (sum * 2) - squareSum
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
var sum = 0
var squareSum = 0
for num in lst {
if num > 0 && num % 1 == 0 {
sum += Int(num)
squareSum += Int(num * num)
}
}
return (sum * 2) - squareSum
}
```if num > 0 && num % 1 == 0 { // '%' is unavailable: For floating point numbers use truncatingRemainder insteadfunc doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an array of numbers, return the sum of squares of the numbers
in the array that are odd. Ignore numbers that are negative or not integers.
If the input array is empty, return 0.
doubleTheDifference(lst: [1, 3, 2, 0]) == 10
doubleTheDifference(lst: [-1, -2, 0]) == 0
doubleTheDifference(lst: [9, -2]) == 81
doubleTheDifference(lst: [0]) == 0
Answer:
```swift
func doubleTheDifference(lst: [Double]) -> Int {
let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) }
let sum = squares.reduce(0, +)
return sum * 2
}
```let squares = lst.filter { $0 > 0 && $0 == Int($0) }.map { Int($0 * $0) } // cannot convert value of type 'Double' to expected argument type 'Int'func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scores and guesses of equal length, where each index shows a match.
Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
the value is 0, and if not, the value is the absolute difference between the guess and the score.
example:
compare(game: [1, 2, 3, 4, 5, 1], guess: [1, 2, 3, 4, 2, -2]) == [0, 0, 0, 0, 3, 3]
compare(game: [0, 5, 0, 0, 0, 4], guess: [4, 1, 1, 0, 0, -2]) == [4, 4, 1, 0, 0, 6]
Answer:
```swift
func compare(game: [Int], guess: [Int]) -> [Int] {
return game.enumerated().map { index, score in
abs(score - guess[index])
}
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.prefix(1).uppercased())\(className.dropFirst()).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.prefix(1).uppercased())\(className.dropFirst()).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className.capitalized).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typeextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className).\(strongestExtension)"
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You will be given the name of a class (a string) and an array of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the extension's name, the strength is given by the fraction CAP - SM.
You should find the strongest extension and return a string in this
format: ClassName.StrongestExtensionName.
If there are two or more extensions with the same strength, you should
choose the one that comes first in the array.
For example, if you are given "Slices" as the class and an array of the
extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
(its strength is -1).
Example:
Strongest_Extension(className: "myClass", extensions: ["AA", "Be", "CC"]) == "my_class.AA"
Answer:
```swift
func Strongest_Extension(className: String, extensions: [String]) -> String {
let className = className.lowercased()
let strongestExtension = extensions.sorted { extension1, extension2 in
let strength1 = extension1.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension1.filter("abcdefghijklmnopqrstuvwxyz".contains).count
let strength2 = extension2.filter("ABCDEFGHIJKLMNOPQRSTUVWXYZ".contains).count - extension2.filter("abcdefghijklmnopqrstuvwxyz".contains).count
if strength1 == strength2 {
return extension1 < extension2
}
return strength1 > strength2
}.first!
return "\(className).\(strongestExtension)"
}
```extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // single-quoted string literal found, use '"'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // expected expressionextensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // consecutive statements on a line must be separated by ';'extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // cannot find 'extensions' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'since' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find type 'the' in scopereturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // consecutive statements on a line must be separated by ';'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // return invalid outside of a funcreturn 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // single-quoted string literal found, use '"'return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // cannot find 'strongest' in scope(its strength is -1). // expected ',' separator(its strength is -1). // expected '{' in extension(its strength is -1). // expected member name following '.'(its strength is -1). // expected type(its strength is -1). // expected ':' following argument label and parameter name(its strength is -1). // expected typefunc cycpatternCheck(a: String, b: String) -> Bool {
let a = Array(a)
let b = Array(b)
let blen = b.count
for i in 0..<a.count-blen+1 {
if a[i..<i+blen] == b {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let a = Array(a)
let b = Array(b)
let blen = b.count
for i in 0..<a.count-blen+1 {
if a[i..<i+blen] == b {
return true
}
}
return false
}
```if a[i..<i+blen] == b { // cannot convert value of type '[String.Element]' (aka 'Array<Character>') to expected argument type 'ArraySlice<String.Element>' (aka 'ArraySlice<Character>')func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let bLength = bChars.count
for i in 0..<aChars.count-bLength+1 {
var j = 0
while j < bLength && aChars[i+j] == bChars[j] {
j += 1
}
if j == bLength {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let bLength = bChars.count
for i in 0..<aChars.count-bLength+1 {
var j = 0
while j < bLength && aChars[i+j] == bChars[j] {
j += 1
}
if j == bLength {
return true
}
}
return false
}
``` // XCTAssertTrue failedfunc cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let bLength = bChars.count
for i in 0..<aChars.count-bLength+1 {
if aChars[i] == bChars[0] && aChars[i+bLength-1] == bChars[bLength-1] {
var j = 0
while j < bLength && aChars[i+j] == bChars[j] {
j += 1
}
if j == bLength {
return true
}
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let bLength = bChars.count
for i in 0..<aChars.count-bLength+1 {
if aChars[i] == bChars[0] && aChars[i+bLength-1] == bChars[bLength-1] {
var j = 0
while j < bLength && aChars[i+j] == bChars[j] {
j += 1
}
if j == bLength {
return true
}
}
}
return false
}
``` // XCTAssertTrue failedfunc cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if aChars.count < bChars.count {
return false
}
for i in 0..<aChars.count {
if aChars[i]!= bChars[0] {
continue
}
var j = 0
while j < bChars.count && i < aChars.count && aChars[i] == bChars[j] {
i += 1
j += 1
}
if j == bChars.count {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if aChars.count < bChars.count {
return false
}
for i in 0..<aChars.count {
if aChars[i]!= bChars[0] {
continue
}
var j = 0
while j < bChars.count && i < aChars.count && aChars[i] == bChars[j] {
i += 1
j += 1
}
if j == bChars.count {
return true
}
}
return false
}
```if aChars[i]!= bChars[0] { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')if aChars[i]!= bChars[0] { // '=' must have consistent whitespace on both sidesif aChars[i]!= bChars[0] { // use of '=' in a boolean context, did you mean '=='?i += 1 // left side of mutating operator isn't mutable: 'i' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let bLength = bChars.count
for i in 0..<aChars.count-bLength+1 {
var j = 0
while j < bLength && aChars[i+j] == bChars[j] {
j += 1
}
if j == bLength {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
let bLength = bChars.count
for i in 0..<aChars.count-bLength+1 {
var j = 0
while j < bLength && aChars[i+j] == bChars[j] {
j += 1
}
if j == bLength {
return true
}
}
return false
}
``` // XCTAssertTrue failedfunc cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if a.count < b.count {
return false
}
for i in 0..<a.count {
if aChars.suffix(b.count) == bChars {
return true
}
aChars.append(aChars.removeFirst())
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if a.count < b.count {
return false
}
for i in 0..<a.count {
if aChars.suffix(b.count) == bChars {
return true
}
aChars.append(aChars.removeFirst())
}
return false
}
```aChars.append(aChars.removeFirst()) // cannot use mutating member on immutable value: 'aChars' is a 'let' constantaChars.append(aChars.removeFirst()) // cannot use mutating member on immutable value: 'aChars' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if aChars.count < bChars.count {
return false
}
for i in 0..<aChars.count {
if aChars[i]!= bChars[0] {
continue
}
var j = 0
while j < bChars.count && i < aChars.count && aChars[i] == bChars[j] {
i += 1
j += 1
}
if j == bChars.count {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if aChars.count < bChars.count {
return false
}
for i in 0..<aChars.count {
if aChars[i]!= bChars[0] {
continue
}
var j = 0
while j < bChars.count && i < aChars.count && aChars[i] == bChars[j] {
i += 1
j += 1
}
if j == bChars.count {
return true
}
}
return false
}
```if aChars[i]!= bChars[0] { // cannot force unwrap value of non-optional type 'String.Element' (aka 'Character')if aChars[i]!= bChars[0] { // '=' must have consistent whitespace on both sidesif aChars[i]!= bChars[0] { // use of '=' in a boolean context, did you mean '=='?i += 1 // left side of mutating operator isn't mutable: 'i' is a 'let' constantfunc cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if a.count < b.count {
return false
}
for i in 0..<a.count-b.count+1 {
if aChars[i..<i+b.count] == bChars {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if a.count < b.count {
return false
}
for i in 0..<a.count-b.count+1 {
if aChars[i..<i+b.count] == bChars {
return true
}
}
return false
}
```if aChars[i..<i+b.count] == bChars { // cannot convert value of type '[String.Element]' (aka 'Array<Character>') to expected argument type 'ArraySlice<String.Element>' (aka 'ArraySlice<Character>')func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if a.count < b.count {
return false
}
for i in 0..<a.count-b.count+1 {
if aChars[i..<i+b.count] == bChars {
return true
}
}
return false
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let aChars = Array(a)
let bChars = Array(b)
if a.count < b.count {
return false
}
for i in 0..<a.count-b.count+1 {
if aChars[i..<i+b.count] == bChars {
return true
}
}
return false
}
```if aChars[i..<i+b.count] == bChars { // cannot convert value of type '[String.Element]' (aka 'Array<Character>') to expected argument type 'ArraySlice<String.Element>' (aka 'ArraySlice<Character>')func cycpatternCheck(a: String, b: String) -> Bool {
let a = Array(a)
let b = Array(b)
for i in 1...a.count {
if a.suffix(i) == b || a.suffix(i) == b.rotated(by: b.count - 1) {
return true
}
}
return false
}
extension Array where Element == Element {
func rotated(by k: Int) -> Array<Element> {
let count = self.count
let index = count - k % count
return Array(self[index..<count] + self[0..<index])
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given 2 words. You need to return true if the second word or any of its rotations is a substring in the first word
cycpatternCheck(a: "abcd", b: "abd") == false
cycpatternCheck(a: "hello", b: "ell") == true
cycpatternCheck(a: "whassup", b: "psus") == false
cycpatternCheck(a: "abab", b: "baa") == true
cycpatternCheck(a: "efef", b: "eeff") == false
cycpatternCheck(a: "himenss", b: "simen") == true
Answer:
```swift
func cycpatternCheck(a: String, b: String) -> Bool {
let a = Array(a)
let b = Array(b)
for i in 1...a.count {
if a.suffix(i) == b || a.suffix(i) == b.rotated(by: b.count - 1) {
return true
}
}
return false
}
extension Array where Element == Element {
func rotated(by k: Int) -> Array<Element> {
let count = self.count
let index = count - k % count
return Array(self[index..<count] + self[0..<index])
}
}
``` // XCTAssertTrue failedfunc evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
evenOddCount(num: -12) == (1, 1)
evenOddCount(num: 123) == (1, 2)
Answer:
```swift
func evenOddCount(num: Int) -> (Int, Int) {
let digits = String(num).map { Int(String($0))! }
let evenCount = digits.filter { $0 % 2 == 0 }.count
let oddCount = digits.filter { $0 % 2!= 0 }.count
return (evenCount, oddCount)
}
```let oddCount = digits.filter { $0 % 2!= 0 }.count // expression is not assignable: binary operator returns immutable valuelet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot convert value of type '()' to closure result type 'Bool'let oddCount = digits.filter { $0 % 2!= 0 }.count // '=' must have consistent whitespace on both sideslet oddCount = digits.filter { $0 % 2!= 0 }.count // cannot force unwrap value of non-optional type 'Int'func intToMiniRoman(number: Int) -> String {
let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
let numerals = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]
var result = ""
var num = number
for i in 0..<values.count {
while num >= values[i] {
result += numerals[i]
num -= values[i]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
let numerals = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]
var result = ""
var num = number
for i in 0..<values.count {
while num >= values[i] {
result += numerals[i]
num -= values[i]
}
}
return result
}
```func intToMiniRoman(number: Int) -> String {
let numeralMap: [Int: String] = [
1000: "m", 900: "cm", 500: "d", 400: "cd",
100: "c", 90: "xc", 50: "l", 40: "xl",
10: "x", 9: "ix", 5: "v", 4: "iv",
1: "i"
]
var result = ""
var remainingNumber = number
for (value, numeral) in numeralMap {
let times = remainingNumber / value
result.append(String(repeating: numeral, count: times))
remainingNumber -= times * value
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let numeralMap: [Int: String] = [
1000: "m", 900: "cm", 500: "d", 400: "cd",
100: "c", 90: "xc", 50: "l", 40: "xl",
10: "x", 9: "ix", 5: "v", 4: "iv",
1: "i"
]
var result = ""
var remainingNumber = number
for (value, numeral) in numeralMap {
let times = remainingNumber / value
result.append(String(repeating: numeral, count: times))
remainingNumber -= times * value
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let romanNumerals = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var remainingNumber = number
for (value, numeral) in romanNumerals {
while remainingNumber >= value {
result += numeral
remainingNumber -= value
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let romanNumerals = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var remainingNumber = number
for (value, numeral) in romanNumerals {
while remainingNumber >= value {
result += numeral
remainingNumber -= value
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
let numerals = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]
var result = ""
var num = number
for i in 0..<values.count {
while num >= values[i] {
result.append(numerals[i])
num -= values[i]
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let values = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
let numerals = ["m", "cm", "d", "cd", "c", "xc", "l", "xl", "x", "ix", "v", "iv", "i"]
var result = ""
var num = number
for i in 0..<values.count {
while num >= values[i] {
result.append(numerals[i])
num -= values[i]
}
}
return result
}
```func intToMiniRoman(number: Int) -> String {
let numeralMap: [Int: String] = [
1000: "m", 900: "cm", 500: "d", 400: "cd",
100: "c", 90: "xc", 50: "l", 40: "xl",
10: "x", 9: "ix", 5: "v", 4: "iv",
1: "i"
]
var result = ""
var remainingNumber = number
for (value, numeral) in numeralMap {
let times = remainingNumber / value
result.append(String(repeating: numeral, count: times))
remainingNumber -= times * value
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let numeralMap: [Int: String] = [
1000: "m", 900: "cm", 500: "d", 400: "cd",
100: "c", 90: "xc", 50: "l", 40: "xl",
10: "x", 9: "ix", 5: "v", 4: "iv",
1: "i"
]
var result = ""
var remainingNumber = number
for (value, numeral) in numeralMap {
let times = remainingNumber / value
result.append(String(repeating: numeral, count: times))
remainingNumber -= times * value
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let roman = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in roman {
while num >= key {
result += value
num -= key
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let roman = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in roman {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let numeralMap: [Int: String] = [
1000: "m",
900: "cm",
500: "d",
400: "cd",
100: "c",
90: "xc",
50: "l",
40: "xl",
10: "x",
9: "ix",
5: "v",
4: "iv",
1: "i"
]
var result = ""
var remainingNumber = number
for (value, numeral) in numeralMap {
while remainingNumber >= value {
result += numeral
remainingNumber -= value
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let numeralMap: [Int: String] = [
1000: "m",
900: "cm",
500: "d",
400: "cd",
100: "c",
90: "xc",
50: "l",
40: "xl",
10: "x",
9: "ix",
5: "v",
4: "iv",
1: "i"
]
var result = ""
var remainingNumber = number
for (value, numeral) in numeralMap {
while remainingNumber >= value {
result += numeral
remainingNumber -= value
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let numeralMap: [Int: String] = [
1000: "m",
900: "cm",
500: "d",
400: "cd",
100: "c",
90: "xc",
50: "l",
40: "xl",
10: "x",
9: "ix",
5: "v",
4: "iv",
1: "i"
]
var result = ""
var remainingNumber = number
for (value, numeral) in numeralMap {
while remainingNumber >= value {
result.append(numeral)
remainingNumber -= value
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let numeralMap: [Int: String] = [
1000: "m",
900: "cm",
500: "d",
400: "cd",
100: "c",
90: "xc",
50: "l",
40: "xl",
10: "x",
9: "ix",
5: "v",
4: "iv",
1: "i"
]
var result = ""
var remainingNumber = number
for (value, numeral) in numeralMap {
while remainingNumber >= value {
result.append(numeral)
remainingNumber -= value
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let roman = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in roman {
while num >= key {
result += value
num -= key
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let roman = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in roman {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc intToMiniRoman(number: Int) -> String {
let roman = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in roman {
while num >= key {
result += value
num -= key
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
intToMiniRoman(number: 19) == "xix"
intToMiniRoman(number: 152) == "clii"
intToMiniRoman(number: 426) == "cdxxvi"
Answer:
```swift
func intToMiniRoman(number: Int) -> String {
let roman = [1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i"]
var result = ""
var num = number
for (key, value) in roman {
while num >= key {
result += value
num -= key
}
}
return result
}
``` // XCTAssertTrue failedfunc rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}
```func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}
```func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}
```func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}
```func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}
```func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}
```func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}
```func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}
```func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[2] == sortedSquares[0] + sortedSquares[1]
}
```func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[0] + sortedSquares[1] == sortedSquares[2]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given the lengths of the three sides of a triangle. Return true if the three
sides form a right-angled triangle, false otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
rightAngleTriangle(a: 3, b: 4, c: 5) == true
rightAngleTriangle(a: 1, b: 2, c: 3) == false
Answer:
```swift
func rightAngleTriangle(a: Int, b: Int, c: Int) -> Bool {
let squares = [a * a, b * b, c * c]
let sortedSquares = squares.sorted()
return sortedSquares[0] + sortedSquares[1] == sortedSquares[2]
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.sorted())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.sorted())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.sorted())
let count = unique.count
if count > max.0 || (count == max.0 && word < max.1) {
max = (count, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.sorted())
let count = unique.count
if count > max.0 || (count == max.0 && word < max.1) {
max = (count, word)
}
}
return max.1
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.sorted())
let count = unique.count
if count > max.0 || count == max.0 && word < max.1 {
max = (count, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.sorted())
let count = unique.count
if count > max.0 || count == max.0 && word < max.1 {
max = (count, word)
}
}
return max.1
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.lowercased())
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.map { String($0) })
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word.map { String($0) })
if unique.count > max.0 || (unique.count == max.0 && word < max.1) {
max = (unique.count, word)
}
}
return max.1
}
```func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word).count
if unique > max.0 || (unique == max.0 && word < max.1) {
max = (unique, word)
}
}
return max.1
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Write a function that accepts an array of strings.
The array contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
findMax(words: ["name", "of", "string"]) == "string"
findMax(words: ["name", "enam", "game"]) == "enam"
findMax(words: ["aaaaaaa", "bb", "cc"]) == "aaaaaaa"
Answer:
```swift
func findMax(words: [String]) -> String {
var max = (0, "")
for word in words {
let unique = Set(word).count
if unique > max.0 || (unique == max.0 && word < max.1) {
max = (unique, word)
}
}
return max.1
}
```@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = max(0, remaining - (need - number))
return [totalEaten, remainingCarrots]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = max(0, remaining - (need - number))
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + remaining
let left = total - need
return [total, left > 0? left : 0]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + remaining
let left = total - need
return [total, left > 0? left : 0]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'return [total, left > 0? left : 0] // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return [total, left > 0? left : 0] // expected ',' separatorreturn [total, left > 0? left : 0] // cannot convert value of type 'Bool' to expected element type 'Int'return [total, left > 0? left : 0] // cannot use optional chaining on non-optional value of type 'Int'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = max(0, remaining - (need - number))
return [totalEaten, remainingCarrots]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = max(0, remaining - (need - number))
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = max(0, remaining - (need - number))
return [totalEaten, remainingCarrots]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = max(0, remaining - (need - number))
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = max(0, remaining - (need - number))
return [totalEaten, remainingCarrots]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = max(0, remaining - (need - number))
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = remaining - min(need - number, remaining)
return [totalEaten, remainingCarrots]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = remaining - min(need - number, remaining)
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let carrotsLeft = remaining - min(need - number, remaining)
return [totalEaten, carrotsLeft]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let carrotsLeft = remaining - min(need - number, remaining)
return [totalEaten, carrotsLeft]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let carrotsLeft = max(0, remaining - (need - number))
return [totalEaten, carrotsLeft]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let carrotsLeft = max(0, remaining - (need - number))
return [totalEaten, carrotsLeft]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = remaining - min(need - number, remaining)
return [totalEaten, remainingCarrots]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let totalEaten = number + min(need - number, remaining)
let remainingCarrots = remaining - min(need - number, remaining)
return [totalEaten, remainingCarrots]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + remaining
let left = total - need
return [total, left > 0? left : 0]
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.
Example:
Variables:
@number : integer
the number of carrots that you have eaten.
@need : integer
the number of carrots that you need to eat.
@remaining : integer
the number of remaining carrots thet exist in stock
Constrain:
* 0 <= number <= 1000
* 0 <= need <= 1000
* 0 <= remaining <= 1000
Have fun :)
eat(number: 5, need: 6, remaining: 10) == [11, 4]
eat(number: 4, need: 8, remaining: 9) == [12, 1]
eat(number: 1, need: 10, remaining: 10) == [11, 0]
eat(number: 2, need: 11, remaining: 5) == [7, 0]
Answer:
```swift
func eat(number: Int, need: Int, remaining: Int) -> [Int] {
let total = number + remaining
let left = total - need
return [total, left > 0? left : 0]
}
```@number : integer // expected expressionthe number of carrots that you have eaten. // expected member name following '.'the number of carrots that you need to eat. // expected member name following '.'return [total, left > 0? left : 0] // value of optional type 'Int?' must be unwrapped to a value of type 'Int'return [total, left > 0? left : 0] // expected ',' separatorreturn [total, left > 0? left : 0] // cannot convert value of type 'Bool' to expected element type 'Int'return [total, left > 0? left : 0] // cannot use optional chaining on non-optional value of type 'Int'func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two arrays operators, and operands. The first array has basic algebra operations, and
the second array is an array of integers. Use the two given arrays to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
Floor division ( // )
Exponentiation ( ** )
Example:
operator['+', '*', '-']
array = [2, 3, 4, 5]
result = 2 + 3 * 4 - 5
=> result = 9
Note:
The length of operator array is equal to the length of operand array minus one.
Operand is an array of of non-negative integers.
Operator array has at least one operator, and operand array has at least two operands.
Answer:
```swift
func doAlgebra(operators: [String], operands: [Int]) -> Int {
var result = operands[0]
for i in 0..<operators.count {
let operator = operators[i]
let operand = operands[i + 1]
switch operator {
case "+":
result += operand
case "-":
result -= operand
case "*":
result *= operand
case "//":
result /= operand
case "**":
result = pow(result, operand)
default:
break
}
}
return result
}
```let operator = operators[i] // keyword 'operator' cannot be used as an identifier hereswitch operator { // expected operator name in operator declarationswitch operator { // expected expression in 'switch' statementfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}
```result.append(String(numbers.index(of: char)!)) // no exact matches in call to initializerfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
var isLetter = false
for char in s {
if letters.contains(char) {
isLetter = true
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(char)
}
}
if!isLetter {
result = String(s.reversed())
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
var isLetter = false
for char in s {
if letters.contains(char) {
isLetter = true
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(char)
}
}
if!isLetter {
result = String(s.reversed())
}
return result
}
```if!isLetter { // expected expression, var, or let in 'if' conditionfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
var isLetter = false
for char in s {
if letters.contains(char) {
isLetter = true
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(char)
}
}
if!isLetter {
result = String(s.reversed())
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
var isLetter = false
for char in s {
if letters.contains(char) {
isLetter = true
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(char)
}
}
if!isLetter {
result = String(s.reversed())
}
return result
}
```if!isLetter { // expected expression, var, or let in 'if' conditionfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
return result
}
```result.append(String(numbers.index(of: char)!)) // no exact matches in call to initializerfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
return result
}
```result.append(String(numbers.index(of: char)!)) // no exact matches in call to initializerfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}
```result.append(String(numbers.index(of: char)!)) // no exact matches in call to initializerfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}
``` // XCTAssertTrue failedfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
return result
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyz"
let numbers = "0123456789"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else if numbers.contains(char) {
result.append(String(numbers.index(of: char)!))
} else {
result.append(char)
}
}
return result
}
```result.append(String(numbers.index(of: char)!)) // no exact matches in call to initializerfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}
``` // XCTAssertTrue failedfunc solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve(s: "1234") == "4321"
solve(s: "ab") == "AB"
solve(s: "#a@C") == "#A@c"
Answer:
```swift
func solve(s: String) -> String {
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
var result = ""
for char in s {
if letters.contains(char) {
if letters.contains(char.lowercased()) {
result.append(char.uppercased())
} else {
result.append(char.lowercased())
}
} else {
result.append(char)
}
}
if result.contains(where: letters.contains) {
return result
} else {
return String(result.reversed())
}
}
``` // XCTAssertTrue failedimport CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
return hash
}
return md5.map { String(format: "%02x", $0) }.joined()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
return hash
}
return md5.map { String(format: "%02x", $0) }.joined()
}
```guard!text.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionCC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}
```guard!text.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}
extension Data {
var md5: Data {
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(self.bytes, CC_LONG(self.count), &hash)
return Data(bytes: hash)
}
}
extension Data {
var hexString: String {
return map { String(format: "%02x", $0) }.joined()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}
extension Data {
var md5: Data {
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(self.bytes, CC_LONG(self.count), &hash)
return Data(bytes: hash)
}
}
extension Data {
var hexString: String {
return map { String(format: "%02x", $0) }.joined()
}
}
```guard!text.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // cannot call value of non-function type 'Data'CC_MD5(self.bytes, CC_LONG(self.count), &hash) // value of type 'Data' has no member 'bytes'return Data(bytes: hash) // 'init(bytes:)' is deprecated: use `init(_:)` insteadimport CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}
```guard!text.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // value of type 'Data' has no member 'md5'import CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}
extension Data {
func md5() -> Data {
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(self.bytes, CC_LONG(self.count), &hash)
return Data(bytes: hash)
}
}
extension Data {
var hexString: String {
return map { String(format: "%02x", $0) }.joined()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}
extension Data {
func md5() -> Data {
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(self.bytes, CC_LONG(self.count), &hash)
return Data(bytes: hash)
}
}
extension Data {
var hexString: String {
return map { String(format: "%02x", $0) }.joined()
}
}
```guard!text.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionCC_MD5(self.bytes, CC_LONG(self.count), &hash) // value of type 'Data' has no member 'bytes'return Data(bytes: hash) // 'init(bytes:)' is deprecated: use `init(_:)` insteadimport CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}
extension Data {
var md5: Data {
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(self.bytes, CC_LONG(self.count), &digest)
return Data(bytes: digest)
}
}
extension Data {
var hexString: String {
return map { String(format: "%02x", $0) }.joined()
}
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.md5()
return md5.hexString
}
extension Data {
var md5: Data {
var digest = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(self.bytes, CC_LONG(self.count), &digest)
return Data(bytes: digest)
}
}
extension Data {
var hexString: String {
return map { String(format: "%02x", $0) }.joined()
}
}
```guard!text.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionlet md5 = data.md5() // cannot call value of non-function type 'Data'CC_MD5(self.bytes, CC_LONG(self.count), &digest) // value of type 'Data' has no member 'bytes'return Data(bytes: digest) // 'init(bytes:)' is deprecated: use `init(_:)` insteadimport CommonCrypto
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
return hash
}
let md5String = md5.map { String(format: "%02x", $0) }.joined()
return md5String
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
guard!text.isEmpty else { return nil }
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
return hash
}
let md5String = md5.map { String(format: "%02x", $0) }.joined()
return md5String
}
```guard!text.isEmpty else { return nil } // expected expression, var, let or case in 'guard' conditionCC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
return hash
}
let md5String = md5.map { String(format: "%02x", $0) }.joined()
return md5String
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
return hash
}
let md5String = md5.map { String(format: "%02x", $0) }.joined()
return md5String
}
```CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var result = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &result)
return result
}
let md5String = md5.map { String(format: "%02x", $0) }.joined()
return md5String
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var result = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &result)
return result
}
let md5String = md5.map { String(format: "%02x", $0) }.joined()
return md5String
}
```CC_MD5(bytes.baseAddress, CC_LONG(data.count), &result) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).import CommonCrypto
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
return hash
}
let md5String = md5.map { String(format: "%02x", $0) }.joined()
return md5String
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return nil.
stringToMd5(text: "Hello world") == "3e25960a79dbc69b674cd4ec67a72c62"
Answer:
```swift
func stringToMd5(text: String) -> String? {
if text.isEmpty {
return nil
}
let data = text.data(using:.utf8)!
let md5 = data.withUnsafeBytes { (bytes: UnsafeRawBufferPointer) -> [UInt8] in
var hash = [UInt8](repeating: 0, count: Int(CC_MD5_DIGEST_LENGTH))
CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash)
return hash
}
let md5String = md5.map { String(format: "%02x", $0) }.joined()
return md5String
}
```CC_MD5(bytes.baseAddress, CC_LONG(data.count), &hash) // 'CC_MD5' was deprecated in macOS 10.15: This function is cryptographically broken and should not be used in security contexts. Clients should migrate to SHA256 (or stronger).func generateIntegers(a: Int, b: Int) -> [Int] {
let min = min(a, b)
let max = max(a, b)
var result = [Int]()
for i in min...max {
let digits = String(i).map { Int(String($0))! }
let evenDigits = digits.filter { $0 % 2 == 0 }
if!evenDigits.isEmpty {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
let min = min(a, b)
let max = max(a, b)
var result = [Int]()
for i in min...max {
let digits = String(i).map { Int(String($0))! }
let evenDigits = digits.filter { $0 % 2 == 0 }
if!evenDigits.isEmpty {
result.append(i)
}
}
return result.sorted()
}
```if!evenDigits.isEmpty { // expected expression, var, or let in 'if' conditionfunc generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
let min = min(a, b)
let max = max(a, b)
var result = [Int]()
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
let min = min(a, b)
let max = max(a, b)
var result = [Int]()
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
let min = min(a, b)
let max = max(a, b)
var result = [Int]()
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
let min = min(a, b)
let max = max(a, b)
var result = [Int]()
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
let min = min(a, b)
let max = max(a, b)
var result = [Int]()
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
let min = min(a, b)
let max = max(a, b)
var result = [Int]()
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
if i % 2 == 0 {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
if i % 2 == 0 {
result.append(i)
}
}
return result.sorted()
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}
```func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}Question:
Write code in Swift programming language. Don't include usage examples or tests.
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generateIntegers(a: 2, b: 8) == [2, 4, 6, 8]
generateIntegers(a: 8, b: 2) == [2, 4, 6, 8]
generateIntegers(a: 10, b: 14) == [] as [Int]
Answer:
```swift
func generateIntegers(a: Int, b: Int) -> [Int] {
var result = [Int]()
let min = min(a, b)
let max = max(a, b)
for i in min...max {
let digits = String(i).map { Int(String($0))! }
if digits.contains(where: { $0 % 2 == 0 }) {
result.append(i)
}
}
return result.sorted()
}
```